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The derivative is the generator of the translation group by Ciro Santilli 35 Updated 2025-01-10 +Created 1970-01-01
Take the group of all Translation in .
The way to think about this is:
- the translation group operates on the argument of a function
- the generator is an operator that operates on itself
So let's take the exponential map:and we notice that this is exactly the Taylor series of around the identity element of the translation group, which is 0! Therefore, if behaves nicely enough, within some radius of convergence around the origin we have for finite :
This example shows clearly how the exponential map applied to a (differential) operator can generate finite (non-infinitesimal) Translation!
Fisher Scientific UVP LM-26E Benchtop 2UV Transilluminator by Ciro Santilli 35 Updated 2025-01-10 +Created 1970-01-01
www.bidspotter.com/en-us/auction-catalogues/bscsur/catalogue-id-bscsur10011/lot-c6605b41-1a14-40e5-a255-a5c5000866e0 (archive) Cannot exact same product on official website, but here is a similar one: www.fishersci.co.uk/shop/products/lm-26-2uv-transilluminator/12382038 (archive).
That's Ciro Santilli's favorite. Of course, there is a huge difference between physical and non physical jobs. But one could start with replacing desk jobs!
This is how you transform the Lagrangian into the Hamiltonian.
Matrix representation of a symmetric bilinear form by Ciro Santilli 35 Updated 2025-01-10 +Created 1970-01-01
Like the matrix representation of a bilinear form, it is a matrix, but now the matrix has to be a symmetric matrix.
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