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The matter part of the massless closed-string vertex operator isIts symmetric trace-free polarization is the graviton, while its antisymmetric polarization is the Kalb–Ramond field, or B-field. The mass-shell condition $k^2=0$ and transversality make $V_{ϵ}$ a primary operator of conformal weights $(1,1)$, as required for an integrated string vertex operator.

The graviton polarization has the linearized gauge redundancywhile the antisymmetric polarization obeysIn either case the change in the integrated vertex is a worldsheet total derivative, hence vanishes on a closed worldsheet; in covariant language it is BRST-exact. This string-state gauge redundancy is the vertex-operator form of linearized target-space diffeomorphism or two-form gauge invariance.

The conserved number operator isSubstitution of $\Psi =\sqrt{\rho }{e}^{-i\theta }$ into the Landau-Ginzburg theory givesThe imaginary term is a total derivative, soThus $\rho$ is the number density and is the canonical momentum conjugate to $\theta$. The canonical commutation relation is $[\theta (\mathbf{x}),\rho (\mathbf{y})]=i{\delta }^{(d)}(\mathbf{x}-\mathbf{y})$. Consequently, for ${\theta }_0=\int d^{d}x\theta$ in volume $V$,Equivalently, the averaged phase $\bar{\theta }={\theta }_0/V$ obeys $\Delta \bar{\theta }\Delta N\ge 1/2$. This number-phase conjugacy means that a state of sharp $N$ has no sharp phase, whereas a phase-selected state exhibiting spontaneous symmetry breaking must superpose different number sectors. Such sectors become effectively degenerate in the thermodynamic limit.

Stability requires $\lambda >0$. The classical potential $r\rho +\lambda {\rho }^2$ has a symmetry-breaking minimum when $r<0$, atWriting $\rho =\bar{\rho }+\delta \rho$ and discarding constants and total derivatives gives the quadratic LagrangianThe density fluctuation is a gapped amplitude mode, while the phase is the prospective Goldstone boson.

In the CP1 spinor representation,where the ${\sigma }_i$ are Pauli matrices. The transformation $z\mapsto e^{i\alpha (x,t)}z$ leaves $\mathbf{n}$ unchanged. For $U\in SU(2)$,with $R$ in the special orthogonal group $SO(3)$, so $z\mapsto Uz$ induces $n_i\mapsto R_{ij}{n}_j$.

A rotationally invariant first-order term is the Ferromagnetic Wess–Zumino termUnder the phase redundancy it changes as ${\mathcal{L}}_{\mathrm{WZ}}\mapsto {\mathcal{L}}_{\mathrm{WZ}}-\kappa \dot{\alpha }$. The change is a total derivative, so the action has the required invariance.

For $z=(e^{-i\varphi }\cos (\theta /2),\sin (\theta /2){)}^T$,Thus $i\kappa z^{†}\dot{z}=(\kappa /2)(1+\cos \theta )\dot{\varphi }$. Dropping the total derivative $(\kappa /2)\dot{\varphi }$ and writing $s=\kappa /2$ givesThe leading rotationally invariant gradient energy is $({\rho }_s/2)(\nabla \mathbf{n}{)}^2$, so an effective Lagrangian is