 Solution

Momentum-resolved photoemission and directional tunneling can map the magnitude and nodes of the cuprate gap. Low-temperature heat capacity, thermal transport and penetration-depth measurements constrain the low-energy quasiparticle spectrum. These probes do not all determine the relative sign of the gap. A phase-sensitive test of d-wave pairing uses Josephson interference between differently oriented crystal regions. In the tricrystal half-flux experiment, a superconducting film crosses three designed grain boundaries; a frustrated ring can produce a half-flux signal detected with a scanning SQUID. Unfrustrated geometries supply controls. This probes phase structure beyond merely finding a V-shaped tunneling spectrum.^[ref]

For the ideal nearest-neighbor square lattice at one electron per site including both spins, particle-hole symmetry puts the chemical potential at zero. The two requested cuts areThe first runs from $-4t$ at the zone center to zero at $k_{x}a=\pm \pi$; the diagonal cut crosses zero at $k_{x}a=\pm \pi /2$. The Fermi surface obeys $\cos k_{x}a+\cos k_{y}a=0$, giving the diamond $|k_x|+|k_y|=\pi /a$ in the first Brillouin zone.

Near the specified node define $\delta \mathbf{k}=\mathbf{k}-{\mathbf{k}}_0$ andExpanding $\cos (\pi /2+\delta ka)=-a\delta k+O((a\delta k{)}^3)$ giveswhere $\alpha =2\sqrt{2}ta$ and $\beta =\sqrt{2}{\Delta }_{0}a$. ThereforeThere are four such nodes. An energy contour about one node encloses momentum area $\pi E^2/(\alpha \beta )$. Counting all four nodes and two independent spin quasiparticles, with one state per $(2\pi {)}^2$ of momentum area per unit real-space area, gives the positive-excitation count and nodal quasiparticle density of states in a two-dimensional d-wave superconductorThis counts thermally excitable Bogoliubov modes, including particle-like and hole-like excitations, not the electron-addition spectral density alone. That distinction prevents a factor-of-two ambiguity. It is a per-layer result; dividing by the layer spacing gives the corresponding volume density in the independent-layer approximation.

The thermal energy density above its zero-temperature value follows from Fermi occupation:ThusThis clean nodal contribution assumes $k_{B}T$ small compared with the scale over which linearization fails; impurity states and other excitations can add further terms.

In the vortex state, each flux quantum occupies area of order $\pi R^2={\Phi }_0/B$, so $R\propto B^{-1/2}$. Outside a core of radius $\xi$, the phase flow has magnitude $v_s(r)\simeq \kappa /(2\pi r)$ in the simple circular-cell estimate, with $\kappa =h/M_{\mathrm{pair}}$ and condensed-pair mass $M_{\mathrm{pair}}$. Its cell average isThe signed vector average can vanish around a vortex; the relevant quantity is a typical magnitude or Doppler shift, not a net transport velocity. Flow shifts nodal energies by order $\hslash {\mathbf{v}}_s\cdot {\mathbf{k}}_F$. Because the zero-field nodal density of states is linear in energy, averaging the magnitude of these shifts produces a residual density of states proportional to $\sqrt{B}$. The resulting Volovik effect givesThis is the clean semiclassical nodal regime, at temperatures below the field-induced Doppler scale and in an appropriate mixed-state field range. Core states, disorder, Zeeman splitting and screening can modify it. Its replacement by a square root of applied field additionally assumes the mean induction tracks that field away from the lower-critical-field onset; it is not an exact all-field law.