Past exam of the chemistry B course of the University of Cambridge 2021 Paper 1 B5 b i Solution 2026-10-20
Two molecules of the carboxylic acid form a cyclic carboxylic-acid dimer. Let Ar denote the meta-methylphenyl group. One molecule donates its OH hydrogen to the other's carbonyl oxygen, and the second donates back:
The two contacts close an eight-membered hydrogen-bonded ring, shown explicitly below.
The two contacts close an eight-membered hydrogen-bonded ring, shown explicitly below.
Both molecules therefore act once as hydrogen-bond donor and once as hydrogen-bond acceptor, giving two O–H···O=C contacts. This is the conventional self-complementary dimer motif; the schematic is not a prediction of every weaker contact in an unprovided crystal structure.
Original hydrogen-bonding structures for the two pure-compound homodimers
. Details. Past exam of the chemistry B course of the University of Cambridge 2023 Paper 1 B1 b iii Solution 2026-10-20
The first base equivalent removes O–H; the second removes the alpha C–H. The first equivalent of lithium diisopropylamide converts the carboxylic acid to its lithium carboxylate. A further equivalent removes the remaining hydrogen on the carbon between the two allyl groups, giving a carboxylic acid dianion:The second negative charge has enolate-like delocalization into the carboxyl group; lithium coordination and aggregation are not represented by this simple charge-bookkeeping structure. The carbon nucleophile attacks methyl iodide with C–I bond cleavage, forming the new C–Me bond. acid workup reprotonates the carboxylate, giving . The two equivalents are therefore chemically necessary for the stated carbon alkylation rather than simply an arbitrary excess. A single equivalent is consumed predominantly by the much more acidic carboxylic proton. The product has formula and still has two identical allyl groups, so this methylation does not create a stereocenter.
Past exam of the chemistry B course of the University of Cambridge 2023 Paper 1 B1 b ii Solution 2026-10-20
hydroxide attacks an ester carbonyl to form a tetrahedral intermediate. Collapse expels ethoxide, and acid–base transfer gives the carboxylate and ethanol. Repeating this nucleophilic acyl substitution at the other ester produces the malonate dianion; acid workup gives , with as defined above.
On heating, one carboxylic acid group is lost through a six-membered cyclic proton-transfer/bond-cleavage arrangement. A carbonyl oxygen of the retained group accepts the proton from the departing carboxyl OH as its C–C bond breaks and carbon dioxide forms; electron redistribution gives the enol-like form of the retained acid. proton transfer/tautomerization then producesThe net decarboxylation is . The central carbon gains a hydrogen, both allyl substituents survive, and only one carboxyl group is removed. It would be incorrect to draw hydrolysis directly giving the final acid without accounting for this carbon loss. The favourable cyclic pathway is characteristic of malonic acid decarboxylation.
Past exam of the chemistry B course of the University of Cambridge 2023 Paper 1 B3 b Solution 2026-10-20
In both cases the alkene undergoes concerted oxygen transfer from metachloroperbenzoic acid. The alkene pi bond forms one C–O bond to the terminal peroxide oxygen; electron redistribution forms the second C–O bond, breaks O–O, and transfers the peracid proton to its carbonyl oxygen as the carboxylic acid product forms. This cyclic epoxidation pathway delivers both C–O bonds from one face, without a freely rotating carbon intermediate.
For 1-methylcyclohexene, the two alkene faces are enantiotopic. Attack from opposite faces gives the two mirror-related epoxides, and an achiral peracid in an achiral environment cannot distinguish their Gibbs energies of activation. The product is racemic, 1:1.
For the cis-fused bicyclic alkene, the junction configuration and its puckered ring conformation make approach from the two faces sterically different. The folded saturated ring shields the concave face; oxygen transfer preferentially approaches the more exposed convex face, directed away from that ring. The alternative attack places the incoming peracid closer to the folded skeleton. The 95:5 ratio represents facial diastereoselectivity, while concerted syn oxygen delivery is retained for either product. It should not be explained by free rotation or by one epoxide subsequently changing configuration. For scale only, if this ratio were measured under irreversible kinetic conditions at 298 K, it would correspond to difference between the competing Gibbs energies of activation; the exam does not specify that temperature.
Past exam of the chemistry B course of the University of Cambridge 2024 Paper 2 B10 d iii Solution 2026-10-20
Glu217 is important for catalysis, most naturally through proton transfer at the purine ring. Changing a glutamic acid residue to glutamine preserves much of the side-chain size and hydrogen-bonding geometry, while removing an ordinary carboxylic acid/base pair. Its placement near N1 makes acid donation there a plausible way to activate C6 for water addition and stabilize the resulting nonaromatic intermediate. The large turnover defect with little change in the Michaelis constant supports that catalytic interpretation, subject to the same and protein-integrity qualifications as above.
The protonated carboxyl drawn at pH 7 need not behave like free glutamate in water: local electrostatics and burial can shift its p, and protonation may change during the cycle. The mutation alone cannot choose between an initially protonated Glu217 acid and a Glu217 residue that first accepts and then relays a proton. Primary mutational work supports catalytic roles for active-site histidine and glutamate groups while explicitly comparing purified enzymes and zinc content.[ref]
Mutational analysis of active site residues of human adenosine deaminase by D. Bhaumik and others. 1993, pp. 5464–5470, kinetic and zinc-content comparisons
Aqueous base selectively converts the methyl ester to a carboxylate, and brief acidification gives the corresponding monoacid while retaining the tert-Butyl ester. At the methyl-ester end, a hydroxide lone pair attacks the acyl carbon and the carbonyl pi pair moves to oxygen. The tetrahedral intermediate collapses as the oxygen anion reforms C=O and the acyl C–OMe bond breaks to methoxide. proton transfer then gives the carboxylate and methanol. carboxylate formation makes the net saponification effectively irreversible under the basic conditions; protonation protonates that carboxylate.
The tert-Butyl ester reacts more slowly under these conditions because its bulky alkoxy group hinders acyl attack, and tert-butoxide is a stronger base and poorer leaving group than methoxide. The selectivity is kinetic, not an assertion that tert-butyl esters can never undergo base hydrolysis. The work-up should be sufficiently mild and brief to avoid the separate acid-labile pathway.
Anhydrous trifluoroacetic acid instead removes the tert-butyl group, leaving the methyl ester. protonation activates the ester; in a useful reactive protonation form the alkoxy oxygen bears the proton. The O–C(tert-butyl) bond then cleaves with its electron pair going to oxygen, producing the carboxylic acid and a tert-butyl-cation-like fragment. Loss of a methyl proton gives 2-methylpropene and regenerates the acid catalyst. Carbonyl-oxygen protonation and charge delocalization can precede cleavage; drawing alkoxy-oxygen protonation is a transparent way of tracking the bonds broken. The key distinction is alkyl–oxygen cleavage here versus acyl–oxygen cleavage in the base reaction. Methyl-cation formation is strongly unfavourable, and without water ordinary acid-catalysed methyl-ester hydrolysis is not available. No water is required to account for the tert-butyl deprotection or its alkene by-product.
The assignments are A → spectrum 3, B → spectrum 4, C → spectrum 1, and D → spectrum 2. The useful infrared spectroscopy evidence is the combination of functional-group absorptions, rather than every feature of the fingerprint region.
A is a saturated diketone: spectrum 3 has a strong ketone C=O band near without the very broad acid O–H absorption. Its two symmetry-related carbonyls do not require two well-separated diagnostic bands.
B is a conjugated dienoic acid: spectrum 4 combines a broad carboxylic acid O–H envelope, approximately –, with a conjugated C=O band near – and C=C absorptions around –.
This is an Ireland–Claisen rearrangement. Number the ester carbonyl carbon , its enolizable carbon , and the three allylic ring carbons , starting at the carbon bearing the ester oxygen.
lithium hexamethyldisilazide removes an proton and trimethylsilyl chloride traps the oxygen of the resulting ester enolate, giving a silyl ketene acetal. Heating permits a six-electron, [3,3]-sigmatropic rearrangement through the arrayThe electron-pair movements are , , and . Acidic work-up cleaves the silyl ester to the carboxylic acid. The benzyl ether remains a protecting group; it is not the migrating bond.
The suprafacial reaction transfers the starting allylic stereochemistry to , where the new side chain is delivered from the original oxygen face. In the product's printed orientation, the new C–C bond is behind the ring and the C methyl group is toward the viewer. At that ring star, the Cahn-Ingold-Prelog priority rules orders the groups as side chain, alkenyl ring direction, saturated ring direction, methyl, giving .
The second star is . Its priorities are carboxyl, substituted ring carbon, , H. A chair-like transition state normally places the bulky side chain pseudoequatorial. However, its absolute configuration also depends on the E/Z geometry of the trapped silyl ketene acetal: opposite geometries give opposite configurations at this star under the same suprafacial ring transfer. The printed conditions do not state solvent or the ketene-acetal geometry. Thus the secure assignment is the ring-star configuration and conditional -star stereochemistry, rather than an unqualified absolute assignment to both stars. Drawing the assumed ketene-acetal geometry and its chair is necessary before selecting one epimer.
Two neutral carboxylic acids can form a carboxylic acid dimer with two reciprocal O–H···O=C hydrogen bonds. In water, each acid group already makes favourable solvent contacts. Association must displace some of those contacts and loses translational freedom, so the extra stabilization of the dimer may be small. Any ionized carboxylate population also cannot form the same neutral two-donor carboxylic acid dimer.
A nonpolar, weakly hydrogen-bond-accepting solvent such as dry toluene or a compatible hydrocarbon generally favours this dimerization relative to water, provided the acid dissolves. The solvent competes less strongly for the donor and acceptor sites. Dilution still disfavors the dimer because : the dimer fraction depends on concentration even in a favourable solvent. Thus trace dimer in the aqueous sample is not evidence that the acid lacks hydrogen-bonding ability.
Pyridine-2,5-dicarboxylic acid 2026-10-20
Saponification Created 2026-10-13 Updated 2026-10-20
Saponification is hydrolysis of an ester under basic conditions. The conductometric saponification assay follows ethyl acetate consumption by hydroxide, producing ethanol and an acetate ion; its equal-starting-concentration case provides a practical second-order reaction example.
Saponification is ester hydrolysis promoted by a chemical base, with net consumption of hydroxide to form a carboxylate and an alcohol. For a carboxylic acid-derived ester, the net chemical equation isThe hydroxide is a reactant, rather than merely a regenerated catalyst.[ref]
21.6 Chemistry of Esters. Organic Chemistry by John McMurry; §21.6, Conversion of Esters into Carboxylic Acids: Hydrolysis; Figure 21.8 discussion of carboxylate formation
For ethyl acetate, the balanced chemical equation becomesBoth sides contain four carbon chemical atoms, nine hydrogen chemical atoms, three oxygen chemical atoms, and net electric charge . A sodium ion supplied by sodium hydroxide is a spectator ion; the net ionic equation omits it without losing electric charge conservation.
In the usual reaction mechanism, hydroxide adds to the carbonyl group, making a reaction intermediate. Departure of the alcohol's conjugate base gives a carboxylic acid; transfer of a proton then gives the carboxylate and the alcohol. Subsequent addition of a chemical acid gives the carboxylic acid by protonation:This separate acidification changes the reaction product's protonation state.[ref]
21.6 Chemistry of Esters. Organic Chemistry by John McMurry; §21.6, Figure 21.8 discussion: addition, elimination, deprotonation and subsequent aqueous HCl treatment
The conductometric saponification assay makes hydroxide consumption observable. A university procedure equilibrates separate ethyl acetate and sodium hydroxide stocks in constant-temperature baths, then mixes them in a rinsed conductivity cell. Two platinum electrodes and an alternating-voltage Wheatstone bridge supply an electrical resistance readout. A matched sodium hydroxide–water dilution checks the initial signal; potassium chloride calibrates the cell constant. Replacing hydroxide with less mobile acetate ions lowers electrical conductance, supporting an inference about changing concentration. The manual supplies a procedure rather than measured outcomes. Temperature drift or additional ions can change the signal; it cannot alone identify the full reaction mechanism.[ref]
Manual for Advanced Physical Chemistry Laboratory-II by Nasima Arshad. Unit 7, Experiment 1, printed p. 63: electrodes, bridge and ionic conductance; Experiment 2, printed pp. 66–67: preparation, resistance readout and controls
Tartaric acid 2026-10-14
Tartaric acid has two hydroxy groups and two carboxylic acid groups. Its meso compound form illustrates why two stereocenters need not make a chiral molecule.
tert-Butyl ester 2026-10-20
Trichloroacetic acid 2026-10-18
Trichloroacetic acid is a chlorinated carboxylic acid, used for protein precipitation in the Nirenberg and Matthaei experiment.


