First verify that is a vector space. Sums and scalar multiples preserve continuity and the condition at zero. For every partition of an interval , the triangle inequality and absolute homogeneity of a norm of the absolute value imply
Taking suprema yields
For the second equality follows directly from . In particular, finite variation is preserved, so is closed under these operations.
Nonnegativity is immediate. For any , use the partition of an interval , omitting repeated endpoints if necessary, to get
Thus forces , and conversely has zero total variation of a function. These observations prove that is a norm on .
Applying the same bound to gives
Therefore convergence in the anchored variation norm implies uniform convergence on . The anchoring condition removes the nonzero constant functions which otherwise have zero total variation of a function.

Articles by others on the same topic (0)

There are currently no matching articles.