For a slender elastic beam undergoing small bending, cross-sections remain approximately plane and perpendicular to the centreline. At distance from the neutral axis, longitudinal strain is , where is curvature. Linear elasticity gives , so the bending moment has magnitudeHere is the second moment of cross-sectional area, not a mass moment of inertia. For width and depth in the bending direction, . The cubic depth dependence explains why a deep beam resists bending more effectively than the same material spread sideways.
For a uniform beam with transverse displacement , and bending energy is . Balancing transverse load yields the Euler-Bernoulli beam equation under a consistent sign convention. Supports specify values of deflection, slope, moment or shear; the equation alone does not fix the response.
Now apply a compressive end load . A small deflection shortens the axial projection by , so the total potential energy relative to the straight configuration isIts stationary equation isFor pinned ends, and the end moments vanish, so . The candidate shapes require . The first loss of stability is consequentlyAt smaller , the quadratic energy is positive; beyond this threshold the straight configuration no longer minimizes it. End restraint changes the threshold: clamped–clamped gives and clamped–free gives , equivalently an effective-length correction. A column buckles in the direction of smaller flexural rigidity. Euler buckling is a geometric instability within elastic response; yielding or crushing can occur first for a short thick strut. Large deflections, shear deformation and imperfections require refinements of the ideal slender-beam model.
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