The coefficient of $x^{n+1}$ in $r_j$ isWith the increasing enumeration, its sign is $(-1{)}^{n+2-j}$. Therefore all terms $(-1{)}^j{c}_j$ have the same sign $(-1{)}^{n+2}$, and $R:={\sum }_j(-1{)}^j{c}_j\ne 0$. The leading coefficient of $t$ is $T:={\sum }_{j}f(y_j)c_j$. Canceling the coefficient of $x^{n+1}$ gives the unique valueBoth interpolants have degree at most $n+1$, so this single cancellation is equivalent to $\mathrm{deg}(t-\lambda r)\le n$.

A recurrent state is null recurrent if its expected elapsed return-cycle time is infinite. Recurrence itself agrees with that of the jump chain, but positive recurrence need not agree, because large states can have very short holding times.

A state is recurrent if, after departure, its return probability is one. For an irreducible nonexplosive continuous-time Markov chain, this is equivalent to recurrence of its jump chain and is shared by all states.

A state of an irreducible continuous-time Markov chain is transient if, after departure, its return probability is less than one. Equivalently its jump chain visits that state only finitely often almost surely. This is a class property.

Perfect correlation means an affine relation almost surely: there are constants $a\ne 0,b$ such that $Y=aX+b$ almost surely. The sign of $a$ is the sign of the correlation coefficient. More precisely, equality in the Cauchy-Schwarz inequality gives

A survey depth $R\sim 400\mathrm{Mpc}$ makes wavelengths substantially larger than its volume poorly measurable. A characteristic inverse depth is $1/R\simeq 2.5\times 10^{-3}\mathrm{Mp}{\mathrm{c}}^{-1}$; a Fourier wavelength that fits across a dimension $L$ instead requires $k\gtrsim 2\pi /L$. For $L$ between $R$ and $2R$, this is roughly $0.008$--$0.016\mathrm{Mp}{\mathrm{c}}^{-1}$. A limited sky patch can have smaller transverse dimensions, so its survey window function raises the practical minimum in those directions. An indicative useful band for a broad survey is around $10^{-2}\mathrm{Mp}{\mathrm{c}}^{-1}$ and above, including scales near equality if its volume is large enough.

There is no upper wavenumber determined by depth alone. Mean separation of observed galaxies, galaxy power spectrum shot noise, angular/redshift resolution, and nonlinear clustering set it. Straightforward linear inference is typically restricted to roughly $k\lesssim 0.1\mathrm{Mp}{\mathrm{c}}^{-1}$ at low redshift, with smaller scales requiring modelling. The magnitude limit does not specify the galaxy comoving number density, so a more precise sampling cutoff cannot be deduced from these data.

The two measurements are complementary. The cosmic microwave background samples a large volume at an early epoch when relevant perturbations are mostly linear, and is free of galaxy bias; its matter-spectrum inference is indirect and depends on projection, cosmological parameters, foregrounds, and cosmic variance. A galaxy survey gives three-dimensional late-time information and can reach smaller scales, but observes biased, discrete tracers: galaxy bias, nonlinear gravitational growth, redshift-space distortions, selection effects, and galaxy power spectrum shot noise must be controlled. Combining both constrains the initial spectrum and its subsequent growth more strongly than either alone, while their overlapping modes test the inferred evolution.

The initial-value problem is a Riemann problem. Both the one-dimensional Euler equations and the two constant initial states are unchanged under the simultaneous scaling $(x,t)\mapsto (\lambda x,\lambda t)$ for $\lambda >0$. There is no imposed length or time scale. Rescaling a physically admissible entropy solution therefore gives another solution with exactly the same initial data. Uniqueness of the physical Riemann solution makes the two coincide, soThe smooth pieces are consequently those in part (a), while shocks and contacts lie on rays $x=st$. Across shocks one uses the conservative mass, momentum and total-energy equations and the entropy admissibility condition, rather than extending the smooth entropy-advection equation through the discontinuity. Scale invariance by itself, without selecting the unique admissible solution, would not justify the uniqueness step.

Secure in the intended ideal setting, with a sound entanglement-purification procedure. Bob confirms receipt before Alice reveals either the random basis string or the randomly chosen check positions. Eve must therefore release the travelling qubits before knowing which basis to use and which positions to protect from disturbance. Bob can then decode because $H^2=I$.

The random check sample tests the same ensemble of encoded transmissions as the retained data. Random computational basis and Hadamard basis encodings make the test sensitive to complementary disturbances; Eve cannot use the targeted zero-error attack available in Protocol 1. For example, measuring every intercepted qubit in one fixed one of these two bases uses the wrong basis half the time, and then disagrees with Alice half the time, producing a bit error rate of $1/4$. A sound entanglement purification protocol uses the tested error bounds, corrects both relevant types of error, and aborts if the noise is too high; secrecy is not claimed for every possible attack without an abort option.

When the protocol succeeds in producing nearly perfect Bell pairs, purity decouples a subsystem from its purification explains why they are nearly independent of Eve, and matching computational basis measurements produce an approximately uniform shared secret key. The disclosed check outcomes are discarded rather than included in that key. This is the standard entanglement-based quantum key distribution ordering: receipt first, basis and sample disclosure second, testing and purification next, and private measurements last.

Impossible to implement as written: Bob is never given the basis string. Step 7 requires him to know which incoming qubits were acted on by a Hadamard gate, but the announcement contains only the check positions. Since $H^{-1}=H$, knowing that a transformation is its own inverse does not identify which qubits need it.

Bob cannot recover the missing information from the qubits alone. For each encoded Bell pair, his reduced density matrix isfor either $b=0$ or $b=1$. His entire received register has the same density matrix $I/2^{2n}$ for every string $b$, so every local measurement in quantum mechanics has statistics independent of $b$. Nor can one fixed unitary undo both possibilities: preserving $|{\Phi }^{+}⟩$ requires that unitary to be proportional to $I$, whereas decoding $(I\otimes H)|{\Phi }^{+}⟩$ requires it to be proportional to $H$. Supplying the missing basis announcement after receipt would repair the protocol and make it the third one, but that communication is absent from the printed sequence.

Insecure as a proposed test-and-purify protocol: the basis string and check positions are announced before receipt. Eve can intercept and store the travelling qubits until the announcement. For each data position with basis bit $b_j$, she measures the stored qubit in the basis $\{H^{b_j}|0⟩,H^{b_j}|1⟩\}$. If the outcome is $z_j$, the Alice–Bob pair becomesand Eve knows $z_j$. She forwards that qubit, and forwards every publicly identified check qubit untouched. After Bob's Hadamard gate decoding, every data pair is the known product state $|z_j{z}_j⟩$, while the unmodified check pairs remain perfect. Thus the check bit error rate is zero even though Eve knows all raw data bits. This is premature basis announcement in quantum key distribution.

The retained data are a separable quantum state with a classical label held by Eve; LOCC cannot turn them into private Bell pairs. Consequently the listed check does not justify the claimed success of the subsequent entanglement purification. A sound purification procedure that independently detects the missing entanglement must fail or abort on this attack. If Step 9 were instead read as an independently guaranteed production of private, nearly perfect Bell pairs, their subsequent key would of course be private; the flaw is that this protocol's test cannot establish that guarantee. Naming an EPP does not repair the information leak or the invalid sampling test.

A secure key can be produced, at one ideal secret bit per copy. Denote Alice's additional flag qubit by $F$. Alice can measure $F$ in the computational basis and, when its outcome is $1$, apply the Pauli Z gate to her half of the shared pair. The two flag outcomes each have probability $1/2$, and $Z_A|{\Phi }^{-}⟩=|{\Phi }^{+}⟩$; either branch therefore supplies the same pure Bell pair.

Equivalently, Alice applies the local controlled unitaryThis local flag correction of a Bell-state phase mixture changes the full density matrix intoThe corrected pair is pure, so every purification factors between $AB$ and $FE$. Eve may know the flag without knowing the key bit obtained from $AB$. Alice need not disclose the flag, but even disclosing it does not compromise the corrected pure Bell pair. Tracing out the flag before correction would give the nonprivate mixture in the preceding case; retaining Alice's local side information is essential.

No secure key can be produced. The off-diagonal terms in the two Bell state projectors cancel, giving the separable quantum stateA possible purification of a density operator is $(|00{⟩}_{AB}|0{⟩}_E+|11{⟩}_{AB}|1{⟩}_E)/\sqrt{2}$. Eve measures her register in the computational basis and learns whether Alice and Bob have $00$ or $11$. Their apparently shared random bit is therefore completely known to Eve. Conditioned on her record the Alice–Bob state is a known product state; public discussion and local private randomness cannot create a shared secret unknown to that record. The state has no distillable secret key in the stated purification model.

No secure key can be produced from this state alone. Factoring the printed amplitudes gives the normalized product stateEve is uncorrelated with the joint pure state, but Alice and Bob also have no correlations with each other: local outcome probabilities factor. They may generate independent private random bits locally, but local operations and classical communication cannot make those bits shared and secret using only public messages. A product state supplies no shared secret resource.

The normalized ray produces a secure key; the literal printed vector is not normalized. The squared norm of the coefficients in the PDF is $8/9+1/81=73/81$. Thus the physical pure state on that ray has normalized coefficients $6\sqrt{2}/\sqrt{73}$ and $1/\sqrt{73}$. This is a genuine entangled state with two nonzero Schmidt coefficients, and Eve is independent of it by purity decouples a subsystem from its purification.

For an explicit way to obtain uniform key bits, Alice applies a two-outcome local measurement in quantum mechanics with Kraus operatorsTheir squared products sum to the identity. The successful unnormalized state is $(|00⟩+|11⟩)/\sqrt{73}$, soAlice announces only success or failure. Success leaves an exact Bell pair, yielding one uniform secret bit; failure leaves $|00⟩$ and is discarded. With many copies the successful fraction is positive. Alternatively, direct computational basis measurements give a shared biased bit with probabilities $72/73$ and $1/73$, from which privacy amplification can extract uniform secret bits. The coefficient $1/9$ has not been silently replaced by $1/3$.

A secure key can be produced, at one ideal secret bit per copy. The shared Bell state is pure, so the preceding factorization shows that Eve's purifying system is independent of it. Measuring both qubits in the computational basis gives matching outcomes $00$ or $11$, each with probability $1/2$. Neither party announces these key outcomes. Eve's state is the same for both possibilities, so each copy supplies a shared uniform private bit.

The agreement of the main light-element abundances with a hot early nuclear-burning phase, and the independent baryon-density consistency between nucleosynthesis and the microwave background, gives strong support to the hot Big Bang framework. These measurements connect the first minutes to recombination, despite their very different temperatures, densities and observables. In particular, the large primordial helium mass fraction and residual deuterium are natural outputs of Big Bang nucleosynthesis, rather than arbitrary products of subsequent star formation.

The cosmological lithium problem prevents claiming that the simplest abundance calculation explains every observation without qualification. One must distinguish nuclear-rate uncertainties, stellar depletion, atmosphere and abundance systematics, and possible new particle physics. Thus the broad hot Big Bang framework is strongly supported, while lithium tests the completeness of its simplest nucleosynthesis and stellar-abundance interpretation. An unresolved lithium discrepancy alone does not erase the independent successes of deuterium, helium and the cosmic microwave background.

Motion toward incoming cosmic microwave background radiation produces a blueshift. The photon occupation function of a blackbody depends on $h\nu /(k_{B}T)$, so the same Doppler factor multiplies both frequency and effective temperature. Looking forward along the Sun's peculiar velocity, one obtainsTaking the mean cosmic microwave background temperature as about $2.73\mathrm{K}$ givesThe numerical total inherits the rounded mean temperature; the robust estimate is the positive millikelvin dipole increment.

In the local, nonrelativistic Hubble law approximation, $c{z}_{\mathrm{tot}}\simeq H_{0}r+v_p$. Ignoring the peculiar velocity gives an inferred distance $r_{\mathrm{est}}=r+v_p/H_0$, soThe requested accuracy therefore requiresAt exactly $120\mathrm{Mpc}$ the worst-case error is $5\%$, so “better than” requires a strictly larger distance. This is the conventional leading-order estimate. If one retains the exact Doppler factor and the product term while treating $r=c{z}_{\mathrm{cosm}}/H_0$ as exact, the positive-velocity case gives $|\Delta r|/r=(1+z_{\mathrm{cosm}})q/z_{\mathrm{cosm}}$, with $q=\sqrt{(1+600/c)/(1-600/c)}-1$. It requires $r>(c/H_0)q/(0.05-q)\simeq 125\mathrm{Mpc}$. That small refinement is conditional on the distance-redshift prescription; the simple $120\mathrm{Mpc}$ answer uses the local approximation consistently.

Let ${\nu }_c$ be the photon frequency in the local comoving frame just after emission. The kinematic redshift gives ${\nu }_e/{\nu }_c=1+z_{\mathrm{kin}}$, and propagation in the FRW metric gives ${\nu }_c/{\nu }_0=1+z_{\mathrm{cosm}}$. Multiplication givesEquivalently, $z_{\mathrm{tot}}=z_{\mathrm{cosm}}+z_{\mathrm{kin}}+z_{\mathrm{cosm}}{z}_{\mathrm{kin}}$. Both redshifts being small is what permits their approximate addition. Here the observer's own peculiar velocity is assumed already corrected to the Hubble flow frame.

Converting size to a regression factor allows two unrestricted contrasts rather than imposing a linear trend on numerical size codes. The command relevel with a numeric second argument selects the second existing factor level as its reference level. For sorted codes $0,1,2$ this is medium, coded $1$. However, the displayed coefficient labels size1 and size3 instead correspond to codes $1,2,3$ with code $2$ as reference. The printed coding and coefficient labels are inconsistent. The actual factor levels and labels must be checked. Under the intended medium-size reference, the two reported contrasts compare small and large businesses with medium ones; with literal $0,1,2$ coding their printed names would be size0 and size2.

Using B's delayed-entry survival object, the Cox proportional-hazards model isHere $h_0$ is the unspecified baseline hazard for a medium-size village business and $c$ is the Cambridge indicator. The fitted hazard ratios are conditional on the other covariates and constant over business age under the proportional hazards assumption. The function fits regression coefficients through partial likelihood; its survival object must actually be B's version, rather than A's earlier object with the same name.

The location coefficient $-0.803$, with standard error $0.344$, gives $z=-2.335$ and a two-sided Wald test p-value about $0.02$. Its reported hazard ratio is $0.448$, with 95% confidence interval $(0.228,0.879)$. At the same age and size, a Cambridge business therefore has an estimated closure hazard about 55.2% lower than a village business. The reciprocal ratio is $2.23$. A hazard ratio is not a survival-probability ratio or a proportional increase in lifetime.

The intended small-versus-medium contrast is $-0.322$, with standard error $0.482$, $z=-0.669$ and p-value $0.50$. Its hazard ratio is $0.724$, with 95% confidence interval $(0.282,1.863)$. The intended large-versus-medium contrast is $-0.224$, with standard error $0.375$, $z=-0.598$ and p-value $0.55$; its hazard ratio is $0.799$, with interval $(0.383,1.666)$. Neither size contrast provides convincing evidence of an effect. The wide intervals also show why these results do not establish equality of size-specific hazards.

The sample has $60$ businesses. The likelihood-ratio test, Wald test and score test jointly test all three coefficients being zero; their statistics are $5.45$, $5.76$ and $6.01$ on three degrees of freedom, with p-values $0.142$, $0.124$ and $0.111$. None rejects at 5%. This is compatible with the significant one-coefficient location test: testing a specified one-dimensional contrast and testing three coefficients together are different questions. The location result offers some adjusted evidence, but the joint output does not demonstrate a strong overall improvement, and interpretation should acknowledge the uncertainty and the number of comparisons.

The reported $R^2=0.087$ is a Cox–Snell likelihood pseudo-R-squared, here $1-e^{-5.45/60}\approx 0.087$. It measures likelihood improvement rather than a literal fraction of variance in lifetimes explained. Its attainable maximum is reported as $0.979$. It does not validate the proportional hazards assumption or establish useful predictive performance. Adjusted survival predictions would require estimating the baseline survival function as well: $S(t\mid z)=S_0(t{)}^{e^{{\beta }^{T}z}}$. The coefficient summary alone does not supply adjusted five- or ten-year survival probabilities.

Before reporting results, check the size coding discrepancy, the precise sampling dates and the survival records. The stated January 2000–December 2005 span is six calendar years, despite being called five years. Check nonnegative ages, entry no later than exit, correctly recorded closure indicators and the same opening-based clock throughout. Establish whether inclusion and censoring are plausibly independent of lifetime given the covariates, and whether different opening cohorts or calendar environments can reasonably share the fitted lifetime model. Simply including delayed entry does not cure informative selection, omitted confounders or dependence between businesses.

Assess proportional hazards using Schoenfeld residuals against time and a proportional hazards assumption test, supplemented by groupwise log-minus-log survival plots. Investigate influential observations with coefficient-deletion diagnostics and deviance residuals, and inspect overall fit using Cox–Snell residuals. Consider a city-by-size interaction or time-varying effects if supported by the available events, rather than relying on the displayed three main effects. Finally, report the uncertainty and declining late risk sets—only six remain at the final listed event—and distinguish a conditional association from a causal explanation or a prediction for all future businesses.