Quantum state continuity at a finite Hamiltonian step Created 2026-10-14 Updated 2026-10-18
For a fixed Hilbert space, a bounded self-adjoint Hamiltonian operator with a finite step at does not deliver an instantaneous rotation of the quantum state. Integrating the Schrödinger equation across a short interval givesFor a normalized quantum state and in operator norm, the difference has norm at most , which tends to zero. The time derivative can jump even though the quantum state is continuous. Here is the reduced Planck constant. An instantaneous replacement of the eigenbasis changes coordinates, not the vector being represented.
For a real switch occupying , remove any real scalar contribution that produces only a global phase, and write . The same integral argument gives the sufficient bounded-model estimateThus controls the sudden approximation up to a global phase. For any normalized final energy eigenstate, its probability amplitude differs from the instantaneous-switch value by at most , and its Born rule probability differs by at most . These are sufficient error bounds, not necessary criteria. For the fixed-gap two-level sudden quench, any switching path with a unit vector has operator norm , giving .
This estimate is deliberately for bounded Hamiltonian operators. An unbounded energy spectrum does not supply a finite global ; relevant quantum states, operator domains and excited energy eigenvalues require separate control. The adiabatic theorem also requires hypotheses about the path and its spectral gaps; there is no universal switch-duration criterion covering all spectra. The cold-atom collapse and revival after a lattice quench illustrates how a single switch can be sudden for one degree of freedom and slow for another.
Sudden approximation Created 2026-10-05 Updated 2026-10-13
The sudden approximation treats a rapid, finite change of a Hamiltonian operator as leaving the quantum state approximately unchanged during the switch. The energy measurement can nevertheless change immediately: the same quantum state has different probability amplitudes in the new eigenbasis. Compute their inner products with the new energy eigenstates, then apply the Born rule. The two-level sudden quench below makes this distinction quantitative without assuming the change is small.
An ideal finite step has exact quantum state continuity at a finite Hamiltonian step; a finite-duration implementation has a small evolution error under the bounded-model conditions below. An impulsive quantum kick is different: its Hamiltonian operator grows as its duration shrinks, retaining a finite integrated action and a finite change of quantum state. A sudden approximation therefore concerns short evolution during switching, not conservation of energy during externally driven change. The subsequent unitary time evolution can be substantial.[ref]
Fluctuation theorems: Work is not an observable by Peter Talkner and others. Talkner, Lutz and Hänggi, p. 2, paragraph before equation (7): sudden switch gives the identity time-evolution operator
Two-level sudden quench 2026-10-14
Take an isolated two-level system, or a spin one-half qubit, with Pauli matrices . Let and . The initial and final Hamiltonian operators areThe energy gaps are . Prepare the initial ground state , with energy eigenvalue . A final orthonormal eigenbasis isDirect matrix multiplication gives and . The unchanged initial quantum state is . Its new probability amplitudes are the inner products ; the Born rule gives . The angle between the real amplitude vectors is , whereas the Hamiltonian axis on the Bloch sphere rotates through .
At , and , so the final energy measurement gives with probability and with probability . At the initial ground state remains the final ground state; at it is the final excited energy eigenstate. These statements are about the new energy labels, not an instantaneous physical rotation of the quantum state.
