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The ground-state D meson family contains open-charm mesons with a charm quark and a light antiquark: $D^0=c\bar{u}$ and $D^{+}=c\bar{d}$, together with their antiparticles. Their spin-parity is $0^{-}$. A Ds meson instead pairs charm with a strange antiquark.^[ref]

These ground states decay weakly, making their lifetimes and final-state distributions probes of charm-changing interactions. Excited D-family states need not share that decay pattern: when kinematically allowed, an excited state can decay strongly to a lower charmed state and other hadrons. The neutral ground state also participates in neutral D-meson mixing.

An inclusive branching fraction sums many exclusive final states. A clean reconstruction mode can be experimentally attractive without dominating the total decay rate. For example, the J/psi has useful electron-pair and muon-pair decays, but predominantly decays to hadrons inclusively. Detector acceptance, branching fraction and background rejection jointly determine the usefulness of a channel.^[ref]

The J/psi meson is the ground spin-triplet S-wave vector state of charmonium, with leading valence content $c\bar{c}$ and quantum numbers $J^{PC}=1^{--}$. It has zero net charm and can decay into hadrons or charged-lepton pairs.^[ref]

Its comparatively narrow decay width makes it a conspicuous resonance in reconstructed mass distributions. An electron–Positron mass peak in a fixed-target experiment and an enhanced event rate during an energy scan in an electron-positron collider were complementary observations in the Richter-Ting independent J/psi discovery experiments of 1974.^[ref][ref] A peak's measured width also includes detector resolution or beam-energy spread, so it must not automatically be identified with the intrinsic lifetime width.

A kaon is a strange meson. The ground-state flavor assignments are $K^{+}=u\bar{s}$ and $K^0=d\bar{s}$, with antikaons $K^{-}=s\bar{u}$ and ${\bar{K}}^0=s\bar{d}$. These ground states have spin-parity $0^{-}$. The anti-strange assignments have strangeness $+1$, with the opposite sign for their antiparticles.^[ref]

Charged and neutral kaons differ in more than electric charge. Through neutral kaon mixing, the neutral flavor states combine into propagation states with markedly different decay behavior. Their time-dependent decays provide sensitive tests of CP violation. Specifying whether a label denotes a flavor state or a propagation state is therefore essential when describing a neutral-kaon experiment.

Neutral B meson mixing converts the flavor eigenstates $B^0=\bar{b}d$ and ${\bar{B}}^0=b\bar{d}$ into one another through the weak interaction. The propagating mass eigenstates are $|B_L⟩=p|B^0⟩+q|{\bar{B}}^0⟩$ and $|B_H⟩=p|B^0⟩-q|{\bar{B}}^0⟩$, with $|p{|}^2+|q{|}^2=1$.

In units $\hslash =c=1$, neglect their width difference and take $|q/p|=1$. Evolution of an initial $B^0$ at proper time $t$ gives the undecayed flavour probabilitieswhere $\Delta m=m_H-m_L$ and $\Gamma$ is the common decay width. Their sum is the survival probability, not one.

For a common final state, mixing and direct decay interfere through ${\lambda }_f=(q/p)({\bar{A}}_f/A_f)$. In the Standard Model, $f=J/\psi K_S$ combines a J/psi meson with a short-lived neutral kaon. Neglecting subleading weak amplitudes and small kaon CP violation,Here the $V_{ij}$ are CKM matrix elements; the minus sign reflects the approximate negative CP parity of this specified final state. A different charmonium-kaon final state need not have that same sign.^[ref]

Neutral D-meson mixing is the time evolution between the flavor states $D^0=c\bar{u}$ and ${\bar{D}}^0=\bar{c}u$. The states with definite propagation masses and decay widths are generally superpositions of these flavor states, so an initially tagged flavor need not remain unchanged before decay.

A measurement tags the production flavor and compares time-dependent rates into selected final states. Some final states can be reached both directly and after mixing, producing interference; a wrong-flavor candidate is therefore not automatically a pure mixing event. The effective two-state Hamiltonian includes both dispersive and absorptive parts. Separating mixing, direct suppressed decays and detector charge asymmetries is part of the inference.^[ref]

For the neutral strange B meson, a charged-current tree amplitude has $\bar{b}\to \bar{c}{W}^{+}$ followed by $W^{+}\to c\bar{s}$, while the initial $s$ is a spectator. The $c\bar{c}$ pair forms the J/psi meson and the $s\bar{s}$ pair forms the phi meson. Charge and quark flavour flow are conserved at each vertex except for the permitted weak flavour change. antiquark arrows point opposite their physical propagation direction.

Useful reconstruction modes are $J/\psi \to {\mu }^{+}{\mu }^{-}$ or $e^{+}{e}^{-}$, through a virtual photon, and $\varphi \to K^{+}{K}^{-}$, a strong decay. The latter is the largest individual $\varphi$ mode, with $K_L^0{K}_S^0$ also important. For the $J/\psi$, the inclusive branching fraction versus reconstruction mode distinction matters: hadronic decays dominate inclusively, principally through three gluons; each charged-lepton pair accounts for about 6%, not most decays. The charm pair lies below open-charm threshold. These distinctions are confirmed by the official particle listings.^[ref]

The radiative $X^0$ decay conserves strangeness and proceeds electromagnetically. A strong $\Lambda \pi$ decay is closed because even the lighter neutral-pion threshold exceeds the supplied $X^0$ mass. The $Y^{-}$ decay has about $65\mathrm{MeV}$ of available energy, but changes strangeness from $-2$ to $-1$, so it requires the weak interaction. Its lifetime is therefore ordinarily much longer than the electromagnetic lifetime of $X^0$; no numerical lifetime follows from these masses alone.

Both particles are baryons with half-integer spin. A radiative transition to spin $1/2$ can couple through photon multipoles $L\ge 1$, giving $J_X=L\pm 1/2$. Electromagnetic parity is conserved, but without the electric/magnetic multipolarity neither $J_X$ nor its parity is fixed. In the weak $Y^{-}$ decay, coupling orbital $L$ to the final $\Lambda$ spin gives $J_Y=L\pm 1/2$; parity conservation cannot be imposed on that weak amplitude. The supplied modes therefore do not determine unique spin-parity assignments.

The masses and flavours identify the familiar candidates as ${\Sigma }^0$ and ${\Xi }^{-}$. Their established ground-state assignments are both $1/2^{+}$, consistent with the lowest-orbital quark model, but this is additional empirical/model information rather than a consequence of the two decay channels alone.^[ref]

A physical baryon is a colour singlet. Its three-quark colour factor is antisymmetric, proportional to ${ϵ}_{abc}|abc⟩$. In the hypothetical scalar-quark theory, the quarks obey Bose-Einstein statistics, so the complete three-particle state must be symmetric under exchange. At $L=0$ the spatial factor is symmetric, and three zero spins supply no nontrivial spin factor. The flavour factor must therefore be antisymmetric to cancel the antisymmetry of the colour factor.

There is exactly one completely antisymmetric state made from three flavour basis states: the flavour singlet of three scalar quarks,Equivalently, $\dim {\bigwedge }^3{\mathbb{C}}^3=1$. A repeated flavour gives zero under complete antisymmetrization. Only one ground-state flavour singlet, containing $uds$ and having $J^P=0^{+}$, remains. Keeping fermionic exchange antisymmetry while changing the spins to zero would contradict the assumed Spin-statistics theorem. The standard antisymmetric colour factor and the ordinary-quark flavour decomposition are documented in the quark-model review.^[ref]

Evidence for quarks comes from several kinds of observation that test different aspects of their interpretation. The light meson and baryon spectra organize into approximate flavour multiplets with the charges and strangeness expected for $q\bar{q}$ and $qqq$. In particular, the baryon octet and baryon decuplet encode the three light quark flavours and their spin couplings. This is an economical account of hadron quantum numbers, but spectroscopy alone would not establish that the constituents behave as localized scattering centers.

Deep inelastic scattering supplies that second test. In energetic electron–proton scattering the outgoing lepton measures the energy and momentum transferred through a virtual photon, while the broken-up target is summed over. Approximate Bjorken scaling means the structure functions depend primarily on $x=Q^2/(2P\cdot q)$ rather than varying rapidly with the resolving momentum scale $Q^2$. It indicates nearly pointlike constituents. In the leading spin-half parton model,The charge-squared weights and the second relation test the constituents' fractional charges and spin-half nature. Scaling violations reflect quark and gluon radiation rather than a failure of the constituent picture.^[ref]

Particle jets give complementary final-state evidence. A high-energy quark produces a collimated spray of hadrons because confinement prevents it from emerging as an isolated particle. Back-to-back jets fit quark–antiquark production; three-jet events show hard gluon radiation. Their angular correlations test a spin-one radiated parton. This distinguishes constituents of hadrons from a literal observation of free fractional-charge particles.

Three independent arguments identify an additional threefold colour degree of freedom. First, the spin-aligned $uuu$ state of a ground-state ${\Delta }^{++}$ would have symmetric space, spin and flavour factors. The Pauli exclusion principle requires an antisymmetric additional factor. The three-quark colour singlet supplies it. The same construction accommodates the spin-aligned $sss$ state of the ${\Omega }^{-}$ without altering its measured quantum numbers.

Second, the inclusive hadronic R ratio, away from thresholds and narrow resonances, is at leading electromagnetic orderEach quark flavour has $N_c$ distinguishable colour final states. With $N_c=3$, the predicted plateaux for three, four and five accessible flavours are $2$, $10/3$ and $11/3$; without the factor three they would be a third as large. The measured inclusive normalization is therefore a colour-counting test, with radiative and threshold corrections included in precision comparisons.^[ref]

Third, the neutral pion's two-photon amplitude contains a quark-loop colour sum, proportional to $N_c(e_u^2-e_d^2)$; its rate and the other evidence are consistent with three colours. Quantum chromodynamics identifies this degree of freedom as a gauge charge, with eight gluons. Observed hadrons are colour singlets; the evidence for colour is its quantitative and symmetry consequences, not visible colours or isolated coloured quarks.

In the Breit-Wigner resonance cross section, $E$ is the total centre-of-momentum energy, $E_0$ the resonance energy, and $p$ either incident particle's center-of-momentum momentum magnitude. The total decay width is $\Gamma =\hslash /\tau$, while ${\Gamma }_i$ and ${\Gamma }_f$ are partial widths into the entrance and specified exit channels. Their ratios to $\Gamma$ are the corresponding branching fractions. The factor $g$ averages over incident spin states and sums over the resonance's magnetic substates.

In natural units, $\hslash =c=1$, the resonant partial-wave cross-sectional scale is an area proportional to the squared reduced de Broglie wavelength, $1/p^2$. Equivalently a partial-wave scattering amplitude carries one factor $1/p$, and its squared modulus supplies $1/p^2$. In SI area units the same scale is $(\hslash /p{)}^2$; if $p$ is expressed in energy units, multiply the final inverse-energy-squared answer by $(\hslash c{)}^2$.

For unpolarized spin-half incident muons, the unpolarized resonance spin factor isHence $g_Z=3/4$ and $g_H=1/4$. The outgoing tau spins do not supply another independent multiplicity here: their allowed final states are already included in ${\Gamma }_f$.

Near a narrow resonance, treat the smooth prefactor $p^{-2}$ and the partial widths as constant across the line. At the peak the denominator is ${\Gamma }^2/4$. Half its height occurs when $(E-E_0{)}^2+{\Gamma }^2/4={\Gamma }^2/2$, namely at $E=E_0\pm \Gamma /2$. Thus the full width at half maximum is $\Gamma$ within the Breit-Wigner narrow-line approximation. A varying prefactor or convolution with the beam-energy distribution can modify an observed line shape.

The production amplitude has a muon pair joined to a Higgs propagator through their Yukawa coupling, followed by the bottom-quark pair at a second Yukawa vertex. The separate $H\to b\bar{b}$ graph is a tree-level Higgs–fermion vertex. There are no tree-level $Hgg$ or $H\gamma \gamma$ vertices in the renormalizable Standard Model: their lowest nonzero graphs are loops. A quark triangle, dominated by the top contribution, produces two gluons. Charged-fermion triangles contribute to two photons; charged-W loops also contribute and are dominant in the Standard Model amplitude. Photon permutations and the W contact topology belong to the full amplitude; the diagram shows these topologies rather than claiming one triangle alone is the entire gauge-invariant W contribution.^[ref]

The negative muon emits a virtual $W^{-}$ and becomes a muon neutrino; the boson creates an electron and an electron antineutrino:Both vertices are weak charged currents.

Typical transfers satisfy $|q^2|\lesssim m_{\mu }^2\ll M_W^2$, so the propagator factor $(M_W^2-q^2{)}^{-1}$ expands as $M_W^{-2}$ plus small corrections. Contracting this short-distance exchange produces the local Fermi interaction, with strength contained in $G_F$. This effective description does not assume that the real W mass vanishes. The same treatment applies to leptonic tau decays with the relevant masses changed.^[ref]

In GeV units, $m_{\mu }=0.106\mathrm{GeV}$ and $\hslash =6.582\times 10^{-25}\mathrm{GeV}\mathrm{s}$. ThusThe modest difference from a precision experimental lifetime is expected from the rounded mass and omitted radiative and final-electron-mass corrections.

Use an inclusive spectator model: one heavy constituent decays through the Fermi interaction, and sum the open charged-current channels. In weak-decay channel counting, each massless final lepton pair gives basic widthA quark pair contributes three colors multiplied by its squared Cabibbo-Kobayashi-Maskawa matrix element. Do not multiply by three just because the initial quark has three colors: its lifetime is the width of one initial state, averaged over initial color when appropriate. Define

For the tau lepton, two leptonic channels contain an electron or a muon; light hadronic channels have $d\bar{u}$ or $s\bar{u}$. ThereforeNo charmed hadron can be produced: the lightest charmed meson exceeds the tau mass. ^[ref] The supplied charm-quark parameter is not a free asymptotic final-particle mass. The leading count neglects electron and muon masses and light hadronic threshold effects.

For the charm quark, $c\to s{W}^{+\ast }$ and $c\to d{W}^{+\ast }$ dominate. The emitted current has two light leptonic channels and the same light hadronic channels as above; a tau cannot be produced:

For the bottom quark, retain $b\to c{W}^{-\ast }$ with the supplied $V_{cb}$ and neglect the much smaller $b\to u$ channel. The emitted current can produce three lepton flavors and two up-type quark families, with three colors for each family. In particular $b\to c\bar{c}s$ is open at the given masses, although suppressed by phase space. Counting each open channel as massless givesSetting Cabibbo sums to one recovers the familiar counts $5$, $5$ and $9|V_{cb}{|}^2$. Despite its larger mass, the bottom quark is slowed by its small interfamily mixing factor.

These are leading estimates rather than precise lifetimes of free quarks. confinement makes charm and bottom observable in hadrons, whose lifetimes involve spectator interactions, Quantum chromodynamics corrections and bound-state effects. mass corrections are significant for bottom: even the single-charm channel with massless leptons has the three-body weak-decay mass correctionTau and double-charm channels have different suppressions, so multiplying the entire width by this one factor is inconsistent. Accurate hadron lifetimes require those channel-dependent factors and hadronic dynamics; the exercise supports the explicitly stated leading counts.

The nuclear determination of $|V_{ud}|$. A $0^{+}\to 0^{+}$ beta decay transition has no nuclear parity change and can proceed with zero lepton orbital angular momentum. The allowed scalar operator gives a Fermi transition; the rank-one Gamow-Teller transition operator cannot connect total nuclear spins zero to zero. The strong isobaric-analog transitions used for precision measurements are superallowed beta decays. A generic $0^{+}\to 0^{+}$ assignment alone would not guarantee superallowed strength if the states were nonanalog.

At the quark level the weak charged current converts $d\leftrightarrow u$ and carries $V_{ud}$ in the amplitude. The nuclear Fermi operator is an isospin ladder operator, givingHere $f$ denotes the known phase space dependence, with the dimensional factors included in the proportionality constant. In the isospin-symmetric limit, $M_F$ between analog states is fixed by isospin algebra, for example $|M_F{|}^2=2$ for the usual $T=1$ analog transitions. A measured partial half-life and the computed phase space factor give the comparative half-life; after radiative corrections and isospin breaking corrections, its inverse determines $|V_{ud}{|}^2$. The decay rate measures a magnitude squared, not the complex phase of $V_{ud}$.

Ds decay diagrams and CKM comparisons. The original PDF has $K^{+}{\bar{K}}^0$, with ${\bar{K}}^0=s\bar{d}$. The local TeX drops that overbar; using $K^0=d\bar{s}$ instead would give a different flavour channel. Use the PDF's neutral antikaon throughout.

In the representative Ds nonleptonic tree amplitudes, the Ds meson spectator is $\bar{s}$. The elementary weak transitions are

In the first two channels, the produced $u$ joins the spectator $\bar{s}$ to form $K^{+}$; the other quark joins $\bar{d}$. For the first channel this uses the $-d\bar{d}/\sqrt{2}$ component of the neutral pion. In the third, $s\bar{s}$ forms the phi meson and $u\bar{d}$ forms ${\pi }^{+}$. The two possible final pairings have different colour contractions and hadronic matrix elements even when their weak CKM factors coincide.

The purely CKM rate suppression of $c\to d$ relative to $c\to s$ isThus $K^{+}{\pi }^0$ is singly Cabibbo suppressed, while $K^{+}{\bar{K}}^0$ and $\varphi {\pi }^{+}$ are Cabibbo-favored at this level. If reduced hadronic strengths and phase space effects were equal, including the neutral-pion component would giveThe supplied branching fractions instead giveThe first observed ratio is $0.814$ times the neutral-pion-corrected simple estimate, requiring only an order-one remaining hadronic and phase space factor. Relative to $\varphi {\pi }^{+}$, that remaining factor is $0.525$. The two Cabibbo-favored channels differ by a factor $0.644$ despite equal CKM magnitudes. The CKM hierarchy therefore explains why one channel is much rarer, but it does not calculate the three exclusive branching fractions; spin, phase space, color charge and strong interaction final-state effects also matter.

What spin and parity establish. In either pseudoscalar-pseudoscalar final state, the total intrinsic spin is zero. Conservation of angular momentum for a spin-zero parent forces $L=0$, so the final parity isopposite to the parent $0^{-}$ Ds meson. ConsequentlyFor a vector meson plus a pion, the intrinsic final spin is one. Coupling to total $J=0$ requires $L=1$, giving $P_f=(-1)(-1)(-1{)}^1=-1$, equal to the parent parity. Thus spin and parity alone permit a parity-conserving $\varphi {\pi }^{+}$ transition. That is the limited sense in which it is not necessarily weak from this information alone. In reality it is also weak: the initial charm flavour disappears, which the strong interaction and electromagnetic interaction conserve.

W branching fractions. In the massless-daughter, tree-level estimate, each leptonic channel contributes one common unit of decay width. Each accessible quark pair contributes $3|V_{ij}{|}^2$ because of the three final colours. The charged-current W branching-fraction counting denominator isOnly $u$ and $c$ are accessible up-type quarks; the large $V_{tb}$ is irrelevant because a W boson cannot decay into the heavier top quark. HenceA final bottom quark arises in $W^{-}\to b\bar{u}$ or $b\bar{c}$, soThis counts the primary decay channels; finite daughter masses and QCD corrections refine the approximation.

The requested top-lifetime estimate and its limitation. Under the instructed equal-coefficient Sargent's rule scaling, $\Gamma \propto m^5$ and the mean lifetime is inversely proportional to that fifth power. Converting both masses to GeV givesThis is the requested order-of-magnitude estimate, assuming the same effective coefficient for the two total decay rates. It corresponds to $c\tau \simeq 54\mathrm{fm}$ and is longer than the hadronization time, roughly a few $10^{-24}\mathrm{s}$. Taken literally, it would allow top-flavored hadrons to form; it does not establish the physical statement that the top decays before hadronizing.

The extrapolation fails because Sargent's rule uses a low-energy Fermi interaction approximation, whereas $m_t>m_W+m_b$ permits $t\to bW$ with an on-shell W boson. The physical leading decay width instead scales asUsing $m_W\simeq 80.4\mathrm{GeV}$, the Fermi constant $G_F=1.16638\times 10^{-5}\mathrm{Ge}{\mathrm{V}}^{-2}$ and $|V_{tb}|=0.999$ gives about $1.55\mathrm{GeV}$ at the supplied top mass. Then ${\tau }_t=\hslash /{\Gamma }_t$, with $\hslash =6.58212\times 10^{-25}\mathrm{GeV}\mathrm{s}$, gives ${\tau }_t\simeq 4.2\times 10^{-25}\mathrm{s}$. This corrected regime explains top-quark decay before hadronization.^[ref]

The table gives the Xi baryon mean lifetime ${\tau }_{{\Xi }^0}=2.90\times 10^{-10}\mathrm{s}$. At $t_1=10^{-12}\mathrm{s}$, an initially resting particle has survival probabilityThus the most probable contents are one undecayed ${\Xi }^0$. The initial momentum is unspecified. For a moving parent, time dilation replaces the denominator by ${\gamma }_{\Xi }{\tau }_{{\Xi }^0}$, making the survival probability at least as large. The times below are characteristic proper mean lifetimes; laboratory times depend on the particle velocities.

The principal first step isIt typically occurs on the $10^{-10}\mathrm{s}$ scale. The neutral pion almost immediately converts to two photons, with ${\tau }_{{\pi }^0}=8.43\times 10^{-17}\mathrm{s}$ and $B_{\gamma \gamma }=0.98823$. The Lambda baryon has ${\tau }_{\Lambda }=2.632\times 10^{-10}\mathrm{s}$ and two dominant routes.

In the charged-pion route,The muon lifetime is a standard additional input, not present in the supplied five table pages.^[ref] The successive contents are approximately $\Lambda +2\gamma$, then $p+{\pi }^{-}+2\gamma$, then $p+{\mu }^{-}+{\bar{\nu }}_{\mu }+2\gamma$. After a few muon lifetimes the dominant stable endpoint isThe leading-path probability including the tabulated two-photon pion branch isHere the last factor is the tabulated dominant muonic charged-pion fraction; rare radiative corrections are being neglected in describing a fixed photon count. Before selecting pion decay channels, the probability of reaching the $p{\pi }^{-}{\pi }^0$ history is $0.99524\times 0.639=0.63596$.

In the neutral-pion route,This produces $n+4\gamma$ by roughly the nanosecond scale. It is a long-lived intermediate state, not the final endpoint: the free neutron has ${\tau }_n=879.4\mathrm{s}$ in the original table and eventually undergoes beta-minus decay,Thus after several thousand seconds the dominant stable endpoint isBefore selecting the two ${\pi }^0\to 2\gamma$ decays, the $n{\pi }^0{\pi }^0$ history has probability $0.99524\times 0.358=0.35630$. The familiar rough description is therefore a $64\%$ charged-pion route and a $36\%$ neutron route; including the specified leading pion branches gives approximately $62.8\%$ and $34.8\%$ for the two displayed endpoints. The remainder includes Dalitz decays and other rare channels, not a failure of probability conservation.

These are particle decay cascades, treating the separated final proton, electron, photons and neutrinos as stable asymptotic particles and neglecting subsequent collisions and rare extra radiation. An infinitely large box prevents escaping particles from being removed from the inventory. Neutrino labels specify their production flavours. Each lifetime describes a stochastic waiting time, so there is no finite sharp instant at which every unstable particle has certainly decayed.

Write $s_{ij}=M_{ij}^2$ and factor the three-body phase space through the pair $q=p_1+p_3$, with $s=q^2$:A scalar parent permits integration over the overall orientation. In its rest frame let the pair have momentum magnitude $p$, and in the pair rest frame let particle 3 have magnitude $p^{\ast }$. After integrating the azimuth of its direction, the two-body factors giveIn that pair rest frame, particle 2 has momentum magnitude $M_{0}p/\sqrt{s}$, so $|d{s}_{23}/d\cos {\theta }^{\ast }|=2M_{0}p{p}^{\ast }/\sqrt{s}$. The Jacobian cancels both momentum factors, leavingThe physical domain is bounded by the requirement that the relative cosine lie between $-1$ and $1$. The phase-space density is uniform within that domain; the event density is uniform only for a constant squared amplitude. Scalar parent spin alone does not forbid resonance-dependent amplitudes. A factor $1/(s_{13}-m_R^2+i{m}_R{\Gamma }_R)$ is a concrete nonuniform example. For two identical pions, a conventional overall $1/2!$ compensates integration over both labelings without changing the local flatness of phase space.^[ref]

The lepton mixing matrix relates charged-current neutrino flavour fields to mass eigenfields: ${\nu }_{\alpha L}={\sum }_i{U}_{\alpha i}{\nu }_{iL}$. Nondegenerate masses then give relative propagation phases and flavour oscillations. This is the three-massive-neutrino extension of the minimal massless-neutrino Standard Model.

A unitary three-by-three matrix has nine real parameters: three rotation angles and six phases. For Dirac leptons, the independent field rephasings remove five phases, because one common phase acts trivially. Three angles and one physical Dirac phase remain. For Majorana neutrinos two additional phases cannot be removed, but they cancel from ordinary oscillation probabilities.

The phases printed in the lower two rows do not give a unitary matrix for general $\delta$. A consistent convention is $U=R_{23}{U}_{13}(\delta )R_{12}$, where the real rotations use the indicated mixing angles andThe lower-row phase factors in the resulting full matrix are $e^{+i\delta }$, opposite to the $e^{-i\delta }$ in $U_{e3}$. For the source's all-minus assignment, the scalar product of the electron row with the conjugated muon row is $-2i{s}_{23}{s}_{13}{c}_{13}\sin \delta$, which is nonzero at $\delta =\pi /2$ and nonzero mixing. This supplies an explicit counterexample. The electron-row moduli used below are unaffected by this correction.^[ref]

Restore the unit conversion in the phase,Equivalently use mass units $\mathrm{eV}/c^2$ and energies in $\mathrm{eV}$, with $\hslash c=1.97327\times 10^{-7}\mathrm{eV}\mathrm{m}$. The numerical conversion factor isThusThe familiar coefficient $1.267$ uses $L$ in metres and $E$ in MeV, or kilometres and GeV; it would be a factor of one thousand too small with the units requested here.^[ref] The quoted differences with units ${\mathrm{eV}}^2$ are interpreted as squared-mass differences, despite the source's abbreviated $\Delta m_{ij}$ notation.

Assume the usual semileptonic flavour selection rule $\Delta S=\Delta Q$, negligible wrong-sign decay probability amplitudes, and equal magnitudes for CP-conjugate allowed probability amplitudes. Then $f_{+}={\pi }^{-}{\ell }^{+}\nu$ is reached directly only from $K^0$, and $f_{-}={\pi }^{+}{\ell }^{-}\bar{\nu }$ only from ${\bar{K}}^0$. Put $|A_{f_{+}}|=|{\bar{A}}_{f_{-}}|=|A|$. The four rates areThere is only one path to each tagged semileptonic channel, so no direct/mixed decay interference survives. The semileptonic wrong-sign mixing asymmetry isIt isolates CP violation in mixing under the stated assumptions. Allowing direct semileptonic CP violation or wrong-sign probability amplitudes would spoil that isolation.^[ref]

Useful examples with no net quark flavor are the eta c meson ${\eta }_c=c\bar{c}$ and the eta b meson ${\eta }_b=b\bar{b}$. Examples with nonzero quark flavor are the kaon $K^{+}=u\bar{s}$ and the D meson $D^{+}=c\bar{d}$. These are pseudoscalar mesons: in the lowest quark model configuration the constituent spins combine to $S=0$, the relative orbital angular momentum is $L=0$, and the total angular momentum and parity are $J^P=0^{-}$. For the self-conjugate examples, meson parity and charge conjugation also gives $C=(-1{)}^{L+S}=+1$. Electrical neutrality alone would not imply zero net quark flavor; for example $K^0=d\bar{s}$ has strangeness.

Restoring reduced Planck constant, decay width and mean lifetime satisfy $\Gamma \tau =\hslash$. Thus the representative numbers correspond toThe mean lifetimes differ by at least $3.0\times 10^{10}$. Hidden-heavy-flavor quarkonium can undergo quark-antiquark annihilation into gluons, followed by hadronization. A $0^{-+}$ color-singlet state can annihilate into two gluons. A lightest open-flavor meson cannot simply annihilate through the strong interaction, which conserves net quark flavor. With no lighter accessible final state carrying that flavor, it must undergo a weak interaction changing a constituent's flavor. The small weak interaction amplitude, CKM matrix factors and available Lorentz-invariant phase space produce a much smaller decay width.

Qualification. A decay width of order tens of MeV is not a universal property of flavor-neutral pseudoscalar mesons. The neutral pion has $\Gamma \simeq 7.8\mathrm{eV}$ and decays predominantly by the electromagnetic interaction, a concrete counterexample. Its mass lies below the lightest allowed hadronic final state. The examples above illustrate the intended annihilation-versus-open-flavor comparison; the numerical scale depends on thresholds and selection rules.^[ref]