Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 216 6 b Solution Created 2026-10-03 Updated 2026-10-05
Put and . The probit regression likelihood is , so with the stated normal prior,Differentiating gives the probit posterior scoreEquivalently, the th likelihood term is . The prior's gradient is essential.
This posterior density is smooth, positive everywhere, and bounded above by a constant times the Gaussian prior, since the likelihood is at most one and has positive normalizing constant. Its derivatives are integrable: differentiating a likelihood factor gives a bounded normal density, and differentiating the prior gives a linear factor times a Gaussian. Integration by parts therefore yieldsThus each component has a known zero expected value and can be used as a posterior score control variate. This identity differentiates the posterior density in the random parameter; it is distinct from the usual mean-zero score identity for a likelihood under repeated sampling.
The requisite second moments are finite. For , is bounded. For ,Hence the score grows at most exponentially in , and the Gaussian upper bound on the posterior gives finite second moments. For a fixed vector , averaging is therefore an unbiased Monte Carlo estimator of the same mean; suitable coefficients can reduce its variance.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 216 6 c Solution Created 2026-10-03 Updated 2026-10-05
All moments below are under the proper posterior distribution of part (b). Write the known covariance matrix in block formThe score covariance is positive definite in this model. Indeed, a further integration by parts gives . If , then almost surely, because . Multiplying by would give , so .
For a fixed coefficient vector , the control variate summand has varianceThus the unique minimum is attained at , givingThe coefficient is fixed because the covariance is assumed known, and the posterior score control variate has mean zero, so this estimator remains unbiased.
We can identify exactly when the improvement is strict. Integration by parts with the bounded smooth function givesThe scalar expectation is strictly positive. Therefore whenever , and positive definiteness gives a strictly smaller variance in that case. If , and both estimators already have variance zero. The printed request for a smaller variance therefore needs this nondegeneracy qualification; a non-increasing variance always holds.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 218 1 b Solution Created 2026-10-03 Updated 2026-10-05
Write for rats and for repeated observations. With diet 1 as the reference level in a regression factor, the random-intercept linear mixed model iswith the two families of normal distributions independent and the covariates treated as fixed. The reported estimates areThe corresponding estimated standard deviations are and grams. Individual realized random intercepts are not parameters in this marginal model, and their predictions are not supplied by this summary. For distinct measurements on the same rat, , while the marginal variance is ; different rats are independent.
The estimated mean weight rises by grams per day, adjusting for diet and the rat's random intercept. This common slope is imposed across all diets: there is no time-by-diet interaction term, so these estimates do not compare diet-specific growth slopes. The intercept refers to time zero for diet 1 and a zero rat effect.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 218 5 b Solution Created 2026-10-03 Updated 2026-10-05
The parameters are , and innovation variance . Stationarity gives , and the Markov property gives . Multiplying the initial density and the transition densities yields the stationary Gaussian AR1 likelihood, with :The initial-observation factor depends on all three parameters and must be retained for the full stationary likelihood function. Omitting it gives a conditional likelihood given , a different objective.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 218 6 b Solution Created 2026-10-03 Updated 2026-10-05
The two predictors have correlation coefficient , so there is severe multicollinearity. Their centered slope Gram matrix isThus either partial slope has variance . Relative to a univariate regression with the same error variance, the two-predictor variance inflation factor and standard-error factor areThe small eigenvalue makes the contrast between the two slope effects particularly poorly estimated. The univariate regressions test marginal association with the response; the bivariate tests ask whether one predictor adds an effect while holding its nearly identical companion fixed. Their much larger standard errors therefore make the partial tests insignificant without contradicting the marginal significance. The two fits also estimate slightly different residual variances, explaining why the reported standard-error ratio is not exactly 5.21.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 1 ii Solution Created 2026-10-03 Updated 2026-10-05
Independence makes the variance of an estimator equal toWith , differentiate to obtain . The second derivative is , so the unique minimum isEquivalently, the inverse-variance weighted mean uses withWe assume positive measurement variances. A zero-variance observation already supplies the true value exactly.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 1 iv Solution Created 2026-10-03 Updated 2026-10-05
Equal variances make every weight , so the inverse-variance weighted mean reduces to the arithmetic mean. Independence givesThus the variance scales as , whereas the uncertainty expressed as a standard deviation scales as .
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 1 v Solution Created 2026-10-03 Updated 2026-10-05
A valid covariance matrix must be real symmetric and a positive semidefinite matrix, with . Conversely, every such matrix is the covariance of a possibly degenerate multivariate normal distribution. The diagonal correlations are ; the printed strict inequality can only concern distinct indices. Pairwise bounds do not suffice: the by correlation matrix with diagonal and every off-diagonal entry has eigenvalue along and is invalid. Even strict pairwise inequalities allow singularity: off-diagonal entries give an eigenvalue zero.
For the inverse requested in the question, assume in addition that is a positive-definite matrix. Write , and . Up to a constant, the log-likelihood is . Its score function and second derivative areThe correlated Gaussian common-mean estimator is thereforeIts expectation is , and direct covariance propagation givesThe Fisher information is , so this variance attains the Cramer-Rao bound and the estimator is an efficient estimator.
If is singular, an ordinary Lebesgue density and are unavailable. When lies in the range of , the same formulas hold on that range with its Moore-Penrose inverse. Otherwise there is with , and determines exactly with zero variance. The usual nonsingular Cramér–Rao calculation then does not apply.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 2 iv Solution Created 2026-10-03 Updated 2026-10-05
A log-flat improper prior is not appropriate when all known are positive: the integrated likelihood in (iii) has a positive finite limit as , so its integral against diverges. One defensible noninformative choice is the scalar Jeffreys prior for an additive variance component, calculated holding the mean parameters fixed:Indeed the normal variance score has information . This is a scalar conditional-information prior, not a claim that its product with the flat mean prior is the joint Jeffreys prior. It is bounded near zero and is at infinity. The integrated likelihood is uniformly bounded near zero and is bounded by a constant times at infinity, independently of the mean-shape parameters, since . Thus and a proper external prior on the physically admissible ensure posterior propriety. Proper weak scale priors are another option. If known errors vanish, the boundary argument and appropriate prior need separate reconsideration.
For an efficient parameterization, use with and . A chain on this joint reduced parameter space targetsThe factor is the Jacobian determinant. At each iteration propose , with for a fixed nonsingular proposal covariance, and accept with probability . Proposals outside the physical prior domain have target zero. Tune during warmup and freeze it for the retained Random-walk Metropolis algorithm. To obtain samples of the full original parameter vector, independently draw from its retained positive prior and reconstruct ; the resulting vector is . Analytically marginalizing using (iii) would also be valid.
Use several dispersed chains, trace plots, rank-normalized split , and the effective sample size of a Markov chain for each parameter and for . These Markov chain Monte Carlo convergence diagnostics reveal poor mixing and disagreement but do not prove convergence. Estimate the integrated autocorrelation time ; with retained draws, . Default to no thinning of a Markov chain, so the thinning factor is . If storage requires thinning, choose a spacing after inspecting the autocorrelation and verify the retained-chain effective sample size; no finite spacing guarantees independent draws.
Using the retained samples, computeThese are posterior summaries, provided the corresponding moments exist, not uncertainties of the numerical estimates. A proper prior alone does not ensure finite second moments; choose or check the external prior accordingly. The Monte Carlo standard error of the posterior mean is approximately .
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 3 i a Solution Created 2026-10-03 Updated 2026-10-05
. The exponential covariance function gives a stationary Ornstein-Uhlenbeck process. At a small lag ,The variance of a difference quotient therefore diverges as , so the process has no mean-square derivative. Its continuous version has rough, nondifferentiable paths, matching the jagged P2 trace in the original PDF.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 3 i b Solution Created 2026-10-03 Updated 2026-10-05
. This is a Gaussian kernel covariance. Near zero, , consistent with a finite mean-square derivative variance. The kernel has derivatives of every order, and the resulting Gaussian process admits a smooth version. P3 is smooth but does not repeat, unlike P1.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 3 iii Solution Created 2026-10-03 Updated 2026-10-05
At the fitted hyperparameters, define , , and , with the matrices formed by pairwise kernel evaluations. Conditional independence of observation noise and future latent values givesThe residual has zero covariance with , so the joint normal law makes it independent of . This derives the conditional multivariate normal distribution and the Gaussian process regression posterior:The covariance is a Schur complement and is positive semidefinite. When nonsingular, its joint density is . Repeated phases can make it singular, in which case the displayed normal law is interpreted on its support.
This predicts the true latent light curve, so no future measurement variance is added. For noisy future observations, add their independent noise covariance to . Fixing the hyperparameters omits their estimation uncertainty, as requested; integrating over their posterior would add it. The periodic model extrapolates by phase, even though all prediction times follow the observed times.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 3 ii Solution Created 2026-10-03 Updated 2026-10-05
Use the periodic covariance functionIts positive semidefiniteness follows by pulling back a Gaussian kernel to the circle . A zero Gaussian process mean is an ensemble statement, whereas an exactly zero long-term average for every periodic light curve is stronger. To impose the latter literally, use a periodic Gaussian process with zero period average, replacing the kernel byHere is a modified Bessel function, and is the period average of the kernel. Subtracting each process's random period average produces this covariance, so it remains positive semidefinite. We use to enforce the stated mean subtraction; using gives the usual ensemble-zero-mean formulation and the same likelihood derivation.
Let and . The prior latent vector is and the independent Gaussian noise is , so with . The Gaussian-process marginal likelihood isPositive measurement variances make positive definite even if is singular. Maximize over all three hyperparameters, using a broad search in to find competing aliases, followed by joint optimization. Cholesky decomposition evaluates the likelihood without explicitly forming an inverse.
For a well-resolved interior maximum, let be the Observed Fisher information in the coordinates . Then . Equivalently, the profile-likelihood curvature in gives the same local nuisance-adjusted variance; keeping the other hyperparameters fixed would generally underestimate it. A profile interval with is a local approximation. If the period likelihood is multimodal or poorly constrained, fit the complete posterior with proper hyperparameter priors and report its modes and marginal credible intervals rather than a single Hessian error bar. The sampling pattern can create period aliases that a single local search misses.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 4 iii b Solution Created 2026-10-03 Updated 2026-10-05
The terms involving giveCompleting the square produces the truncated normal distributionFor , its normalized density is on . The exponential prior shifts the untruncated conditional mean downwards before truncation; changing the variance here to the intrinsic variance would be incorrect. These are the other latent-variable updates of the formal Gibbs sampler.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 219 4 iii c Solution Created 2026-10-03 Updated 2026-10-05
Keeping the powers and exponentials of and in the joint kernel gives the two inverse-gamma distributions, using the printed shape–scale convention:Indeed their kernels are and . With positive measurement variances and generic continuously drawn latent values, the two scale parameters are positive almost surely. Together with (a),(b), these are all formal full conditional updates.
There is, however, no joint posterior probability distribution to sample under the stated priors. Integrate out the intrinsic first. For fixed , the observational marginal density iswhere is the centred normal density of variance . Substitute . Dominated convergence givesThe convergence is uniform on any compact interval and any compact positive interval, since the normal densities are uniformly bounded and continuous there. Hence some such region has for all sufficiently small , andIntegrating over those positive-measure intervals proves that the full normalizing constant is infinite. If all , the boundary also gives a positive marginal likelihood and a divergent integral at fixed . Thus , even though its generic full conditionals are proper. Apparent stability of a simulated chain cannot establish a nonexistent stationary probability law.
A valid repair that preserves direct sampling is to replace the two log-flat priors by independent proper and , with all four constants positive. The normal and truncated-normal updates remain as above, whileWith positive , the flat prior is then harmless: after integrating it out, the Gaussian measurement likelihood is bounded uniformly over the latent shifts and the scales, and the remaining proper priors integrate to one. A proper prior on is also possible.
For this repaired model, initialize , and finite . Repeatedly choose one of the coordinates with fixed positive probabilities and redraw from its full conditional using the latest values. This Random-scan Gibbs sampler preserves the proper target and satisfies detailed balance: for each coordinate, both forward and reverse flows equal the marginal density of the remaining coordinates times the product of the two conditional densities. A systematic full sweep is another invariant scheme, though it need not itself be reversible.
Run several dispersed chains; inspect traces of both scales, , representative latent values and the log posterior. Assess rank-normalized split , autocorrelation, and the effective sample size of a Markov chain, and extend runs until relevant Monte Carlo errors are sufficiently small. Scale–latent dependence can cause slow mixing, so diagnostics must include boundary exploration and alternative initializations. Keep post-warmup draws without automatic thinning. These are convergence checks for the repaired posterior; the printed model admits only the formal update algorithm, not a valid posterior-sampling interpretation.