Bednorz-Müller experiment 2026-10-18
In 1986, Johannes Georg Bednorz and Karl Alexander Müller precipitated mixed oxalates from aqueous barium, lanthanum and copper nitrates using oxalic acid. Heating at for five hours preceded pressing at and reheating for sintering. X-ray diffraction resolved three phases. Rectangular pieces carried gold electrodes and indium wires; four-terminal sensing in a continuous-flow cryostat measured electrical resistance versus temperature. Annealing atmosphere and measuring electric current density were varied; larger electric current densities suppressed the drop. An onset near differed from the much lower temperature where the drop approached three orders of magnitude.[ref]
This was evidence for possible granular superconductivity, with phase identification unfinished. The paper deferred Meissner effect and heat capacity tests; its proof note corrected bulk lanthanum/barium ratios. A resistive onset did not establish a uniform bulk superconducting transition temperature.[ref]
Possible high Tc superconductivity in the Ba-La-Cu-O system by Johannes Georg Bednorz and Karl Alexander Müller. §IV, p.192; proof note, p.193
Their 1987 authored lecture describes later magnetometer checks on lead, followed by magnetic susceptibility measurements: samples with a resistive drop developed diamagnetism at somewhat lower temperatures. Combining magnetic, transport and X-ray diffraction results identified barium-substituted as the superconducting phase. These later results strengthened the case beyond the initial mixed-phase transport evidence.[ref]
Diamagnetism 2026-10-18
Diamagnetism is a magnetic response in which the induced magnetization opposes the applied magnetic field intensity. In a linear isotropic description, with negative magnetic susceptibility .
Magnetic polarizability of a perfectly conducting sphere Created 2026-10-20 Updated 2026-11-05
In the small-sphere oscillatory-field limit, surface current density excludes the changing magnetic field. Adding a central magnetic dipole to a uniform applied field and imposing zero normal field at the sphere gives . The minus sign expresses diamagnetism; it does not make this dipole's backward radiation cancel the electric contribution.[ref]
Past exam of the chemistry B course of the University of Cambridge 2023 Paper 2 B6 a iv Solution 2026-10-20
Both complexes have all their electrons paired, so . Their spin-only magnetic moment is thereforeThey exhibit diamagnetism. The formula describes the spin contribution; it does not say that a closed-shell sample has no diamagnetic response to an applied field.
Past exam of the chemistry B course of the University of Cambridge 2023 Paper 2 B7 b i Solution 2026-10-20
The neutral product is cis-, and the displaced material is six waters per nickel:The two phosphorus donors of dppe chelate the same metal, forcing adjacent donor positions. The diamagnetism identifies a square-planar, paired Ni(II) centre rather than a tetrahedral high-spin centre. Its valence count is electrons. The reaction is ligand substitution, not reduction of Ni(II).
Past exam of the chemistry B course of the University of Cambridge 2024 Paper 2 B8 a ii Solution 2026-10-20
iron remains Fe(II), , in both states; the change is a spin crossover, rather than a change in oxidation state. At the higher temperature the high-spin complex has : four unpaired electrons, , andThis matches the observed moment. At low temperature a low-spin complex with has and shows diamagnetism. Cooling switches high-spin to low-spin . Emptying the metal–ligand antibonding orbitals strengthens and shortens the Fe–N bonds, accounting for the contraction by roughly .
The octahedral splitting and electron pairing energy must be sufficiently close for both states to be accessible. The low-spin state gains electronic energy, while the high-spin state has greater spin degeneracy and usually greater vibrational entropy because of its softer bonds. The resulting Gibbs free energy balance favors high spin at higher temperature. The two endpoint observations do not by themselves specify hysteresis or transition cooperativity; those require a temperature series. Coupled structural and magnetic measurements distinguish this explanation from a mere bond-length anomaly.
Past exam of the chemistry B course of the University of Cambridge 2025 Paper 2 B6 b v Solution Created 2026-10-20 Updated 2026-10-31
Both complexes contain cobalt(III), hence a metal ion. The approximately octahedral molecular geometry, relatively high metal oxidation state and five Ammonia donors make the octahedral splitting large enough that pairing is favorable. Their low-spin configuration isAll six metal electrons are paired, and the ligands in coordination chemistry have closed shells, so neither complex has a permanent spin magnetic moment: both exhibit diamagnetism. The difference between N and O attachment is insufficient to change this low-spin assignment.
There are valence electrons, all paired, so diazomethane exhibits diamagnetism. A localized orbital occupancy consistent with the double-bond construction in 2(c)(i) isHere mean central and terminal. Each listed occupied spatial orbital contains two electrons of opposite spin. The central N's two p atomic orbitals are perpendicular, so they can support the two perpendicular pi bonds. No central-N lone pair is left over: its positive formal charge accompanies four bonding pairs in this Lewis structure.
Allowing resonance mixes a terminal-N lone pair into the C–N–N orbitals. In the alternative terminal- basis, the same electron count is four occupied orbitals ( electrons), one terminal- lone pair (), one perpendicular N–N orbital (), and two occupied orbitals of a three-centre C–N–N system (). The -electron count and the paired ground state survive this change of description; the localized picture does not assert two perfectly isolated double bonds.
Past exam of the condensed matter physics course of the University of Oxford 2016 3 b Solution 2026-10-25
A shell has one hole in the otherwise filled shell. Hund's rules give , , and, for a more-than-half-filled shell, : the free-ion term is . Its Landé factor isDistinguish the Curie effective moment from a saturated projection:The question then explicitly asks us to use orbital quenching in the crystal. Ligand fields split and mix orbital states, suppressing their freely orientable angular momentum. The spin-only approximation has , , so but the two field-axis projections are . The latter, not , belong in the tanh argument and saturation magnetization.
The sulfate and water environment supplies mainly closed-shell, weakly magnetic surroundings, stabilizes localized Cu2+ sites and separates their moments so that exchange can be weak on the temperature scale considered. Paramagnetism here is an approximation of weakly interacting local spins, not a claim that dilution guarantees no magnetic ordering at any temperature. Elemental copper has a filled band and itinerant conduction electrons rather than one localized Cu2+ spin per atom. Pauli spin response and orbital/core contributions then replace a local-spin Curie law; ordinary pure copper has a weak net diamagnetic response.[ref]
https://www.sciencedirect.com/science/article/pii/S1090780715000774. 2015 primary measurement, abstract: negative volume susceptibility of high-purity copper wire
There is one Cu2+ per formula unit, hence m. The spin-only weak-field SI volume susceptibility isThese neglect exchange, anisotropic factors and background diamagnetism. At high field and low temperature, saturation requires the nonlinear response in a; a field-independent Curie value then describes only the zero-field slope.
Past exam of the condensed matter physics course of the University of Oxford 2017 2 c Solution 2026-10-25
Let denote the spin-summed density of states per volume. An electron moment with magnitude the Bohr magneton has Zeeman energies . At low temperature, the two spin populations areThe common chemical potential changes only at order , so it does not affect this linear imbalance. The magnetization is . Define SI volume magnetic susceptibility by and take the weak applied field as . Then Pauli paramagnetism givesThe last equality uses the three-dimensional parabolic free electron model, . This susceptibility is nearly independent of temperature for , unlike the Curie law for localized independent moments. The displayed result excludes orbital diamagnetism and interaction enhancements. If susceptibility instead denotes , omit ; confusing that convention with changes the units.
Past exam of the condensed matter physics course of the University of Oxford 2018 4 a Solution 2026-10-25
A material with paramagnetism develops a magnetization parallel to a weak applied magnetic field intensity, with positive magnetic susceptibility and no spontaneous magnetization in its paramagnetic phase. Molecular oxygen is an example; it has unpaired electron spins.
A material with diamagnetism develops an induced magnetization opposing the applied magnetic field, with negative magnetic susceptibility. A closed-shell atom such as helium is an example; its orbital response is diamagnetic.
A ferromagnet has a spontaneously ordered magnetization below its Curie temperature, even in the limit of vanishing applied magnetic field. Iron below its Curie temperature is an example. Different magnetic domains can cancel the net moment of an unmagnetized bulk sample, despite nonzero local spontaneous magnetization.
Past exam of the condensed matter physics course of the University of Oxford 2019 4 a Solution 2026-10-25
A material showing paramagnetism has an induced magnetization in the direction of a weak applied field, giving positive magnetic susceptibility, and no spontaneous magnetization once the field is removed in the paramagnetic phase. Alignment of permanent atomic or nuclear moments is one mechanism.
A material showing diamagnetism develops an induced moment opposing the applied field, giving negative magnetic susceptibility. Closed electronic shells supply a familiar orbital contribution; the response need not require permanent moments.
A ferromagnet has a phase with a spontaneous ordered magnetization below its Curie temperature, produced by cooperative alignment of moments. Its magnetic domains can cancel in a macroscopic zero-field sample, so a measured zero net moment alone does not show that the material lacks ferromagnetism.
Past exam of the condensed matter physics course of the University of Oxford 2019 4 b Solution 2026-10-25
The helium atom has a closed electronic shell with total electronic spin and orbital angular momentum zero. The nucleus of helium-4 also has spin zero. At low temperature there is no Curie response from permanent atomic or nuclear moments; the leading atomic response is diamagnetism.
Let denote the number of atoms per volume and let be the mean squared radius of one electron. Use the symmetric magnetic vector potential . Expanding the electron kinetic Hamiltonian gives the quadratic field termwhere isotropy gives . The term linear in orbital angular momentum vanishes in the spherical electronic ground state. ThusFor weak susceptibility, , so the Langevin diamagnetic susceptibility isIf the supplied density is a mass density , use , with the atomic mass unit. The result is approximately temperature independent at fixed density. The factor two for the two electrons is already included; has not been defined as their summed radius.
Past exam of the condensed matter physics course of the University of Oxford 2019 4 d Solution 2026-10-25
Add the electronic diamagnetism of each helium atom to the nuclear magnetic susceptibility, using the same for both contributions in the helium-3 sample:The density cancels when the two terms balance. The sign-change temperature in the independent-atom approximation is thereforeNo numerical atomic radius was supplied, so the exact numerical value remains conditional on that electronic length scale. Taking , where is the Bohr radius, gives . A slightly more explicit estimate uses the helium variational effective charge , for which a hydrogenic orbital has , givingAbove this scale the electronic contribution is negative and dominates; below it the positive nuclear contribution dominates within the independent-moment approximation. The estimate is not a precision prediction of a real interacting helium phase.
Past exam of the condensed matter physics course of the University of Oxford 2021 4 a Solution 2026-10-25
Undoped gallium arsenide is expected to be diamagnetic at zero temperature. Its valence band is filled and its conduction band empty, so there are no mobile conduction band electrons to give Pauli paramagnetism. The specified absence of localized magnetic moments removes a Curie law response and the usual mechanism for ferromagnetic ordering. The remaining induced orbital response is diamagnetism. This classification uses the ordinary weak-field band insulator picture; the band gap suppresses thermally generated carriers as .
Past exam of the condensed matter physics course of the University of Oxford 2021 4 b Solution 2026-10-25
The number of formula units per volume follows from the mass density:Each neutral formula unit contains electrons, so . Let be the electron-weighted mean-square orbital radius, averaged over all these electrons. The supplied Larmor-Langevin susceptibility then gives the dimensionless SI volume magnetic susceptibilitywhere is the Bohr radius. An explicit rough atomic-scale assumption gives .
The quoted bulk data do not determine : a nuclear charge does not specify an orbital radius in a screened many-electron chemical atom. Consequently the numerical estimate just made has atomic-model uncertainty; it is not a deduction with guaranteed 30 percent accuracy. For example, the alternative assumed gives four times the magnitude while leaving every supplied bulk number unchanged. Atomic wavefunctions, an explicit screened-orbital model, or measured atomic magnetic susceptibilities of materials exhibiting diamagnetism would be needed to support that accuracy. Keeping explicit makes the later comparison independent of an unadvertised radius assumption. The bare electron mass belongs in this atomic formula; the conduction band effective mass is relevant instead to the large donor envelope in part (c).
Past exam of the condensed matter physics course of the University of Oxford 2021 4 c Solution 2026-10-25
In the hydrogenic donor state approximation, the screened Coulomb potential energy is and the kinetic term uses . Rescaling the hydrogen atom gives the effective Bohr radius of a hydrogenic donor and the positive binding energyThereforeThe radius here is the exponential length of the ground-state wavefunction, not its root-mean-square radius. With , radial integration gives and .
For dilute independent donors of number density , a bound spin one-half electron has magnetic moment magnitude , with the Bohr magneton defined using the bare electron mass. Its weak-field Curie law response isFor the orbital response, expand the effective mass Hamiltonian in a uniform magnetic field, using . The spherical ground state has zero orbital angular momentum; the quadratic term raises its energy byDifferentiating this energy twice and using givesThe donor-only magnetic susceptibility cancels whenThe negative sign of drops out of the linear magnetic susceptibility. This crossover is far below , consistent with donor binding. It assumes sufficiently weak magnetic field, negligible exchange between donors and a thermal scale above any inter-donor splitting; sufficiently dilute donors can satisfy those assumptions. The background diamagnetism from part (b) is excluded from this cancellation.
In paramagnetism, a material develops magnetization along a weak applied field, with positive susceptibility; in diamagnetism, it develops an induced moment opposing it, with negative susceptibility. In a simple localized-moment paramagnet, Zeeman alignment competes with thermal disorder. For independent two-state moments ,when the field is weak and demagnetizing corrections are negligible. Stronger fields saturate the moment; interactions and conduction-electron Pauli paramagnetism can depart from this Curie law.
Ordinary diamagnetism comes from a field-induced change of orbital motion, including in closed-shell matter without permanent atomic moments. Its weak susceptibility is often nearly temperature independent away from a transition, and it contributes a background even when another magnetic response dominates. A nonuniform field tends to attract a paramagnetic specimen toward stronger field and repel a diamagnetic specimen in the weak linear regime. Calibrate the holder contribution and field gradient and measure a temperature/field series to distinguish induced response from retained magnetization. Ferromagnetic hysteresis and superconducting flux expulsion require different collective explanations.
Past exam of the physics B course of the University of Cambridge 2011 Paper 1 Section B B7 Solution 2026-10-20
The microscopic magnetic response becomes a macroscopic field problem through the magnetization , the magnetic dipole moment per unit volume. Definein magnetostatics. Bound currents are represented by and surface current . Normal is continuous across an interface, while . It is generally incorrect to impose continuity of every component of both fields. A linear isotropic material has and , but a ferromagnet usually requires a nonlinear, history-dependent constitutive relation.
Internal field differs from externally applied field. For uniform magnetization along a principal axis of an ellipsoid, the demagnetizing field is and . A linear specimen therefore has apparent susceptibility relative to the applied field. Shape is especially important for large susceptibility. A long closed magnetic circuit reduces stray fields; a bar magnet still has demagnetizing fields despite the absence of magnetic monopoles. Equivalent magnetic-pole descriptions are bookkeeping for magnetization divergence, not free magnetic charge.[ref]
Permanent Ferromagnets. Equations (699)–(706): magnetization, scalar potential and effective pole density
In paramagnetism, permanent localized moments are preferentially aligned by the field, against thermal disorder. For independent spin-one-half moments with projections , the two Zeeman energies givein the dilute weak-field limit with . This is a Curie law; the response saturates at when alignment dominates. More generally, spin gives . Interactions can produce a Curie–Weiss response over a suitable range. Conduction-electron Pauli paramagnetism need not show the localized-moment law.
In diamagnetism, the field induces a magnetic moment opposing it, so the linear susceptibility is negative. The microscopic cause is the change in orbital electronic motion, and a closed-shell insulating material has no permanent atomic moment to orient. This weak response is often only mildly temperature dependent away from other transitions. It also exists as a background in materials with a stronger positive response. Perfect flux expulsion in a superconductor is a distinct collective phenomenon and should not be identified with ordinary weak atomic diamagnetism.
In ferromagnetism, exchange interactions stabilize spontaneous magnetic order below the Curie temperature. A specimen can have zero net moment while its magnetic domains remain locally magnetized in different directions. Domain-wall motion and moment rotation produce a large response; anisotropy and pinning lead to remanence, coercivity and hysteresis. Increasing field eventually approaches saturation. Heating above the ordering transition removes spontaneous order, although an applied field still induces a response. Soft magnetic cores favor easy reversal and small cyclic loss; hard permanent-magnet materials favor retained magnetization and resistance to reversal. These properties concern collective order and barriers, not merely independent moments all following a weak field.[ref]
University Physics Volume 2 by Samuel J. Ling and others. §12.7, Magnetism in Matter: susceptibility, magnetic domains, Curie temperature and hysteresis
A practical distinction requires a controlled field sweep and a separate magnetic readout. A toroidal core with drive winding , path length and current has approximately . A pickup winding measures ; integrating after calibration gives , and . Reversing the sweep reveals a loop whose positive loss area per volume is . An air-core/empty-holder reference, known geometry and turn count, offset correction, temperature control and slower sweeps test background, heating and rate-dependent eddy-current losses. A single force or susceptibility reading cannot establish spontaneous order or hysteresis. The original curves below are illustrative responses, not measured material data.
Magnetic response and hysteresis
. Details. Paramagnetism has positive susceptibility: permanent spin or orbital moments tend to align with a field against thermal disorder. Independent localized moments in the classical weak-field regime give , the Curie law. Conduction-electron Pauli paramagnetism has a different origin and need not follow that temperature law.
Diamagnetism is the induced magnetic response opposing the applied field, giving negative susceptibility. Changes in orbital motion underlie this response; it exists even without permanent moments. It is often relatively weak and only weakly temperature dependent, although particular quantum systems have stronger or more complicated behaviour.
Ferromagnetism arises from interactions favouring parallel magnetic order. Below the Curie temperature a domain can have spontaneous magnetization even at zero applied field. A sample can nevertheless have nearly zero net moment if differently oriented domains cancel. Domain rearrangement and rotation produce a nonlinear magnetization curve, saturation, remanence and coercivity; hysteresis dissipates energy in a field cycle. Above the ordering temperature the spontaneous order disappears, and a Curie-Weiss susceptibility is a useful mean-field approximation. The signs of weak-field susceptibility distinguish para- and diamagnetism; spontaneous order and domain dynamics distinguish ferromagnetism from independent-moment alignment.
