Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 13B b iii Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 13B b ii Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 13B b i Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 13B a Solution Created 2026-09-24 Updated 2026-10-03
A branch point of a multivalued analytic function is a point around which analytic continuation along a closed loop can return a different value. A branch cut is a curve or union of curves removed from the domain so that loops causing this monodromy are excluded and one single-valued branch can be chosen.
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 11F b v Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 11F b iv Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 11F b iii Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 11F b ii Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 11F b i Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 11F a Solution Created 2026-09-24 Updated 2026-10-03
For , define its Bernstein polynomialIf , thenLet . By uniform continuity, for any choose such that whenever . Splitting the expectation according to that event and using Chebyshev's inequality gives, uniformly in ,For sufficiently large this is below . Thus uniformly on . An affine change of variable treats every compact interval, proving the Weierstrass approximation theorem.
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 10D b Solution Created 2026-09-24 Updated 2026-10-03
The no-cloning theorem for two pure states states that no single unitary operator can clone two distinct nonorthogonal states. Suppose, to the contrary, thatPreservation of the inner product by givesWriting , this requires or . The first case is orthogonality; the second means that the normalized states represent the same ray. Both contradict the assumptions. Therefore distinct nonorthogonal quantum states cannot be cloned by a unitary process.
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 10D a Solution Created 2026-09-24 Updated 2026-10-03
For , the Controlled-NOT gate givesA cloned product would instead beEquality up to a physically irrelevant global phase requires . ThusFor a genuine superposition it creates quantum entanglement instead of two independent copies.
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 7B b Solution Created 2026-09-24 Updated 2026-10-03
Start from the product of two Gamma function integrals:Use the sum-and-ratio substitution for gamma integralswhose Jacobian is . Absolute convergence for justifies the change of variables and separates the integral:Therefore
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 7B a Solution Created 2026-09-24 Updated 2026-10-18
In the integral defining the Beta function, put and then . Symmetry givesThis proves the identity for . Both sides extend by analytic continuation to the same meromorphic function, equivalently by the beta-gamma identity and the Gamma duplication formula. The identity holds meromorphically for every ; both sides are finite for and have matching poles at the excluded points.
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 6C c Solution Created 2026-09-24 Updated 2026-10-03
The deterministic equation has solution and is identical in form to the equation for the stochastic expected value. It therefore identifies only the net rateThe variance equation also contains the total event rate . Once and are inferred,The deterministic trajectory cannot distinguish frequent births and deaths that nearly cancel from infrequent events with the same net growth, whereas fluctuations can.
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 6C b Solution Created 2026-09-24 Updated 2026-10-03
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 6C a Solution Created 2026-09-24 Updated 2026-10-03
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 4G c Solution Created 2026-09-24 Updated 2026-10-03
Take a context-free grammar for with start symbol , rename nonterminals if necessary, and add a fresh start symbol withEvery derivation concatenates finitely many words of , and every finite concatenation can be derived. The resulting grammar generates , proving closure of context-free languages under Kleene star.
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 4G b iii Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 4G b ii Created 2026-09-24 Updated 2026-09-24
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