For normalized pure states and , the trace distance and quantum fidelity satisfy
The last two expressions distinguish the unsquared quantum fidelity from the squared quantum fidelity. Identical pure states give , and orthogonal pure states give . The equality need not hold for mixed states; the Fuchs-van de Graaf inequalities give bounds in that case.
Brief proof: for two distinct pure states, their two-dimensional span contains the nonzero part of . This restriction has trace zero and determinant , hence eigenvalues . Its trace norm is twice the positive eigenvalue, giving trace distance . For identical pure states, directly.
Compare the qubit pure state
with , using the computational basis. Its Bloch vector is : it follows a meridian of the Bloch sphere from the north pole through to the south pole . The inner product with is , nonnegative on this interval. Consequently quantum fidelity, squared quantum fidelity, and trace distance are
At the triple is ; at it is ; at it is . The angle between the Bloch vectors is , while the quantum fidelity uses its half-angle. The pure-state trace distance and fidelity identity becomes the familiar relation .
Figure 1.
A Bloch sphere meridian and the corresponding unsquared fidelity F, squared fidelity Fsq, and trace distance D relative to the north-pole state
. Details.
For equal prior probabilities, the Holevo–Helstrom theorem gives optimal quantum state discrimination success . Along this meridian it rises from to one, with at . This connects the geometric trace distance to the best possible decision from a single preparation; it is a different measurement task from the target-acceptance probability defining squared quantum fidelity.

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