Past exam of the physics B course of the University of Cambridge / 2014 / Paper 2 / Section B / B8

An isotropic linear elastic solid has two independent elastic constants. For infinitesimal strain,The shear modulus $G$ governs shape change and the bulk modulus $K$ governs volume change. Young's modulus $E$ and Poisson's ratio $\nu$ are equivalent parameters:Positive strain energy requires $G,K>0$, hence $-1<\nu <1/2$; $\nu \to 1/2$ is the incompressible limit. Small-amplitude bulk waves have speeds $c_P=\sqrt{(K+4G/3)/\rho }$ and $c_S=\sqrt{G/\rho }$. Isotropy removes directional dependence, not the distinction between compression and shear. These laws apply within the elastic small-strain regime, not after yielding or fracture.

For a rigid body about a chosen origin,The inertia tensor is real and symmetric, so orthogonal principal axes diagonalize it. Angular momentum is parallel to angular velocity for rotation about a principal axis, but need not be parallel in a general direction. Its eigenvalues are the principal moments of inertia.

If the origin is translated from the centre of mass by $\mathbf{a}$, the parallel-axis theorem becomes $I_{ij}=I_{ij}^{\mathrm{CM}}+M(a^2{\delta }_{ij}-a_i{a}_j)$. In body axes, Euler's equation is $\mathbf{\tau }=(d\mathbf{L}/dt{)}_{\mathrm{body}}+\mathbf{\omega }\times \mathbf{L}$. Thus the full tensor is needed whenever the rotation is not confined to one fixed principal axis.

For two bodies interacting through $U({\mathbf{r}}_1-{\mathbf{r}}_2)$, defineTheir kinetic energy separates exactly:Without external forces, the centre of mass moves uniformly while $\mu \ddot{\mathbf{r}}=-\nabla U$. The relative orbit is a one-body problem with reduced mass $\mu$, not generally either individual mass. For $m_2\gg m_1$, $\mu \simeq m_1$; for equal masses $m$, $\mu =m/2$. If the interaction is central, relative angular momentum is conserved and the relative motion is planar.

Dynamic viscosity measures resistance to a velocity gradient. In Newtonian simple shear, ${\tau }_{xy}=\eta \partial u_x/\partial y$; positive viscosity dissipates mechanical energy into heat. Kinematic viscosity is $\nu =\eta /\rho$. For an incompressible fluid of constant viscosity,Scaling velocity by $U$ and length by $L$ gives the Reynolds number $\mathrm{Re}=\rho UL/\eta =UL/\nu$, the ratio of inertial to viscous terms. At small Reynolds number, creeping-flow approximations neglect inertia; at large Reynolds number, inertia dominates much of the bulk but viscosity can remain crucial in boundary layers. A large Reynolds number permits instability and turbulence; it does not by itself specify a universal transition threshold. Geometry and disturbances also matter.