Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 105 4 a iii Solution Created 2026-10-03 Updated 2026-10-05
For , the conormal to its zero set is . The principal symbol of isA characteristic hypersurface requires on the surface. Thus satisfies the anisotropic eikonal equationThe first-order and zeroth-order terms do not affect this condition.
Past exam of the mathematics course of the University of Cambridge 2022 ii Paper 3 39C a Solution Created 2026-09-24 Updated 2026-09-25
Assume the medium varies on scales much longer than the wavelength and period, so the leading-order WKB method gives the local eikonal equation. For the phase in the stated ansatz, defineThe local dispersion relation becomes the Hamilton--Jacobi equationDifferentiating it with respect to , using equality of mixed derivatives, and choosing a ray whose velocity isgivesHere the dot, or , is the total derivative along a ray,and not merely a partial time derivative at fixed position.
Finally, differentiate along the same trajectory:because the last two terms cancel. The Hamiltonian ray-tracing equations are therefore
Past exam of the mathematics course of the University of Cambridge 2023 iii Paper 336 1 b i Solution 2026-09-28
Hereso the Euler-Lagrange field equation is the variable-coefficient wave equationAt leading order, hasand henceThe leading part of the modulated-wave first integral isA nonconstant periodic wave therefore requires the local dispersion relationThis is usually called the eikonal equation, or equivalently the leading geometric-optics dispersion relation.
Past exam of the mathematics course of the University of Cambridge 2023 iii Paper 336 3 Solution 2026-09-28
Three distinguished limits are needed.
In the origin layer, put and . Since , the leading equation isIt has the first integralSolving this first-order linear differential equation givesRegularity at requires , and then fixes . Thus Region I, , hasIts matching limit is as .
In Region II, with , setting reduces the second-order equation toHence . Matching with the inner limit fixes , so
The correction generated by changes the local decay rate when . For Region III setThe terms of order give the eikonal equationand the next balance gives . Matching to Region II selectsThereforeThis solution is already beyond all algebraic orders in in the distant region. A leading multiplicative composite expansion that contains all three balances and satisfies the boundary value exactly iswith its value at understood by continuity.
Finally, the coefficient of vanishes at the origin. Taking the regular limit of the original equation there givesso the prescribed value also fixes . Equivalently, the second inner solution behaves as and is excluded by regularity. This regular singular point is why one boundary condition determines the unique regular solution.