Codex @codex  0

For a specified transcription unit, the coding strand is the DNA strand matching the initial RNA product in the $5^{\prime }\to 3^{\prime }$ direction, with T in place of U. The opposite DNA strand is the template. The name does not imply that every transcribed gene encodes a protein. See Clark, Douglas and Choi: coding and template strands.

Gene expression uses a gene's information to produce functional RNA or a protein. Transcription makes RNA from a DNA template; for a protein-coding gene, biological translation then uses messenger RNA to specify an amino acid chain. Many genes instead produce functional RNA, including transfer RNA and ribosomal RNA, without a translated protein product. See Alberts et al., Molecular Biology of the Cell, 4th edition (2002): from DNA to RNA.

Follow the chosen coding strand $5^{\prime }\text{-}\mathrm{ATGGCTTAA}\text{-}{3}^{\prime }$: transcription of its complementary template gives $5^{\prime }\text{-}\mathrm{AUGGCUUAA}\text{-}{3}^{\prime }$ in messenger RNA. In the stated reading frame, its three codons are AUG, GCU and UAA: methionine, alanine and a stop codon. Thus nine nucleotides specify two amino acid residues followed by termination, not three residues. This is an illustrative coding segment embedded in suitable expression and initiation context, not a claim that an isolated nine-nucleotide RNA is sufficient to initiate biological translation.

The distinction between copying and use explains how biological cells can preserve the same DNA yet produce different products. DNA replication duplicates the record; gene expression selects and uses parts of it. Transcription does not use all DNA at once, and gene expression can be controlled at several steps, including transcription, RNA processing and biological translation. See Clark, Douglas and Choi, Biology 2e: regulation of gene expression. The arrows describe template-directed synthesis: the DNA does not physically turn into a protein, and the messenger RNA does not supply the amino acids from which that protein is assembled.

A mutation changes inherited genetic sequence. Under an infinite sites mutation model, every mutation occurs at a previously unmutated position, so mutations below the sample's common ancestor correspond to segregating sites.

More precisely, a mutation changes a genetic nucleotide sequence; in cellular organisms this is a DNA sequence. An altered sequence can be copied by DNA replication into descendant biological cells, changing their genotype whether or not an observable phenotype changes. Inheritance along a cell lineage does not require transmission to an offspring organism. In animals, germline mutations can enter offspring through gametes, whereas somatic mutations remain in body-cell lineages.^[ref]

A DNA lesion is damage to the physical DNA molecule, such as a damaged nucleobase or a broken strand. It need not become a lasting mutation: DNA repair can restore the original sequence. Conversely, a copied nucleotide substitution can leave an ordinary, correctly paired DNA duplex whose sequence differs from the ancestor. The distinction is between a damaged template and a changed inherited message, not simply between harmful and harmless effects.^[ref]

Small mutations include nucleotide substitutions and indels. Larger changes can remove a gene, duplicate a chromosome region or rearrange its order. Genetic recombination can bring existing alleles together without creating a new nucleobase at the exchanged positions; the mechanism and the resulting sequence change are different questions. A molecular description of a mutation, its effect on a gene product and its effect on a phenotype are likewise three separate statements.

For an original consequence ledger, choose the coding strand segment $5^{\prime }\text{-}\mathrm{ATG}\mathrm{TTT}\mathrm{GAA}\mathrm{TAA}\text{-}{3}^{\prime }$ with initiation at the first displayed codon. Use the standard genetic code, the same reading frame and suitable gene expression context throughout. Its messenger RNA has U in place of T, and the predicted amino acid chain is methionine–phenylalanine–glutamic acid residue, followed by a stop codon. This is a constructed coding segment, not an experimentally measured gene.

In the second row, position 6 changes from T to C, replacing TTT by TTC. Both corresponding RNA codons specify phenylalanine, so the predicted chain is unchanged. Changing position 5 from T to C instead gives TCT, whose RNA codon specifies serine. Changing position 7 from G to T gives TAA and therefore a stop codon before the original glutamic acid residue. Each is one nucleotide substitution, but their coding consequences differ. Even preservation of the amino acid chain does not guarantee unchanged gene expression or phenotype.

Insert GGA after ATG to add a glycine codon, or remove the complete TTT codon to remove phenylalanine. Both indels preserve the downstream reading frame because their lengths are three nucleotides. A one-nucleotide insertion at that location instead produces a frameshift mutation; the positional explanation and a worked regrouping appear under frameshift mutation. The ledger illustrates why interpreting a genetic variant requires its position and context, rather than just the label mutation.

Mutation supplies new inherited variation on which natural selection can act. The Luria-Delbrück experiment makes the distinction unusually visible: natural selection reveals resistant descendants, while the timing of a prior mutation determines how many descendants are available to reveal. This connects an invisible change in one biological cell to a visible pattern across cell cultures.

Transcription is synthesis of RNA using one DNA strand as a template by an RNA polymerase. During elongation the RNA polymerase reads that template $3^{\prime }\to 5^{\prime }$ while extending RNA $5^{\prime }\to 3^{\prime }$. Only the selected region is transcribed; other regions need not be active, and the template strand can differ between genes. See Alberts et al.: RNA polymerase and selection of transcribed DNA regions.

For the displayed example, align these three nucleotide sequences in the same left-to-right positions:The first template triplet TAC selects AUG: T pairs with A, A with U, and C with G. The next CGA selects GCU, and ATT selects UAA. The coding strand therefore matches the RNA lettering except for T versus U, whereas the template is complementary. Reading that template in its own $5^{\prime }\to 3^{\prime }$ direction gives $5^{\prime }\text{-}\mathrm{TTAAGCCAT}\text{-}{3}^{\prime }$; orientation cannot be discarded. The gene expression diagram keeps all three rows aligned. See Clark, Douglas and Choi, Biology 2e: template and coding strands in transcription.

This correspondence makes nucleotide sequences interpretable, but replacing T by U is valid only after identifying the coding strand. Moreover, RNA may be processed after transcription, so the initial product and mature messenger RNA need not have identical uninterrupted nucleotide sequences. Transcription also makes functional RNA that will not undergo biological translation. See Alberts et al.: RNA processing and RNA as the final gene product.