Solution

Past exam of the mathematics course of the University of Cambridge / 2018 / ii / Paper 1 / 29K / a / Solution

{c}
{wiki=Hardy–Weinberg_principle}

For two alleles $A,B$ sampled independently with frequencies $1-\theta$ and $\theta$, the genotype probabilities under Hardy-Weinberg equilibrium are
$$
P(AA)=(1-\theta)^2,
\qquad P(AB)=2\theta(1-\theta),
\qquad P(BB)=\theta^2.
$$


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 Incoming links: Hardy-Weinberg principle