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Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 309 2 a Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
For any vector field , apply the Leibniz rule to the scalar :Using and expanding the Lie bracket in a coordinate chart leavesThe connection terms cancel because the Levi-Civita connection is torsion-free. Applying this formula to each slot of the metric tensor and using metric compatibility givesEquivalently, one may prove both identities at a point in normal coordinates; since both sides are tensors, the result then holds in every coordinate system.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 307 2 b Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
Only the Weyl fermions in the charged chiral multiplets contribute to the Abelian triangle gauge anomaly. Their cubic coefficient isand the mixed gauge-gravitational coefficient is . Diagrammatically, the oppositely charged and fermion triangles have equal magnitudes and opposite signs. The neutral gaugino also contributes nothing, so the theory is anomaly free.
Gauge invariance and renormalizability permit the most general superpotentialAfter setting the linear and quadratic parameters to zero, the supersymmetric non-renormalization theorem ensures that perturbative quantum corrections do not regenerate them in the Wilsonian superpotential.
Write the scalar components as . For generic nonzero , the F-term scalar potential and D-term scalar potential, including a Fayet–Iliopoulos term, areEvery term is nonnegative. The F-flat equations force and . If , the vacuumalso makes ; if , interchange and and use . Thus for nonzero the charged vacuum expectation value spontaneously breaks the gauged through the Higgs mechanism, but means supersymmetry remains unbroken. For , the origin preserves both the gauge symmetry and supersymmetry.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 307 2 a Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
A chiral superfield obeysExamples in the Minimal supersymmetric Standard Model include the quark, lepton and Higgs chiral superfields. Such a multiplet contains a complex scalar , a two-component Weyl spinor , and a complex auxiliary field ; only the scalar and fermion propagate on shell.
The chiral coordinate is annihilated in the required combination by , so the solution has the simple formTaylor-expand each component about . Nilpotence truncates the series, and the Grassmann identitygives the chiral-superfield component expansionTherefore
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 307 1 d Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
Fermion parity is defined byIt anticommutes with and . At fixed nonzero energy and momentum, choose a supercharge combination for which with . Taking the finite-dimensional trace over one supermultiplet givesbecause cyclicity of the trace and anticommutation of with make the two terms cancel. ThereforeThis is boson-fermion degeneracy in a supermultiplet.
If explicit or soft supersymmetry breaking terms are added, the supercharge is no longer a conserved symmetry of the full Hamiltonian and states need not form representations of the supersymmetry algebra at equal energy. The positive anticommutator cannot be replaced by a constant on a purported multiplet, so the supertrace proof and mass degeneracy fail.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 307 1 c Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
Apply parity to the mixed anticommutator. The transformed left-hand side isbecause . The Pauli-matrix identity represented by this product leaves the temporal matrix unchanged and reverses the three spatial matrices, so it equalsBut a parity transformation acts on momentum as and . This is exactly the parity transform ofso is consistent with the stated transformation law. The arbitrary intrinsic phase cancels.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 307 1 b Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
An internal generator is a Lorentz scalar. The Coleman–Mandula theorem and the graded extension allow it to act nontrivially on supercharges only as an R-symmetry. Since R-symmetries are excluded,
Translation invariance of a conserved global supercharge and the graded Jacobi identities giveLorentz covariance requires the supercharges to transform as Weyl spinors,with the complex-conjugate dotted-spinor relation for , up to the sign convention used for the action of generators.
The anticommutator transforms as a Lorentz vector because . The only translation generator with that transformation law is , and a normalization of fixesAn equal-chirality anticommutator could only contain an antisymmetric spinor contraction times a central charge, but the anticommutator is symmetric under exchange of the complete supercharges. For one supercharge and no central extension this forcesTogether with the stated Poincare brackets, these are the four-dimensional Super-Poincare relations.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 307 1 a Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
The Coleman–Mandula theorem says that, under its assumptions on a nontrivial analytic relativistic S-matrix and the particle spectrum, every continuous bosonic symmetry algebra is a direct sum of the Poincare algebra and an internal symmetry algebra. Supersymmetry becomes possible by weakening the assumption that the symmetry algebra is an ordinary Lie algebra: a Z2-graded Lie superalgebra admits odd generators whose bracket is an anticommutator. The Haag–Łopuszański–Sohnius theorem then classifies the allowed extension and leads to the Super-Poincaré algebra.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 306 4 v Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
Let label directions tangent to the D-brane and label transverse directions. The endpoints obey Dirichlet conditions transversely,and the boundary variation of the metric and constant B-field terms gives mixed tangential conditionsup to the orientation sign at the two ends. A worldvolume gauge potential contributes in the same place, so the gauge-invariant condition contains .
From the brane perspective, the pullback of the background B-field is therefore indistinguishable locally from a constant worldvolume electromagnetic field strength, modulo its two-form gauge symmetry and a compensating transformation of the brane gauge field. This is the open-string boundary condition in a B-field; sufficiently general constant also induces the familiar noncommutative deformation of D-brane endpoint coordinates.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 306 4 iv Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
First, the displayed equations are only the one-loop sigma-model beta functions. Higher worldsheet loops generate additional covariant terms with more curvatures, H-fields and derivatives, each accompanied by higher powers of . Second, string scattering amplitudes contain momentum corrections from the finite string length and from integrating out the infinite tower of massive string states. Their low-energy expansion produces the same higher-derivative spacetime operators, such as curvature-squared and higher-curvature terms. Both arguments require corrections even though local field redefinitions can move individual correction terms between equations.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 306 4 iii Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-03
Define the leading right-hand side of the dilaton equation byTake a divergence of the metric equation. The contracted Bianchi identity, commutation of covariant derivatives on , the B-field equation , and the supplied H-field identity giveThe metric equation contracted with saysSubstitution cancels the curvature, Hessian and H-field terms in , leavingThus is constant on each connected component. The remaining constant is fixed by the central-charge deficit; it vanishes in the critical 26-dimensional bosonic theory at this order.
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