The ground state is the single energy eigenstate . Its coefficient in the normalized wavefunction is , so the Born rule givesThis probability is independent of because unitary time evolution changes only the dynamical phases of the energy eigenstates.
The parity operator exchanges and . Their coefficients in the wavefunction are equal, soThus the wavefunction is a parity operator eigenstate with eigenvalue at every time. The orthogonal projection onto the eigenspace is , which annihilates it. By the Born rule,
The initial quantum state is , up to global phase, and . Applying unitary time evolution givesSince and , the Born rule givesThe other outcome has probability , verifying that the two probabilities sum to one. This is a two-level quantum return probability.
By the Born rule, the probability for a measured energy eigenvalue is the squared norm of the orthogonal projection onto its whole energy eigenspace. ThusEvery other energy eigenvalue has probability zero. These probabilities are independent of : unitary time evolution under the unchanged Hamiltonian operator changes the dynamical phases but not the squared expansion coefficients. The two equal-energy terms describe one measurement outcome.
For an arc represented by , take . The Born rule usesIntegrate using :The result is zero at and one at , checking the wavefunction normalization. At it reduces to , the stationary position probability. Longer intervals on the periodically identified coordinate require specifying the corresponding subset of the circle; integrating multiple turns would count the same positions repeatedly.
Diagonalizing the matrix gives the normalized eigenvectorswith eigenvalues , respectively. The first projective measurement prepares up to global phase, regardless of the earlier state, conditional on obtaining .
The unitary time evolution under gives, with ,The probability amplitudes for the second projective measurement areThe Born rule therefore gives the general spin-one transverse measurement after axial precession:At the specified times , , soFor even , the result is certainly ; for odd , it is certainly . Although zero belongs to the spectrum of the observable, it never occurs at these times. Indeed, for even the evolved vector is , while for odd it is , where the minus sign is a global phase.
Apply the position version of the Born rule to the normalized wavefunction:The result is independent of because the state and the measurement interval scale together. Most position probability lies towards the right wall, since the probability density grows as .
In the stated ordered propagation basis, a downward input is transmitted downward and reflected upward, giving the first column . An upward input is reflected downward with the opposite reflection phase and transmitted upward, giving the second column . ThereforeEqual mirror reflection phases exchange the two directions. Choosing a phase of per reflection givesEach path encounters one mirror, so describes both arms together, not two successive reflections of each photon. Changing its common phase leaves all detection probabilities unchanged. Direct multiplication gives , so both are unitary matrices. They preserve the norm of a quantum state and hence total probability for these lossless optical elements.
Ideal detectors are represented by measurement matrices, but detection itself is not unitary evolution within the two traveling modes. With and , the projective measurement operators areThey give Born rule probabilities and sum to . An absorbing detector maps the incident photon to an excited detector and vacuum field; a complete physical description includes those additional degrees of freedom.
For an axis halfway from toward , let . The Born rule givesThe negative-outcome probabilities are complementary. Both outcomes can occur for both inputs, so one result cannot distinguish them perfectly. Repeated measurements on independently prepared copies distinguish their different statistics with arbitrarily high confidence. Reversing the diagonal direction exchanges the two numbers. This separates single-copy certainty from statistical distinguishability.
A vertical Stern-Gerlach spin measurement is a -spin measurement. The Born rule givesThus this measurement cannot distinguish the two preparations, even by repeating the same measurement on many identically prepared copies: it discards their relative-phase difference in this basis.
For a normalized quantum state, , and the Born rule gives . If the displayed coefficients are not normalized, divide both by . A quantum superposition is a coherent linear combination: relative phase affects other spin measurements, unlike an incoherent statistical mixture with the same -measurement probabilities.
Every pure qubit quantum state is an eigenstate of spin along some axis. Its Bloch vector isFor real normalized , choose modulo with and , allowing an irrelevant global sign. ThenEquivalently, . A Stern-Gerlach spin measurement on this axis yields its positive result with certainty, so the state is not a nontrivial quantum superposition in that measurement basis.
Measuring the first qubit applies or . The Born rule givesThe normalized conditional quantum states areEach expression applies only when its denominator is nonzero; an impossible outcome has no defined conditional state.
Expand a normalized product state asThus , , , , givingConversely the nonzero coefficient matrix has determinant zero precisely when it has rank one, so the condition also suffices for a pure two-qubit state to factor.
For any fixed pair of local measurement settings with operators , the Born rule factorizes:Hence a product state has independent local results in every pair of local bases. This assumes independent settings and local measurements; shared classical randomization of preparations or a subsequent joint interaction can generate correlations. A separable mixture is not necessarily a single product state.