Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 26 1 Solution Created 2026-10-03 Updated 2026-10-14
A monad on a category consists of an endofunctor , a unit natural transformation , and a multiplication , satisfyingAn algebra for a monad is with and . A morphism of algebras for a monad satisfies . These objects and arrows form the Eilenberg-Moore category .
For an adjunction with , the monad induced by an adjunction is , with . The Eilenberg-Moore comparison functor is and . The functor is monadic when this comparison is an equivalence of categories; this is a monadic adjunction.
The precise monadicity theorem says that is monadic exactly when it has a left adjoint, reflects isomorphisms, and satisfies the following condition: whenever the image of a parallel pair in admits a split coequalizer in , the pair has a coequalizer in and preserves that coequalizer. Equivalently, these coequalizers are created up to the canonical isomorphism identifying their underlying coequalizer objects. Here a split coequalizer of consists of , , and withThese equations prove its universal property: if , then , and is the unique factor through . Every functor preserves these equations, so every functor preserves split coequalizers.
First consider the forgetful functor . It has the free algebra functor as a left adjoint: the inverse transposition formulas are and . An monad algebra morphism whose underlying arrow is invertible has an algebra-morphism inverse, by rearranging its structure equation. Thus reflects isomorphisms.
Suppose have an underlying split coequalizer . Applying gives a coequalizer of . The equation therefore gives a unique with . The monad algebra laws follow by cancellation: composing with the epimorphism reduces it to , and composing with reduces it to . Both and are epimorphisms because they remain split coequalizers. Thus is an algebra for a monad and is an monad algebra morphism. If an algebra map equalizes , its underlying factor obeys , since this equation becomes after composition with . This proves that creates the required coequalizers. An equivalence of categories transfers these properties to any monadic , proving necessity.
Conversely assume the three conditions and write . Given , take the pairIts image is , with split coequalizer : the splittings are and , becauseLet be its coequalizer in . Preservation gives a canonical isomorphism under which . Transporting the algebra action of along this isomorphism gives . Naturality of the adjunction counit says that is an monad algebra morphism, hence . But too, and is a split epimorphism, with section . Therefore . Every algebra is consequently isomorphic to some .
It remains to establish full faithfulness, rather than merely construct objects. For , put . The adjunction counit coequalizes . The coequalizer supplied by the hypothesis has underlying coequalizer . The induced arrow from that coequalizer object to is therefore sent by to an isomorphism; reflection of isomorphisms makes it invertible. Thus itself is this coequalizer.
Now let be an monad algebra morphism, and put . The arrow coequalizes the two arrows in the preceding presentation. To check this directly, use transposition along : the transposes of and are respectively and , which agree by the algebra-morphism equation. Hence a unique satisfies . Applying gives ; cancellation of the split epimorphism yields . Finally, any arrow satisfies by naturality, so two arrows with equal image under are equal by the coequalizer property. The comparison is full and faithful and essentially surjective, hence an equivalence of categories. This proves the theorem.
For the application, the free compact Hausdorff space on a set is the Stone-Čech compactification of the corresponding discrete space. Its standard extension property says that every set map , for compact Hausdorff , extends uniquely to a continuous map . This constructs the required left adjoint. Also a continuous bijection from a compact space to a Hausdorff space is a homeomorphism, so reflects isomorphisms.
Take continuous maps whose underlying functions have a split coequalizer with splittings . The splittings need not be continuous. LetThe set is compact and hence closed. Since , it is contained in . Conversely . ThusThe set of triples on the right is closed in the compact Hausdorff space , so its projection onto the first two coordinates is compact and closed. This proves that the equivalence relation is closed, without assuming continuity of either splitting.
Give the quotient topology. The allowed closed-relation criterion makes it a compact Hausdorff space. If a continuous map equalizes , the split-coequalizer property makes it constant on the fibres of ; its unique factor is continuous by the quotient topology. Hence this is a coequalizer in compact Hausdorff spaces, preserved by . Its topology is forced uniquely, since any continuous surjection from a compact space to a Hausdorff space is a quotient map. All three conditions hold, and therefore the forgetful functor from compact Hausdorff spaces to sets is monadic.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 26 2 Solution Created 2026-10-03 Updated 2026-10-14
An essay arguing against the claim. A good definition can change which mathematical questions are visible. Nevertheless, I would argue that category theory derives its explanatory force from the interaction between definitions and theorems; there is no sound general ordering in which definitions contribute more than theorems.
The strongest case for the contrary view comes from universal properties. A product in a category is characterized by maps into it, rather than by a particular construction of ordered pairs. The same definition applies to sets, groups, and topological spaces. An adjunction goes further: its natural correspondence of arrows puts free constructions, quotient constructions, and several kinds of completion into a common language. Such definitions remove irrelevant choices and expose relationships that would be difficult to recognize from separate constructions.
But a universal-property definition does not supply an object. The definition of a product in a category says what a product would accomplish; an existence theorem says whether the category actually has one. Even uniqueness up to unique isomorphism is a short proof, not an extra clause to be silently supplied by the word “universal”. Given two products, their universal properties produce maps in both directions, and uniqueness forces the two composites to be identities. This elementary theorem makes the definition usable independently of a chosen construction.
The Yoneda lemma illustrates the distinction especially clearly. A representable functor is a definition, but the lemma proves that its natural transformations into any set-valued functor are determined by one element. Its proof evaluates at the identity and reconstructs the whole transformation by functoriality. Consequently the Yoneda embedding is full and faithful: an object's pattern of incoming arrows recovers its morphisms without loss. That is a substantive explanation of why the chosen definition is powerful. Merely calling a functor representable would not establish it.
Similarly, defining a monadic adjunction gives a precise meaning to recovering structured objects as algebras for a monad. It does not decide whether a given forgetful functor is monadic. The precise monadicity theorem translates that difficult classification into a usable test involving adjoint functors, reflected isomorphisms, and specific coequalizers. For compact Hausdorff spaces, the crucial step is proving that a set-split relation is closed. The definition of a monad alone does not contain this topological argument. The theorem connects the algebraic language to an independently meaningful class of spaces.
There is also a danger in praising definitions without hypotheses. A Cartesian closed category has exponential objects, but a category of structured objects need not be cartesian closed merely because underlying sets have function sets. The correct exponential in a functor category generally involves natural transformations out of representable functors, not pointwise function sets. Its existence and universal property require an argument. Theorems also reveal when tempting definitions cannot support the intended construction.
Definitions provide the vocabulary and select the structures worth studying; proofs establish existence, consequences, and limitations. Category theory makes this partnership unusually explicit because its definitions are often expressed through universal properties. Its distinctive achievement is to turn well-chosen definitions into reusable theorems, rather than to make theorems secondary.
An alternative essay arguing for the claim. In category theory, theorems are indispensable, but a carefully chosen definition often performs the greater act of organization. It identifies what many apparently unrelated constructions have in common and makes whole families of proofs possible. In that explanatory sense, definitions can be the subject's most influential contributions.
Consider a universal property. Describing a product in a category as an object representing pairs of incoming arrows replaces several different concrete constructions by one invariant pattern. The corresponding uniqueness proof is important but short; the lasting insight is that the same pattern is the right question in every category. Once the definition is available, it becomes meaningful to ask which functors preserve products, whether the products exist in a new category, and how they interact with other universal constructions.
An adjunction is an even more striking example. The existence of free groups, free modules, and a Stone-Čech compactification can be proved separately. The definition of an adjunction recognizes their common relation to forgetful functors and explains why arrows out of a free object are determined by arrows out of its generators. It also packages the relation as a monad. A large collection of isolated existence results becomes an instance of a shared structure, with reusable consequences about composition and categorical limits.
A valuable definition also has to distinguish structures rather than merely rename them. An abelian category is not just an additive category with categorical kernels and categorical cokernels: normality of monomorphisms and epimorphisms matters. The additive example with truncated primary torsion shows why those clauses belong in the definition. The definition therefore preserves exactly the structure on which theorems about images and exact sequences depend.
This view does not make proofs dispensable. The Yoneda lemma justifies the use of representable functors, and the precise monadicity theorem tests when a proposed algebraic description is valid. Rather, it argues that the best categorical definitions have unusually broad explanatory reach: they select the invariant structures to which those proofs apply. If “matter more” means providing the reusable framework in which many theorems become instances of one idea, category-theoretic definitions have a strong claim to that role.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 26 3 Solution Created 2026-10-03 Updated 2026-10-14
For a locally small category , an object , and a functor , the covariant form of the Yoneda lemma is the natural bijectionFor define , where . For , functoriality gives , so this is a natural transformation. Conversely, naturality of at gives . The two constructions are inverse. They are natural in , because a natural transformation commutes with evaluation. They are also natural in : an arrow induces by precomposition, and the resulting map corresponds to . Applying the result to the opposite category gives for .
Now let be a small category, and let . Finite products in a category in exist pointwise; the terminal functor is the constant singleton functor. Define the exponential of covariant set-valued functors bySmallness ensures that these natural transformations form a set. For , define at byPrecomposition respects identities and composition, so this defines a functor. Its evaluation map of an exponential object isTo check naturality, for both sides give : one side uses naturality of , and the other uses the defining action of .
Here is the full universal property. Given , define byFor , naturality of makes this commute with , so is a natural transformation. Replacing by is the same as precomposing by , proving naturality in . Conversely, gives . Starting with recovers it immediately. Starting with , its naturality at yieldsso it too is recovered. The formulas are natural in and , giving the required adjunction . Therefore the covariant functor category is cartesian closed. This proof supplies the actual exponential and does not need a colimit presentation of its arguments.
Finally suppose itself is a small category which is a Cartesian closed category. In its presheaf category, the same construction, applied to , givesThe first isomorphism uses the product's universal property: a map into is precisely a pair of maps into and . The next is the Yoneda lemma, and the last is the exponential adjunction in . Each step is natural in , , and . Under these identifications, evaluation corresponds to of the evaluation . Hence the Yoneda embedding preserves exponentials, with the natural identification .
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 26 6 Solution Created 2026-10-03 Updated 2026-10-14
A preadditive category has an abelian group of morphisms between each pair of objects, and composition is additive in both variables. An additive category is a preadditive category with a zero object and finite products in a category; equivalently one may require finite coproducts. The equivalence, and the stronger assertion that these constructions agree canonically, follow from the argument below. An abelian category is an additive category with kernels in a category and cokernels in a category, in which every monomorphism is a categorical kernel and every epimorphism is a categorical cokernel. A monomorphism with the first property is a normal monomorphism; an epimorphism with the second is a conormal epimorphism.
Let , with projections . There is a unique with , interpreting the other components as zero. Since every sends to , the product's universal property givesGiven arrows , put . Then . Conversely any arrow with these restrictions equals , so it is uniquely this sum. Thus is a coproduct in a category. The empty product is the zero object and also the empty coproduct. The dual argument starts from coproducts and constructs projections; it proves the equivalent definition. Hence finite products and coproducts are the same biproducts, with the displayed identities giving the canonical identification.
For the image factorization in an abelian category, let , let be its cokernel, and let be the kernel of . Since , write . We prove that is epic. Suppose satisfies and let be its categorical kernel. Then for some . The composite is monic and hence is a normal monomorphism, say for . Since , the categorical cokernel property makes factor through , and therefore . The categorical kernel property of gives with . Cancellation of yields ; since is monic this also gives . Thus is invertible and . In a preadditive category, now implies , hence . This proves is an epimorphism and supplies the required factorization.
For uniqueness, an epimorphism that is a categorical cokernel is the categorical cokernel of its own categorical kernel. Indeed, if and , then factors through ; an arrow killing therefore kills and factors uniquely through . Dually, a normal monomorphism is the categorical kernel of its own categorical cokernel. If is any epi–mono factorization, monicity of gives . Both and are consequently categorical cokernels of this same categorical kernel. Their universal properties give a unique isomorphism between the intermediate objects with , and cancellation of gives . Therefore the epi–mono factorization is unique up to the unique compatible isomorphism.
Here is an additive category with truncated primary torsion, with the prime fixed as . Its objects are finitely generated abelian groups having no element of order , and its morphisms are all group homomorphisms. Equivalently their -primary torsion subgroup has exponent at most . It is a full subcategory of abelian groups, closed under finite direct sums and subgroups. Its hom groups and bilinear composition are inherited, and the zero group and finite direct sums belong to it, so it is additive. Categorical kernels are ordinary subgroup categorical kernels, which are still finitely generated and have no element of order .
To construct categorical cokernels, for an arbitrary finitely generated abelian group let be its -primary torsion subgroup, and defineThe Fundamental theorem of finitely generated abelian groups shows that this quotient lies in the subcategory: it leaves the free and odd-primary parts unchanged and replaces each cyclic -primary summand by either or . Every homomorphism to an allowed group kills , because it sends -primary torsion into a subgroup killed by . Thus has the universal property of a reflection. For , its categorical cokernel in the subcategory isThis has exactly the categorical cokernel universal property by the preceding factorization. Finite categorical limits exist because equalizers are categorical kernels of differences and finite products exist. Finite colimits exist dually because coequalizers are categorical cokernels of differences and finite coproducts exist.
The epimorphisms in this example are precisely the surjective homomorphisms. A surjection is epic already in abelian groups. Conversely, if is epic in the subcategory, its categorical cokernel is zero, so . A nonzero finitely generated abelian group has nonzero reflection: a nonzero free or odd-primary summand survives, and a nonzero finite -primary summand has a nonzero quotient modulo twice itself. Hence and is surjective. Its ordinary categorical kernel belongs to the subcategory, and its quotient by that categorical kernel is its codomain, which also belongs to the subcategory. It is therefore the categorical cokernel of its categorical kernel. This proves that every epimorphism is conormal.
The monomorphismis not normal. Its categorical cokernel in this category is reduction modulo , since . The categorical kernel of that categorical cokernel is the inclusion , whereas the image of is . A normal monomorphism is the categorical kernel of its own categorical cokernel, as proved above, so cannot be normal. In fact multiplication by is itself the categorical kernel of reduction modulo , up to the identification . Its composite with itself is multiplication by . Thus this example already exhibits two normal monomorphisms whose composite is not normal.
For the general assertion, let be a nonnormal monomorphism in any additive category of the specified kind. Put and be its categorical kernel, and factor . Both and are monic, so is monic. Set and be its categorical kernel. Then are normal, and for some .
Suppose their composite were normal, say . Since , factors through , whence . The categorical kernel property of supplies with ; cancellation shows , and monicity makes an isomorphism. Because , this forces . In a preadditive category, vanishing of the categorical cokernel of implies that is epic: any with have factor through the zero categorical cokernel. By hypothesis is therefore a categorical cokernel, and it is also monic. If , monicity and force ; a categorical cokernel of a zero arrow is an isomorphism. Thus is invertible, making normal, a contradiction. Consequently normal monomorphisms cannot be closed under composition in any such category; the explicit pair witnesses the failure.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 30 2 Solution Created 2026-10-03 Updated 2026-10-14
Let be the matrix of multiplication by in the basis from Question 1. Define the Coleman norm operator by the norm for a finite free ring extension:The entries lie in , and is an isomorphism, so this determines uniquely. If is a unit, is invertible and its determinant is a unit. Also , giving . Splitting the conjugates, or diagonalizing multiplication after adjoining the roots of unity and inverting , gives the equivalent formulaIn particular, this definition has the required target , rather than merely a ring with extra roots of unity in its coefficients.
For the requested ring congruence, observe that the reduction of is the injective map . If , its reduction first gives . Then ; repeat to obtain . Applying this to provesThis congruence reflection for Frobenius substitution is valid for all , without assuming is a unit.
A further property needed for the fixed points is Coleman norm contraction. If with , expand the determinant:Here is the coefficient of degree in . The trace formula from Question 1 makes the linear term divisible by ; every later term is divisible by and . Reflecting the resulting ring congruence through givesIf and , iteration gives for every . Since , .
To identify all fixed points, we also need for every unit . In characteristic , the extension has degree and its norm for a finite free ring extension is . Indeed, after passing to fraction fields it is a purely inseparable field extension of degree , so multiplication has only the eigenvalue , with multiplicity , after splitting. Its determinant is . Thereforeand congruence reflection for Frobenius substitution gives .
Now choose any lift of a given and put . Multiplicativity givesThus is a Cauchy sequence for the finer of the topologies on integral formal power series and converges to a unit reducing to . The Coleman norm operator is continuous: multiplication matrices and their determinants are continuous, and the finite-free coordinate decomposition and its inverse preserve the -adic filtration defining the finer of the topologies on integral formal power series. Hence . If two fixed units reduce to , their quotient is fixed and belongs to , so it is by the preceding argument. This proves uniqueness, independence of the initial lift, and multiplicativity of the Coleman norm-fixed lift. In particular,Every unit consequently has a unique factorization with , giving the canonical Coleman decomposition of power-series units:The final assertion as printed is false. The original PDF identifies a ring with a product of unit groups. With multiplication, has a zero and is not a group. With addition, it has exponent , whereas has a nonidentity element of order : because is odd and . Thus neither interpretation makes the printed assertion true. The two boxed isomorphisms above are the valid natural conclusions; they do not require guessing which symbols the author intended to replace.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 30 3 Solution Created 2026-10-03 Updated 2026-10-14
For a profinite abelian group , its Iwasawa algebra is the completed group algebrawhere runs over open subgroups. The transition map sums the coefficients over the fibers of when . Consequently an element gives compatible values on cosets, equivalently a finitely additive -valued p-adic measure on the clopen sets of . Conversely these values specify every finite-quotient coefficient. Integration of a continuous function with values in is obtained by uniform approximation by locally constant functions; the integrals converge because all measure values have -adic absolute value at most . Multiplication in the Iwasawa algebra becomes convolution of p-adic measures. This is its measure realization of an Iwasawa algebra.
The Mahler theorem states that each continuous function has the unique expansion converging in the sense of uniform convergenceIts Mahler coefficients areand . The same assertion holds for continuous functions with values in with coefficients in .
Given , define the bounded linear functionalThe sum converges because and . Its values on indicator functions of clopen sets give a p-adic measure, denoted , withConversely, a p-adic measure determines these coefficients , and continuity allows termwise integration of every Mahler expansion. Thus the inverse iswhich is the Amice transform. These two constructions are inverse, proving the canonical bijection . In fact it is an isomorphism of rings: the identity identifies convolution of p-adic measures with multiplication of formal power series. For example, and , where is the Dirac measure at .
For the moment identity, let denote a Stirling number of the second kind. The finite polynomial identitygives . On the other hand, satisfies for every nonnegative integer . Expanding and evaluating at yieldsComparison in the basis of binomial polynomials gives . Terms with have zero constant term after at most differentiations, so no infinite-series interchange is needed. ThereforeThe case says that the total mass is .
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 30 4 Solution Created 2026-10-03 Updated 2026-10-14
The preceding constructions lead to the Iwasawa theorem on local cyclotomic units. Its significance is that an explicitly calculated local unit quotient is governed by a p-adic L-function; class field theory then suggests that the same analytic object should govern global arithmetic. The latter prediction is the Iwasawa main conjecture, rather than a consequence of the local calculation alone.
Fix compatible roots of unity and put , . Let be the norm limit of the local principal units. Take its even part under complex conjugation to obtain , the local principal-unit limit in the real tower. Let be the closed subgroup generated by norm-compatible real cyclotomic units, with their finite-order residue factors removed. WriteHere the last map is augmentation. Normalize the p-adic zeta pseudomeasure byThe expression is well defined on for even . A pseudomeasure lies in the total fraction ring of the Iwasawa algebra; the pole on its trivial finite-character component is removed by the augmentation ideal, so . In this normalization the local theorem isThe following steps outline its proof and explain where the earlier questions enter.
First encode local units by Coleman power series. Evaluation at is surjective from to , and the product defining the Coleman norm operator givesThus norm-fixed series give norm-compatible sequences of local units. Conversely, lift from such a sequence to and take , where . This has . The estimates in Question 2 give . Consequently for fixed , the series differs from modulo and its value at is . The compactness of in the coarser of the topologies on integral formal power series supplies a convergent subsequence. Continuity of the Coleman norm operator and of evaluation shows that its limit is norm-fixed and takes every value . It is a unit because the original principal units have residue . Uniqueness follows from the Weierstrass preparation theorem: a nonzero series in has only finitely many zeros in the open unit disk, whereas the distinct give infinitely many interpolation points. This constructs the Coleman power series .
Next turn its multiplicative information into an integral p-adic measure. For a norm-fixed unit , use the Frobenius-corrected logarithmThe ratio belongs to by reduction modulo , and the logarithm divided by is integral because is odd. Equivalently , interpreting the constant coefficient with the p-adic logarithm on units. The averaging identity for the logarithm is understood on the open -adic unit disk, where the translated logarithmic series converge; the corrected result itself lies in . The logarithmic product formula and Question 1 giveUnder the Amice transform, the root-of-unity average projects a p-adic measure onto its restriction to : the averaged factor survives exactly for . Consequently says that is supported on . This gives a Galois group-equivariant homomorphism from local principal units to the Iwasawa algebra of .
The integral lifting step in this proof is the Coleman unit-measure exact sequenceHere . The last map is surjective, since , and it has the cyclotomic action on its target. Its composition with is zero: implies . The kernel on the unit side consists of norm-compatible -power roots of unity. To see the shape of the kernel, write ; the equation becomes for , so only its linear term can survive. Integral solutions are , , after excluding finite residue factors by the principal unit condition. For the image, use the following explicit integral lifting of the corrected cyclotomic logarithm.
Take a p-adic measure on the units with first moment zero, and write for its Amice transform. Then and . Put and solve with . The constant equation is solved by . In degree one the terms involving cancel, and the remaining condition is , exactly ; choose any . For , after fixing the lower coefficients, the coefficient multiplying the unknown isThe other terms are divisible by : for the already integral truncated series, , while . Division therefore gives an integral , since and are units. Recursion constructs with . Now , and by Question 2. The p-adic logarithm is injective there, so . This supplies the desired Coleman power series of a norm-compatible sequence of local units. The freely chosen linear coefficient accounts precisely for the kernel . It proves the integral surjectivity step, including the integrality that rational inversion of would leave unproved.
Complex conjugation acts by on both copies of . As is odd, taking the even part is exact and removes both end terms. It follows that . The integral exact sequence is essential here: the support calculation alone would not prove this isomorphism.
It remains to calculate the image of the cyclotomic units. For , consider the symmetric cyclotomic unit seriesThe quotient has an invertible constant term , because both numerator and denominator have a simple zero at . The factor makes the expression unchanged under . The product over the roots of unity gives ; one may verify this first for integer prime to and then extend by continuity. Dividing by the norm-compatible Teichmuller representative makes the series correspond to principal units and does not change its logarithm. The generating function for the Bernoulli numbers, with , givesThe symmetric factor cancels the linear term. Applying , and then the moment formula of Question 3, yieldsfor even . These moments determine an even p-adic measure on the units: polynomials are dense by the Mahler theorem, even projection preserves density, and multiplication by is invertible on the units, so the positive even-degree polynomials are dense there as well. ThusThe closed ideal generated by all differences is . The closed subgroup generated by the corresponding cyclotomic units, including its Galois group translates, therefore has image exactly . Taking the quotient of the isomorphism proves the boxed local theorem.
Finally introduce global arithmetic. Let be the closure of norm-compatible global units in the real tower, let be its p-ramified Iwasawa module, and let be its unramified Iwasawa module. With compatible unit and splitting conventions, class field theory gives the class-field unit sequence; quotienting its unit terms by givesIn the cyclotomic tower the prime above is principal, so the unramified class-field convention also makes it split. On the torsion character components, multiplicativity of characteristic ideals impliesThe local theorem has already calculated the first factor analytically. Equality of the global unit and class-group factors would therefore identify the characteristic ideal of with the same ideal of the p-adic L-function. That is the content predicted by the Iwasawa main conjecture. More explicitly, for a nontrivial even finite character , the character component of is the whole component and the prediction isHere is the power-series algebra of the pro- part with coefficients in the character-value ring. The trivial component requires the augmentation correction for the zeta pole. Equivalently the characteristic ideals of and agree componentwise. A formulation using odd class-group characters must include the appropriate cyclotomic twist and inversion, as in Kummer reflection in Iwasawa theory. The motivation is an analytic formula for local units together with a global class-field exact sequence; the global equality is the additional arithmetic assertion.
The related class-number growth theorem illustrates why passage to an Iwasawa module is powerful. For the cyclotomic -extension, let be the -part of the class number at level . The unramified Iwasawa torsion theorem, the Iwasawa module structure theorem and the class-group control relations give, for sufficiently large ,Here are the Iwasawa invariants. To see the two growth terms, use a topological generator and, after a fixed sufficiently high level , the norm polynomial . An elementary summand contributes to the length of its quotient by this polynomial. A summand associated with a distinguished polynomial of degree contributes plus a constant: at each root the valuation of the norm polynomial is plus a fixed constant for large . If is a root of unity already killed at level , its value is instead exactly and gives the same linear contribution. The finite errors in the structure and control maps stabilize and contribute to . Thus module structure explains growth, while the Iwasawa main conjecture goes further by identifying the characteristic series of an Iwasawa module themselves with analytic ones.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 31 2 ii Solution Created 2026-10-03 Updated 2026-10-14
For , the quadratic Hilbert symbol is one if is a field norm from , and minus one otherwise; a square gives the trivial extension and symbol one. It depends only on the two square classes. Equivalently, the conic has a nonzero rational point precisely when the symbol is one. Interchanging and in the conic gives . The Hilbert norm residue symbol is a group homomorphism in each argument; for nonsquare , the cyclic local norm index makes its group kernel a subgroup of index two. The resulting pairing on square classes is nondegenerate. Alsosince . In the language of local class field theory, ; in the Brauer group, it records whether the quaternion cyclic algebra splits. These are compatible norm-obstruction descriptions.
An unramified extension of local fields of degree two has norm group consisting precisely of elements with even valuation. Indeed,and the norms on units are surjective. For the latter assertion, the norm on the finite residue fields is surjective. On successive higher principal-unit groups, the congruenceallows one to correct a proposed unit norm one digit at a time: the residue field trace is surjective, and completeness makes the corrections converge. An unramified quadratic field is unique up to isomorphism. Therefore, if is its defining nonsquare class,
For odd , choose the nonsquare unit from part (i). The polynomial has irreducible separable reduction, so it defines the unramified quadratic extension. ThusThe trivial class is included in , since a degree-one extension is unramified. The two units pair trivially, while . Any class outside has odd valuation and consequently pairs nontrivially with . This proves directly
For , the unit square classes from part (i) give . The element satisfies ; its reduction is irreducible and separable over . This shows that is unramified of degree two, givingFor a fully explicit pairing check, use the generators . We have and , since and from . But : a norm equal to would be a sum of two squares. If either summand had negative valuation, the sum would have negative valuation (equal negative valuations give valuation ); if both were integral, their squares could not sum to . Finally, the unramified norm criterion gives . The identity and determine the remaining entries. Writing , the exponent matrix isFor , annihilating both generators of requires , so . Annihilating alone requires , so is a unit class. HenceThese are the Hilbert-symbol annihilators of units and unramified square classes. Annihilators here are taken with respect to this pairing, or equivalently in the character group of a finite abelian group after identifying square classes with their Hilbert-symbol characters.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 31 3 Solution Created 2026-10-03 Updated 2026-10-14
We give the detailed norm-index argument for a cyclic extension of p-adic fields; thus is a finite extension of . Write , . For an additive -module , put and . The two periodic Tate cohomology of a cyclic group groups and the Herbrand quotient arewhen these groups are finite. For multiplicative modules, is the product of conjugates and .
The periodic complex alternating and gives a six-term exact sequence for every short exact sequence of modules. Taking the alternating product of the finite group orders in that exact sequence provesFor a finite module, the counting fibers gives and , so the two Tate groups have equal order. This proves the Herbrand quotient of a finite module is one. It follows that replacing a module by a finite-index submodule does not change its quotient, whenever the cohomology groups are finite.
Two basic calculations drive the norm computation. For the trivial module , and is multiplication by , so . For a regular lattice , with , invariants are constant coefficient vectors and every such vector is a norm: put its constant coefficient in just one coordinate before applying . The group kernel of consists of the coefficient vectors of sum zero. Successively taking partial sums solves the cyclic difference equation for every such vector . Thus both Tate groups vanish and . This is cyclic cohomology of a regular lattice.
Let and . For sufficiently large , the p-adic logarithm and p-adic exponential are inverse -equivariant isomorphismsTo make the range explicit, suffices: the higher terms in the logarithm and exponential have greater valuation than their leading terms, their series converge there, and the identities and remain valid. Thus a deep multiplicative unit group becomes an additive -lattice in .
By the normal basis theorem, as a -module. As a -module it is therefore . Transport the regular lattice into . Both and are full -stable -lattices, so their intersection has finite index in each. The exact sequences with finite quotients show that the Tate groups of are finite and thatSince is finite, the exact-sequence formula for the Herbrand quotient gives . Finally, the valuation sequencehas trivial -action on . Hence the Herbrand quotient of the local multiplicative group is
For completeness, the denominator vanishes by Hilbert theorem 90. If , put and . Independence of distinct field automorphisms lets us choose with . Since , shifting the sum gives . Thus , a multiplicative coboundary. Therefore . The invariant subgroup of is , soThis proves the cyclic local norm index without assuming local reciprocity. If the extension has ramification index and residue degree , the valuation formula shows that the valuation contribution to the index is . A norm is a unit only when is a unit, so the remaining contribution isIn particular, unit norms are surjective in an unramified cyclic extension. The norm subgroup is open: on deep units its logarithm is , a nonzero full lattice in , and therefore contains a sufficiently deep principal-unit group. This connects the index calculation to the open finite-index norm subgroups classified by local class field theory.
To finish, the Hasse norm theorem for a cyclic extension of number fields states that a nonzero element is a global norm if and only if it is a norm at every finite and infinite completion. Here is its Brauer-theoretic proof outline. Associate to the cyclic algebra , with relations and . The splitting criterion for a cyclic algebra says that it splits exactly when : if , multiplication by and the operator realize it as ; conversely, in a split matrix representation, the underlying -dimensional space is one-dimensional over , so must act as and .
Apply this criterion at every completion, using the restricted cyclic character and any one completion of above that place. If is a local norm everywhere, every localized Brauer class is zero. Injectivity in the Albert-Brauer-Hasse-Noether theorem forces in ; the global splitting criterion gives . Conversely, a global norm is a local norm after completion, since the norm on is the product of the component norms, whose images coincide in the Galois case. The cyclic hypothesis is essential; the stated local-global principle does not hold for arbitrary extensions.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 31 4 Solution Created 2026-10-03 Updated 2026-10-14
The Brauer group of a field consists of equivalence classes of central simple algebras, with addition induced by tensor product, zero represented by matrix algebras, and inverse represented by the opposite algebra. Localization sends a global algebra to its scalar extensions at the completions. For a non-Archimedean completion of a number field, the local Brauer invariant is an isomorphismNormalize it so that an unramified cyclic algebra of degree , with arithmetic Frobenius generator and parameter , has invariant . For a real completion, with the Hamilton quaternion algebra mapped to ; for a complex completion the Brauer group is zero.
The global computation is the exact sequence in the Albert-Brauer-Hasse-Noether theorem:Thus a global Brauer class is determined uniquely by a finite-support family of local invariants. Such a family occurs if and only if its sum is zero; at real places the only allowed entries are , and at complex places the entry is zero. Injectivity is a local-global splitting principle; the middle exactness is the reciprocity constraint; surjectivity of the sum follows already from any one finite local summand. These are separate assertions, not merely different descriptions of the sum formula.
For an explicit group description, choose one finite place . Assign arbitrary finite-support invariants at all other finite places and arbitrary allowed invariants at the real places, then set the invariant at equal to minus their sum. This givesThe description by the entire invariant family is canonical; this displayed elimination of one coordinate depends on the choice of .
The connection with Artin reciprocity is especially transparent for cyclic algebras. Let describe a cyclic extension, with . Write for the class of . The local reciprocity pairing isIt follows from the local fundamental class construction of the Local Artin map; on an unramified character it is precisely the normalization . The group kernel in the parameter is the local norm group, and restriction/corestriction give the norm compatibility of this pairing.
For a principal parameter , the zero-sum identity for its global cyclic algebra therefore readsOn the other hand the idelic Artin reciprocity law isand evaluating this product by gives exactly that zero-sum identity. Conversely, testing every cyclic character of a finite abelian Galois group separates its elements, so the zero-sum identities for cyclic algebras imply this principal-idele reciprocity law for every finite abelian extension. At almost all places a unit and an unramified character pair trivially, so the sums and products are finite.
The full idelic statement identifies the group kernel as and induces . It explains why the local norm-residue pairings must glue globally. The global Brauer theorem supplies, in addition, the injectivity and realization statements needed to compute all algebra classes; the principal-product identity alone would not prove those statements. For cyclic algebras its injectivity yields the Hasse norm theorem, as in Question 3. In degree two, an invariant is either zero or , so the zero-sum law becomes the Hilbert reciprocity law . For example, a quaternion algebra over can be ramified at precisely a prescribed finite set of places, including possibly the real place, if and only if that set has even cardinality; the invariants uniquely determine its Brauer class. This illustrates how arithmetic reciprocity becomes a concrete constraint on global algebra structure.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 31 5 ii Solution Created 2026-10-03 Updated 2026-10-14
Put and . The ring of integers is , and the fundamental discriminant is . For a reduced positive definite binary quadratic form of discriminant , reduction givesThe coefficient is even; checking and , with the usual nonnegative sign choice at boundary equalities, leaves preciselyThe correspondence between proper quadratic forms and ideal classes therefore gives . All four classes equal their inverses, since inversion replaces by . HenceThe three nontrivial classes may be represented by the ramified prime ideals , and . They square to principal ideals and satisfy . None is principal: an integral generator of norm , or would require to equal that number, which is impossible. The relation then makes the three classes distinct, consistently with the four-form calculation.
ConsiderThe three rational square classes are independent, so . Their radical product is , so and ; the extension is abelian. To verify that it is unramified, rather than assuming that radical adjunctions are harmless at , use the conductor-discriminant formula. The seven quadratic subfields have fundamental discriminantsThe formula givesThe discriminant tower identity now givesThus the relative discriminant is the unit ideal and no finite prime ramifies. The base has no real places, so there is no infinite ramification to check. This unramified abelian degree-four extension has degree , and part (i) provesThis is the Hilbert class field of Q of square root minus thirty.
Next translate prime representation into an ideal class. For , we claimIf a representation exists, lies in and has . The integral ideal has norm , so it is a prime ideal . Its class is . Conversely, if , the product is principal, say . Since this ideal lies in , its generator has the form with integers . Taking norms gives , proving the reverse implication. This is prime representation via an ideal class, and it proves sufficiency as well as necessity.
Identify the required class in through the Artin map. We can use the explicit representation : has norm , so the prime above obtained from has class . Its Frobenius in the multiquadratic extension acts on the three radicals with signsTheir product is one, so this automorphism fixes . Because is abelian, for any unramified rational prime that splits in , the Frobenius at either prime of of norm is its rational Frobenius restricted to . The Artin isomorphism therefore makes the required class condition equivalent toConversely, these signs already imply splitting in , since their product is . No extra splitting condition is missing.
The supplementary law for , quadratic reciprocity for and , and then the Chinese remainder theorem turn these sign conditions intoTheir four simultaneous residue classes modulo are . Finally, is represented by , whereas and cannot be represented: gives a value at least , and gives twice a square. We have proved the complete criterion