Stoichiometry of ionic compounds (${\sum }_i{\nu }_i{z}_i=0$)

For a neutral formula unit, let ${\nu }_i$ count ions of type $i$ with electric charge $z_{i}e$, where $e$ is the elementary charge. The stoichiometry must satisfyFor ${\mathrm{Na}}^{+}$ and ${\mathrm{Cl}}^{-}$, the smallest positive counts are $1:1$. For ${\mathrm{Ca}}^{2+}$ and ${\mathrm{Cl}}^{-}$, they are $1:2$, giving calcium chloride $\mathrm{CaC}{\mathrm{l}}_2$: $1(2)+2(-1)=0$. The formula counts ions, not the number of nearest neighbours. A counterion is the oppositely charged partner needed to balance a charged species; its identity can change solubility and other properties without changing the identity of that species.^[ref]