Migratory insertion 2026-10-20
M. Kunitz 2026-11-05
M. Kunitz isolated crystalline inorganic pyrophosphatase from yeast and characterized its catalytic activity in a 1952 study. The purified protein accelerated hydrolysis of pyrophosphate to separate phosphate units. By testing a purified preparation, the experiment could connect a reaction to a particular enzyme rather than merely observing that an unfractionated biological extract changed its reaction substrate.[ref]
Crystalline inorganic pyrophosphatase isolated from baker's yeast by M. Kunitz. abstract, isolation and catalytic specificity
A revealing result was the requirement for activating metal ions, including magnesium. The reaction rate also depended on pH, temperature and the amounts of enzyme and reaction substrate. Related organic phosphate compounds were not equivalent substrates for this preparation. Thus a shared chemical linkage does not guarantee recognition by the same enzyme. As a simple assay illustration, complete cleavage of 10 micromolar pyrophosphate produces 20 micromolar additional phosphate units. Measuring that increase requires subtracting any phosphate already present; measuring an initial reaction rate further requires a time interval before substantial substrate depletion.[ref]
Crystalline inorganic pyrophosphatase isolated from baker's yeast by M. Kunitz. abstract, activating ions, rate dependence and tested organic compounds
Nickelocene 2026-10-20
Oxidative addition 2026-10-20
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B6 a Solution 2026-10-20
Each thiocyanate is a three-metal bridge, -: its nitrogen donates to one metal and its sulfur donates to two other metals. Thus the coordination ligand is ambidentate, but the structure uses both ends and shares the sulfur donor. Each metal receives two nitrogen and four sulfur donors, giving an approximately octahedral coordination sphere. Six donor contacts per metal are consistent with two coordination ligands per metal because each coordination ligand contributes three contacts across the lattice. Sharing these contacts produces a coordination polymer within each layer; the interlayer Van der Waals force does not add coordination bonds. The index counts metal centres, whereas a hapticity label would count adjacent coordinated coordination ligand atoms and would not describe this connectivity correctly.[ref]
Strengthening the Magnetic Interactions in Pseudobinary First-Row Transition Metal Thiocyanates, M(NCS)2 by Euan N. Bassey and others. Structural discussion of the layered first-row metal thiocyanates
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B6 b Solution 2026-10-20
Charge balance fixes each metal as . In an octahedral crystal field the lower set is and the upper set is . The measured spin-only magnetic moments select the following occupations:The result follows from and . Manganese(II) and iron(II) are high-spin complexes: their octahedral splitting is too small to compensate the additional pairing cost of their low-spin alternatives. Copper(II) is , with one unpaired electron regardless of which member of the upper pair is singly occupied. spin-orbit coupling and exchange interactions can produce deviations from the spin-only estimate in real measurements; no such correction is required to explain the supplied values.
Octahedral occupations consistent with the three magnetic moments
. Details. Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B6 c Solution 2026-10-20
At fixed oxidation state, increasing effective nuclear charge across the first transition series generally contracts the ionic radius. The first expectation is therefore shorter average metal–nitrogen and metal–sulfur distances toward copper. This is a trend in comparable coordination environments, rather than a requirement that every individual contact shorten monotonically. The occupation of metal–coordination ligand antibonding orbitals, donor identity and lattice distortion all affect the observed distances.
The high-spin and ions both have two electrons in the strongly sigma-antibonding set, so adding the sixth electron to does not itself introduce another sigma-antibonding electron. Copper(II), however, has occupation and is subject to the Jahn-Teller effect. A tetragonal Jahn-Teller distortion commonly gives four shorter and two longer contacts, so an elongated copper contact can oppose the overall size trend. Here the nitrogen and sulfur donors are already chemically inequivalent; the supplied schematic alone does not determine which trans pair becomes longest. One should compare actual M–N and M–S sets separately, rather than infer a unique axis or a numerical distance from the magnetic moments. The experimentally determined structures illustrate why the donor geometry and individual contacts matter.[ref]
Strengthening the Magnetic Interactions in Pseudobinary First-Row Transition Metal Thiocyanates, M(NCS)2 by Euan N. Bassey and others. Crystallographic characterization and comparison of the layered structures
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B6 d Solution 2026-10-20
For A, linear nitrogen coordination with predominantly nitrile-like bonding is consistent with all three measurements:The short C–N and long C–S distances correspond approximately to a triple bond and a single bond. An approximately nitrogen donor has its donor lone pair directed along the N–C axis, explaining the linear M–N–C angle.
For B, bent nitrogen coordination with increased chemical resonance character accounts for the longer C–N and shorter C–S bonds. In this limiting description both internal bonds have substantial double-bond character and nitrogen is approximately . One nitrogen lone pair can bind a metal with an M–N–C angle near ; alternatively, donation of both nitrogen lone pairs can give a trigonal, nitrogen-bridging unit:The nitrogen-bridging drawing is a compatible proposed bonding mode, but the listed internal distances and one angle alone do not prove the number of attached metals. In particular, B cannot be identified simply as terminal sulfur coordination: the specified angle explicitly contains an M–N bond. resonance structures explain relative bond orders; they do not imply an isolated coordination ligand with permanently localized integer bonds.
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B6 e Solution 2026-10-20
A distinct possibility is terminal sulfur coordination, . Unlike the sulfur donor in the layer, this sulfur need bind only one metal. The limiting resonance structure suggests and . These are single-/triple-bond-based estimates, not exact predictions for an unspecified metal complex. The M–S–C linkage should be bent, consistent with sulfur lone-pair donation.
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B7 a Solution 2026-10-20
Take the M–C–O direction as . carbon monoxide binds through carbon because its occupied donor orbital has a substantial carbon-end lobe. End-on overlap with an empty metal orbital of sigma symmetry gives CO-to-metal sigma donation. At the same time, occupied metal and orbitals overlap sideways with the two corresponding empty CO orbitals, giving metal-to-CO pi backbonding. Both channels strengthen the metal–carbon bond, while backbonding lowers the internal C–O bond order. The processes are synergic: sigma donation helps supply metal electron density for backbonding, while backbonding relieves electron accumulation at the metal.
The original orbital sketch shows one of the two perpendicular pi channels. It is the occupied metal orbital, rather than an empty metal orbital, that supplies electrons to CO antibonding orbitals.
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B7 b Solution 2026-10-20
The arene and three carbonyl ligands are neutral, so chromium is in oxidation state zero, with a metal count. The eta-six arene contributes six electrons and each CO contributes two:The methoxy group changes the electronic properties of the arene without changing this formal electron count. The complex is a piano-stool complex, with the coordinated arene as the seat and the three carbonyl ligands as the legs.
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B8 a Solution 2026-10-20
Let be normal to the Cp ring through its centre. The five carbon orbitals form symmetry-adapted linear combinations with angular patterns , , and . The all-in-phase combination has sigma symmetry about this axis and can interact with . The pair matches by pi symmetry, while the pair matches by delta symmetry. Rotating within either degenerate pair changes the drawing but not the physical interaction.
For the usual eta-five geometry, the metal interactions are ranked qualitatively pi > delta > sigma. The lobes overlap effectively with the occupied ring combinations. The delta interaction is weaker and involves the higher, initially unoccupied Cp combinations; the interaction with the ring is particularly weak because its axial and equatorial parts contribute little net overlap in this geometry. Thus the statement that a sigma bond is always stronger than a pi bond cannot be transferred indiscriminately to this delocalized ring–metal overlap problem. metal and orbitals also have the symmetry of the coordination ligand combination and contribute to overall bonding, so weak overlap does not mean the entire sigma-symmetry channel is absent.
In ionic electron counting, Cp is with six pi electrons in its three occupied ring combinations, hence a six-electron donor. The same coordination ligand is assigned five electrons in neutral counting.
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B8 b Solution 2026-10-20
In a metallocene, several orbitals with substantial metal character are nonbonding molecular orbitals or only weakly bonding or antibonding with respect to the strong Cp–metal framework. Adding or removing a small number of electrons from them can therefore change oxidation state or spin without destroying the principal ring–metal bonds. This allows stable compounds on either side of the 18-electron count: for example, the usual neutral counts for chromocene, ferrocene, cobaltocene and nickelocene are respectively 16, 18, 19 and 20. The 18-electron rule remains a useful reference, but occupation of a weakly antibonding orbital is much less disruptive than occupation of a strongly antibonding orbital. Redox stability also depends on geometry, substituents and reaction conditions, so this is a bonding explanation of the observed flexibility rather than a guarantee of equal stability for all counts.
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B8 c Solution 2026-10-20
Use neutral electron counting consistently: each terminal Cp supplies five electrons, while the eight pi electrons of neutral pentalene must be allocated across the shared fused framework rather than counted twice as two independent Cp coordination ligands. One set of 18-electron-consistent proposals is:
- Iron: syn - pentalene with an Fe–Fe single bond. The two iron–Cp fragments lie on the same face. Assigning four pentalene electrons to each iron gives before direct bonding; the Fe–Fe bond contributes one electron to each count, giving 18. Its direct bond naturally accounts for the especially short metal–metal separation. An anti arrangement cannot retain this short same-face bond.
- Cobalt: - pentalene without a Co–Co bond. The count is at each metal. Syn and anti arrangements are possible at this formal level because there is no required direct bond. Removal of the bond relative to iron accounts for a larger separation.
- Nickel: slipped - coordination to the two outer allylic portions. The fusion bond remains an uncoordinated alkene in this limiting bonding picture, while each outer three-carbon portion contributes three electrons in neutral counting: . Equivalent ionic counting gives a nickel(II) centre, a six-electron Cp and a four-electron allyl ligand. Moving the metal binding sites toward the outer three-carbon portions increases the separation further. Syn and anti arrangements can again be drawn.
The original schematic shows the donor regions and the required iron–iron bond; dashed metal-to-region lines denote delocalized coordination rather than localized carbon–metal single bonds.
These proposals explain the requested electron counts and distance ordering. electron counting alone does not establish the unique ground-state structure: orbital calculations on related pentalene complexes also identify stable formally electron-deficient arrangements. In particular, the formal requirement of a metal–metal bond in the proposed 18-electron iron model should not be converted into a claim that every known iron pentalene complex adopts that model.[ref]
The Versatility of Pentalene Coordination to Transition Metals: A Density Functional Theory Investigation by S. Bendjaballah and others. Discussion of syn/anti coordination, hapticity and electron-count exceptions
Past exam of the chemistry B course of the University of Cambridge 2021 Paper 2 B8 d ii Solution 2026-10-20
Cleavage of the disulfide supplies one methylthiolate per cobalt. A monomer would have only electrons by ionic counting. Dimerization with two bridging thiolates supplies a second sulfur interaction at each cobalt, and a direct Co–Co bond completes each count. Thus a suitable structure is with a Co–Co single bond, containing an diamond:Each cobalt is formally : Cp and methylthiolate each carry one negative charge. The stoichiometry isThe molecular formula reduces to the required empirical formula. The sulfur–sulfur bond has been cleaved, both sulfur atoms now bridge the metals, and the loss of two CO molecules per cobalt is balanced. Formally cobalt(I) is oxidized to cobalt(II), while the disulfide is reduced to thiolate.
Past exam of the chemistry B course of the University of Cambridge 2022 Paper 2 B6 a Solution 2026-10-20
Six inward-directed donor orbitals form symmetry-adapted linear combinations of symmetry. They mix respectively with metal , and orbitals. Thus the sigma framework contains six occupied bonding molecular orbitals and six corresponding antibonding molecular orbitals. The metal orbitals have no sigma-compatible partner and remain nonbonding orbitals in this model. The important metal-dominated octahedral splitting isThe orbitals point directly toward the donors; the orbitals point between them. The original diagram shows the entire sigma framework, rather than treating the five metal d levels as the whole molecular-orbital diagram.
Sigma-only octahedral orbitals and the donation/backbonding channels of end-on dinitrogen
. Details. For the same donor set and approximately the same geometry, . The higher metal charge usually shortens the metal–donor distances and strengthens the interaction that raises . This comparison holds other chemical variables fixed: changing the ligand at the same time could reverse a comparison between two unrelated complexes.
Past exam of the chemistry B course of the University of Cambridge 2022 Paper 2 B6 b iii Solution 2026-10-20
water lies below pyridine and cyanide ligand in the spectrochemical series. At fixed metal and dioxolene charges, replacement by water decreases and favours the high-spin limits: Co(II) remains ; Co(III) can become if the splitting falls below the pairing threshold. Replacement by cyanide increases and favours Co(III), , and Co(II), . The two unchanged semiquinonate ligands would then give the Co(II) form a combined independent-spin moment of . The ranking predicts the direction of the change; two substituted donors alone do not guarantee a Co(III) spin crossover, since all six donors determine its splitting. A shift of the valence-tautomer equilibrium is also possible and is separate from this fixed-charge comparison.
Past exam of the chemistry B course of the University of Cambridge 2022 Paper 2 B6 b ii Solution 2026-10-20
A Co(III) centre has , and charge balance requires one closed-shell catecholate ligand and one semiquinonate ligand. For low-spin Co(III), , the metal has , giving an independent-spin magnetic moment ofThus contains low-spin Co(III), , with its observed moment residing on the free radical ligand. High-spin Co(III), , would have and give under the stated independent-spin approximation, so it is inconsistent with this measurement.
For Co(II), , charge balance instead requires two semiquinonate ligands. High-spin Co(II) has and , soTherefore contains high-spin Co(II), . Low-spin Co(II), , would give when the two ligand spins are included. These four checks distinguish both oxidation state and metal spin.
The larger octahedral splitting at Co(III) exceeds the effective pairing energy and favours a low-spin complex; the smaller octahedral splitting at Co(II) favours a high-spin complex with occupation of both orbitals before further pairing. Interconversion also transfers an electron between cobalt and a dioxolene ligand, so this is valence tautomerism, rather than a metal-only spin change. Squared moments add here because the supplied model treats the centres as independent; adding the three spins first would be a different, exchange-coupled model.
Past exam of the chemistry B course of the University of Cambridge 2022 Paper 2 B7 b Solution 2026-10-20
In ionic counting, two cyclopentadienyl anions donate electrons. Therefore ferrocene, cobaltocene and nickelocene contain 18, 19 and 20 valence electrons, respectively: Fe(II) is , Co(II) and Ni(II) . ferrocene fills the bonding and approximately nonbonding levels while leaving the next metal–ring antibonding pair empty. cobaltocene and nickelocene add one and two electrons to that antibonding set.
Increasing antibonding occupation lowers the net metal–ring bond order. It therefore explains the simultaneous increase in M–C distance and decrease in dissociation enthalpy from Fe to Co to Ni. The trend does not follow the shrinking size of the isolated metal ions; the orbital occupation is decisive here. The specified enthalpy separates the entire sandwich into a gaseous metal dication and two gaseous ring anions. It measures that complete ionic dissociation process, not ten independent localized M–C bond energies, so dividing it by ten is not a justified bond-energy determination.
Past exam of the chemistry B course of the University of Cambridge 2022 Paper 2 B8 a ii Solution 2026-10-20
Both coordinated frequencies are substantially lower than that of free N. In a local harmonic model,Thus coordination lowers the approximate N–N stretching force constant by about 27%, with B marginally more activated than A by this measure. Donation into N pi-antibonding orbitals provides the natural explanation: the M–N bond has an important backbonding component and N–N loses some multiple-bond character.
The same qualitative red shift occurs for CO when metal-to-CO backbonding populates CO orbitals. N is generally a poorer pi acceptor than CO, so low-valent electron-rich metal fragments are particularly helpful for stabilizing its complexes. A numerical claim that N always shifts more or less than CO would require a matched metal/ligand comparison. Neither the two frequencies nor the local-force approximation establish integer N–N bond orders, complete N–N cleavage, or catalytic nitrogen conversion; they establish significant weakening of intact coordinated N.




