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The first law of thermodynamics isso, regarding $S$ as a function of $(T,V)$,Equality of mixed partial derivatives gives the thermodynamic derivation of blackbody radiation pressureWriting $a={\pi }^2/(15{\hslash }^3{c}^3)$, we have $E=aV{T}^4$, and henceEquivalently, $d(P/T)/dT=a{T}^2$, soThe condition $P=o(T)$ as $T\to 0$ forces $C=0$. Therefore the radiation pressure is