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A spatial rotation and rescaling put the future null vector in the form $k^{\mu }=(1,0,0,1)$, so the profile depends on $z-t$. Transversality gives four linear relations among the ten symmetric components. The four residual gauge functions satisfying $\square {\xi }^{\mu }=0$ remove the time and longitudinal components; the remaining trace can be removed by the residual transformation indicated in the question. The resulting transverse-traceless gauge isThe two arbitrary functions are the plus and cross gravitational-wave polarizations. They are the two physical degrees of freedom left after the four gauge conditions and four residual coordinate freedoms are removed.

On the positive $z$ axis, $x=y=0$ and $r=z$. Taking this limit in the spatial components giveswith $A,B,C$ evaluated at retarded time $t-r$. A wave propagating toward the observer along the $z$ direction has polarization matrixConsequently the observed gravitational wave polarization amplitudes areThe $B$ mode and the orthogonal combination of $A,C$ do not contribute on this symmetry axis. The observer therefore sees a purely plus-polarized wave; a rotation of the transverse $x,y$ axes would represent the same physical polarization as the corresponding spin-two mixture of plus and cross.