Past exam of the soft condensed matter course of the University of Cambridge / 2022 / Section B / 4

For an ideal chain, independent Kuhn length steps give the random walk relationwhere $R_{\mathrm{sub}}$ denotes the end-to-end displacement of a subchain. Equivalently the mass-size fractal exponent is $2$. Numerical factors depend on the chosen definition of blob diameter.

A subchain smaller than the adsorption height explores three dimensions much as a free ideal chain does. At scales exceeding $\xi$, adsorption restricts its perpendicular extent to order $\xi$, so the coil is anisotropic. Its in-plane projection may still have a random walk law for an ideal chain, but the isotropic three-dimensional blob construction cannot be extrapolated to $\sigma >\xi$. This is the reason to use adsorption blobs of size $\xi$.

Here $T$ is the absolute temperature and $k_B$ the Boltzmann constant. An adsorption blob contains $g\sim (\xi /b{)}^2$ monomers, so there are $N/g\sim N(b/\xi {)}^2$ such blobs. Confining a blob removes an amount of conformational entropy of order $k_B$; thus the positive confinement contribution to the Helmholtz free energy isThe statement about one blob's entropy is used as an entropy loss relative to the free chain, rather than as an absolute entropy.

In the assumed slab model, contacts occur within a monomer-scale distance $b$ of the substrate. The contact fraction is approximately $b/\xi$, giving $N_c\simeq Nb/\xi$. Multiplying this by the negative contact energy yieldsThe two contributions express the competition between loss of conformational entropy and gain of adsorption energy. The numerical coefficients are the ones stipulated by this blob approximation.

Minimize the Helmholtz free energy at fixed $N,T$. Its derivative isThe physical stationary point for $ϵ>0$ isTo check the minimum directly, put $x=b/\xi$. Then $F/(N{k}_{B}T)=(x-ϵ/2{)}^2-{ϵ}^2/4$, which is globally minimized at $x=ϵ/2$. The binding free energy gain per monomer is consequently $\mu =k_{B}T{ϵ}^2/4>0$.

The weak-adsorption blob picture requires $b\ll {\xi }_{\ast }\ll b\sqrt{N}$, or $2/\sqrt{N}\ll ϵ\ll 2$ in this model. If $ϵ$ is too large, the layer saturates at a monomer-scale thickness; if too small, a many-blob adsorbed layer has not formed.

The stretched segment is a Gaussian chain of $n$ Kuhn length steps, with unperturbed root-mean-square end-to-end distance $l=b\sqrt{n}$. Its end-to-end probability density is proportional to $\exp [-3z^2/(2n{b}^2)]$, so its leading elastic Helmholtz free energy is $3k_{B}T{z}^2/(2n{b}^2)$. Adding the remaining segment's adsorption free energy givesAn additive constant independent of $n,z$ is irrelevant. At the optimal adsorption height this becomesThe original PDF's hint labels the positive quantity proportional to $k_{B}T{R}^2/l^2$ an entropy. It has units of energy and is the stretching free energy. The corresponding change of conformational entropy is $\Delta S=-3k_B{R}^2/(2l^2)$. This dimensional and sign correction is essential to the minimization.

This is the leading extensive Gaussian chain approximation: endpoint normalization and junction corrections give subleading terms. It requires many stretched monomers and $z\ll nb$, rather than extension near the full contour length.

During slow peeling in atomic force microscopy, $n$ adjusts to minimize the Helmholtz free energy at each imposed height. Define the positive binding gain $\mu =k_{B}T[ϵb/\xi -(b/\xi {)}^2]$ for the adsorbed segment. The stationary point satisfiesSince ${\partial }_n^{2}F=3k_{B}T{z}^2/(b^2{n}^3)>0$, this is a minimum while $0<n_{\ast }<N$. The upward pulling force is the height derivative of the minimized free energy. The implicit $n_{\ast }(z)$ term vanishes because ${\partial }_{n}F=0$, givingUsing $\xi =2b/ϵ$,It is independent of $z$: extra pulling height releases more monomers while leaving the fractional extension of the stretched part unchanged. Equivalently $F_{\min }=-N\mu +f_{\mathrm{peel}}z$. This is the equilibrium peeling force of an adsorbed Gaussian chain.

The plateau ends when $n_{\ast }=N$, atThereafter all monomers are detached and the Gaussian chain force is $f=3k_{B}Tz/(N{b}^2)$, agreeing continuously with the plateau at $z_{\det }$. Very near the start and final release, finite-chain and junction effects lie outside the blob approximation.

For the usual interpretation of a real chain in a good solvent, the detachment force is smaller in the weak-adsorption regime. Excluded volume swells the chain, increasing the cost of confinement near the substrate. The adsorbed layer becomes thicker and its binding free energy per monomer decreases. The same contact energy therefore does not mean the same total binding strength.

The scaling argument can include both adsorption and stretching. Let $\xi \sim b{g}^{\nu }$, where $\nu =1/2$ for an ideal chain and approximately $3/5$ for a self-avoiding walk in three dimensions. With the same contact-fraction approximation,Minimization gives $\xi /b\sim {ϵ}^{-\nu /(1-\nu )}$ and $\mu /(k_{B}T)\sim {ϵ}^{1/(1-\nu )}$. At detachment, a tensile blob of size ${\xi }_t\sim k_{B}T/f$ costs approximately $k_{B}T$; its monomer count is $g_t\sim ({\xi }_t/b{)}^{1/\nu }$. Equating the stretching gain per monomer $k_{B}T/g_t$ to $\mu$ givesThus $f_{\mathrm{real}}\sim (k_{B}T/b){ϵ}^{3/2}$, compared with $f_{\mathrm{ideal}}\sim (k_{B}T/b)ϵ$, so their ratio scales as ${ϵ}^{1/2}<1$ for weak attraction. These are scaling relations, not exact prefactors. The real-chain adsorption exponents here use the same simple uniform-contact model as the earlier parts; a more detailed surface theory of critical phenomena can refine them. The thicker, more weakly bound layer reflects the higher cost of confining a good solvent chain.^[ref]

“Real” alone does not specify solvent quality: a collapsed chain in a poor solvent, strong adsorption, or substantial bending stiffness requires a different comparison. The smaller-force conclusion concerns the flexible good solvent chain implicit in the excluded-volume correction.