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The signed accumulated rotation about a specified fixed axis. Unlike an angle specified only modulo $2\pi$, angular displacement counts complete revolutions as well as the final orientation. Its derivative with respect to time is angular velocity. The displayed formula therefore follows from the fundamental theorem of calculus.

Charles-Augustin de Coulomb used a torsion balance to turn weak electric forces into measurable angular displacements. The restoring torque of a twisted silver wire supplies a calibrated mechanical comparison with the electric force. In his first electrical memoir for 1785, he varied the wire's imposed twist and compared the equilibrium separations of two small bodies carrying like electric charges. The total twist, including the moving arm's deflection, determines the restoring torque. These measurements supported the inverse-square dependence expressed by Coulomb's law, joining a mechanical calibration with the geometry of electric charges.^[ref]

Physicist and engineer whose work includes friction and strength of materials. His name appears in the Mohr-Coulomb failure criterion.

A gear is a toothed mechanical element that transmits motion and torque through contact with another gear or a rack and pinion. The teeth maintain a prescribed relation between the motions: unlike a smooth friction drive, the ideal gear ratio is set by geometry and tooth counts. The gear pitch circle supplies an imaginary rolling geometry for describing that relation; it is not the circle through the tooth tips.^[ref]

For two external gears on fixed parallel axes, let $N_1,N_2$ be their tooth counts and let signed angular velocities ${\omega }_1,{\omega }_2$ use the same orientation. Each tooth on one gear must pass a tooth space on the other, so counting tooth passages givesThus a 20-tooth input driving a 40-tooth output makes the output turn half as fast in the opposite direction. An input of $1200$ revolutions per minute gives an output of $600$ revolutions per minute in magnitude. These signs describe an external pair; a rack and pinion instead converts rotation into translation.

The useful trade is between angular speed and torque. In an ideal steady transmission, conservation of energy equates input and output power, $|{\tau }_1{\omega }_1|=|{\tau }_2{\omega }_2|$. The same 20-tooth/40-tooth pair therefore turns an input torque of $2\mathrm{N}\mathrm{m}$ into an output torque of $4\mathrm{N}\mathrm{m}$ while halving angular speed. This does not create energy: more torque accompanies less angular displacement per input revolution. Real gears dissipate energy through friction, and backlash permits a small lost motion on reversal; tooth strength and bearings, rather than the gear ratio alone, determine allowable load.

Henry Cavendish used a torsion balance to infer the mean density of the Earth. Nearby lead masses exert a gravitational force on smaller masses carried by a suspended horizontal arm. The wire's restoring torque opposes the resulting angular displacement; the arm's oscillation period calibrates that response. Moving the attracting masses to opposite sides reverses the deflection. Comparing this measured gravitational force with terrestrial gravity then determines the mean density of the Earth. To reduce convection caused by uneven heating, he enclosed the apparatus and observed its scale through telescopes from outside the room.^[ref]

Experimental natural philosopher who measured terrestrial gravitational attraction and inferred the mean density of Earth in 1798.

In screw thread geometry, lead $L$ is the axial advance in one complete relative revolution of the screw and its matching nut. The term screw lead distinguishes this geometric quantity from the chemical element. For $n$ thread starts with axial thread pitch $p$,A single-start thread has $L=p$, whereas a three-start thread with $p=2\mathrm{mm}$ has $L=6\mathrm{mm}$.^[ref]

Assume the screw is restrained axially and the nut is guided against rotation. If the relative angular displacement is $\theta$, consistent signs giveDifferentiating gives $v=L\omega /(2\pi )$, where $\omega$ is relative angular velocity. Equivalently, rotation at $f$ revolutions per second gives axial speed $v=Lf$. With $L=6\mathrm{mm}$ per revolution and $f=5$ revolutions per second, the ideal speed is $30\mathrm{mm}{\mathrm{s}}^{-1}$; a $90^{\circ }$ turn advances $1.5\mathrm{mm}$.

Unwrapping a cylindrical reference surface of radius $R$ gives a right triangle with circumferential run $2\pi R$ and rise $L$. Its helix inclination $\alpha$, measured relative to a plane perpendicular to the axis, therefore obeysThis is a geometric statement about the chosen reference radius. It does not by itself determine the drive torque, because contact geometry and friction also matter.

A commanded turn is a prediction from geometry, rather than a guarantee of measured travel. Backlash can delay reversal motion, and mechanical compliance changes displacement under load. These effects remain relevant even when the nominal screw lead is known exactly.

A lead screw converts relative rotation into axial movement through a screw thread and matching nut. In a common arrangement the screw rotates while the nut is restrained from rotating and is guided along the screw axis. The constraint is essential: the useful output is their relative movement, rather than rotation of both parts together.^[ref]

Let $L$ be the screw lead, the axial advance per complete relative turn. With consistent directions and no backlash, an angular displacement $\theta$ produceswhere $\omega$ is the relative angular velocity. A screw with $L=4\mathrm{mm}$ per revolution advances $1\mathrm{mm}$ in a quarter-turn. This is a geometric prediction; free play, deformation and manufacturing deviations can change the measured motion.

The thread pitch $p$ is the axial spacing of adjacent threads. A screw with $n$ thread starts has $L=np$, so a two-start screw with $p=2\mathrm{mm}$ has $L=4\mathrm{mm}$. Lead and pitch agree for a single-start screw but need not agree otherwise.^[ref]

An ideal slowly moving screw also illustrates the exchange of torque for axial force. Neglecting friction, changes in stored energy and other losses, equality of input and output work givesFor $F=500\mathrm{N}$ and $L=0.004\mathrm{m}$, the required ideal torque is about $0.318\mathrm{N}\mathrm{m}$. Real drive torque must also account for friction and other loads. Geometry alone does not determine whether an applied axial load can drive the mechanism backwards.

A lead screw is therefore both a motion-conversion mechanism and a load path. Its backlash affects reversals, while its mechanical compliance affects movement under changing force; these are distinct contributions to positioning error.

The central prediction of the ATP synthase ATP synthase rotary mechanism is relative motion of the central shaft and catalytic head, not simply a change in bulk ATP concentration. In the foundational single-molecule experiment, a visible marker coupled to the central gamma shaft reported its angular position relative to the immobilized catalytic head. Sustained directional rotations during ATP hydrolysis demonstrated rotary motion directly. The catalytic head contains three beta sites within an alpha-three beta-three assembly; their changing nucleotide affinities motivate the binding-change mechanism. ^[ref]

An angular trajectory gives more information than an average rotational speed. At low ATP, pauses before roughly 120-degree advances become longer as ATP falls, supporting an ATP-binding-limited wait. Reducing marker drag and improving temporal resolution reveals substeps and ATP-independent catalytic dwells. The early high-speed study resolved approximately 90-degree and 30-degree substeps, with more than one slow event during the catalytic dwell. Numerical angles vary with preparation and operational definition, so these observations should not be imposed as exact universal geometric increments.^[ref]

The dwell-time model in b tests serial chemical kinetics; the angle histogram tests preferred positions. Comparing probe loads checks whether viscous drag limits the observed speed. Measuring torque and angular displacement estimates mechanical work, while a separate hydrolysis readout tests chemical coupling. With one ATP per 120-degree step, the chemical budget per revolution is three ATP, but rotation alone does not count every chemical event or establish unity efficiency.

A probe can perturb the very process it reports, and inhibited pauses or unresolved reversals can bias averages. Isolated F1 observed during hydrolysis also does not demonstrate proton-driven ATP synthesis by intact membrane F0F1. Testing reverse synthesis requires evidence for chemical gene expression under the corresponding driving conditions; a rotation movie by itself is insufficient. These distinctions connect the single-molecule motion to the free-energy balance without overinterpreting it.

Definitions. The torque of a force $\mathbf{F}$ about an origin is $\mathbf{\tau }=\mathbf{r}\times \mathbf{F}$, where $\mathbf{r}$ runs from that origin to the force's point of application. Its component about a fixed axis changes angular momentum about that axis. The moment of inertia about that axis iswhere $s$ is perpendicular distance to the axis. It measures resistance to angular acceleration; for fixed-axis rigid rotation, ${\tau }_{\mathrm{net}}=I\alpha$. The units are $\mathrm{N}\mathrm{m}$ for torque and $\mathrm{kg}{\mathrm{m}}^2$ for moment of inertia.

Mass and axial inertia. Slice the shaft perpendicular to its common axis. A slice of radius $r(z)$ has mass $dm=\rho \pi r(z{)}^{2}dz$ and moment of inertia $dI=\frac{1}{2}r(z{)}^{2}dm$, using the moment of inertia of a uniform disc. Thus the axial moment of inertia of a solid of revolution uses the second and fourth powers of its radius:For the tapered section, take $z$ from its narrow end toward its wide end, so $r(z)=a(1+z/l)$ for $0\le z\le l$. Its contributions areThe two cylinders contribute $4\rho \pi a^{2}l$ and $\rho \pi a^{2}l$ to mass, and $8\rho \pi a^{4}l$ and $\frac{1}{2}\rho \pi a^{4}l$ to moment of inertia. Adding the three sections givesAll slice rotation axes coincide with the shaft axis, so the moments add directly.

Frictional torque. The normal load on the narrow circular end is $Mg$. With the stipulated uniform pressure, $p_N=Mg/(\pi a^2)$. A contact annulus of radius $s$ and width $ds$ has area $dA=2\pi sds$, normal force $p_{N}dA$ and tangential kinetic friction $dF=\mu p_{N}dA$. Multiplying by its lever arm $s$ and integrating gives the uniform-pressure friction torque on a circular contact:Here $G_f$ is the positive magnitude; its torque opposes the angular velocity.

Steady speed and stopping rotations. Mechanical power in rotation is $P=\tau \omega$. At steady angular velocity, the driving and frictional torques balance, so constant-power rotation against dry friction givesUsing $g=9.81\mathrm{m}{\mathrm{s}}^{-2}$ and $a=0.100\mathrm{m}$,Once the motor is removed, the speed-independent kinetic friction gives constant angular acceleration $-G_f/I$. Equivalently, the initial rotational kinetic energy is dissipated as frictional work. The stopping angle under constant resisting torque is thereforeThe total angular displacement corresponds toHence the shaft completesand then another $0.16668$ of a rotation. Its stopping time is $I{\omega }_{\ast }/G_f=2.05461\mathrm{s}$. Using the rounded value $g=9.8\mathrm{m}{\mathrm{s}}^{-2}$ changes the fractional rotation slightly but leaves four complete rotations.

A pendulum clock uses a periodically swinging simple pendulum as its timekeeping element. For small angular displacement, an ideal simple pendulum of length $\ell$ has period $T\simeq 2\pi \sqrt{\ell /g}$. This weak dependence on amplitude at small amplitude makes the simple pendulum useful for producing nearly equal time intervals.

Real friction would stop the swing. An escapement transfers small amounts of energy from a falling weight or wound spring while counting oscillations through a gear train. Changing the effective length changes the rate: increasing $\ell$ increases the period and makes the clock run slower. Temperature-dependent length and finite-amplitude corrections limit the ideal formula.

A rack and pinion is a meshing gear pair that converts between rotation and straight-line motion. The pinion is the circular gear and the rack has teeth along a straight path. The ideal motion is described using the gear pitch circle, rather than the outer tips of the teeth. Manufacturer diagrams compare rack travel over one full pinion revolution and show how tooth spacing affects that travel.^[ref]

For a fixed pinion axis and a guided rack, let $r$ be the pitch-circle radius and choose consistent positive directions. With angular displacement $\theta$ in radians,where $\omega$ and $\alpha$ are angular velocity and angular acceleration. For an original example, $r=20\mathrm{mm}$ and a quarter-turn give $x=10\pi \mathrm{mm}\simeq 31.4\mathrm{mm}$. A rotation rate of2revolutions per second gives $v=80\pi \mathrm{mm}{\mathrm{s}}^{-1}\simeq 251\mathrm{mm}{\mathrm{s}}^{-1}$.

Ideal lossless work transfer also givesThus a1newton-metre torque at the same20millimetre pitch radius corresponds to50newtons of tangential rack force. This is a kinematic and energetic model; it omits tooth deformation and friction. Backlash makes reversal especially important: a small rotation can take up clearance before the rack moves. The manufacturer's catalogue explicitly describes backlash adjustment through mounting geometry.^[ref]

In a flywheel-based inerter, a rack and pinion makes relative terminal translation rotate the flywheel. The motion conversion then changes the apparent mechanical inertance without requiring the translating assembly to have that same physical mass.

A rigid body's axial moment of inertia $I$ and a constant resisting torque ${\tau }_f>0$ give constant angular acceleration $-{\tau }_f/I$. Hence $t_{\mathrm{stop}}=I{\omega }_0/{\tau }_f$ and the angular displacement is the displayed expression. Equivalently, the lost rotational kinetic energy $I{\omega }_0^2/2$ equals the resisting work ${\tau }_f\Delta \varphi$. The total number of revolutions is $\Delta \varphi /(2\pi )$; the number of whole revolutions completed is its floor function.