Enolate alkylation 2026-10-20
Enolate alkylation forms a carbon–carbon bond by attack of an enolate carbon on an alkyl electrophile, commonly through an SN2 reaction. Solvent, counterion, aggregation and electrophile identity affect competition with oxygen alkylation.
Halohydrin 2026-10-20
Past exam of the chemistry B course of the University of Cambridge 2023 Paper 1 B1 b i Solution 2026-10-20
The malonate carbon receives two allyl groups. With , attached through its first carbon, the product issodium hydride removes a methylene proton from diethyl malonate; molecular hydrogen formation accompanies production of an enolate stabilized by resonance in chemistry. Its carbon attacks the bromomethylene carbon of allyl bromide in an SN2 reaction, expelling bromide. The monoalkylated malonate still has one hydrogen between the carbonyls. Excess base removes that hydrogen, and a second equivalent of allyl bromide produces a second carbon–carbon bond. The final malonate carbon has no remaining hydrogen and cannot undergo a third analogous deprotonation there.
The two alkenes are preserved because the substitution occurs at the primary carbon bearing bromine. Counting the introduced groups gives for the diallylated diethyl ester. Its two identical allyl groups also mean that the central carbon is not a stereocenter. This stage is the alkylation portion of the malonic ester synthesis.
Past exam of the chemistry B course of the University of Cambridge 2024 Paper 1 B1 a ii Solution 2026-10-20
Lithium diisopropylamide removes an alpha proton from the ethyl side of the ketone. The C–H electrons form the C=C part of a lithium enolate, while the C=O pi electrons move to oxygen. The phenyl side has no competing alpha C–H site. Diisopropylamine is the conjugate-acid byproduct.The carbon end of this enolate attacks the primary carbon bearing iodine in . The C–I bond breaks to iodide in an SN2 reaction, and carbonyl reformation givesThus a three-carbon methoxypropyl chain is attached at the ketone alpha carbon. The remote methyl ether survives. The hindered amide base is chosen to generate the enolate rather than to add to the carbonyl. No absolute stereochemical preference is specified for the new stereocenter under these achiral conditions.
Past exam of the chemistry B course of the University of Cambridge 2024 Paper 1 B1 a i Solution 2026-10-20
An enolate is an ambident nucleophile: the negative charge is concentrated toward oxygen, while its occupied conjugated orbital also has substantial reactive amplitude at the alpha carbon. An alkyl iodide presents an accessible, polarizable carbon electrophile. carbon attack through an SN2 reaction is generally kinetically favorable, while the more strongly charged oxygen is often coordinated to the counterion or solvated. The carbonyl reforms as the new C–C bond is made.carbon alkylation restores the carbonyl and makes the new C–C bond. oxygen alkylation instead gives an enol ether. The two outcomes are not resonance contributors of one product, and their ratio is not determined just by where the largest formal negative charge is drawn. electrophile, counterion, solvent and aggregation can change selectivity; hard silicon electrophiles and suitable acylating reagents often favor oxygen trapping. Product stability alone would not explain an irreversible kinetic choice.
Past exam of the chemistry B course of the University of Cambridge 2025 Paper 1 B1 b i Solution 2026-10-20
The first stage is a Stork enamine reaction. Pyrrolidine attacks the ketone carbonyl, and proton transfers give a carbinolamine. Loss of water gives an iminium ion; removal of the benzylic alpha proton produces the enamine conjugated with the aromatic ring. Removal of water and prolonged heating favour this condensation. That conjugated enamine is preferred over the alternative with its double bond on the other side of the original carbonyl.
The nucleophilic enamine carbon attacks the methylene carbon of bromoacetonitrile by an SN2 reaction, displacing bromide and making the carbon–carbon bond. It is the carbon beside the aromatic fusion that acquires , as in D. Finally, water adds to the alkylated iminium carbon; proton transfers and cleavage of the C–N bond regenerate the ketone and release pyrrolidine. This explains carbon alkylation, its position, and restoration of the carbonyl rather than treating the amine as a permanent substituent.
Past exam of the chemistry B course of the University of Cambridge 2025 Paper 1 B2 b i Solution 2026-10-20
The aniline nitrogen attacks the ipso carbon bearing fluorine. The aromatic electrons shift to give a Meisenheimer complex, with negative charge delocalized to the positions ortho and para to the attacked carbon. At either nitro substituent, that charge can be delocalized further onto nitro oxygen. Subsequent proton transfer and fluoride elimination restore aromaticity and give the diarylamine.
Both the ortho and para nitro groups stabilize the addition intermediate in 1-fluoro-2,4-dinitrobenzene. The para-mononitro compound lacks the additional ortho stabilization, so addition is less favourable and generally slower under the stated conditions. This comparison concerns stabilization of the addition pathway; the presence of fluorine does not make the reaction an ordinary aliphatic SN2 reaction.
A transition structure is a saddle point on the potential-energy surface: motion along the reaction coordinate lowers energy in either direction. It has one unstable vibrational direction and no intermediate residence basin.
An intermediate is a local minimum, separated from neighboring states by barriers, with a finite lifetime. It may be short-lived, but that does not make it a transition structure. The elementary SN2 reaction step has a transition structure and no distinct bonded intermediate.
Single-barrier substitution profile and the trigonal-bipyramidal SN2 transition structure
. Details. Draw one maximum for the concerted SN2 reaction step, with no intermediate minimum. Its transition structure iswith O-C forming and C-X breaking, both shown as partial bonds. O-C-X is approximately linear, and the three C-H bonds lie in the equatorial plane. The overall charge is , distributed over the entering and leaving groups.
The sketch illustrates an exergonic case; the elementary-step description alone does not supply a numerical reaction energy or determine the product-reactant energy difference for every possible X.
First, proton transfer from acetic acid to the carbon of diazomethane gives methyldiazonium and an acetate ion:Draw an electron-pair arrow from carbon, using the carbon-negative resonance contributor, to the acidic hydrogen, and another from the acid O–H bond to oxygen. Second, an acetate oxygen attacks the diazonium methyl carbon by an SN2 reaction; an arrow from the C–N bond to nitrogen expels neutral :The acid's hydroxyl hydrogen has become the third hydrogen of the newly installed methyl group. This is a methyl-transfer sequence driven by formation of molecular nitrogen, without forming a free methyl carbocation or invoking Fischer esterification.
The oxygen substituent changes position through a halohydrin–epoxide sequence. First, hydroxide attacks the acetate carbonyl of , giving a tetrahedral intermediate. Collapse expels the substrate alkoxide, and proton transfer gives plus acetate. This is saponification, breaking the acyl–oxygen bond rather than replacing bromide directly with hydroxide.
A small equilibrium population of undergoes intramolecular SN2 reaction at the adjacent primary carbon: the O lone pair attacks and its C–Br pair leaves with bromide. The result is 2,2-Dimethyloxirane. Addition of HBr protonates the ring oxygen. bromide then attacks preferentially at the more substituted carbon, where the protonated ring has greater carbocation character, breaking that C–O bond and leaving oxygen attached to the former primary carbon:The middle formula denotes a three-membered epoxide, not an open-chain ether. Acidic opening of this highly unsymmetrical epoxide has the opposite regioselectivity to a simple basic nucleophilic opening at its less substituted carbon.
Finally, the primary alcohol oxygen attacks acetyl chloride. The tetrahedral intermediate collapses with chloride departure, and triethylamine removes the O–H proton and captures HCl. The product is . oxygen is carried through the epoxide to the other carbon; it is not necessary to invent a methyl migration or a carbon-skeleton rearrangement.
The ordering is allyl chloride 1-chloropropane 2-chloropropane. Iodide is a good nucleophile but a weak base, and polar aprotic solvent acetone favours its SN2 reaction. SN2 reaction and C–Cl cleavage occur in one step; precipitation of sodium chloride can also favour halide exchange without changing the basic steric comparison.
The primary saturated chloride supplies the reference rate. Allyl chloride is also primary, but its neighbouring pi system stabilizes the developing delocalized electronic structure in the substitution transition state. It can therefore react about 64 times faster without requiring a free allylic carbocation. The secondary chloride is sterically crowded at the attacked carbon, making backside approach and the crowded transition state less favourable; its rate is about 0.02 times the primary value. The leaving group and nucleophile are the same in the comparison, so assigning the ordering to different halide leaving groups would be incorrect. If prefactor differences are neglected, at 333 K gives roughly and for the allylic and secondary substrates respectively: modest barrier changes produce large rate ratios.
The first product is , with the original alkene geometry retained. methoxide attacks the primary saturated carbon bearing bromine from the backside. Its oxygen lone pair forms the new C–O bond as the C–Br bonding pair leaves with bromide. The other bromine is vinylic, directly bonded to an sp carbon: ordinary SN2 reaction is unfavourable there, and ionization would require an unstable vinyl cation. Thus the primary alkyl bromide is replaced selectively, rather than replacing the vinylic halide or moving the double bond. There is no observable inversion label at the attacked carbon because it is a methylene.
The second product is sodium 4-propoxybutane-1-sulfonate, . sodium hydride first removes the alcohol proton, giving propoxide and hydrogen. The propoxide oxygen then attacks the primary ring carbon bonded to the ring oxygen; simultaneous cleavage of that carbon–oxygen bond opens the sultone. The departing ring oxygen remains attached to sulfur as part of the resonance-stabilized sulfonate anion. The carbon attached directly to sulfur is not the substitution site, because cleavage there would not expel the same stable sulfonate leaving group. This is carbon-centred ring opening of a cyclic sulfonate ester, not addition across an S=O bond.
The primary chloride undergoes an SN2 reaction; the triphenylmethyl chloride undergoes an SN1 reaction. The primary site is accessible to back-side attack, whereas three phenyl groups make back-side attack at the triphenylmethyl site extremely hindered and stabilize its carbocation through resonance.
For the SN2 reaction, a suitable transition state isThe entering C and leaving Cl lie on opposite sides of the reacting carbon, with partial C–C and C–Cl bonds. The total charge is . This transition state is not a discrete reaction intermediate.
For the SN1 reaction, the approximately planar carbocation is a genuine reaction intermediate. Assuming its formation by C–Cl heterolysis is rate determining and trapping is rapid,Thus the limiting rate law is independent of ethanol concentration. The successive attack and proton transfer occur after the slow ionization; a cation-stabilizing environment and efficient trapping underpin this idealized SN1 description.
The first transformation is an Achmatowicz rearrangement, followed by protection and selective reduction; the last is a Johnson-Claisen rearrangement.
- Butyllithium removes the furan 2-proton, giving a 2-lithiofuran. Its carbon attacks the aldehyde carbonyl; protonation of the resulting alkoxide gives the furfuryl alcohol. Carbon-carbon bond formation occurs at the lithiated position.
- Electrophilic oxygen transfer from mCPBA to the electron-rich furan gives an oxidized, ring-opened intermediate. Opening the oxygenated furan gives a hydroxy enedicarbonyl: the original furfuryl hydroxyl then attacks the remote aldehyde intramolecularly. This expands the five-membered furan into a six-membered lactol containing an enone carbonyl. The original furfuryl oxygen becomes the pyran ring oxygen; oxidation of the furan supplies the new carbonyl and lactol functionality.
- AgO/MeI converts the lactol OH into its methyl acetal: oxygen attacks methyl iodide by SN2 reaction, with iodide removal and proton transfer. This protects the anomeric position.
- LiAlH delivers hydride to the remaining ketone carbonyl, followed by protonation. The methyl acetal survives these basic reducing conditions, leaving the depicted allylic alcohol.
- Under weak-acid catalysis, that allylic OH replaces an ethoxy group of triethyl orthoacetate. Loss of another ethanol molecule, with removal of a methyl proton, gives the mixed ketene acetal . A six-electron, chair-like Claisen rearrangement breaks the allyl-O bond, forms a bond between the terminal allyl carbon and the ketene-acetal CH, and moves the ring double bond one position. Carbonyl formation gives the substituent.
The acetal protects the other oxygenated position during hydride reduction. The orthoester transfers an acetate-derived two-carbon unit through a ketene acetal; it does not directly substitute the allylic OH with an intact acetate ion.
First the tertiary amine attacks the primary allylic bromide carbon by SN2 reaction, giving the quaternary ammonium salt. The less hindered nitrogen face is favored by the pre-existing fused-ring stereochemistry.
DBU removes the proton at the carbon alpha to both the ammonium nitrogen and the ester carbonyl. The resulting ammonium ylide undergoes a concerted 2,3-sigmatropic rearrangement: the N–CH(allyl) bond breaks, a bond forms between the ylide carbon and the aryl-bearing terminal allyl carbon, and the double bond moves to give . Nitrogen becomes neutral again. An ordinary alkyl substitution would attach the wrong end of the allyl unit.
An envelope-like five-membered transition structure keeps Ar outside the crowded bicyclic framework. With the pre-existing OMe dash and ring-junction geometry fixed, place the newly installed side chain on the solid-wedge face at the former ylide carbon and choose the benzylic configuration that places Ar outward, as in the displayed intermediate. This is diastereoselective, suprafacial allyl transfer.
Finally methanesulfonic acid protonates the methyl acetal. Methanol leaves to give an oxocarbenium/iminium-stabilized electrophilic centre, which is attacked intramolecularly by the electron-rich arene at its available ortho position. Deprotonation restores aromaticity and closes the bridge. The terminal isopropenyl group survives; it is not the bond consumed in this final Intramolecular Friedel-Crafts reaction. The constrained tether selects the displayed bridged diastereomer.
Triethylamine attacks the benzyl carbon and bromide leaves, giving the quaternary benzyltriethylammonium salt. A useful substitution transition structure iswith developing N-C bonding and breaking C-Br bonding. The C-H/D bonds remain intact, so the small effects are secondary.
For X=NO, a relatively associative SN2 reaction transition state can give a small inverse effect, , through altered bending constraints. The unsubstituted case, , is close to cancellation of opposing contributions. Electron-donating OMe stabilizes benzylic positive charge, favoring a looser, more dissociative transition state and a slightly normal effect, ; it also explains the increased relative rate, versus for H and for NO.
Thus the data indicate increasing dissociative character with electron donation. A contribution from a separate ionization pathway is possible for the strongest donor, but these small isotope effects and three relative rates do not uniquely require a sharp SN2-to-SN1 mechanism switch.
The terminal alkene of D first undergoes Wacker oxidation, giving the side chain . Alkene coordination to Pd(II), water attack, proton transfers and beta-hydride elimination give the ketone. Copper and oxygen regenerate the active palladium oxidation state.
Base removes a proton from the terminal methyl of that ketone. Its enolate attacks the neighboring aromatic aldehyde intramolecularly, closing a six-membered ring. Dehydration gives a conjugated cyclohexadienone-type intermediate, and keto-enol tautomerism furnishes aromatic naphthol E. The retained methoxy and MOM-protected oxygen groups follow the original aromatic-carbon positions.
F is the O-allyl ether of E. Carbonate forms the naphthoxide and allyl bromide undergoes an SN2 reaction at its terminal carbon. Heating F then causes a [3,3]-Claisen rearrangement: the O–allyl bond breaks, the terminal allyl carbon bonds to the adjacent naphthalene C1, and the phenolic carbon temporarily becomes a ketone. Rearomatization gives G, with a free phenolic OH and a C1 allyl group. The C1 position gives the favored alpha-substituted naphthol and avoids the alternative less favorable annulation pattern.
The final step is a dearomative Michael addition, not a Nef conversion of the nitro group. Hydrogen bonding from the thiourea activates nitroethylene. The nucleophilic C1 resonance form of G attacks the terminal carbon of , and proton transfer converts the nitronate to a 2-nitroethyl substituent. The phenolic carbon becomes a ketone.
H is the corresponding 1-allyl-1-(2-nitroethyl)naphthalen-2-one, retaining the methoxy and MOM substituents of G. The second ring now has a C2=O group and a C3=C4 bond, while the other ring remains aromatic. The reported C signal near ppm is consistent with that newly formed ketone. Related dearomative additions establish this reaction class.[ref]
C1 is now an all-carbon quaternary stereocenter bearing both allyl and 2-nitroethyl groups. Both the drawn thiourea and the starting materials are achiral, so H is racemic. A chiral catalyst would be needed to select one absolute configuration.
O-allyl intermediate and dearomative Michael-addition product
. Details. A is 1-propyl-1,2,4-triazole, with propyl on the nitrogen that is adjacent to one N and one C in the triazole ring, rather than on the nitrogen between the two carbon atoms.
DBU removes the ring NH proton, producing a resonance-stabilized triazolide anion. Nitrogen attacks the primary bromide carbon by an SN2 reaction, displacing bromide and giving the N-propyl product. Alkylation at the equivalent tautomer-related N1/N2 positions gives the same constitutional product, while N4 alkylation would give a different isomer. Charge distribution in the triazolide and the accessibility of its nitrogen lone pairs favor the N1 product under the stated conditions. This is kinetic regioselectivity, not an assertion that the unalkylated tautomer has a permanently localized negative charge.
The drawn aryl dichloride is expected to undergo no analogous substitution under ordinary ethoxide conditions. Its chlorines are attached directly to sp2 aromatic carbons, rather than to the benzylic sp3 carbon of the previous substrate.
A normal SN2 reaction cannot follow the accessible backside geometry available at a primary benzylic carbon. A simple SN1 reaction would require a highly unfavorable aryl cation. Addition–elimination aromatic substitution would need suitable ring activation, such as a strong electron-withdrawing group in an appropriate position, which the drawing lacks. Forcing aryne chemistry cannot be inferred from ethoxide alone.






