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For inverse-gamma distribution observations of known shape $k$ and scale $\Theta$, their likelihood function in $\Theta$ is proportional to ${\Theta }^{nk}\exp (-\Theta {\sum }_i{x}_i^{-1})$. A shape-$\alpha$, rate-$\lambda$ gamma distribution conjugate prior therefore gives the displayed Bayesian posterior. The Bayes estimator under squared error loss of the conditional claim expected value $\Theta /(k-1)$ is $(\alpha +nk)/[(k-1)(\lambda +{\sum }_i{x}_i^{-1})]$. It depends on reciprocals, rather than the sample mean of the claims.

For conditionally independent gamma distribution observations of known shape $\alpha$ and unknown scale $\Theta$, an inverse-gamma distribution prior with shape $k$ and scale $\lambda$ gives an inverse-gamma distribution posterior with shape $k+n\alpha$ and scale $\lambda +{\sum }_j{x}_j$. The posterior mean of the conditional claim expected value $\alpha \Theta$ is $\alpha (\lambda +{\sum }_j{x}_j)/(k+n\alpha -1)$ when the denominator is positive.

Take independent proper normal prior distributions for the two segment means and a proper inverse-gamma distribution for the common variance. A uniform prior distribution over $m=1,\dots ,n$ may then retain the empty second segment. The posterior distribution is proper: its likelihood function is bounded above by $(2\pi {)}^{-n/2}{v}^{-n/2}$, whose integral against $\mathrm{IG}(a_0,b_0)$ is finite for $a_0,b_0>0$. At $m=n$ the second mean has its unchanged proper prior distribution as its full conditional distribution. The configuration's posterior probability now has the meaningful interpretation of no change inside the observed sample.

Let $\bar{x}=m^{-1}{\sum }_i{x}_i$ and $S={\sum }_i(x_i-\bar{x}{)}^2>0$. With Lebesgue base measure $d\mu dv$ for $v={\sigma }^2$, the likelihood-power law has conditionalsThe joint law is proper for $T<m/3$, since its marginal $v$ is inverse-gamma distribution with shape $m/(2T)-3/2$ and scale $S/(2T)$. There is also a direct convergence proof for successive Gibbs sampling updates with deterministic $0<T_n\le m/10$ and $T_n\to 0$. Update ${\mu }_n$ from $v_{n-1}$, then $v_n$ from ${\mu }_n$. Inverse-gamma distribution moments and conditional normal moments giveThe coefficients of the preceding moments are bounded by $1/6$ and $1/8$, so these moments stay bounded from a finite deterministic initial variance. Letting $T_n\to 0$ gives $\mathbb{E}{v}_n\to S/m$ and $\mathbb{E}{v}_n^2\to (S/m{)}^2$. Also $\mathbb{E}({\mu }_n-\bar{x}{)}^2=T_n\mathbb{E}{v}_{n-1}/m\to 0$. Thus the iterates converge in mean square to the normal maximum-likelihood estimate.

In a finite normal distribution mixture with allocation labels $z_j$, independently assign ${\mu }_i\sim N(m_0,{\tau }^2)$, $v_i\sim \mathrm{InvGamma}(\alpha ,\beta )$ and weights a Dirichlet distribution. Let $n_i$ count allocations to component $i$ and $s_i$ sum their observations. The conditional mean precision is $V_i^{-1}={\tau }^{-2}+n_i/v_i$, giving ${\mu }_i\mid \cdots \sim N(V_i(m_0/{\tau }^2+s_i/v_i),V_i)$. The conditional variance is the displayed inverse-gamma distribution; weights have Dirichlet parameters increased by allocation counts. Allocation probabilities are proportional to ${\omega }_i\phi (x_j;{\mu }_i,v_i)$. Independence of the mean prior from $v_i$ is important: its density does not add an extra inverse-gamma shape term.

With independent prior distributions $\beta \sim N(\mu ,\Sigma )$ and $s\sim \mathrm{IG}(a,b)$ in a normal distribution regression model, the conditional posterior distribution of $\beta$ has covariance matrix $V=(X^{T}X/s+{\Sigma }^{-1}{)}^{-1}$ and mean $V(X^{T}y/s+{\Sigma }^{-1}\mu )$. The conditional posterior distribution of $s$ is inverse-gamma distribution $\mathrm{IG}(a+n/2,b+\Vert y-X\beta {\Vert }^2/2)$. The shape contains no half-dimension contribution from $\beta$, since its prior distribution is independent of $s$. These conditionals give a two-block Gibbs sampler.

Start with $v^{(0)}>0$ and any coefficient vector. At sweep $m$, draw $a_k^{(m+1)}$ from the multivariate normal distribution above using $v^{(m)}$, then draw $v^{(m+1)}$ from the inverse-gamma distribution using the newly drawn coefficients. For the second step one may generate $1/v$ from a gamma distribution with the same shape and rate equal to the displayed inverse-gamma scale.

Each block update uses an exact conditional distribution, so it preserves the joint posterior distribution. The resulting pairs form a dependent Gibbs sampler sample. With proper priors, positive scale and positive-definite coefficient covariance, these conditionals have full probability support on ${\mathbb{R}}^{k+1}\times (0,\infty )$ and the usual posterior ergodicity applies. A burn-in reduces dependence on initialization; retained sweeps are still serially dependent and Monte Carlo errors should account for that dependence.

Write $v={\sigma }^2$, $d=k+1$, $X=X_k$, $a=a_k$, $\mu ={\mu }_k$ and $\Sigma ={\Sigma }_k$, with $\Sigma$ positive-definite. For fixed $v$, the terms involving $a$ in the posterior exponent areComplete the square. With $V_k=(X_k^T{X}_k/v+{\Sigma }_k^{-1}{)}^{-1}$ and $m_k=V_k(X_k^{T}y/v+{\Sigma }_k^{-1}{\mu }_k)$, this givesFor fixed $a_k$, collect the powers and exponential terms involving $v$:Hence, in the paper's shape-scale inverse-gamma distribution convention,There is no extra $(k+1)/2$ in this shape, because the normal coefficient prior is independent of $v$. These are the independent normal and inverse-gamma regression priors conditionals.

The Gaussian normalization printed in the PDF is incorrect. The proper $d$-dimensional prior probability density function is $(2\pi {)}^{-d/2}|{\Sigma }_k{|}^{-1/2}\exp [-(a_k-{\mu }_k{)}^T{\Sigma }_k^{-1}(a_k-{\mu }_k)/2]$. For fixed $k$ this correction is constant in $a_k,v$ and leaves the two conditionals unchanged, but it must be retained when comparing different model orders in part (b).

We prove convergence of the actual sequential updates above, not just concentration of ideal equilibrium distributions. Write $M_m=\mathbb{E}{v}_m$ and $N_m=\mathbb{E}{v}_m^2$. Given $v_{m-1}$, the centered normal draw satisfiesThe conditional inverse-gamma distribution moments therefore giveFor $T_m\le n/10$, the coefficient multiplying $M_{m-1}$ is at most $1/6$, so $M_m$ stays bounded by a geometric-recursion argument. The coefficient multiplying $N_{m-1}$ is at most $1/8$, and the other terms are bounded using the first-moment bound, so $N_m$ also stays bounded. These bounds start from the finite deterministic $v_0$.

Since $T_m\to 0$, the boundedness makes every term containing $T_m{M}_{m-1}$ or $T_m^2{N}_{m-1}$ vanish. Hence $M_m\to S/n$ and $N_m\to S^2/n^2$. ConsequentlyThusThis establishes mean-square convergence for the specified Gaussian annealer. It does not assert that every implementation or cooling rule for every objective has the same guarantee, nor that mean-square convergence alone is almost-sure convergence.

Write $v_i={\sigma }_i^2$ for each component variance and ${\tau }^2$ for the fixed prior variance denoted ${\sigma }^2$ in the source; these must not be confused. Let $\phi (x;\mu ,v)$ be the normal distribution probability density function and $D_j={\sum }_{i=1}^k{\omega }_i\phi (x_j;{\mu }_i,v_i)$. Independent observations and independent parameter priors give the posterior distributionIts support has $v_i>0$, ${\omega }_i>0$ and ${\sum }_i{\omega }_i=1$, with $\alpha ,\beta ,{\tau }^2,{ϵ}_i>0$. The component means have independent fixed-variance priors with a normal distribution, not means with variances proportional to $v_i$. The factor $e^{-\beta /v_i}$ follows from the stated inverse-gamma distribution. The later printed augmented expression instead has $e^{-\beta v_i}$ and an undefined prior mean; those are inconsistent with this specification. The intended model uses $e^{-\beta /v_i}$ and prior mean zero throughout.

For minimization of an energy $E(\vartheta )$, simulated annealing at temperature $t>0$ targets the Boltzmann distribution ${\pi }_t(\vartheta )\propto e^{-E(\vartheta )/t}$ relative to a specified parameter reference measure. With proposal distribution $q({\vartheta }^{\prime }\mid \vartheta )$, accept withAt each temperature run the chain long enough to explore that law, then cool and retain the best state seen. For symmetric proposals every improvement is accepted, while a worsening move is accepted with probability $e^{-\Delta E/t}$. Equilibrium laws concentrate near global minima when their normalizing integrals are finite and the minima are suitably isolated. A particular rapid cooling schedule does not automatically inherit this guarantee.

Likelihood maximization uses energy $E=-\ell$, not $E=\ell$. The source's later wording “$f(p)$ equal to the log-likelihood” conflicts with its preceding minimization convention. The intended maximum-likelihood Boltzmann distribution is proportional to $e^{\ell /t}=L^{1/t}$. With the opposite sign, likelihood maxima would be disfavored; for binomial data with both successes and failures the density often would not even be integrable near the endpoints as $t$ decreases.

For the maximum-likelihood estimates, write $s={\sum }_{j=1}^m{x}_j$, $\bar{x}=s/m$ and $S={\sum }_j(x_j-\bar{x}{)}^2$. In the binomial distribution model with known positive integer $n$, the log-likelihood isDifferentiating gives $s/p-(mn-s)/(1-p)=0$, hence $\hat{p}=s/(mn)$. The second derivative is negative in the interior. If $s=0$ or $s=mn$, the maximum is at the corresponding endpoint. This model requires integer observations in $\{0,\dots ,n\}$; otherwise its likelihood is zero.

For the normal distribution model write $v={\sigma }^2$. Its log-likelihood isFor fixed $v$, the unique maximizing mean is $\bar{x}$. Substituting it and differentiating in $v$ gives $v=S/m$, so, assuming $S>0$,If $S=0$, the normal density likelihood grows without bound as $v\downarrow 0$ with $\mu =\bar{x}$; there is no finite interior maximum or ordinary finite AIC for that fit.

For Gaussian likelihood Gibbs annealing, use $L_N^{1/t}$ relative to $d\mu dv$. Completing the square and identifying an inverse-gamma distribution gives the Gibbs sampler conditionalsIntegrating out $\mu$ contributes a factor proportional to $v^{1/2}$, so the marginal is $v\sim \mathrm{InvGamma}(m/(2t)-3/2,S/(2t))$. The joint target is proper for $0<t<m/3$ when $S>0$; starting the Lebesgue-based annealing above this range would require a proper reference factor or bounded parameter domain. For sufficiently small $t$, its moments satisfyThus equilibrium draws concentrate at $(\bar{x},S/m)$ as $t\downarrow 0$.

There is also a direct convergence proof for the actual successive Gibbs sampler updates here. Choose deterministic $0<t_r\le m/10$ with $t_r\to 0$, start at a finite deterministic $v_0>0$, draw ${\mu }_r$ from the first conditional using $v_{r-1}$, then draw $v_r$ from the second using ${\mu }_r$. Conditional normal moments give $E[({\mu }_r-\bar{x}{)}^2\mid v_{r-1}]=t_r{v}_{r-1}/m$ and $E[({\mu }_r-\bar{x}{)}^4\mid v_{r-1}]=3t_r^2{v}_{r-1}^2/m^2$. The permitted inverse-gamma moments therefore yieldThe coefficient on the preceding first moment is at most $1/6$, and that on the preceding second moment is at most $1/8$. The remaining coefficients are uniformly bounded, so both moment sequences are bounded by iteration. Since $t_r\to 0$, the recursions then give $E[v_r]\to S/m$ and $E[v_r^2]\to (S/m{)}^2$. Also $E[({\mu }_r-\bar{x}{)}^2]=t_{r}E[v_{r-1}]/m\to 0$. HenceThis proves convergence in mean square, and thus in probability, to the normal maximum-likelihood estimates for this explicit cooling/update scheme, rather than merely assuming equilibration.

For binomial likelihood-power annealing, normalizing $p^{s/t}(1-p{)}^{(mn-s)/t}$ on $(0,1)$ givesIts mean is $(s+t)/(mn+2t)$, and its variance isThe mean tends to $s/(mn)$ and the variance tends to zero, proving concentration at the binomial maximum-likelihood estimate, including the endpoint cases. Independent exact draws from these beta laws are a simple annealing implementation within this model.

For model selection, the Akaike information criterion is $2d-2\hat{\ell }$ with $d_B=1$ and $d_N=2$. ThusUse the endpoint convention $0\log 0=0$. For a trans-dimensional annealing for penalized likelihood construction, target the disjoint model spaces with unnormalized densitiesrelative to $dp$ and $d\mu dv$, respectively. The energies are half the unoptimized AIC, $d-\ell$; their joint minimizer is the fitted model with smaller AIC. Keep constants such as $C_B$ and the normal density normalization, which do not cancel across models. The within-model conditional draws are unchanged by these constant penalties.

Here is a complete dimension-changing proposal. Select a binomial-to-normal move with probability $b>0$ and a normal-to-binomial move with probability $d>0$, both fixed; other steps can use the within-model updates. From $B,p$, draw $u\sim N(0,1)$ with density $h(u)=(2\pi {)}^{-1/2}{e}^{-u^2/2}$ and setThis bijection from $(p,u)\in (0,1)\times \mathbb{R}$ onto $({\mu }^{\prime },v^{\prime })\in \mathbb{R}\times (0,\infty )$ has inverse $p=(1+e^{-{\mu }^{\prime }}{)}^{-1}$, $u=\log v^{\prime }$. Its absolute Jacobian determinant is $v^{\prime }/[p(1-p)]$. The Binomial-normal reversible-jump annealing acceptance ratio is thereforeFor a reverse proposal from $N,\mu ,v$, compute $p^{\prime }=(1+e^{-\mu }{)}^{-1}$ and $u^{\prime }=\log v$ deterministically and accept withThese ratios are reciprocal at inverse states and enforce detailed balance on the dimension-matched augmented spaces. They specify the proposal density, model-selection probabilities and Jacobian explicitly. The map is a valid example, not a claim of optimal mixing. Positive-temperature beta draws stay in the open interval even when the limiting estimate is an endpoint. At each temperature ensure adequate model switching; retain the best fitted penalized likelihood encountered. If minima tie, limiting concentration need not choose a unique model.

There is a material measurement qualification. A binomial probability mass and an unrounded normal density use different observation reference measures. Their raw AIC values are not an invariant, scientifically calibrated comparison of the same recorded data. The expressions and jump algorithm above implement the formal density comparison suggested by the question, with its units fixed. For integer-recorded measurements, a compatible normal model instead assigns probabilities $P_{\mu ,v}(x-1/2<Z\le x+1/2)$, suitably adjusting boundaries or truncation if required. Then both models describe the same recorded outcomes relative to counting measure. Use those masses in the normal likelihood and the same reversible-jump formula; its simple normal MLE and conjugate Gibbs updates will generally no longer apply. This observation-model correction cannot be silently combined with the continuous-normal formulas.

For minimizing an energy $F(\theta )$, simulated annealing at temperature $T>0$ uses the Boltzmann distribution ${\pi }_T(\theta )\propto e^{-F(\theta )/T}$. At each temperature run a Metropolis–Hastings algorithm or Gibbs transition preserving that law, then reduce $T$. With a symmetric proposal, accept ${\theta }^{\prime }$ with probability $\min \{1,e^{-[F({\theta }^{\prime })-F(\theta )]/T}\}$: downhill moves are accepted and uphill moves remain possible. Keep the best state encountered. As temperature decreases, equilibrium mass favors global minima, provided the target is proper and the relevant concentration hypotheses hold. An arbitrary finite cooling run does not by itself prove global convergence.

Let $s={\sum }_{i=1}^m{x}_i$, $\bar{x}=s/m$ and $S={\sum }_i(x_i-\bar{x}{)}^2$. For the Poisson distribution model the observations must be nonnegative integers. Its log-likelihood isFor $s>0$, differentiation gives ${\ell }_P^{\prime }=-m+s/\lambda$ and ${\ell }_P^{\prime \prime }=-s/{\lambda }^2<0$. If $s=0$, the likelihood is decreasing and the maximizer is the boundary value zero. For the normal distribution model write $v={\sigma }^2>0$, givingFor each $v$, this is maximized at $\mu =\bar{x}$, and differentiating there gives $v=S/m$. HenceThe normal variance estimate has denominator $m$, not $m-1$. A finite positive normal maximum requires $S>0$; if all observations coincide, the likelihood is unbounded as $\mu =\bar{x},v\downarrow 0$. The normal annealing calculation below assumes $S>0$.

To maximize likelihood, choose the energy $-\ell$, so the annealing law is $L^{1/T}$, not $L^{-1/T}$. This sign is important in the Poisson request: literally inserting a positive log-likelihood into a minimizing Boltzmann law would give a nonnormalizable probability density function growing like $e^{m\lambda /T}$ at infinity. We use likelihood-power annealing with the maximizing sign.

For the normal distribution model, take base measure $d\mu dv$. The joint annealing probability density function isCompleting the square gives the Gibbs sampling conditional for $\mu$. Matching the conditional $v$ probability density function to the supplied inverse-gamma distribution convention givesIntegrating out $\mu$ contributes a factor $\sqrt{v}$, so the marginal law isThus this joint Boltzmann law is proper for $T<m/3$. Its variance marginal and the normal conditional both concentrate at the stated estimates as $T\downarrow 0$. For example, for $T<m/7$ its marginal mean and variance areAlso ${\mathbb{E}}_T(\mu -\bar{x}{)}^2=(T/m){\mathbb{E}}_{T}v\to 0$.

There is a direct convergence proof for the actual changing-temperature Gibbs algorithm, beyond convergence of its equilibrium probability densities. Start at a finite deterministic $v_0>0$, choose deterministic $0<T_n\le m/10$ with $T_n\to 0$, draw ${\mu }_n$ conditional on $v_{n-1}$, then draw $v_n$ conditional on ${\mu }_n$ using the two boxed distributions. Conditional normal moments giveThe inverse-gamma distribution first and second moments consequently yieldandIn the first recursion the coefficient of the preceding mean is at most $1/6$; in the second the coefficient of the preceding second moment is at most $1/8$. The means therefore stay bounded, and then so do the second moments. Letting $T_n\to 0$ in these formulas gives $\mathbb{E}{v}_n\to S/m$ and $\mathbb{E}{v}_n^2\to (S/m{)}^2$. Together with $\mathbb{E}({\mu }_n-\bar{x}{)}^2=T_n\mathbb{E}{v}_{n-1}/m\to 0$, this provesThis Gaussian likelihood Gibbs annealing convergence uses the explicit conditional structure and does not assume that one Gibbs sampling sweep is an exact equilibrium draw.

For the Poisson distribution model, the likelihood-power law with respect to $d\lambda$ has the normalized probability density functionsoThe mean tends to $\bar{x}$ and the variance to zero, proving convergence to a point mass at the Poisson maximum-likelihood estimate, including the zero-boundary case.

The Akaike information criterion is $2k-2\ell (\hat{\theta })$, counting one parameter for Poisson and two for normal. With $0\log 0=0$ and $S>0$, the two forms areandChoose the smaller criterion. Likelihood constants that differ between models, including the factorial and $2\pi$ terms, cannot be discarded.

For a fully specified trans-dimensional annealing for penalized likelihood, let $M=P$ or $N$ and defineUse the combined target, relative to counting measure on models and Lebesgue measure on their parameters,where $w_P,w_N>0$ are fixed reference weights. For $S>0$ and $0<T<m/3$ both model components are integrable. The factor $2T$ is a convenient temperature convention keeping the within-model laws exactly those already derived. The extra factor $e^{-k_M/T}$ makes the zero-temperature objective AIC rather than unpenalized likelihood.

Use, for example, probability $1/2$ for a model-change attempt in either model and probability $1/2$ for a within-model update. Within the Poisson distribution model draw a fresh gamma value from its boxed law; within the normal distribution model perform the boxed Gibbs sampling sweep. For a Poisson-to-normal proposal, draw $u\sim q(u)=N(0,{\tau }^2)$ with a fixed ${\tau }^2>0$, and setThe inverse normal-to-Poisson proposal is $\lambda =v$ with reverse auxiliary $u=\mu -v$. This dimension matching uses one auxiliary variable to augment the one-dimensional Poisson parameter space. The absolute Jacobian determinant isIf the forward model-jump selection probability is $b$ and the reverse probability is $d$, the reversible-jump Markov chain Monte Carlo acceptance ratio isAccept with probability $\min (1,R_{P\to N})$. For the reverse move compute $\lambda =v,u=\mu -v$ and useFor the suggested equal selection probabilities, $b=d=1/2$ and those factors cancel. The probability density function $q$ must still be included, despite symmetry of its normal distribution: it is an auxiliary draw in only the forward dimension-increasing proposal. Pairing a move with its inverse makes the accepted forward and reverse probability flows equal after the change of variables, proving detailed balance for each fixed-temperature model-switch kernel.

Cool through proper temperatures, allow enough model and parameter exploration at each stage, and retain the smallest observed $E_M$. The minima of the two energies are exactly the two AIC values above. Low-temperature equilibrium mass concentrates on the better criterion and its fitted parameters; if they tie, the minimizing set contains both models. Unlike the direct normal Gibbs argument, this multimodel exploration claim needs an appropriate cooling/mixing justification and is not guaranteed by an arbitrary short run.

Finally, an exact statistical comparison must put both likelihoods on the same observable and reference-measure convention. A Poisson distribution model is a probability mass function on counts, whereas the displayed normal distribution model is a continuous probability density function. The formulas above are the question's formal Gaussian working-likelihood comparison. A coherent exact normal approximation for count observations can instead use probabilities of rounding intervals; that changes its likelihood and generally loses the simple analytic normal estimates. This distinction matters when interpreting the numerical AIC difference, while leaving the dimension-matching and annealing construction applicable to properly specified likelihoods.

Let $v={\sigma }^2>0$, $d_k=k+1$, and $S_k(a)=\Vert y-X_{k}a{\Vert }^2$. Under the standard interpretation that the two stated priors are independent, multiply the normal likelihood by the normal coefficient prior and the inverse-gamma distribution density. The independent normal and inverse-gamma regression priors giveFor a fixed model the determinant and Gaussian normalizing constants are independent of $a_k,v$ and may be omitted here; ${\Sigma }_k$ is assumed positive-definite. The coefficient prior is not scaled by $v$, so replacing its precision by ${\Sigma }_k^{-1}/v$ would describe a different prior.

For an additional check, completing the coefficient square and reading the variance kernel give the full conditional distributionsandMarginal priors alone would not determine their joint prior without the independence assumption. The front-page inverse-gamma mean has a typographical error: this density has mean $\beta /(\alpha -1)$ when $\alpha >1$, not a denominator $\alpha +1$. The density itself, used in the posterior calculation, fixes the correct parameterization.

Use the shape-scale convention for the inverse-gamma distribution: $\mathrm{IG}(a,b)$ has density proportional to $s^{-a-1}{e}^{-b/s}$ for $s>0$. Write $X=X_k$, $\beta ={\beta }_k$, $\mu ={\mu }_k$, $\Sigma ={\Sigma }_k$ and $s={\sigma }^2$. The independent normal and inverse-gamma regression priors make the conditional log-likelihood plus log prior in $\beta$ equal, up to a constant, toDefine $V=(X^{T}X/s+{\Sigma }^{-1}{)}^{-1}$ and $m=V(X^{T}y/s+{\Sigma }^{-1}\mu )$. Completing the square turns this expression into $-(\beta -m{)}^T{V}^{-1}(\beta -m)/2$ plus a constant. Thus the conditional posterior distribution is the multivariate normal distributionPositive definiteness of the prior covariance matrix makes this well defined even if the design matrix is rank deficient.

Holding $\beta$ fixed, the factors depending on $s$ areConsequentlyThere is no additional $(k+1)/2$ in the shape: the normal distribution prior for ${\beta }_k$ is independent of ${\sigma }^2$. A prior scaled by ${\sigma }^2$ would be a different model and would change that calculation.

A reversible-jump Markov chain Monte Carlo calculation compares normalized model-specific densities. The fixed-order posterior written only up to proportionality in part (a) omits normalizing factors that depend on $k$ and therefore cannot simply be canceled between dimensions. Moreover, the printed question does not specify the model-order prior distribution or the probabilities of selecting birth and death moves. Denote those by $p_k$, $b_k$ and $d_k$, respectively, retaining them in the answer.

Put $s={\sigma }^2$, $c=n^{-1}{\sum }_i{x}_i^{k+1}$, $v_i=x_i^{k+1}-c$, and $r=y-X_k\beta$. The centered polynomial birth move in reversible-jump sampling changes the fitted vector by $zv$, so its new residual is $r^{\prime }=r-zv$. ThereforeThe map from $({\beta }_0,\dots ,{\beta }_k,z)$ to $({\beta }_0^{\prime },\dots ,{\beta }_{k+1}^{\prime })$ has ones down the diagonal and a single additional entry $-c$ in the intercept row. Its Jacobian determinant is one.

Write $Q_k=(\beta -{\mu }_k{)}^T{\Sigma }_k^{-1}(\beta -{\mu }_k)$ and $Q_{k+1}=({\beta }^{\prime }-{\mu }_{k+1}{)}^T{\Sigma }_{k+1}^{-1}({\beta }^{\prime }-{\mu }_{k+1})$. The normalized multivariate normal distribution prior ratio isDivide also by the forward proposal density $q(z)=(2\pi {\sigma }_{\beta }^2{)}^{-1/2}{e}^{-z^2/(2{\sigma }_{\beta }^2)}$. The common inverse-gamma distribution prior for $s$ and the common normal-likelihood normalization cancel, since $s$ stays fixed. The forward acceptance ratio is consequentlyHere ${\sigma }_{\beta }>0$ is the proposal standard deviation. If equal model priors and symmetric birth/death selection are explicitly adopted, their ratios become one; they are not determined by the PDF. The expression assumes the same hyperparameters for the variance prior in both models, as in part (a). A dimension-dependent variance prior would contribute its own ratio.