Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 340 1 c Solution Created 2026-10-03 Updated 2026-10-06
A wavelet with vanishing moments satisfies and for . The moment differentiation of the Fourier transform theorem states that these weighted integrability hypotheses make , with . Hence . The MRA projection Fourier identity, together with density of the approximation spaces and continuity of at zero, gives . These are the two analytic theorems needed in addition to the quadrature mirror filter construction.
For the ordinary derivative conclusion, assume also that the MRA low-pass filter is near and is near zero. These hypotheses hold, for example, for a compactly supported scaling function with a finite refinement filter. The wavelet identity givesThe denominator is nonzero near zero. Its reciprocal and the exponential are , so the product rule and the zero Taylor polynomial of give the smooth-mask vanishing-moment criterion
The printed integrability hypothesis alone does not guarantee ordinary higher derivatives. It gives only a continuous . Without added smoothness, Taylor theorem for still gives for the representative defined by the quotient: a Peano zero. This establishes the value at , and for the first derivative there, but it does not automatically establish iterated derivatives.
Here is a lacunary scaling-phase regularity counterexample for . Start with a compactly supported Daubechies wavelet having vanishing moments, with scaling function and finite MRA low-pass filter . Define the periodic phaseThe Fourier coefficients of are absolutely summable. The Wiener algebra is closed under multiplication and the exponential series, so and have absolutely summable Fourier coefficients. Thus is an absolutely summable combination of integer function translations of , belongs to , and generates the same . Unimodularity preserves orthogonality and unit norm of its integer function translations; the inverse phase preserves their complete span. The same approximation spaces therefore give a multiresolution analysis.
The identity gives , so the periodic phase change of a scaling function produces . In the high-pass formula the phases cancel:The associated wavelet is therefore exactly the original one, with unchanged vanishing moments.
At any dyadic point , the difference quotient of the terms with is per term. The sum of these errors and the remaining tail divided by are bounded; the finitely many earlier terms have finite limits. Hence , which has no finite limit. The exponential has the same failure of differentiability. Dyadic points are dense, and is nonzero for sufficiently small . Thus is not differentiable on any neighborhood of , so an ordinary second derivative at , understood as the derivative of a locally defined first derivative, need not exist. The Peano zero remains valid. This separates the intended smooth-mask theorem from what the literal assumptions establish.
Smooth-mask vanishing-moment criterion 2026-10-06
Suppose an integrable orthonormal scaling function has a low-pass filter of a multiresolution analysis that is near , and its Fourier transform is near zero. If the associated wavelet has integrable vanishing moments, then for . Indeed, moment differentiation of the Fourier transform makes , while . In , division by the nonzero smooth factor proves the conclusion. With only continuity of that factor one still obtains a Peano zero, but not automatically higher ordinary derivatives.