For steady electric currents in vacuum, Ampère's circuital law is
Choose an oriented closed contour and a spanning surface; the positive enclosed electric current crosses that surface according to the right-hand rule for the contour. First use the source symmetry to establish the direction of and which positions have the same magnitude. Then choose the contour so its useful segments are parallel to with constant magnitude, and the remaining segments are perpendicular to or have vanishing field contribution. The line integral reduces to the unknown magnitude times a known length or sum of lengths.
For example, cylindrical symmetry around an infinite wire allows a circular contour, giving . A uniform current sheet instead calls for a rectangle straddling it. The law is always valid in this magnetostatic setting, but by itself does not determine the local magnetic field from an arbitrary enclosed current without these extra symmetry arguments. Here is the vacuum permeability.
Choose along the electric current, upward normal to the sheet, and to complete a right-handed frame. In the interior region far from its edges, treat the sheet as infinite in its plane. Its surface current density is
Reflection and translational symmetry make the magnetic field parallel to the sheet, perpendicular to its current, and equal in magnitude with opposite direction above and below. Choose an Ampère's circuital law rectangle with length along , straddling the full thickness. The two long sides each contribute with the same sign; on the vertical sides since is horizontal. The enclosed electric current is . Thus
The right-hand rule fixes the directions:
The current density inside the finite-thickness conductor is , so integrating through thickness gives the same . These are exterior fields in the broad-sheet approximation, not exact finite-width edge fields.
Keep along the upper-sheet current and upward, putting the lower sheet at and upper sheet at . Between them, the upper sheet's lower-side magnetic field is . The lower sheet carries current in , so its upper-side magnetic field is also . The superposition principle therefore gives
Each perfect conductor is an equipotential. The circuit's resistor carries current from upper to lower, so Ohm's law fixes their electric potential difference:
The broad parallel faces and their constant potentials make the electric field perpendicular to them and independent of the coordinates along them, away from edges. There is no volume electric charge in the gap. Apply Gauss's law to a small pillbox wholly within the gap, with equal face areas at heights . Its side flux is zero, so
Thus is independent of height as well. Since ,
It points from the higher-potential upper sheet to the lower sheet. Gauss's law requires the planar symmetry argument: zero enclosed charge alone would not prove a uniform electric field in a general geometry. These combined fields characterize parallel current sheets with a resistive termination.
For injected velocity , the Lorentz force is
For nonzero electric charge and nonzero operating current, the velocity selector condition is
The requested nonrelativistic kinetic energy is consequently
Both electric current and electric charge cancel. Reversing the sign of reverses both component forces and preserves their cancellation. The dimensions are consistent because has units of speed, while is dimensionless. The assumed nonrelativistic particle regime requires ; the problem supplies no values with which to evaluate a numerical energy.

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