Rotate any geodesic into an equatorial plane of the magnetically charged dilaton black hole. Conserved energy and angular momentum are and . Normalizing its tangent to , with for timelike, null and spacelike geodesics, gives . Thus its radial equation is . Radial null rays have and use the same Schwarzschild tortoise coordinate with replaced by .
Past exam of the mathematics course of the University of Cambridge 2008 ii Paper 4 36E Solution Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 52 1 a Solution Created 2026-10-03 Updated 2026-10-06
Use geometrized units and metric signature , with . In the exterior of Schwarzschild spacetime, put . The Schwarzschild tortoise coordinate satisfiesThe retarded and advanced null coordinates and then give . The logarithmic divergence of suggests exponentiating these null coordinates. In the right exterior define the Kruskal–Szekeres coordinatesTheir product eliminates :Since and , the Schwarzschild metric becomesHere is an implicitly defined function of . The derivative of the right side with respect to is , which is nonzero at . The inverse function theorem therefore makes smooth across that surface, and the coefficient of tends to . Thus the Schwarzschild event horizon is a coordinate singularity of the original chart, while this Lorentzian metric remains regular there.
Extend the Kruskal–Szekeres coordinates to all real with . The signs give two exterior regions, and , a future black hole region , and a past white hole region . The event horizons are or , intersecting at the bifurcation surface. The boundary has and is a genuine Schwarzschild singularity, as the Kretschmann scalar diverges there.
Finally, and give and a radial metric proportional to . Hence radial null geodesics have slopes , the event horizons are , and the singular boundaries are . This constructs the maximal Kruskal extension; a black hole produced by collapse need not contain the second exterior or the white hole of that eternal extension.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 311 1 a i Solution Created 2026-10-03 Updated 2026-10-06
Use geometrized units and metric signature . Put in the Schwarzschild metric. The Schwarzschild tortoise coordinate satisfies , soSubstituting gives the Ingoing Eddington-Finkelstein coordinates:The radial metric tensor has determinant and inverse components , , . Thus it is nondegenerate and analytic at . The same expression defines a Lorentzian metric for every , extending the exterior across the future Schwarzschild event horizon into the black hole. It does not include the other exterior or the white hole of the full Kruskal spacetime. At , the Kretschmann scalar diverges, so this is a curvature singularity, not a removable coordinate singularity.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 311 3 iii Solution Created 2026-10-03 Updated 2026-10-05
A radial null geodesic has and , so and . In the exterior, for a future-directed ray. Define the analogue of the Schwarzschild tortoise coordinate byThen an outgoing ray satisfies , whereas an ingoing ray satisfies . Thus is constant on outgoing rays and on ingoing rays. The radial two-dimensional metric becomes .
The ingoing coordinate is regular at the future horizon: substituting gives . Inside the horizon, the words outgoing and ingoing refer to the continued null families; both future-directed families in the future interior decrease .
Past exam of the mathematics course of the University of Cambridge 2025 ii Paper 3 37E a Solution Created 2026-09-24 Updated 2026-09-25
WriteFor a radial null ray, the Schwarzschild spacetime line element givesOutside the horizon an ingoing ray has , so it takes the minus sign. Since the Schwarzschild tortoise coordinate obeys ,It follows thatis constant along every ingoing radial light ray.