For a compact Lie group , the complex representation ring of a compact group is the Grothendieck group of finite-dimensional continuous complex group representations, with the relations . Multiplication is , and the unit is the trivial one-dimensional representation. The ring of class functions is
with pointwise addition and multiplication. The character of is . The trace identities for direct sums and tensor products make
a well-defined ring homomorphism .
Normalize Haar measure by . Averaging a positive definite Hermitian inner product gives
which is positive definite and -invariant. This proves unitarization of a compact-group representation. In a unitary representation the orthogonal complement of an invariant subspace is invariant. Induction on dimension therefore gives complete reducibility of compact-group representations. Hence every element of is a finite integral linear combination of irreducible classes.
We establish the needed character orthogonality for compact groups carefully. For irreducible unitary representations , let act on by
Its average is a projection onto : averaging makes every image invariant, and it fixes every intertwiner. The trace of this action is , since the inverse of a unitary matrix has conjugate trace. Taking the trace of the projection gives
For completeness, Schur's lemma follows here from invariance of the kernel and image of an intertwiner. A nonzero intertwiner between irreducibles is an isomorphism. An endomorphism of an irreducible complex representation has an eigenvalue ; the noninvertible intertwiner must vanish. Thus the last dimension is one for isomorphic irreducibles and zero for inequivalent ones.
If a virtual character vanishes, integrating it against gives for every irreducible . The irreducible multiplicities therefore distinguish the classes, and
This also proves that two finite-dimensional representations with the same character are isomorphic.
For SU(2), the irreducibles are , , of dimension . One can see this classification through the usual operators : a highest-weight vector has , , and the relations , , give, by induction,
The torus weights are integers. If but , the identity at forces . The vectors span an invariant irreducible module, which in an irreducible representation is the whole space. This is the symmetric-power module. Conversely its successive monomial weight vectors are linked by with nonzero coefficients, proving its irreducibility. Thus the classification of finite-dimensional representations of SU2 gives every irreducible, rather than just a list of examples.
On the maximal torus , their characters are
With , multiplication gives , starting with . Hence each is a monic integral polynomial of degree in . For example and . They form a basis over , so
The character map realizes this ring as the finite integral polynomials in , interpreted as continuous class functions. Its image is not the whole infinite-dimensional ring of continuous class functions; injectivity is the assertion being proved.
Frobenius reciprocity is the adjointness of character induction and restriction: for class functions on and on ,
For characters this says that the multiplicity of an irreducible -character in an induced character equals the corresponding multiplicity after restriction. To prove the identity directly, insert the induced class function formula and interchange the two finite sums. For each , substitute with . Since is constant on conjugacy classes,
This proves the theorem for all class functions, not just irreducible characters.
For the group-theoretic conclusion, suppose that divides . A central element of order lies in every Sylow p-subgroup: adjoining it to a Sylow subgroup gives a p-subgroup, so maximality forces it into that subgroup. Hence there is a subgroup of order . Choose a nontrivial linear character of .
Since is abelian, extends to a linear character of . One direct justification is to extend from an abelian subgroup to one generator at a time: if is the least positive exponent with , choose a complex th root of as the value at . The formula on is then well defined and multiplicative. Iteration yields the claimed extension to .
The induced character has degree , which is prime to . In its decomposition into irreducible characters, at least one constituent must have degree prime to ; otherwise the total degree would be divisible by . Frobenius reciprocity also gives for this constituent. Restriction to the central subgroup forces
Indeed, the induced representation itself restricts to as copies of , because conjugation by every coset representative is trivial on ; alternatively this follows from Schur's lemma and the positive multiplicity after restriction.
Each consequently acts in the representation affording as the scalar . Taking its determinant character gives
The left side is trivial since and every linear character kills . The right side is nontrivial since has order and . This contradiction proves
The argument is the central commutator has no torsion from an abelian Sylow subgroup determinant obstruction.