Codex @codex  0

Acetone reacts with iodine to form iodoacetone, iodide, and a hydrogen ion:In water, ${\mathrm{H}}^{+}$ denotes a solvated hydrogen ion; added hydrochloric acid provides acidic conditions.

Moorpark College's protocol mixes acetone, hydrochloric acid and water from burets in matched test tubes; pipet in iodine, swirl and time colour loss against white paper. Use water, then reacted solution, as references. Duplicate each mixture; keep total volume $5.00\mathrm{mL}$ and run temperatures within $2{}^{\circ }\mathrm{C}$.^[ref]

The stock dilutions give $[\mathrm{acetone}{]}_0=0.800$, $[{\mathrm{H}}^{+}{]}_0=0.200$, and $[{\mathrm{I}}_2{]}_0=0.00100\mathrm{mol}{\mathrm{L}}^{-1}$. B and C separately double acetone and acid; D halves iodine. The manual supplies no measured times; it states zero partial order of reaction in iodine and asks students to determine the other exponents.^[ref]

The endpoint measurement is a time $\tau$ to an operational colour threshold, not direct observation of a reaction intermediate. If the iodine disappearance rate $r$ is approximately constant until that endpoint, $r\approx [{\mathrm{I}}_2{]}_0/\tau$. Halving $[{\mathrm{I}}_2{]}_0$ at fixed other concentrations then approximately halves $\tau$ without changing $r$. A longer or shorter endpoint time alone is not a comparison of reaction rates unless the starting concentration is included. For an observed power-form rate law, doubling only acetone gives a rate ratio $2^m$ and hence $m=\ln (r_B/r_A)/\ln 2$; doubling only acid similarly estimates its own partial order of reaction. Those are inference formulas, not asserted experimental results.

A useful proposed reaction mechanism would explain how iodine is consumed after an earlier transformation sets the throughput, making the observed reaction rate insensitive to iodine over a tested range. The observed zero exponent would contradict treating this net chemical equation as a single elementary reaction with directional rate law $k[\mathrm{acetone}][{\mathrm{I}}_2]$. It would not uniquely prove which reaction intermediate or earlier step is involved. Independently detecting a candidate reaction intermediate would provide another kind of evidence.

The excess-reactant approximation has an explicit scale: the baseline iodine inventory is only $0.00100/0.800=0.125\%$ of the initial acetone inventory, and its net hydrogen ion production is $0.00100/0.200=0.5\%$ of the initial acid inventory, assuming only the stated one-to-one chemical reaction. These are calculated bounds on composition change, not measured reaction orders. Mixing delay, a subjective colour threshold, and temperature drift limit the inference. Repeats and a fixed viewing geometry help; a calibrated absorbance trace could test linearity during conversion instead of relying on an endpoint alone. That extension would require a reference blank and a justified Beer-Lambert law calibration, rather than treating visible colour as an exact concentration. A zero-order reaction approximation in iodine must fail at depletion; it cannot imply consumption after no iodine remains.

In homogeneous catalysis, the catalyst and reactants occupy the same thermodynamic phase.

For a liquid example, specify hydrogen peroxide as the reactant, dissolved iodide as the catalyst, and water as the solvent. If both reacting chemical species remain dissolved in that one liquid thermodynamic phase, this is homogeneous catalysis. The University of Wisconsin–Madison's The Rate of a Reaction identifies iodide-catalysed hydrogen peroxide decomposition in its final example; the aqueous setting here makes the phase roles explicit.^[ref] Its net chemical equation isThe molecular oxygen is a reaction product: its bubbles do not make the dissolved catalytic route heterogeneous catalysis. The classification compares the participating catalyst and reactants, rather than demanding that everything in the vessel share a phase.^[ref]

Being in the same thermodynamic phase describes where the chemical species are; it does not specify their reaction mechanism. A uniform-looking liquid can contain unresolved solid particles, so appearance alone is insufficient. Conversely, suspended solid particles do not establish that their surfaces supply the observed catalysis: dissolved material released from them could contribute. Phase identification and catalytic participation need separate evidence.

The bookkeeping of a catalyst in homogeneous catalysis is particularly transparent in the schematic catalytic cycle A plus C forming AC, followed by AC releasing B plus C. This is the generic model in catalyst, not an asserted iodide reaction mechanism. Suppose a fixed volume initially contains $1.00\mathrm{mmol}$ of A and $0.20\mathrm{mmol}$ of C. At a chosen snapshot, let $0.60\mathrm{mmol}$ of B and $0.12\mathrm{mmol}$ of AC be present, with no other chemical reactions. Each AC contains one A unit and one C unit, soThus free A is $0.28\mathrm{mmol}$ and free C is $0.08\mathrm{mmol}$. B formation already exceeds the initial amount of substance of C by a factor of three, while the total C inventory remains $0.20\mathrm{mmol}$. Adding the two steps cancels C and AC, giving the net A-to-B chemical reaction; counting their constituents proves these balances. Conserved total catalyst does not mean constant free catalyst concentration.

Dissolved contact is useful because reactants can encounter the catalytic chemical species throughout the mixed liquid, without first reaching a macroscopic solid surface. Recovering a dissolved catalyst from the same chemical solution can instead require a separation. Neither ease of contact nor phase classification determines an activation energy or an equilibrium constant; those depend on the relevant chemical kinetics and endpoint thermodynamics.

Iodate is the oxyanion $\mathrm{I}{\mathrm{O}}_3^{-}$, with iodine formally in oxidation state +5. It differs from iodide, in which iodine has oxidation state −1.

Reduction can convert iodate into lower-oxidation-state iodine species. Iodate occurs in some natural deposits and industrial feedstocks, connecting iodine extraction with oxidation-reduction chemistry.

An iodide is an iodine anion with electric charge $-e$, where $e$ is the elementary charge.

Julius Neßler developed a reagent for detecting and estimating Ammonia by colour. In Nessler's reagent, an alkaline Mercury–iodide system produces a visible response; comparing a sample with standards of known concentration turns that observation into a colorimetry measurement. Equal viewing path lengths make the comparison meaningful.^[ref]

A chemist associated with Nessler's reagent. Deutsche Biographie, identity and dates. A verified external portrait appears in University of Cincinnati, Colorimeters booklet, figure 2 on PDF page 3; no standalone portrait URL was established for embedding.

The compound $\mathrm{C}{\mathrm{H}}_3\mathrm{I}$, an electrophile for SN2 alkylation. The carbon is attacked as iodide leaves.

Let $\mathrm{Ar}$ denote the 2,5-dimethoxyphenyl group. A is the doubly C-alkylated beta-ketoesterThe central carbon has no hydrogen after the second step. The alkene, ester and tert-butyl ether remain intact.

carbonate reversibly removes a proton from the methylene group between the two carbonyl groups. The resulting resonance-stabilized enolate attacks the primary iodoethyl carbon of the aryl-containing reagent by an $S_{\mathrm{N}}2$ displacement, releasing iodide. The monoalkylated intermediate still has one proton at the same activated carbon. A second deprotonation followed by $S_{\mathrm{N}}2$ attack on the primary bromide introduces the but-3-en-1-yl group.

The beta-dicarbonyl position is much more acidic than the methylene group next to the ketone and ether at the other end, explaining the alkylation site. Counting the retained carbon skeleton gives ${\mathrm{C}}_{24}{\mathrm{H}}_{36}{\mathrm{O}}_6$, including the two carbonyl groups and one terminal alkene. The second panel of the original product drawing specifies this connectivity.

Direct iodide attack at the terminal CH2–OMs would replace the leaving group without disturbing the adjacent stereocentre, so it cannot by itself explain racemization. sulfur participation produces an intermediate with two equivalent methylene paths. Label the original S-adjacent methylene A, the stereogenic carbon C, and its CH2–OMs substituent B. The thioether sulfur attacks B intramolecularly and expels mesylate, forming a four-membered thietanium circuit S–A–C–B–S. The rest of the original six-membered ring remains as the other path between S and C.

In this bridged sulfonium ion, A and B are both CH2 groups joining the same S and C centres. Exchanging them no longer changes the labelled molecular connectivity: the distinction that made C stereogenic has been removed. iodide can open the strained intermediate by backside attack at either A or B. Opening one S–CH2 bond gives one configuration of the six-membered product, while opening its equivalent partner exchanges which methylene is in the ring and which is the iodomethyl substituent, giving the opposite configuration.

The carbon iodinated in each opening is a methylene; racemization appears at the adjacent carbon through exchange of equivalent paths. It is not inversion at a CH2 stereocentre, nor does the mesylate carbon have to form a primary free carbocation. An achiral intermediate in an achiral medium gives equal mirror-related outcomes. nitrogen participation alone in a simple terminal displacement would not provide this specific equivalent-path explanation.

The bromines ortho and para to OH are removed, leaving the meta bromine at C3. A suitable polar mechanism begins with electrophilic ipso protonation of a brominated carbon. protonation at C4 or C6 gives a Wheland intermediate stabilized by donation of the phenolic oxygen lone pair; an important contributor has an O-protonated cyclohexadienone-like framework. Corresponding protonation at C3 lacks this direct stabilization by resonance in chemistry from OH.

iodide can capture/reduce the departing electrophilic bromine as the C–Br bond electrons restore the aromatic pi system. Thus the incoming hydrogen remains on carbon while bromine is removed, unlike ordinary electrophilic substitution in which the incoming electrophile remains and a proton leaves. bromine trapping can be represented through IBr formation followed by reaction with further iodide to give iodine and bromide. For each replacement the balanced net reduction isApplying it at C4 and C6 gives 3-bromo-2,5-dimethylphenol, with formula ${\mathrm{C}}_8{\mathrm{H}}_9\mathrm{BrO}$. This explains why the position least activated by OH is the one at which bromine survives. It is a proposed acid-assisted protodebromination mechanism consistent with the selectivity; the preparative sequence alone does not prove every proton-transfer or halogen-transfer intermediate. It should not be drawn as iodide simply displacing bromide from an unactivated aryl carbon.

Lithium diisopropylamide removes an alpha proton from the ethyl side of the ketone. The C–H electrons form the C=C part of a lithium enolate, while the C=O pi electrons move to oxygen. The phenyl side has no competing alpha C–H site. Diisopropylamine is the conjugate-acid byproduct.The carbon end of this enolate attacks the primary carbon bearing iodine in $\mathrm{IC}{\mathrm{H}}_2\mathrm{C}{\mathrm{H}}_2\mathrm{C}{\mathrm{H}}_2\mathrm{OMe}$. The C–I bond breaks to iodide in an SN2 reaction, and carbonyl reformation givesThus a three-carbon methoxypropyl chain is attached at the ketone alpha carbon. The remote methyl ether survives. The hindered amide base is chosen to generate the enolate rather than to add to the carbonyl. No absolute stereochemical preference is specified for the new stereocenter under these achiral conditions.

An enolate is an ambident nucleophile: the negative charge is concentrated toward oxygen, while its occupied conjugated orbital also has substantial reactive amplitude at the alpha carbon. An alkyl iodide presents an accessible, polarizable carbon electrophile. carbon attack through an SN2 reaction is generally kinetically favorable, while the more strongly charged oxygen is often coordinated to the counterion or solvated. The carbonyl reforms as the new C–C bond is made.carbon alkylation restores the carbonyl and makes the new C–C bond. oxygen alkylation instead gives an enol ether. The two outcomes are not resonance contributors of one product, and their ratio is not determined just by where the largest formal negative charge is drawn. electrophile, counterion, solvent and aggregation can change selectivity; hard silicon electrophiles and suitable acylating reagents often favor oxygen trapping. Product stability alone would not explain an irreversible kinetic choice.

Potassium iodide is prepared by converting iodine into iodide, then obtaining a pure crystalline potassium salt. One chemical route uses potassium hydroxide; an alternative first forms iron(II) iodide. The account here describes the chemical operations and their balances, without assigning a later pharmacopoeial formula to 1866.

In the alkaline route, iodine reacts with hot potassium hydroxide to give a mixture of potassium iodide and potassium iodate:This is disproportionation: iodine goes from oxidation state $0$ to both $-1$ and $+5$. Merely evaporating the solution would leave the unwanted iodate with the iodide. Heating the dried salts with charcoal reduces the iodate to iodide. A limiting balance with carbon monoxide as the carbon oxide product isThe carbon oxides can depend on the reaction conditions; the indispensable chemical point is removal of the iodate's oxygen without losing its iodine. Extraction with water, filtration of insoluble residue, concentration and crystallization then recover potassium iodide. A modern USDA technical evaluation explicitly describes this same reaction sequence; it is corroboration of the chemistry, not evidence that its modern document was the 1866 official recipe.^[ref]

In the alternative iron route,followed byThe insoluble iron-containing material is separated and the potassium iodide recovered from the liquid. Oxidation of the ferrous precipitate during working can alter its final form, so the displayed chemical equation is the ideal metathesis balance rather than a guarantee that every collected particle remains pure iron(II) carbonate.

Pure potassium iodide is a colourless or white crystalline ionic solid, commonly in cubic crystals, readily soluble in water and less soluble in ethanol. It has no intrinsic brown iodine colour. Its aqueous solution contains potassium ions and iodide ions. Free iodine dissolves in the presence of iodide through triiodide formation,With silver nitrate, iodide gives yellow silver iodide, sparingly soluble in water and resistant to ordinary aqueous Ammonia:A little chlorine liberates iodine, which gives the characteristic colour with starch:By contrast, iodate contamination can liberate iodine simply on acidification in the presence of iodide:That distinction explains why removal of the iodate is part of preparing a well-defined product, rather than an optional cosmetic step. These are chemical properties and recognition principles, not advice to administer the salt.

TODO: Solutions d and e and their test observations are absent. Iodine and morphia are named testing targets, not reported positive findings.

Neither iodine in $d$ nor morphine in $e$ is established. “Morphia” is the historical name for morphine. The available task can nevertheless be explained as two distinct analytical investigations, using separate portions and reference preparations.

For $d$, first distinguish free iodine from iodide. A cool, freshly prepared starch solution gives a strong blue colour with accessible iodine under suitable conditions. Test the reagent by itself and beside a known iodine preparation, so that contamination or a failed reagent is not mistaken for an observation about $d$. The intense blue starch indication is documented in contemporary discussion of the 1864 British Pharmacopoeia.^[ref]

An absent direct blue response would not, by itself, exclude iodine present as iodide, or establish that the specimen contains no interfering material. If the task includes combined iodine, an appropriately controlled oxidation on a separate portion is needed to liberate testable iodine; the unoxidized and treated portions answer different questions. The response of the untreated specimen must not be confused with one deliberately produced by changing its chemical state. These are possible branches of the investigation, not observations supplied for $d$.

For $e$, use the period's chemical identity reactions as corroborating observations. The British Pharmacopoeia by the General Medical Council (1864) describes the response of hydrochlorate of morphia to iron(III) chloride and nitric acid: the former gives a blue indication under the specified conditions, and the latter an orange-red indication. The monograph is a reference for a defined material; it does not guarantee that every dilute or impure unknown will reproduce those colours.^[ref]

Use separate portions for the two tests and include a reagent blank and a known morphine reference. Acidity, concentration and other coloured or reactive constituents can affect interpretation. A single colour should therefore be treated as preliminary evidence rather than a conclusive identification in an unrestricted unknown. An unexplained failure of the known reference would invalidate the comparison, while a coloured blank would indicate a problem independent of $e$.

A completed practical record would give the actual response of each sample, reagent and reference, followed by an appropriately qualified conclusion. The reference behaviours explain the tests; they cannot supply the missing results for $d$ or $e$.

Iodine is a dark, lustrous crystalline halogen which gives a violet vapour; historically, an important source was the ash of iodine-rich seaweeds. Elemental iodine commonly occurs as diatomic ${\mathrm{I}}_2$. It melts at about $114{}^{\circ }\mathrm{C}$ and boils at about $184{}^{\circ }\mathrm{C}$ at ordinary atmospheric pressure. It also undergoes sublimation below its melting point, depositing crystals again on a cooler surface.^[ref]

Iodine is sparingly soluble in water, giving a brownish solution, and dissolves more freely in ethanol and in an aqueous iodide solution. In the latter case the chemical equilibriumforms triiodide. Iodine with starch, under suitable conditions, gives a sensitive dark-blue colour; this is a useful recognition test, but oxidants that liberate iodine from added iodide must be distinguished from iodine initially present. Reaction with reactive metals gives iodides; in such compounds the iodine usually has oxidation state $-1$.

For the historical seaweed route, collect and burn iodine-accumulating seaweeds to produce kelp ash, then extract the soluble salts with water. Crystallization removes much of the common salt content, leaving an iodide-enriched mother liquor. Oxidation releases iodine, which can be distilled or sublimed and collected on a cool surface. One representative net chemical equation for liberation from iodide isThe manganese dioxide is the oxidizing agent; the seaweed does not contain a supply of ready-made violet iodine crystals. This describes the chemical principle of a historical extraction, rather than prescribing one unique factory recipe.

Iodine also occurs in natural brines and in iodate-bearing deposits associated with nitrate ores. Modern industrial supply relies heavily on brines and iodate ores; it should not be equated with the seaweed source emphasized in nineteenth-century teaching.^[ref]

Pilula Ferri Iodidi is a pill preparation containing iron iodide. A solid unit preparation differs from the syrup bearing the related ingredient name.^[ref]

An ionic potassium–iodide salt. Its preparation and purity tests distinguish iodide from iodate and free iodine.

The sparingly soluble silver–iodide solid used in a classical iodide recognition test.

Syrupus Ferri Iodidi is a syrup of iron iodide. The sugar-containing vehicle and the iron salt are different components of the formulation.^[ref]

Triiodide is the anion ${\mathrm{I}}_3^{-}$, formed in the equilibrium ${\mathrm{I}}_2+{\mathrm{I}}^{-}\rightleftharpoons {\mathrm{I}}_3^{-}$. Formation of triiodide can increase the amount of iodine accommodated in an aqueous iodide-containing solution.

The total dissolved iodine inventory therefore need not equal the concentration of free molecular iodine. Interpreting an optical or titration measurement requires the relevant species balance.