Burgers Riemann problem with positive flux 2026-10-14
Consider the Riemann problem on with initial condition for and for . No endpoint boundary conditions are imposed. When , its entropy solution is a shock wave with constant speed . In the original example , , the Rankine-Hugoniot condition givesThe left characteristic speed is and the right characteristic speed is , so : both sides enter the entropy shock. The Viscous Burgers travelling shock gives an exact smooth family tending to this solution.
Reversing the states to , still gives a Rankine-Hugoniot condition speed of , but now characteristic curves move away from the discontinuity. That expansion jump is a weak solution and fails entropy admissibility. For general , the selected entropy solution is the continuous self-similar solutionThis rarefaction wave fills the expanding gap between the two exterior characteristic curves. Inside its fan, and , verifying the Inviscid Burgers equation; its values agree continuously with both exterior states. For to , the fan occupies . If , the solution is constant.[ref]
Burgers' equation. Rarefaction wave, full piecewise solution; expansion-shock example; The entropy condition
Inviscid Burgers equation Created 2026-09-24 Updated 2026-10-14
The Inviscid Burgers equation is the scalar conservation lawFor a classical solution, the chain rule makes this equivalent to , a nonlinear transport equation with characteristic speed . The conservative form remains meaningful for a discontinuous weak solution, whereas the product cannot simply be evaluated pointwise at a jump. Its discontinuities obey the Rankine-Hugoniot condition ; this condition alone permits inadmissible expansion jumps. For bounded initial conditions on the infinite line, imposing the Kruzhkov entropy inequalities and the initial trace selects a unique entropy solution. For step data, incoming characteristic curves select , while produces a rarefaction wave.[ref]