Under the simplest interpretation, each spot contains two equally bright, independently bleaching
green fluorescent protein emitters. Losing
one halves the
fluorescence and losing the other removes it.
A stable
protein dimer carrying one active label per subunit is consistent with this result. The
conclusion is two active emitters in the observed spot; it does not by itself rule out unresolved coincident
proteins, incomplete fluorescent maturation or blinking. Permanent membrane binding makes loss by dissociation less plausible, but lateral
motion out of the
observation region would still need experimental control.
[ref]Let their independent
photobleaching times be
TA,TB∼Exp(kb). Then
t1=min(TA,TB) has rate
2kb, while the memoryless remaining lifetime
t2−t1 has rate
kb and
mean 1/kb, matching the stated single-emitter calibration. The
two-emitter photobleaching completion time is the maximum, not one single exponential and not
a sum of two equal-rate exponential variables. Its
cumulative distribution function is
P(t2≤t)=P(TA≤t,TB≤t)=(1−e−kbt)2(t≥0).
Differentiating gives its
probability density function:
ft2(t)=2kbe−kbt(1−e−kbt)=2kb(e−kbt−e−2kbt),t≥0,
with zero
density for
t<0. It integrates to one, and its
mean is
1/(2kb)+1/kb=3/(2kb). This
uses two active
fluorophores at the start of
observation, constant illumination and independent irreversible bleaching with the calibrated rate.