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The trivial representation sends every element of the Lie algebra to the zero linear map. For a complex semisimple Lie algebra, the irreducible representation of highest weight zero is the one-dimensional trivial representation.

Suppose the full Lie algebra of Killing fields has basis $T,\Phi$ and the flow of $\Phi$ has a nonzero period $P$. Write $[T,\Phi ]=aT+b\Phi$ with constant coefficients. The Adjoint representation of the periodic flow satisfies $e^{P\mathrm{ad}\Phi }=1$. Its real eigenvalues are $-a$ and zero, so $a=0$. The remaining adjoint operator is nilpotent and its exponential is $1+P\mathrm{ad}\Phi$, forcing $b=0$. This proves commutation from genuine periodic axial symmetry, without differentiating mere asymptotic component limits.

Over an algebraically closed field, a finite-dimensional Lie algebra is nilpotent exactly when every two-dimensional Lie subalgebra is abelian. A nonnilpotent Adjoint representation matrix has a nonzero eigenvalue $\lambda$ with eigenvector $y$, so $[x,y]=\lambda y$ generates a nonabelian two-dimensional subalgebra. Conversely a subalgebra of a nilpotent Lie algebra is nilpotent, while a nonabelian two-dimensional algebra has a basis $u,v$ with $[u,v]=v$ and a nonnilpotent adjoint matrix. Algebraic closure is what guarantees the required eigenvector.

The real Lie algebra of the unitary group is $\mathfrak{u}(N)=\{X:X^{†}=-X\}$, of real dimension $N^2$. Differentiating unitarity gives necessity; exponentiating any skew-Hermitian matrix gives a curve in the group, proving sufficiency.

The unitary orbit consists exactly of density operators with the same spectrum. If distinct eigenvalues have multiplicities $n_j$, its stabilizer is ${\prod }_{j}U(n_j)$ and its real dimension is $N^2-{\sum }_j{n}_j^2$. A reachable compact group with Lie algebra $\mathfrak{g}$ is transitive on this orbit exactly when $\dim \mathfrak{g}-\dim (\mathfrak{g}\cap \{X:[X,\rho ]=0\})$ equals the orbit dimension. Global phases act trivially by conjugation.

Each term is the preimage of the center of a Lie algebra after quotienting by the preceding term. Equivalently, $Z_{i+1}=\{x:[\mathfrak{g},x]\subseteq Z_i\}$. A Lie algebra is nilpotent exactly when this series reaches the whole algebra after finitely many steps. For the Heisenberg Lie algebra, the series is $0\subset \mathbb{C}c\subset \mathfrak{g}$.

The boundary four-form is $\Theta =\mathrm{Tr}[\delta A(FA+AF-\frac{1}{2}{A}^3)]$. To derive the identity, put $B=dA$ and $a=\delta A$. The variations of the three polynomial terms in $Q_5$ are respectively $3\mathrm{Tr}(a{B}^2)+d\mathrm{Tr}[a(BA+AB)]$, $3\mathrm{Tr}[a(A^{2}B+B{A}^2)]+\frac{3}{2}d\mathrm{Tr}(a{A}^3)$, and $3\mathrm{Tr}(a{A}^4)$. Their sum gives the identity because $F=B+A^2$. For variations in a Lie algebra with basis $T_{\alpha }$, the bulk field equations are $\mathrm{Tr}(T_{\alpha }{F}^2)=0$, not necessarily the unprojected matrix equation $F^2=0$. Conjugation of both the Lie algebra and the gauge curvature proves covariance of these equations under Yang-Mills gauge transformations.

In the symmetric power ${\mathrm{Sym}}^m{\mathbb{C}}^n$ of the defining unitary group representation, diagonal torus weights are indexed by nonnegative integer tuples summing to $m$, with one monomial per weight space. Torus averaging extracts a monomial from any nonzero invariant complex subspace. The complexified Lie algebra acts by $E_{ij}=x_i{\partial }_{x_j}$ on the symmetric algebra. Whenever $a_j>0$, the displayed action moves one unit of degree from $j$ to $i$ with nonzero coefficient. Finite transfers connect every degree-$m$ monomial, so the subspace is the entire representation. The case $m=0$ is the one-dimensional trivial representation. This proof needs neither the Weyl character formula nor the Weyl dimension formula.

The Witt algebra is the Lie algebra of vector fields on a circle with Laurent-polynomial coefficients. Its nontrivial central extension of a Lie algebra is the Virasoro algebra.

Let $H$ be a Cartan subalgebra of a finite-dimensional complex Lie algebra $L$. In the adjoint generalized-weight decomposition for a nilpotent Lie algebra, its zero summand satisfies $L^0=H$. Nilpotence gives $H\subseteq L^0$. If $L^0/H$ were nonzero, all adjoint operators of $H$ on this quotient would be nilpotent, so the Engel theorem would supply a nonzero coset $x+H$ with $[H,x]\subseteq H$. That contradicts self-normalization. The derivation rule ensures that $L^0$ is a subalgebra, so the quotient action is well-defined.