Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 59 4 d Solution Created 2026-10-03 Updated 2026-10-06
Assume a circular orbit of radius , a spherical planet, bolometric Bond albedo , negligible internal heat, unit thermal emissivity and complete redistribution of absorbed heat over the sphere. The stellar luminosity is , and the planet absorbs the incident radiative flux through its projected cross-section:Thermal reradiation is . Equating these gives the planetary equilibrium temperatureThe planet's radius cancels. A non-black thermal emissivity divides the absorbed flux by in the fourth-power balance. For uniform dayside-only reradiation, the emitting area is and . With no local redistribution, the substellar point has , while other points depend on incidence angle. These are different temperature conventions, not contradictory formulas.
The planetary equilibrium temperature is not the surface greenhouse temperature or the internal effective temperature of a planet. If intrinsic cooling matters and both powers escape through the same emitting area, the total effective temperature obeys .
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 64 1 b Solution Created 2026-10-03 Updated 2026-10-06
The standard thin-disk dissipation flux, summed over both faces, follows by substituting the Keplerian accretion disk profile into the viscous heating rate:The Stefan–Boltzmann law gives because there are two emitting faces. Local radiative equilibrium consequently gives the effective-temperature profile of a zero-torque diskHere is the Stefan-Boltzmann constant. The scale is not the temperature exactly at the inner boundary: the zero-torque inner boundary condition makes that formal temperature zero. Maximizing shows that the maximum effective temperature of a zero-torque disk occurs at , with .
At equal central mass and accretion rate, characteristic effective temperatures scale as . Thus, comparing corresponding values of ,The neutron-star disk is about 180 times hotter. The Planck law and Wien displacement law move its characteristic emission to about 180 times higher frequency, or 180 times shorter wavelength. A white dwarf disk commonly emits in optical and ultraviolet bands, while the hotter neutron star disk can emit in X-rays. Absolute bands require an actual accretion rate; the relative shift follows directly from the stated scaling.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 64 1 c Solution Created 2026-10-03 Updated 2026-10-06
For the Rayleigh-Jeans spectrum of a finite blackbody disk, the Rayleigh-Jeans law replaces by . Here is the Planck constant and the Boltzmann constant. The multitemperature blackbody disk therefore hasFor example, setting makes its frequency-independent coefficient proportional to the finite dimensionless integralAlthough the exact effective temperature vanishes at the inner edge, the very narrow cold rim where the Rayleigh-Jeans law fails makes a negligible contribution in this limit. More formally, after dividing the integrand by , the inequality bounds it by , so dominated convergence justifies the result even at that edge.
At large radius, , and the contribution per logarithmic interval is . The outer disk dominates the low-frequency emission because its much greater area outweighs its lower effective temperature.
For intermediate frequencies use the allowed power-law approximation to the effective temperature and introduceThensoThe lower limit is much smaller than one and the upper limit much larger than one. Extending them to zero and infinity leaves a constant: near zero the integrand behaves as , and at infinity it decays exponentially. Hence the intermediate spectrum isThis is the one-third spectrum of a multitemperature disk. Much of the emission comes from radii where is of order , moving inward as the frequency rises. With the exact inner-edge profile, a broad intermediate interval also requires frequency well below ; the supplied approximation captures its slope away from the hottest annuli.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 64 1 e Solution Created 2026-10-03 Updated 2026-10-06
For a slowly rotating central star, the accretion-disk boundary layer radiates a luminosity . A layer of thickness comparable to the disk scale height has emitting area times a geometric constant. Applying the Stefan–Boltzmann law to this blackbody area givesComparing with gives the boundary-layer temperature scalingOnly the scaling is fixed: for a two-faced annulus of area , for example, . A surface belt gives a different order-one coefficient.
For a thin disk, , so a comparable luminosity emerges from a smaller emitting area at a higher effective temperature. The boundary-layer emission is harder than the disk emission, with its Planck law peak shifted to higher frequency. It is also closer to a single-temperature component than the broad multitemperature blackbody disk spectrum, under the adopted uniform-temperature approximation. Rapid stellar rotation weakens the heating and this conclusion's temperature contrast.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 315 3 a Solution Created 2026-10-03 Updated 2026-10-06
The two relevant categories are strongly irradiated, often transiting hot Jupiters, and young directly imaged exoplanets with large residual-entropy radii. The young objects are inflated relative to an old cold mass-radius sequence; a large young radius is not automatically anomalous relative to an age-appropriate formation model.
For a transit, the depth gives after geometric and limb darkening corrections; an independently estimated stellar radius sets . A measured planet mass then tests its location on the planetary mass-radius relation. For a directly imaged object, distance and integrated spectral flux give luminosity; a fitted effective temperature suppliesThe imaged radius is model-dependent because temperature, gravity and exoplanet clouds are inferred from its spectrum; its mass may also depend on age and evolutionary models unless dynamically measured.
Two broad explanatory classes are slower loss of existing heat and addition of heat to the deep interior. Specific delayed-cooling proposals are enhanced atmospheric opacity, which restricts radiative loss, and composition gradients producing layered convection in a giant planet. Specific heating proposals are tidal heating and Ohmic heating from currents induced by magnetized atmospheric winds, the proposed Ohmic heating of a giant planet. Heating must reach or influence sufficiently deep layers to maintain the interior specific entropy; merely heating the optically thin upper atmosphere is not equivalent. For young distant objects, retention of formation heat, described by hot and cold starts of a giant planet, itself explains much of the large radius without requiring the hot-Jupiter heating mechanisms.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 315 3 c Solution Created 2026-10-03 Updated 2026-10-06
The spherical stellar structure equations apply to a planet as well, with its appropriate equation of state:The last equation is the local first law, including gravitational contraction through the specific entropy change. For an isolated non-burning planet, , soIf the convective interior has nearly uniform specific entropy , positive outgoing luminosity gives . This entropy loss of an isolated convective planet describes its secular cooling.
During assembly, the gravitational energy scale provides a source of heat. Integrating hydrostatic equilibrium gives the virial theorem, , neglecting the surface-pressure term. For a monatomic ideal gas this becomes , hence . Contraction makes more negative, releases radiation, and heats part of the gas. A characteristic formation temperature has scale up to structure factors. The retained fraction depends on the accretion shock, producing hot and cold starts of a giant planet.
Formation releases heat, and an isolated planet subsequently loses specific entropy and intrinsic luminosity as it approaches a cooler, more degenerate state. The structure equations alone do not fix one initial temperature, and the early contraction of an ideal gas can increase its central temperature while its total energy decreases. “Cools” therefore need not mean that every depth becomes colder at every instant. Once degeneracy limits contraction, the thermal reservoir declines more directly; the emergent effective temperature usually falls along a fixed-mass cooling track.
This makes young giant planets attractive for exoplanet direct imaging: their thermal near/mid-infrared emission can be far brighter than that of old planets of the same mass. Imaging and spectroscopy measure projected separation, astrometry, luminosity, an exoplanet emission spectrum, temperatures and atmospheric molecular and exoplanet cloud signatures. Radius follows from luminosity and fitted temperature; mass and initial specific entropy generally require age/evolutionary information, or an independent dynamical mass measurement. A detected luminosity alone is not a model-independent planet mass.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 317 1 Solution Created 2026-10-03 Updated 2026-10-06
At the stellar surface boundary condition, match the interior to a stellar atmosphere, rather than setting the temperature and pressure to zero at an arbitrary radius. At a photosphere of radius , the enclosed mass is , the luminosity is , and the outward radiative flux defines the effective temperature through . With no external illumination the incoming specific intensity satisfies for . A deeper boundary is matched to the nearly isotropic radiative diffusion field. A grey atmosphere commonly matches near ; under the Eddington surface boundary condition this gives . For roughly constant gravity and opacity, the total pressure rises by relative to its outer boundary value; if radiation supplies appreciable support, the gas-pressure gradient uses the effective gravity instead.
Take increasing outward and the outward direction cosine. If is emission per unit path length and solid angle, the radiative transfer equation isDefine inward-increasing optical depth by and the source function by . Then . This states the emission-coefficient convention; if is defined per unit mass instead, the emission term is .
For frequency-integrated intensity, introduce the radiation-field momentsThe first angular approximation writes . Its odd part does not contribute to , soThis is the Eddington closure approximation, not an exact description of the escaping angular distribution. An approximate surface condition takes the outgoing hemisphere to have direction-independent intensity and the incoming hemisphere to be dark. Its moments give and . Integrating the moment equations with the closure then gives ; in thermal equilibrium, gives . This derives the usual approximate photospheric matching condition rather than imposing a zero surface temperature. For conservative coherent isotropic scattering, . Integrating the transfer equation gives and , the moment conditions for radiative equilibrium.
The exponential ansatz in the PDF has a genuine consistency problem. Compute its moments before making any approximation. For a nonsingular real intensity on all , take and defineThe continuous zero limits are , , . Direct integration yieldsFor a decaying nontrivial correction, and . Exact constant flux then requires . But for every nonzero real , so forces . Thus exact radiative equilibrium cannot imply a small nonzero for this ansatz.
Substitution into the full transfer equation makes the obstruction sharper. The exponential coefficient must satisfy, for every ,Comparing the constant and linear coefficients gives and . Hence regular real coefficients require , eliminating any decaying correction. This is the obstruction to a single smooth exponential mode in conservative grey transfer. There is no exact nontrivial real solution of the stipulated form with a small nonzero decay parameter. Choosing, for example, and supplies an explicit counterexample to the claimed exact flux constancy, because .
Several requested conclusions remain useful as formal approximations, provided they are identified as such. If , the large-depth exponential vanishes, giving , hence for the asymptotic physical flux. It also gives . Since , neglecting second-order angular errors yields the formal relation . However , so the finite-depth flux still varies at first order. The formal relation is not an exact transfer or constant-flux solution.
There is also a flux-normalization mismatch in the PDF's last displayed relation. With the same physical used above, the Hopf function of a grey atmosphere is defined byThe PDF's coefficient would require redefining its as physical flux divided by ; it cannot simultaneously use the earlier for the same physical flux. With the consistent physical-flux normalization, formal moment matching givesIn the intended small- approximation this isThe approximate outgoing surface ansatz then gives the limb darkening ratioFor finite , gives a parameter-dependent ratio, not a unique exact value. The two Hopf endpoint values alone do not determine the exact emergent intensity: the formal solution of the radiative transfer equation uses the entire source profile, for . Nor does the simple linear-plus-exponential ansatz satisfy the exact no-incoming-radiation condition for every negative . Thus is a clearly labelled approximate disk-centre-to-limb result, not an exact consequence of inconsistent premises.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 317 2 ii Solution Created 2026-10-03 Updated 2026-10-05
At the photosphere, use the stated boundary pressure and the effective temperature relation . The radiation constant obeys by the Stefan–Boltzmann law. Substitution into the radiative temperature gradient givesThis uses the approximate stellar surface boundary condition at optical depth ; it is not a universal photospheric gradient for arbitrary atmospheres.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 317 4 Solution Created 2026-10-03 Updated 2026-10-14
Assume an isolated star of initial mass five solar masses of approximately solar stellar metallicity. Rotation, convective overshooting and mass loss change numerical ages and the extent of a blue loop, so the ages below are estimates. Take zero age at the zero-age main sequence; the pre-main-sequence star phase adds a much shorter contraction time.
The original schematic Hertzsprung-Russell diagram marks the stages discussed below. The strip denotes the approximate Cepheid instability strip; the track is illustrative, rather than a computed stellar model.
The main sequence lasts roughly – years. CNO cycle hydrogen burning is concentrated in a mixed convective core. Its declining hydrogen mass fraction and rising helium mass fraction are nearly uniform there, while the retreating core leaves a composition gradient. The unprocessed envelope remains hydrogen rich. At the terminal-age main sequence, core hydrogen is exhausted and a hydrogen-burning shell takes over.
The inert helium core grows through shell burning. The Schönberg-Chandrasekhar limit is approximatelyBeyond this limit an isothermal nondegenerate core cannot remain in thermal equilibrium with its envelope. Core contraction and envelope expansion carry the star across the Hertzsprung gap. An initial slower shell-burning interval can precede the rapid crossing; the crossing itself is governed by Kelvin-Helmholtz contraction, with a representative – years. First dredge-up then mixes hydrogen-processed material into the convective envelope, lowering its hydrogen mass fraction and increasing helium and nitrogen, while leaving a composition discontinuity where the envelope later retreats.
At an age still of order years, core helium burning begins quietly: the core is nondegenerate, so there is no helium flash. The Triple-alpha process and subsequent alpha capture build a carbon-oxygen core. Core helium burning lasts roughly – years in representative solar-composition models. Pols's stellar-evolution notes illustrate the substantial dependence of these lifetimes on convective overshooting.
During a blue loop the envelope contracts and effective temperature increases, before the star returns redward. The loop depends on core and envelope structure and the hydrogen discontinuity left by first dredge-up. A loop reaching the Cepheid instability strip produces two further crossings, blueward and redward, in addition to the earlier rapid crossing of the Hertzsprung gap. Cepheid variables pulsate through the opacity mechanism, involving helium ionization. Neither loop extent nor all three strip crossings are guaranteed for every composition or mixing prescription. The hydrogen-burning shell continues moving outward in enclosed mass while central helium is depleted. Lattanzio's five-solar-mass tutorial shows these composition changes.
After helium exhaustion, at an age roughly – years, the star ascends the Asymptotic giant branch. An inert carbon-oxygen core is surrounded by helium-rich material and a hydrogen-rich envelope. Second dredge-up mixes helium and hydrogen burning products into the envelope and reduces the hydrogen-exhausted core mass. Subsequently a helium-burning shell and hydrogen-burning shell alternate in importance. A thermal pulse of an asymptotic-giant-branch star causes intershell convection, expansion and temporary quenching of hydrogen burning; third dredge-up can carry carbon and slow neutron-capture process products outward. Between pulses hydrogen burning rebuilds the helium layer. These mechanisms are illustrated in Lattanzio's AGB tutorial.
The following original stellar composition profile sketches distinguish hydrogen exhaustion from helium exhaustion; their mass boundaries are illustrative.
Schematic internal composition profiles during stellar evolution
. Details. The final giant phases add at most a few million years at this level of accuracy. Strong stellar winds remove the envelope; the hot remnant can illuminate a planetary nebula and then cool as a carbon-oxygen white dwarf. A typical remnant is of order one solar mass. The ordinary isolated case does not reach sustained carbon burning and core collapse. Thus the usual endpoint is a carbon-oxygen white dwarf, at a total age of order years, with its subsequent cooling age added separately.
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 317 1 iii Solution Created 2026-10-03 Updated 2026-10-05
The Stefan–Boltzmann law defines the effective temperature through . The stellar homology relations give , soThusIn a logarithmic Hertzsprung-Russell diagram, with plotted vertically against ,The usual horizontal axis increases in effective temperature toward the left, so the hotter, more luminous end lies toward the upper left. The quoted algebraic slope uses increasing as the coordinate.
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 322 3 Solution Created 2026-10-03 Updated 2026-10-14
An Algol binary is a semidetached binary: a cool evolved donor fills its Roche lobe, while a hotter and more massive mass gainer remains on or near the main sequence. Roche-lobe overflow feeds the companion through a stream, sometimes forming an accretion disk. A suitably inclined system is an eclipsing binary. The prototype's periodic dimming led John Goodricke to propose an occulting companion in 1783; his original observations record an early eclipse interpretation.
The Algol paradox arises if the present masses are assumed to have been constant: the lower-mass star is the more evolved one, even though coeval isolated stars of higher mass normally exhaust core fuel sooner. The mass-luminosity relation gives the rough nuclear-lifetime scaling , decreasing strongly with mass. The resolution is binary mass-ratio reversal. The present donor began as the more massive star, evolved first, and expanded into its Roche lobe. Transferring much of its envelope made it less massive and made its initially less massive companion the present mass gainer. Their current masses therefore do not reveal their original evolutionary ordering.
On a Hertzsprung-Russell diagram, both components start on the zero-age main sequence. The initially more massive donor leaves the main sequence first, moving toward lower effective temperature and higher luminosity as a subgiant or red giant. During envelope stripping, it remains oversized and overluminous for its decreasing mass because its evolved core continues to supply energy. The accretor gains mass, moves to higher effective temperature and luminosity, and can undergo stellar rejuvenation if fresh hydrogen mixes into its core. After substantial envelope removal, the donor contracts to a hot stripped star; a sufficiently low-mass helium core ultimately becomes a helium white dwarf. The schematic below separates the two identities through the transfer episode rather than relabelling them when their masses cross.
During the long-lived slow-transfer phase, conservative binary mass transfer from the lighter donor to the heavier accretor widens the orbit: for and . Transfer eventually stops when the donor's shrinking envelope can no longer maintain contact. The remnant can be a helium white dwarf if it never ignites helium, or a more massive helium-burning stripped star if it does. Later the mass gainer also leaves the main sequence. Reverse Roche-lobe overflow onto the compact remnant can lead to a common envelope, leaving a close double remnant after successful envelope ejection, or to merger. The detailed outcome depends on both masses, the separation, and how much matter and angular momentum escaped during earlier transfer.
The approximate mass-ratio boundary in the question has a stability interpretation. For an ideal fully convective donor star with adiabatic stellar radius response exponent , the conservative Roche-radius approximation gives . Dynamical stability of binary mass transfer requires , so a long-lived stable system hasA more massive convective donor expands relative to its shrinking lobe under mass loss, favouring runaway transfer and a common envelope instead of a persistent Algol phase. This explains the approximate Algol mass-ratio stability limit in that model. It is not a universal observational boundary: a donor with a radiative envelope or a substantial evolved core has a different adiabatic response, and nonconservative loss changes the Roche-lobe response. Van Rensbergen and collaborators' observed and modelled Algol distributions include reported mass ratios above and discuss uncertainties in their determination. The literal claim that all Algols obey the same cutoff is therefore too strong.
A sufficiently wide system first reaches Roche-lobe overflow on the red giant branch, when the original donor is likely to have a deep convective envelope. Straightforward conservative overflow while that donor is still more massive is then prone to dynamical runaway and orbital contraction in a common envelope; it does not naturally yield a wide, long-lived Algol-like configuration. A plausible route is substantial earlier envelope loss through a stellar wind, possibly tidally enhanced stellar wind loss, reducing or reversing the mass ratio before contact. Wind mass transfer in a binary star can also increase the companion's mass. The lower donor mass, reduced envelope and larger core fraction make later transfer easier to stabilize. Alternatively, a detached pair with the same reversed evolutionary appearance may be interacting only through a wind and need never have undergone overflow. Its current width alone does not uniquely determine the initial orbit, but it indicates that prior mass loss or a more general nonconservative history must be considered, rather than applying the simple conservative convective-donor picture unchanged.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 317 1 ii Solution 2026-09-25
Along the pp-chain homologous sequence, is constant and therefore . Normalizing to the Sun gives the transition mass
For the CNO cycle law , the nuclear scaling becomesThe opacity law is unchanged, so . Equating them givesand then
The effective temperature follows from the Stefan–Boltzmann law . Thus the pp branch has and , whereas the CNO branch hasOn a Hertzsprung-Russell diagram, both branches rise toward larger luminosity and, conventionally, leftward toward larger temperature. They join near ; the CNO branch has the steeper -- logarithmic slope and lies to the cooler side of the extrapolated constant-radius branch at fixed luminosity.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 317 2 ii Solution 2026-09-25
For , the angular moments areandThus this angular form satisfies the Eddington closure approximation, , and
Part (i) gives . Substitution in yieldsMatching powers of gives and , the latter being constant flux. Hence .
At the surface there is no incoming intensity. Applying this condition to the outgoing hemisphere in the moment approximation,so . ConsequentlyNow and the effective temperature is defined by . It follows thatAt the top of the grey atmosphere,
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 317 1 Solution Created 2026-09-24 Updated 2026-09-25
For a homologous star, hydrostatic equilibrium, mass conservation, and the ideal gas equation give the central scalingswhere is the mean molecular weight. Integrating the nuclear energy-generation law over a fixed homologous profile givesRadiative stellar structure gives independentlyEquating the two luminosities yieldsAt fixed zero-age composition, the stars are therefore homologous with
The effective temperature satisfies , so . The zero-age main sequence consequently hasIt is a steep line rising toward high luminosity and high temperature on a Hertzsprung-Russell diagram.
For fully ionized hydrogen and helium with ,while . At fixed mass,and the corresponding radius relation is
At the pure-hydrogen zero-age point ,whereasHenceandAs hydrogen is consumed, falls, so both and rise. In the usual diagram with temperature increasing leftward, the evolutionary track initially moves upward and leftward from the zero-age main sequence.
Planetary equilibrium temperature Created 2026-09-28 Updated 2026-10-06
For a planet of Bond albedo orbiting a blackbody star of radius and temperature , complete global redistribution and negligible internal heat giveUniform dayside-only reradiation replaces by . The planetary equilibrium temperature describes absorbed stellar power; including an intrinsic cooling flux gives a total effective temperature , distinct from . Neither quantity is necessarily the greenhouse-warmed surface temperature.
Radiative conductivity 2026-10-14
In the optically thick radiative diffusion in a star approximation, the heat flux is . The conductivity depends on opacity, mass density and temperature. It relates a material temperature gradient to energy transport and must not be confused with the emergent effective temperature.


