A form $a{x}^2+bxy+c{y}^2$ is positive definite when $a>0$ and $d=b^2-4ac<0$; equivalence is change by $S{L}_2(\mathbb{Z})$, and reduced means $|b|\le a\le c$ with the standard boundary sign convention. Translating $x\mapsto x+my$ reduces $|b|$, and swapping variables reduces $a$; discriminant bounds force termination. For a reduced form, $|b|\le a\le \sqrt{|d|/3}$ and $b\equiv d(\mathrm{mod}2)$. Discriminant $-28$ has one primitive reduced class, represented by $x^2+7y^2$. Therefore an odd prime is represented exactly when it splits in $\mathbb{Q}(\sqrt{-7})$, namely $(p/7)=1$, with the ramified exception $p=7$. Thus $p=7$ or $p\equiv 1,9,11,15,23,25(\mathrm{mod}28)$.

For the standard symplectic form, $D_f={\sum }_a(f_{p_a}{\partial }_{q^a}-f_{q^a}{\partial }_{p_a})$; a transformation is canonical when it preserves the symplectic form, equivalently Poisson brackets. The Jacobi identity gives $[D_f,D_g]=D_{\{f,g\}}$ with the stated convention. For $Z^A=e^{-s{D}_f}{z}^A$, differentiate $\{Z^A,Z^B\}$ in $s$; Jacobi makes the derivative the Lie transport of the bracket, preserving the canonical constant brackets at $s=0$. Hence every map in the one-parameter flow is canonical.

A point $z_0$ is regular singular when $(z-z_0)p$ and $(z-z_0{)}^{2}q$ are analytic there. The Papperitz symbol records the three singular points and their two local exponents. Here the finite points are $0,1$ and the third is $\infty$. The indicial equations give exponents $(0,-1)$ at $0$ and $(0,0)$ at $1$. Comparing with the hypergeometric equation gives $c=2$, $a+b=2$, $ab=1$, hence $a=b=1$ and exponents $(1,1)$ at infinity. Thus