Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 52 4 c Solution 2026-10-14
With and , and , where . No carrier momentum is withdrawn; hence the integrated momentum flux is exactly constant:On an initially small-Froude number branch, the pressure term dominates. At leading orderA slightly more accurate large-distance amplitude is , so . The Froude number satisfies and remains small. The growing depth can eventually violate confinement or the shallow water assumption; this does not make the asymptotic momentum calculation inconsistent within its intended regime.
On an initially large-Froude number branch, horizontal momentum flux dominates instead. The leading depth is constant, , while the decaying reduced gravity makes the Froude number still larger. To resolve the small change, put and :soThe depth decreases slightly and tends exactly to . Its Froude number grows like . Both approximations agree with the exact depth equation : the subcritical flow deepens, while the supercritical flow thins.
Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 52 5 e Solution 2026-10-14
The filling box model requires the first outflow to spread across the enclosure and remain above unmodified fluid, while a narrow nearly vertical plume rises below it. Several mechanisms can defeat those assumptions. A tall narrow box makes the plume a substantial fraction of the width, so its compensating return velocity is no longer small and modifies both fluid entrainment and momentum flux. A fast ceiling current can descend the sidewalls and overturn the initially stable upper region. In both cases a horizontally uniform slowly descending filling-box first front is inappropriate. Strong plume displacement from the centre, imposed crossflow, large source volume, vents or substantial wall cooling likewise alter the volume and heat budgets.
A useful diagnostic is whether the ceiling outflow's inertial acceleration, of order , overwhelms the restoring buoyancy of the nascent layer. If is not small for its depth , the outflow can penetrate or overturn the stratification rather than remain trapped above it. This is a diagnostic Froude number, not a universal threshold without specifying the wall-current geometry and mixing. Low Reynolds number invalidates a constant turbulent entrainment coefficient, and thermal diffusion or wall heat loss can erase the sharp first-front jump. Thus large aspect ratio, strong return circulation, overturning, ventilation or diffusion require a model beyond the standard filling-box approximation.
Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 76 3 c Solution 2026-10-14
Assume the jump is stationary, short compared with the scale of width variation, hydrostatic on either side, and has negligible bed stress integrated over its short length. Treat its width as constant. It must occur on the downstream supercritical branch, at . The discharge from the control gives the local unit-width dischargeBefore the jump the energy is still . Writing , its equation is . Its positive roots are and ; the former is supercritical. ThusMass conservation gives . The hydraulic jump momentum balance conserves . Factoring out the non-jump solution gives the conjugate-depth relationConsequently the conditions immediately after the jump areIts Froude number is below one. The specific-energy loss isSelecting the deeper root of the unchanged energy equation would be wrong: that would conserve the energy across a turbulent jump instead of the momentum.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 75 3 c Solution Created 2026-10-03 Updated 2026-10-14
Close the unresolved head of the gravity current byHere the speed is measured relative to the resting deep ambient, and are the depth and reduced gravity immediately behind the head. The Froude number expresses conversion of the head's hydrostatic pressure head into motion and depends on the ambient-depth ratio and head physics.
A front condition can be motivated by a steady control volume in the front frame: balance mass conservation, momentum conservation and the upstream/downstream Bernoulli equation, with a stagnation region and the appropriate ambient return flow. Assumptions include small density contrast, approximately hydrostatic far fields, negligible imposed ambient current, specified far-field depths, and a prescription for any mixing or energy loss. Viscous/turbulent head structure and finite-depth return flow change ; it is not fixed by the outer one-layer equations alone. A deep-ambient ideal head often motivates a constant order-one value, but no numerical choice is needed here.
The shallow-water approximation fails locally in the head because its vertical and horizontal dimensions are comparable and vertical accelerations are appreciable. The Froude number closure is a boundary condition for the outer shallow water equations, not a claim that they resolve the front itself.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 75 3 d Solution Created 2026-10-03 Updated 2026-10-14
Without settling, and . The left-running rarefaction wave has the unchanged Riemann invariant and similarity coordinate . HenceMatching to the Froude number condition givesThe full outer profiles are for ; the displayed fan for ; and for , whereAhead of there is only ambient fluid, so the particle-laden layer has zero depth. The shelf width is for every finite positive . It disappears only in the formal dry-front limit, where . For , the fan/shelf junction lies to the left of the initial barrier; the profiles remain consistent. This is the finite-Froude lock-release rarefaction, valid while the reservoir can be treated as semi-infinite.
Lock-release depth and velocity profiles, with settling attenuation of the reservoir disturbance and approximate front
. Details. Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 80 3 Solution Created 2026-10-03 Updated 2026-10-14
Balanced variables and PV derivation. Write the disturbance reduced pressure as . Leading geostrophic balance gives , and leading hydrostatic balance gives buoyancy anomaly . The geostrophic material derivative isIt includes horizontal advection, not an independent prognostic vertical velocity. The appropriate regime has small Rossby number, small stratified Froude number, thin aspect ratio and slow evolution; a common scaling has of order one and .
Only the vertical rotation component is retained in the traditional approximation. In the horizontal momentum balance, the horizontal part of the rotation vector multiplies the small vertical velocity; in vertical momentum, its contribution is small compared with leading hydrostatic pressure and buoyancy in the thin-layer scaling. Away from the equator these corrections are smaller by a factor of order . They need not be small in equatorial or strongly nonhydrostatic settings, so the approximation has a definite regime of validity.
Put . Eliminating from buoyancy givesThe last step needs justification because and do not commute on arbitrary fields. Their extra terms here areSubstitution into the supplied vorticity equation givesSince ,This is three-dimensional quasi-geostrophic potential vorticity conservation; the height-dependent coefficient is retained inside the derivative.
At a small steady lower elevation , impermeability gives , evaluated at to leading order. Substitution into buoyancy and division by gives the topographic buoyancy boundary condition for quasi-geostrophic flow,
Rossby waves at rest. For constant let and . Linearization about relative rest gives . A Fourier wave givesFor , the zonal phase speed is westward. At fixed altitude the PV perturbation is ; its total field is the background with sinusoidally displaced contours, as sketched below.
Rossby-wave PV contours and meridional flow producing westward phase propagation
. Details. A northward parcel displacement has : it retains the smaller background PV of its origin. The inverted geostrophic velocity associated with a positive PV crest is northward on its eastern flank and southward on its western flank. Advection of the background PV then decreases the anomaly on the eastern flank and increases it on the western flank, shifting the crest westward. This is a PV-restoring mechanism, not a westward mean current.
Differentiating the dispersion relation gives the group velocityFor nonzero , the vertical phase speed is , soThus upward energy propagation accompanies downward vertical phase propagation, and conversely. For the vertical group speed is zero and a vertical phase speed is not defined.
Stationary topographic response. Assume , and nonzero corrugation wavenumber . In a uniform current the laboratory dispersion is . For a stationary quasi-geostrophic mountain wave, , givingFor , the linear lower-boundary condition becomes . Its forced nonzero- component therefore hasIf , the vertical wavenumber is real. Both signs would be bounded aloft, so boundedness alone is insufficient for uniqueness. Impose an upward radiation condition, excluding waves incident from infinity; equivalently switch on the terrain forcing causally with arbitrarily weak absorption aloft. Since has the sign of , chooseThe unique outgoing forced component is thenThe bottom derivative and verify the phase and amplitude. In this stationary pattern it is the intrinsic frequency that describes downward vertical phase propagation relative to the current; the laboratory frequency is zero.
If or , defineExclude exponential growth at infinity. The unique decaying forced component isAt the excluded value , a nonzero prescribed bottom derivative cannot be matched by a bounded constant/linear vertical solution; the steady idealization is singular. At the boundary is not crossed and there is no forced response in the linear nonzero- sector: , rather than an expression obtained by dividing by . Uniqueness throughout refers to the prescribed forced Fourier component, with the reference state fixed and no independently incident waves or added mean-state changes.
The propagation criterion explains why topographically forced planetary Rossby waves can carry energy into a moderately westerly stratosphere, while easterlies and sufficiently strong westerlies block their vertical propagation. Larger horizontal scales more readily meet the criterion. Real dissipation, height-dependent winds and critical levels modify the simple solution and allow wave–mean-flow interaction; the ideal constant-coefficient calculation establishes the propagation filter, not a complete theory of stratospheric evolution.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 80 4 Solution Created 2026-10-03 Updated 2026-10-14
Stable stratification is a constraint on motion, not an isolated parcel spring. A light-over-heavy density profile has . An adiabatically displaced parcel has buoyancy anomaly relative to its surroundings. If one neglects the pressure response and movement of surrounding fluid, the vertical equation would be . A finite spherical blob cannot satisfy that isolated-oscillator picture: incompressible flow requires surrounding fluid motion, and the pressure perturbation communicates its acceleration to the rest of the fluid.
This can be shown directly with the linear Boussinesq equations. For a uniform background, take a Fourier wavevector . Pressure removes the component of the buoyancy force parallel to this wavevector. Taking the divergence of momentum to determine pressure and projecting the vertical component givessoThis pressure projection in a displaced stratified blob produces frequencies less than except for wavevectors with . A localized spherical perturbation contains a range of directions and therefore a range of frequencies. It deforms and emits internal gravity waves, rather than remaining one sphere oscillating coherently at . The added mass of a rigid sphere is a useful inertia analogy, but its numerical correction does not define an exact oscillation frequency for a deformable material blob in stratified fluid.
Internal waves and energy transport. The restoring force supports anisotropic internal gravity waves: their frequency depends on the direction, not just the length, of the wavevector. For a two-dimensional positive-frequency branch, with . Differentiation givesThe vertical group and phase velocities have opposite signs. Wave energy therefore travels along a direction different from the direction of phase propagation, a point essential in selecting radiation conditions for wave-generating obstacles.
For constant , the linear perturbation energy density per reference mass isDot momentum with velocity and multiply buoyancy evolution by ; the terms cancel, leaving . The second term is the available potential energy stored by displacement against the stable density profile. In an ideal fluid, that energy is exchanged with kinetic energy or transported away, not irreversibly dissipated by buoyancy diffusion.
Steady flows, layers and topography. Stable stratification penalizes vertical displacement and favors flows with small vertical motion when the stratified Froude number is small. The natural vertical displacement scale associated with kinetic energy is of order ; obstacles requiring much larger displacements can cause blocking and diversion instead of simple overpassing. In the ideal model fluid retains its buoyancy label, so motion tends to follow density surfaces. This inhibits vertical mixing but does not forbid horizontal rearrangement or turbulence powered by a shear flow.
A uniform current crossing topography generates stationary internal waves when its intrinsic frequency lies in the internal-wave range. For horizontal wavenumber , stationarity gives . Height-dependent wind and stratification replace this by the Scorer parameter relation derived in Question 1. A decrease of that parameter can produce a turning level, evanescence and vertical trapping, explaining lee-wave trains confined near a lower boundary. The exact channel superpositions in Question 1 also show that nonlinearity does not automatically destroy every wave solution.
Stability of the background density profile does not imply stability of every flow built on it. Sufficiently large waves can overturn density surfaces, and shear can supply energy to disturbances. Ideal advection can create fine structure, but irreversible homogenization of buoyancy in a real fluid additionally involves diffusion or dissipation. A finite-amplitude ideal solution is consequently distinct from a guaranteed stable or physically realizable state.
How rotation changes the picture. With the vertical Coriolis parameter , the corresponding uniform-background inertia–gravity dispersion becomesWhen , the propagating branch lies between and . Rotation also allows a slow balanced sector: horizontal pressure and Coriolis forces balance, vertical pressure and buoyancy balance, and the circulation can be described through potential-vorticity inversion. Small Rossby number and small stratified Froude number lead to the quasi-geostrophic equations rather than to the fast internal-wave dynamics. Vertical shear is then tied to horizontal buoyancy gradients through thermal-wind balance.
In this balanced sector, a planetary or topographic PV gradient supports Rossby waves, whose restoring mechanism is conservation of PV under displacement across that gradient. Stable stratification couples horizontal levels through the term, and the mountain-wave calculation in Question 3 illustrates its vertical propagation filter. Thus stratification can support rapid buoyancy-restored waves, constrain slowly evolving balanced circulation, and shape interactions with boundaries; which description applies depends on the velocity, length, time and rotation scales.
Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 83 3 Solution 2026-10-14
Model the post-eruption flow as an axisymmetric, shallow, hydrostatic, turbulently mixed layer on a horizontal bed. Neglect entrainment, erosion, heat exchange, rotation and large-scale viscous drag. Particles are dilute, with density , uniform-in-depth particle volume fraction and constant downward settling speed relative to the carrier gas. Deposited particles are not resuspended. Their volume is small enough that settling does not significantly change the bulk carrier volume. Let be ambient air density and carrier-gas density at its local temperature, and use a leading Boussinesq approximation for the mixture motion. DefineThe hot gas reduces the density excess; the ground-hugging current model requires . If density contrasts are too large for Boussinesq dynamics, density-weighted balances would be needed instead. The equations below are a stated shallow-layer model, not a description of the initial explosive vent jet.
For layer height and radial depth-averaged speed , the appropriate shallow-water balances areThe hydrostatic force gives the nonconservative momentum equation . In particular a spatially varying particle fraction must not be treated as constant reduced gravity when differentiating pressure. With no heat exchange or entrainment, a carrier-temperature anomaly is advected:At this order is proportional to . At the bed the carrier has no normal penetration and particles have absorbing deposition flux ; at the top the pressure equals ambient pressure. Axis regularity requires and smooth scalar fields, with no further source after the initial pulse. The initial height, particle inventory and temperature anomaly specify the released volume and ash content. Outside the front , the current layer is absent. At a resolved advancing head, use the material-front condition and the gravity-current front condition , where is an order-one front Froude number and refer to the fluid feeding the head. The front closure replaces unresolved head dynamics; simply prescribing both a zero-depth mathematical edge and a finite-depth box-head speed would be inconsistent.
To obtain a gravity-current box model, assume horizontal as well as vertical mixing, uniform in a disk of radius , and a negligible-volume head whose feeding depth is the box depth. The conserved bulk volume givesA bulk velocity satisfies interior continuity for this box. Rather than impose a uniform pressure on the full shallow-water equations and thereby lose the head force, replace their momentum dynamics by the front closure. Total suspended particle volume is , so bed deposition givesThese ordinary differential equations, together with initial , are the axisymmetric settling box model. The maintained negative thermal term may eventually cancel particle buoyancy and cause lift-off; beyond this horizontal gravity-current model does not apply.
For the requested particle-only calculation set and define the initial reduced gravity . The equations reduce toEliminating time gives . Integrating from the release state yieldsThus the monodisperse circular ash runout has limiting radiusThe maximum outward distance beyond the initial release edge is . When the vent scale is negligible, set in this late-time source idealization. The resulting radius scales as ; it is not obtained by conserving reduced gravity after particles settle out.
To determine the time, put , and . The concentration relation becomes , and the front equation reduces toConsequentlyThe furthest reach is a limiting radius, approached asymptotically rather than attained at a finite stopping time. As the residual particle concentration vanishes, the front slows exponentially. A finite observational threshold for remaining ash would give a finite practical stopping time, but no such threshold is part of these balances.
The local ash deposit density is most naturally its mass per horizontal area, . Once the front has arrived at , its local deposition flux is . For , define ; the arrival time is zero inside the initial footprint and otherwise . Sincewe can integrate the flux exactly. Using gives the circular ash deposit profileIt is constant under the initial disk, then decreases to zero at the limiting edge. Particle solid volume per area is ; deposit thickness is if a bulk deposit density including voids is supplied. The problem does not determine that packing density.
For a negligible initial radius this simplifies toIts integral confirms that the complete initial ash inventory is deposited. The finite- formula gives the same budget including its central flat portion.
Monodisperse axisymmetric ash box: asymptotic runout and decreasing radial deposit density
. Details. The diagram uses the negligible-vent-radius idealization and time normalized by . It illustrates both the asymptotic approach to and the smoothly vanishing outer deposit. All these predictions depend on the mixing and constant-Froude head closure; they do not claim to resolve the initial blast or the ultimate inertia-dominated motion of almost particle-free gas.
Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 77 3 Solution Created 2026-10-03 Updated 2026-10-14
For the shallow-water approximation, let the vertical scale be much smaller than the horizontal scale, so vertical acceleration is negligible and pressure is hydrostatic. Assume constant density, a flat impermeable bottom, a free surface under constant atmospheric pressure, and a horizontally moving column with no leading-order vertical shear. Neglect friction. Taking the bottom at , hydrostatic pressure is , so its horizontal gradient is independent of . The horizontal momentum equations are thereforeIntegrating incompressibility from the bottom to the free surface, using zero bottom vertical velocity and the surface kinematic condition , givesTogether these are the nonrotating shallow water equations.
Rotation with angular velocity adds Coriolis force terms and to the left sides of the and equations, respectively. The centrifugal potential is absorbed into the background pressure and effective gravity. ThusWrite and . Taking the horizontal curl, including the derivatives of the advecting velocity, yieldsFor example the curl of the Coriolis force contribution is , and the curl of nonlinear advection supplies . Since and , division givesThis is exact shallow-water potential vorticity conservation within the rotating shallow water equations.
For the quasi-geostrophic approximation, take a horizontal scale , speed , mean depth , and slow time . Require small Rossby number and small surface departure . Introduce the Rossby deformation radius and Burger number . Geostrophic balance gives , hence . The Froude number is . These assumptions select slow balanced motion, with fast gravity-wave transients absent at leading order.
Define the quasi-geostrophic streamfunction by . The leading geostrophic flow is , which is horizontally nondivergent. Expanding the exact shallow-water potential vorticity givesThe correction is smaller than by . Advecting it by the leading geostrophic flow, while the constant leading term has zero gradient, givesHere potential-vorticity conservation means that is carried unchanged by the leading horizontal trajectories. Potential-vorticity inversion means solving the elliptic equation , with appropriate boundary or decay conditions, to recover and thus the velocity. Conservation evolves the scalar field; inversion obtains its velocity field.
For a mean current , substitute and into potential-vorticity conservation. Retaining first-order terms givesLet . Differentiating the mean inversion relation gives . Away from this is zero, so decay at both infinities gives . A velocity jump would introduce a derivative of a delta function, absent from , so is continuous. Integrating through zero now gives , and therefore
For the regular interfacial normal mode , the linear equation readsIn each region, choose zero perturbation potential vorticity, giving . This supplies a regular solution even if at isolated locations away from the interface. Continuity and decay require , where . Integrating the equation across zero givesSince , the nonzero normal mode hasThis potential-vorticity step edge wave is an interfacial Rossby wave. Displacing the potential vorticity jump creates alternating anomalies; their inverted velocity displaces the interface further with an intrinsic propagation opposite to the positive mean current. The mechanism requires a nonzero jump, or more generally a gradient, of the mean potential vorticity. It does not require planetary variation of . Reversing the jump reverses the intrinsic propagation; setting the jump to zero removes this interfacial restoring mechanism.
Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 77 4 Solution Created 2026-10-03 Updated 2026-10-14
Define the quasi-geostrophic streamfunction by . Leading horizontal geostrophic balance, , gives . The hydrostatic approximation gives , henceThus is the material derivative along the leading geostrophic flow, and the vertical derivative of pressure determines the buoyancy perturbation. This also gives thermal wind: and .
The balanced regime is favored by small Rossby number, a shallow aspect ratio, and a Burger number of order one. Equivalently the stratified Froude number is small. On a beta plane, require , and take slow, initially balanced motion away from the equator. Under the traditional approximation, the horizontal Coriolis force generated by vertical velocity is small because vertical velocity is small, while the vertical rotational force is small compared with the leading hydrostatic pressure and gravity terms. Strong stratification and small aspect ratio justify retaining only the vertical component of Earth's rotation in this regime; this argument is not uniform near the equator.
Put . The buoyancy equation gives . Substitution into the vertical vorticity equation yieldsThere is an important commutator cancellation. With ,Also for . Adding terms therefore proves potential-vorticity conservation:This is the three-dimensional quasi-geostrophic potential vorticity.
At an impermeable stationary lower boundary , the kinematic condition is . For small elevation and slope, evaluate this at the reference level to leading order. Combining it with the buoyancy equation gives the rigid-boundary buoyancy condition for quasi-geostrophic wavesThe quantity in parentheses is the boundary displacement plus its buoyancy-equivalent displacement.
Now take constant and the mean quasi-geostrophic streamfunction . Its mean buoyancy perturbation is , consistent with thermal wind, and its interior potential vorticity is constant. In the boundary condition, the perturbation velocity advects the mean boundary buoyancy gradient. Keeping this contribution givesIn particular the term must not be omitted.
The linear interior potential-vorticity equation is . Starting with zero interior perturbation potential vorticity, and with forcing only through the boundary, it remains zero. For a steady solution this is also the regular zero-interior-PV choice, continued through any isolated zero of . The inversion equation for a horizontal mode isThe printed convention takes ; for either hemisphere the decay rate is defined using . Boundedness aloft selects the decaying mode. Writewith real part understood. The linear boundary condition becomesFor , a steady quasi-geostrophic mountain wave is thereforeOn , its real meridional velocity isFor the positive-parameter convention and , the velocity minimum lies one quarter wavelength downstream of each topographic maximum; its maximum lies one quarter wavelength downstream of each topographic minimum. If the velocity prefactor changes sign, maxima and minima interchange. The condition alone does not fix that prefactor if is allowed to be negative. The upper panel shows the positive-current convention.
Meridional velocity relative to topography for a steady mountain wave and a resonantly growing edge wave
. Details. At , the free boundary Eady edge wave has zero frequency in the ground frame. If , a steady amplitude cannot satisfy the forced amplitude equation. With , integration givesConsequentlyThe symbol multiplying here is the horizontal wavenumber , as in the PDF. Taking the real part and differentiating in givesFor , positive , and , the meridional-velocity minima coincide with topographic maxima, and its maxima with topographic minima. This is the lower panel. The change from quadrature to opposition is the phase of a resonantly forced topographic edge wave.
The stationary relief continuously excites a boundary Rossby wave whose intrinsic propagation exactly cancels mean advection. The forcing therefore remains coherent with that wave; with no damping or radiation loss for this trapped mode, its linear amplitude grows secularly. This is a resonant topographic quasi-geostrophic wave. Unlimited growth is a conclusion of the linear idealization: eventually the small-disturbance approximation fails.
The assertion that resonance must be unsteady needs nonzero forcing. If , then and the boundary current does not cross the relief; if , the forcing also vanishes. In either case the zero disturbance is a steady solution even if . For example, choose , , and ; this is a concrete exception to an unconditional resonance claim. When both horizontal wavenumbers vanish, and the stated decaying-wave ansatz itself does not apply.
Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 83 1 a Solution Created 2026-10-03 Updated 2026-10-14
Assume a steady, incompressible, inviscid flow with a nearly uniform velocity across each water section. The channel varies slowly enough for vertical accelerations to be negligible, pressure to be hydrostatic and the water surface to be nearly horizontal across the width. Atmospheric pressure is uniform; neglect surface tension, wall friction and energy losses. The hydraulic equations apply away from jumps and short nonhydrostatic regions.
The Euler equation for horizontal momentum, with hydrostatic pressure, givesIntegrating gives a constant Bernoulli equation head . Conservation of mass gives the constant volume discharge . Thus the shallow-water specific energy, measured above the local bed, isDefine the Froude number by for the positive flow direction. ThenAt fixed discharge and width, energy tends to infinity at both zero and infinite depth. It has a unique minimum atIndeed . Above the minimum there are two depth branches: the shallower one is supercritical flow and the deeper one is subcritical flow.
Specific-energy minimum and the subcritical and supercritical depth branches
. Details. The local long-wave propagation speeds from the shallow water equations are . In subcritical positive flow, one wave family travels upstream and one downstream. In supercritical flow both travel downstream. At critical flow the upstream-directed speed is zero, so the flow can provide hydraulic control separating upstream adjustment from downstream conditions. This statement concerns long waves in the slowly varying hydraulic approximation, rather than all short-wave disturbances.
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 90 1 a Solution Created 2026-10-03 Updated 2026-10-14
Assume the shallow-water approximation: the horizontal scale is long compared with the depth, the hydrostatic approximation applies, and the cross-section-averaged velocity is approximately uniform. Neglect viscosity and drag for this part. Volume conservation gives the constant discharge . The steady horizontal momentum equation isso its integral is the Bernoulli equation head . The shallow-water specific energy measured above the bed is thereforeThe Froude number compares the flow velocity with the long-wave speed :At fixed , the shallow-water specific energy tends to infinity as tends to zero or infinity. Its unique minimum occurs at the critical depthThe two depth branches above that minimum are subcritical flow, with , and supercritical flow, with . The long-wave characteristic speeds relative to the bed are . Thus a subcritical flow can receive information from downstream, whereas both characteristic curves travel downstream in a positive supercritical flow.
A hydraulic control is a critical section where one characteristic speed vanishes and a smooth flow can pass between the two branches. Regularity there supplies a condition relating , the depth and the geometry; together with reservoir or inlet data, it can determine the discharge. Merely finding is not enough: a finite depth gradient also requires the geometric forcing to vanish in the critical momentum equation.
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 90 3 c Solution Created 2026-10-03 Updated 2026-10-14
Assume the carrier fluid has ambient mass density , the particles have mass density , and volumes add. The well-mixed current then hasHere is the particle-fluid reference reduced gravity per unit volume fraction, which is the convention needed in the requested expansion. The initial current reduced gravity is ; it should not be confused with itself. The Boussinesq approximation requires .
For particles to remain well mixed, the turbulent vertical mixing time must be short compared with the settling time. In a turbulent diffusion description with diffusivity , require , or . Equivalently, characteristic turbulent vertical speeds should substantially exceed the particle settling velocity. Turbulence can maintain an approximately uniform concentration in the body while particles still settle relative to the fluid. At the impermeable bed, fluid has no normal transport into the solid boundary, but particles can reach and be captured by it. Assume no resuspension after capture.
Use a gravity-current box model of length , uniform depth and uniform concentration . Neglect ambient entrainment and the small volume change caused by depositing dilute solids, so remains constant. Take a constant front Froude number and the gravity-current front condition . With , the deposition flux is per unit bed area. The particle-volume budget isHence the integral model isThe model assumes a fixed rear boundary, one advancing front, a deep stationary ambient, negligible drag during the inertial spreading regime, and a perfectly absorbing bed. The supplied hindered-settling law is retained in the deposition closure.
For , eliminating time givesThe concentration integral is . ThereforeAs the particle concentration tends to zero, the current reduced gravity and front speed tend to zero. The hindered-settling runout in a rectangular channel isIt is a finite limiting distance; in this idealized model, the exponential tail of particle loss makes complete stopping asymptotic in time. For , omit . Using givesThe original PDF has in this expression; the TeX aid's is a transcription error. Dimensions independently confirm the square: has dimensions of length to the fifth power. If one instead names the initial current reduced gravity , the same expansion is . Late loss of turbulent mixing, viscous resistance or bed resuspension can change the physical runout beyond this specified box model.
Past exam of the mathematics course of the University of Cambridge 2009 ib Paper 1 17D Solution 2026-10-14
Use the steady inviscid, hydrostatic, slowly varying channel approximation, without a hydraulic jump. Conservation of volume flux per unit width gives . The free-surface Bernoulli equation isDividing by yieldsThe parameter here is the squared upstream Froude number. For nonzero discharge, regarding as a function of , its derivative is . It has its unique maximum at , where the local Froude number is one. Substitution gives . This maximum is the hydraulic control over a smooth hump.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 79 3 c Solution Created 2026-10-03 Updated 2026-10-14
For a high-Reynolds number thermal, buoyancy force scales as and inertial resistance scales as . Their balance gives . It is therefore natural to write a diameter-based Froude number closureThe order-one coefficient accounts for the thermal's shape, entrainment and flow structure. The main resistance is inertial pressure or form drag and the momentum needed to entrain and accelerate surrounding water, rather than molecular skin friction. Added mass matters when the thermal accelerates, so the Froude closure is a quasi-steady approximation.
In a homogeneous ocean all of the leading buoyancy comes from the bubbles. Parts (a) and (b) giveSubstituting into the speed law yieldsFor , this becomesThe square root is essential both physically and dimensionally. This approximation still requires dilute bubbles and retained gas; it is not a valid prediction of infinite speed where the pressure approximation approaches zero.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 80 3 Solution Created 2026-10-03 Updated 2026-10-14
Use an inertial gravity-current box model in a horizontal prismatic V-shaped valley. Let its section have area and width , where the dimensionless constant is half-width divided by depth. Let be front position and the representative uniform current depth. Assume negligible entrainment and volume loss, hydrostatic cross-sections, large Reynolds number, and negligible bed friction and axial bed slope. These assumptions describe the bulk spreading after the short dam-break adjustment; they do not give a universal law for a steep or friction-dominated valley.
For water of fixed volume , conservation gives . Close the front speed by the gravity-current front condition , where is a constant order-one Froude number for the chosen inertial front model. ThereforeIntegration gives . Once the initial reservoir length is negligible, the inertial dam-break current in a triangular valley satisfiesThe time exponent differs from a flat-bottomed channel because a V-shaped section stores volume proportional to . A viscous V-shaped channel gravity current obeys a different spreading law, so retaining the inertial assumption is essential.
For the short-lived eruption, interpret as the bulk mixture volume released during the event. Let be the well-mixed particle volume fraction, initially , let and be particle and ambient carrier densities, and assume a dilute Boussinesq approximation for the mixture. The particles provide reduced gravityAssume thermal buoyancy, compressibility, erosion and continued injection are negligible, and that the carrier volume remains . Turbulent mixing keeps the particles suspended uniformly while they settle vertically at a constant terminal settling velocity . For small spherical particles of radius in carrier viscosity , the Stokes settling velocity is when the particle Reynolds number is small. If an eruption volume is quoted as solid particle volume rather than mixture volume, replace the used here by that volume divided by .
The particle deposition flux per horizontal projected bed area is . The current's projected settling area is , soThe factor two reflects the triangular section's mean depth . Put and . The front and concentration balances becomeTaking the initial release length negligible compared with the final runout, integration yields the constant-settling runout in a triangular valley:In particular at fixed valley shape and front coefficient. With a finite initial length, replace by in the corresponding integrated relation.
The whole time dependence is determined analytically by the quadratureEarly spreading has , the water law with replaced by . At late times the concentration loss slows the flow, and decays exponentially with rate , where . The final length is a limiting runout reached as , not a finite-time stopping event in this ideal model.
To calculate the deposit profile of a finite triangular-valley particle current, let be final deposited particle mass per unit downstream length, and the initial particle mass. Deposition at a fixed section starts at arrival time , when the front first reaches . With the instantaneous front coordinate denoted , use to obtainWriting , this evaluates toand beyond . The profile decreases downstream, vanishes quadratically at the runout, and obeys . This integral check ensures that all initially suspended particle mass is accounted for.
For an areal rather than a linear deposit density, the changing valley width must also be specified. At lateral coordinate , the current covers the bed only while . Set , with on the valley axis. The mass per horizontal projected bed area is zero if , and otherwise isOn the axis this reduces to . Divide projected areal density by to obtain mass per actual sloping bed area. A specified packed deposit density then converts this areal mass to local deposit thickness; the spreading model itself predicts deposited mass, not a packing fraction.
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 71 3 b Solution Created 2026-10-03 Updated 2026-10-14
For dilute sediment volume concentration , define . Neglecting particle volume in the fluid-volume balance,This applies the Boussinesq approximation to the bulk mixture, requiring , and uses a deep ambient layer . A gravity-current front condition closes the unresolved nose. Write it as , with a prescribed order-one front coefficient . If the chosen Froude number is instead , then .
Use a parabolic-channel sediment-current box model for one side of the dam: initially its length is , depth , and uniform concentration . Its conserved fluid volume isFor vertical settling onto the channel sides, the projected deposition width is . Thus the total particle deposition flux is andThe geometric factor follows from ; using a rectangular deposition formula would give a different result.
Eliminate time and use :The runout length of a gravity current is the limit where suspended concentration vanishes:The model approaches this length asymptotically in time. It assumes negligible entrainment, erosion and water loss, and does not resolve the initial release or nose. If the initially disturbed region supplies both sides, apply the formula to each side using its share of the initial volume and length.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 74 2 c Solution Created 2026-10-03 Updated 2026-10-06
At the gravity current nose, the depth and velocity change over a distance comparable with the depth, with appreciable vertical acceleration and mixing. The hydrostatic approximation and the depth-uniform interior model do not resolve that structure. A suitable gravity-current front condition iswith a positive, order-one Froude number determined by the nose closure and geometry. It is not fixed by the interior equations alone. This definition uses ; if the front condition is expressed using , its numerical coefficient changes by .
For a late-time gravity-current box model, take the depth and particle volume fraction to be uniform over , and neglect entrainment and resuspension. The initial volume is , soThe total particle volume is . Deposition over the projected boundary width gives . With the specified hindered settling factor, the prismatic triangular-channel gravity-current box model isInitializing this approximate model with and matches the original volume and concentration; it does not assert that the immediate dam-break flow is a uniform box.
Eliminate time to obtainSince the left primitive is , the hindered-settling runout invariant in a prismatic triangular channel isThis relation, the volume constraint and determine the late-time evolution. If desired, the time is given by the quadrature . The physical branch has nonnegative right-hand side in the boxed relation; it ends when that expression reaches zero.
Thus the limiting runout length of a gravity current, measured from the closed end, isThe advance beyond the dam is . In the dilute limit, . The ideal model approaches its finite runout length of a gravity current only as : near the limit decays exponentially with rate and the front speed tends to zero. The exponent uses the prismatic triangular geometry; a channel widening with has a different volume constraint and runout law.




