Machine instruction 2026-10-24
A machine-encoded operation executed by a processor. An assembly language mnemonic can denote one machine instruction or an assembler expansion into several.
Opcode 2026-10-24
Use the conventional integer calling convention:
$a0 holds the argument and $v0 holds the result. The function is recursive, so every call must preserve its own return address and original argument. The first recursive result must also survive the second call; a caller-saved register alone would not protect it.This implementation reserves a 32-byte stack frame, keeping the stack pointer eight-byte aligned. Offsets 0–15 are available as the outgoing argument area, 16 stores the original argument, 20 stores the first result, 24 is padding, and 28 stores the return address. It changes no callee-saved register. Assemble in classic MIPS delayed-branch mode with instruction reordering disabled, such as
.set noreorder.foo:
addiu $sp,$sp,-32 # allocate 32-byte aligned frame
sw $ra,28($sp) # save caller return address
sw $a0,16($sp) # save original n
beq $a0,$zero,foo_base
sll $zero,$zero,0
addiu $t0,$zero,1
beq $a0,$t0,foo_base
sll $zero,$zero,0
addiu $t0,$zero,2
beq $a0,$t0,foo_base
sll $zero,$zero,0
addiu $a0,$a0,-1
jal foo
sll $zero,$zero,0
sw $v0,20($sp) # preserve foo(n-1) across next call
lw $a0,16($sp) # recover original n
sll $zero,$zero,0
addiu $a0,$a0,-3
jal foo
sll $zero,$zero,0
lw $t0,20($sp)
sll $zero,$zero,0
addu $v0,$v0,$t0 # combine the two recursive results
beq $zero,$zero,foo_return
sll $zero,$zero,0
foo_base:
addu $v0,$a0,$zero # base case result is n
foo_return:
lw $ra,28($sp)
sll $zero,$zero,0
addiu $sp,$sp,32 # release the frame
jr $ra
sll $zero,$zero,0All displayed operation mnemonics denote single machine instructions. In particular,
sll $zero,$zero,0 is the actual harmless shift encoding often abbreviated by the pseudoinstruction nop; addu $v0,$a0,$zero performs a copy without the move pseudoinstruction. Each branch or jump has an explicit harmless branch delay slot, and harmless shifts also separate loads from their subsequent uses. The base cases return the original argument; other calls return the sum of the two recursive values. Every return restores the saved return address and exactly undoes the stack allocation.[ref]MIPS32 Architecture For Programmers Volume II by MIPS Technologies. Revision 2.00, ADDIU and ADDU, pp. 37–38; JAL and JR, pp. 139 and 144
More processor registers can reduce register spills and the associated loads and stores. A richer instruction set may also replace several old machine instructions by one new operation. Both effects can decrease the number of instructions in a compiled program, although a particular program might obtain no benefit.
Wider instruction encodings increase the bytes per instruction. Consequently the total machine-code size can increase or decrease: approximately, it is instruction count times average encoded instruction width, with alignment and padding also relevant. There is no universal net direction without the program and revised encoding. The length of assembly language source text is a separate matter and is not determined by instruction bit widths.
Pseudoinstruction 2026-10-24
An assembler convenience that expands into one or more actual machine instructions. Its expansion matters when counting instructions, reasoning about temporary registers, or filling a branch delay slot.