Electroweak interaction Created 2026-09-24 Updated 2026-10-18
The electroweak interaction is the gauge theory that unifies the weak and electromagnetic interactions.
An instructive tension motivates the unification: the photon is massless, while the W boson and Z boson are massive; electromagnetic interaction and weak interaction also have different observed low-energy strengths and chiral couplings. A gauge theory can relate their interactions while the Higgs field gives different masses after electroweak symmetry breaking. The resulting theory predicts relationships between processes, not merely a common name for observed phenomena.
Its useful organizing principle is the combination of weak isospin and hypercharge. The surviving electromagnetic generator is in the convention used here. The photon and Z boson are different mixtures of neutral gauge fields, while the charged current uses the charged combinations. The electroweak doublet gauge-boson mass matrix explains why one neutral mixture stays massless. At low energies, a massive W boson propagator instead produces the approximate Fermi interaction, withHere is the gauge coupling and the Higgs doublet vacuum expectation value. The inverse squared mediator mass suppresses low-energy weak rates. Unification does not require setting equal to the electromagnetic coupling : their relation is .
A striking experimental consequence is a neutral current in addition to the familiar charged current. The Gargamelle experiment tests this extra channel through visible charged secondaries, with a background problem fundamentally different from directly identifying a Z boson. The muon-neutrino electron recoil spectrum shows how the same Weinberg angle enters another process quantitatively.
Leptonic pseudoscalar decay width 2026-10-14
In the convention , the Fermi interaction gives . With a massless antineutrino, the external Dirac equations reduce this to . The spin sum is . The two-body Lorentz-invariant phase space has integrated value , and the initial flux factor is , giving the displayed width. If the decay constant is instead defined without the square root of two, and the denominator is . A weak mixing coefficient multiplies the amplitude and its modulus squared multiplies the width.
Neutrino scattering on an antiquark 2026-10-06
For a massless neutrino scattering on an unpolarized up antiquark through the Fermi interaction, . The corresponding down-quark channel has . Their difference follows from the chiral weak-current trace contraction. The parton distribution functions weight these rates in a hadron.
Past exam of the gauge field theory course of the University of Cambridge 2012 Paper 1 3 b Solution 2026-10-20
In units , a dimensionless action fixes . Canonical kinetic terms then give , and . If an interaction operator has dimension , its coefficient has mass dimension . Thus scalar quartic, Yukawa and gauge couplings are dimensionless; a scalar cubic coupling has dimension one, a four-fermion coupling has dimension minus two, and the Weinberg coefficient has dimension minus one. These are engineering dimensions; anomalous scaling is an additional quantum effect.
For a connected graph with independent loop momenta, boson lines, fermion lines and derivatives at vertex , ordinary covariant-gauge ultraviolet counting gives the superficial degree of divergenceThe second form follows from and counting field ends at vertices. It presumes the canonical large-momentum propagators; unitary-gauge vector propagators can obscure the cancellations of a renormalizable gauge theory. A nonnegative signals a possible overall ultraviolet divergence, not proof of one. Symmetries can cancel it, while a graph with can still contain divergent subgraphs.
With only operators of dimension at most four, increasing the vertex count does not require counterterms of unbounded dimension. Subject to the necessary symmetry identities and absence of gauge anomalies, scalar quartic theory, Yukawa theories and the Standard Model are perturbatively renormalizable when all required interactions are included. In particular, coupling a scalar to other fields can require a scalar quartic counterterm even if its coefficient was initially set to zero. The Higgs mechanism does not destroy renormalizability of the underlying anomaly-free gauge theory.
By contrast, repeated insertions of the dimension-six Fermi interaction or a dimension-five operator allow increasingly high-dimensional counterterms. Such terms are useful in an effective field theory with a stated expansion in energy over a high scale; nonrenormalizable does not mean unpredictive at a fixed order. A scalar interaction and perturbative Einstein gravity in four dimensions provide other examples. Renormalizability also does not assert small coupling at every scale or a complete ultraviolet theory.
Each Dirac current has mass dimension three, so their product has dimension six. Its coefficient therefore has dimension :The Fermi interaction is not power-counting renormalizable, but its success at low energies is explained by effective field theory. Exchange of a heavy W boson between the appropriate chiral weak currents has a propagator that expands as . The leading term is a local four-fermion interaction and further terms are suppressed by powers of . The complete spontaneously broken electroweak gauge theory resolves the pointlike approximation at higher energies. The source's vector-current product illustrates the operator dimension; the actual weak interaction also has its specific flavors and chiral structure.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 48 2 Solution Created 2026-10-03 Updated 2026-10-14
The derivative convention uses hypercharge Y with . For each lepton family , the left-handed fields form an SU(2) doublet , with . Their weak isospin values are and their electric charges are . The right-handed charged lepton is an SU(2) singlet, with , and charge . The minimal model used here has no right-handed neutrino. A sterile right-handed neutrino, if added as a singlet with , would have no charged weak current interaction. Antiparticles carry the conjugate representations and opposite electric charges.
Expanding supplies . The off-diagonal entries of are and . With the chiral projector , one has . Thus the two W boson interactions areFor quarks, separate rotations diagonalize the up-type and down-type mass terms. If their left-handed rotations are and , the charged interaction contains the CKM matrix :There is an implicit sum over color charge. This quark mixing permits transitions between different families, rather than just the paired fields in a single doublet.
Let and . At momenta much smaller than , neglect derivatives in the heavy W boson equation. Its mass and source terms can be completed to a square:This explicitly performs integrating out a charged vector boson. The resulting Fermi interaction isThe omitted terms contain derivatives and are relatively suppressed by momentum squared divided by .
For the leptonic pion decay, Lorentz covariance restricts a vacuum-to-spin-zero current matrix element to a constant times . In the rest frame, rotations eliminate the spatial components. Under parity, the temporal vector current is even, whereas the vacuum is even and the pion is odd, so its temporal matrix element equals its negative and vanishes. The temporal axial current is odd and is allowed. This proves the vacuum-to-pseudoscalar current selection rule, rather than merely assuming an axial current. Define the pion decay constant byThen the vector-minus-axial charged weak current has matrix element , up to an irrelevant overall phase convention. Consequently the scattering amplitude for the decay can be writtenUse , the momentum-space Dirac equation , and for a massless neutrino. Since , the neutrino contribution vanishes, leavingThe fermion spin sum is, using the supplied gamma matrix trace identities,Here , , and . The mass term in the trace vanishes; anticommuting reduces the remaining trace to twice . It follows thatUsing two-body decay phase space, with final momentum magnitude , gives the leptonic pseudoscalar decay widthThus the requested factor is already present in the squared amplitude, and the phase space supplies one more threshold factor.
The physical explanation is helicity suppression. In the pion rest frame the two momenta are opposite. The massless antineutrino has positive helicity; zero total angular momentum would require the electron to have positive helicity too. The charged weak current instead creates a left-chiral electron, whose helicity is negative when its mass vanishes. A nonzero electron mass admits the required opposite helicity with an amplitude proportional to . The decay amplitude vanishes for , and the rate is suppressed by .
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 53 3 Solution Created 2026-10-03 Updated 2026-10-14
At momentum transfers small compared with , the two weak charged current vertices each carry when written with , and the W boson propagator reduces to a local factor proportional to . Matching their product to the Fermi interaction gives, at tree level,The Fermi constant is thus determined by the electroweak coupling and symmetry-breaking scale; the four-fermion description is a low-energy effective interaction.
Only the cross term can annihilate the pion and create the stated charged-lepton/antineutrino pair. Its leptonic matrix element is . Lorentz covariance permits a vacuum-to-spin-zero current matrix element only proportional to . At rest this has only a temporal component. The vacuum is parity-even and the pion is parity-odd, while is parity-even, so equals its own negative and vanishes. Lorentz covariance then makes the full vector matrix element vanish. The temporal axial current is parity-odd and is allowed: this is the vacuum-to-pseudoscalar current selection rule.
The minus sign in cancels the interaction's minus sign, up to an irrelevant common S-matrix phase. ThereforeThe pion decay constant convention here includes the given in its current matrix element. Momentum conservation and the external Dirac equations give , , . Since , the neutrino term vanishes andThis is helicity suppression: the amplitude vanishes in the zero charged-lepton-mass limit despite the larger available phase space.
For the spin sum, the Dirac adjoint of is , and the completeness relations giveThe chiral projectors automatically eliminate the unused neutrino helicity when the full massless completeness relation is inserted. There is no initial spin average for a spin-zero pion.
In the pion rest frame, let , . After integrating the spatial delta function and angles, the two-body Lorentz-invariant phase space becomesThe root is and . The absolute derivative of the delta-function argument is . Thus . Multiplying by the spin sum and the initial factor yields the leptonic pseudoscalar decay widthIf the decay constant were instead defined by a matrix element without , then and the width coefficient would be ; mixing these conventions would introduce a factor-of-two error.
The same derivation for a muon cancels the common hadronic and weak factors in the pion electron-to-muon decay ratio:The numerical value uses approximate masses MeV. Agreement with the corresponding Standard Model prediction tests lepton universality and the chiral, helicity-suppressing structure of the weak charged current, rather than the poorly calculable hadronic decay constant. A difference in the electron and muon weak couplings would multiply the ratio by their squared coupling ratio. Precision agreement must be assessed after radiative corrections, with matching photon-inclusive experimental definitions; the displayed tree-level ratio is not itself the radiatively corrected precision prediction.
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 54 1 Solution Created 2026-10-03 Updated 2026-10-14
Use metric and the hypercharge convention . Then the Higgs doublet has and transforms under electroweak gauge invariance asThe covariant derivative sign consistent with the requested expression isA convention that instead calls the doublet hypercharge one puts in the charge generator and derivative; the physical coupling is the same. Here and the matrix-valued connection transforms as , making transform like .
In unitary gauge, the upper component of the derivative comes from the off-diagonal Pauli matrices:The lower component isWriting , , inversion of the neutral rotation gives and . Since , the coefficient of the photon vanishes, whereas . ThusThe zero photon coupling expresses the neutrality of the surviving radial Higgs boson.
The scalar Lagrangian density is . Adding gives the complete bosonic electroweak Lagrangian density. Its scalar and vector mass terms, after electroweak symmetry breaking, are obtained directly asIndeed, the shifted quartic Higgs potential normalization gives . Comparing with a canonically normalized real scalar mass term, a complex vector mass term and a real vector mass term yieldsThe extra factor one half in this paper's Higgs potential is why is , rather than in another common convention. The tree-level electroweak gauge-boson masses give : measure the two vector masses and take their ratio. Beyond tree level this extraction requires a specified renormalization convention and radiative corrections.
Expanding the vector terms gives the cubic and quartic Higgs couplings to electroweak gauge bosons:The four elementary Feynman diagrams and their all-incoming Feynman rules are shown below. Differentiating with respect to two identical fields supplies a factor two; differentiating with respect to two identical Higgs fields supplies another factor two in the quartic rules.
Tree-level Higgs vertices with charged and neutral electroweak gauge bosons
. Details. There are no elementary , , or vertices in this tree-level Lagrangian density. Loop-induced photon interactions are a different order. The scalar self-interactions, if included, have rules and .
The prime LEP2 search used the Higgs boson coupling to Z bosons through Higgsstrahlung, , shown in the first panel of the process figure in Question 3. This identifies an associated-production interaction, rather than an on-shell decay of a single into a heavier Higgs. The channel's historical role is documented in the LEP2 Higgs-search account.
For the free charged W boson, take , with the conjugate field carrying . In the action, multiplying the two field strengths gives . ThereforeTo invert it, separate the transverse and longitudinal projectors , . The operator is , soSince the quadratic action kernel is , its Proca propagator isFor all momentum components small relative to , the low-momentum limit is , with corrections of relative order or . This local limit leads to the Fermi interaction, with for the charged-current normalization used here.
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 62 3 i Solution Created 2026-10-03 Updated 2026-10-20
Work in natural units , at temperatures far below the -boson mass but of order or above the electron mass. The Fermi interaction then supplies a local four-fermion amplitude. The Fermi constant has dimension energy. In scattering of a thermal lepton from a nonrelativistic nucleon, the nucleon current matrix element has size , while the lepton current has size . Thus . The two-body relativistic scattering cross-section contains the kinematic factor ; when the final and initial lepton energies are comparable, their momentum ratio is of order one. Consequently . This estimates temperatures above the electron mass and mass-splitting thresholds; those scales only affect the dimensionless rate function near freeze-out.
The light leptons in the thermal bath have number density and speed of order unity. Their conversion rate per nucleon is thereforeFor example, and change the neutron-to-proton ratio. The bath density here is the lepton density, not the much smaller baryon density. Dimensionless weak couplings, phase-space integrals and the several reaction channels set a numerical coefficient. Electron masses and the neutron-proton splitting also become important for a precision rate near cosmological weak freeze-out.
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 45 3 Solution Created 2026-10-03 Updated 2026-10-14
The product of leptonic weak charged currents in the Fermi interaction contains four-fermion cross terms such asThis produces , and the same interaction permits neutrino-electron scattering and inverse muon decay. Pure electromagnetic interactions have no neutrino coupling and preserve the separate charged-lepton species, so cannot produce these processes by themselves. The factor fixes the chiral structure of the weak charged current.
The pion is a pseudoscalar with negative parity, while the strong-interaction vacuum is parity even. Lorentz covariance restricts a vacuum-to-pion vector-current matrix element to . In the pion rest frame only its temporal component could be nonzero, but a vector current's temporal component is parity even, whereas the pion is parity odd. The matrix element therefore equals its negative and vanishes. The temporal component of an axial current is parity odd, so its matrix element is allowed and Lorentz covariance fixes it to a constant times . Defining the pion decay constant in the printed normalization givesThis proves both the vector-current exclusion and the axial-current form; itself is a strong-interaction parameter, not fixed by symmetry.
The cross term gives, up to an irrelevant overall phase, the decay amplitudeTake the antineutrino mass to be zero. Since , , and , anticommutation with givesThe amplitude has helicity suppression by one power of the charged-lepton mass.
Using the external spin sums, with no initial spin average for a spin-zero pion,The middle equality follows from , , and the gamma matrix trace identities. Summing a full massless neutrino spin basis introduces no factor of two: the current projector annihilates the inactive helicity.
For completeness, evaluate the two-body Lorentz-invariant phase space in the pion rest frame. Its three-momentum delta function sets , and the energy delta function is . The radial root isCombining its derivative with and integrating solid angle givesThe invariant squared amplitude is independent of direction, so the supplied decay formula yields the leptonic pseudoscalar decay widthThe denominator is because the matrix element contains . With the alternative definition , the same width is . In either convention it vanishes as .
Replacing the electron by a muon gives the same hadronic factor and weak coupling. Hence the pion electron-to-muon decay ratio isThis is a tree-level result with massless neutrinos. The cancellation of and makes the ratio a clean test of the predicted helicity suppression and electron–muon universality in the chiral weak charged current. For example, scalar or pseudoscalar four-fermion interactions could remove the charged-lepton mass factor and substantially enhance the electron mode. Radiative corrections are required for a precision experimental comparison.
With two quark generations, the charged hadronic current containsA contains , so its annihilation into the lepton pair selects the term proportional to . Strong strangeness conservation excludes the term from its vacuum matrix element. Its amplitude is thus multiplied by and its width by :Here is the pure strong-interaction decay constant in the same square-root-of-two convention. If the pion current's quark mixing coefficient is also shown explicitly, its width carries ; it is already absorbed if the stated pion matrix element uses the full weak current. Thus the isolated weak-factor ratio is , while the kaon suppression relative to unit weak coupling is the requested Cabibbo suppression factor .
Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 45 1 Solution Created 2026-10-03 Updated 2026-10-06
Use the metric and the usual Dirac basis, with and . In this solution the sign of the chirality matrix is the one specified in the paper, . Define and , with no summation in componentwise transformation formulas.
Complex conjugation changes the explicit to . Three spatial gamma matrices each contribute another minus sign, soAlso and by the Clifford algebra.
The quantum time-reversal operator is antiunitary: it conjugates numerical coefficients, including the Dirac spinors and plane-wave exponentials in the mode expansion of a Dirac field. To fix the spin phase explicitly, put and useThis convention gives on a one-fermion state, since . In the transformed expansion, change variables from to . The Lorentz-invariant phase-space measure is unchanged, and . The coefficient of is thereforeThe same calculation applies to the antiparticle coefficient. Thus, with this explicitly fixed spin convention,The spin phase in the Dirac time-reversal matrix matters here: a common change of the one-particle time-reversal phase replaces by ; the phase-independent relation is . It changes neither the defining conjugation property nor any bilinear result below. Normalize to be a unitary matrix. In the Dirac basis, is real and commutes with , so transforming the Dirac adjoint givesHere complex conjugation of the matrix defining the Dirac adjoint is essential. An explicit realization consistent with the sign of used here is and ; it has , so conjugation by and by coincides. The usual changes of Dirac spinor basis by unitary matrices carry the adjoint and time-reversal matrix with them.
For the charge-conjugation matrix, the gamma matrix adjoint and transpose identities give . Consequently . Since in the chosen phase convention,This proof uses a temporal Hermitian matrix and spatial skew-Hermitian matrices explicitly; the transpose identity is preserved when is transformed appropriately with the gamma matrices.
For the Fermi interaction, let and . In the displayed Dirac basis, the inverse version of the conjugation relation also holds. Antiunitarity, and giveThe leptonic weak charged current has the same component signs. In the contraction of leptonic and hadronic currents, the two factors cancel. Its two independent operators thus keep their form while their coefficients become and . The Hermitian-conjugate term transforms separately; its presence does not remove a relative complex phase between the vector and axial couplings.
With all intrinsic phases fixed to one and a real positive Fermi constant, invariance requires real coefficients in that convention. A common phase of and can instead be absorbed into a rephasing of the nucleon fields, and hence into their intrinsic time-reversal phases. The convention-independent condition, for , isThis is the relative weak phase condition for time reversal. If one coefficient vanishes, there is no relative phase to constrain; the remaining common phase can be removed. A nonreal ratio violates time-reversal symmetry even though the Lagrangian density includes its Hermitian conjugate.
Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 45 3 Solution Created 2026-10-03 Updated 2026-10-06
The strong-interaction matrix element between two spin-zero pseudoscalar mesons has only and available. The product of the two intrinsic parities is positive. An axial current would require a pseudovector constructed from these momenta, but an expression involving the Levi-Civita symbol needs three independent four-vectors and therefore vanishes. This is a consequence of parity conservation in the hadronic matrix element, not of parity conservation in the weak interaction. The vector current can have the two independent structures and . Its coefficients are Lorentz scalars; with and fixed, their only varying invariant is . HenceThese are the pseudoscalar-to-pseudoscalar form factors. With relativistically normalized states they are dimensionless. The vanishing axial matrix element and this decomposition explain the two equalities separately.
Write and for the outgoing electron and antineutrino momenta. From the Fermi interaction, an invariant scattering amplitude, up to an irrelevant overall sign or phase, isThe CKM matrix element multiplies the quark current in the convention of this interaction. Let . For massless leptons, the massless Dirac equation and chirality matrix anticommutation giveIn the second term move through the chiral projector before applying . Since , this transverse massless leptonic current givesThe disappearance of uses the massless approximation; for a massive charged lepton its contraction is proportional to the lepton mass.
Use the fermion spin sum and the supplied gamma matrix trace identities. The symmetric part of the leptonic tensor isThe Levi-Civita symbol term is antisymmetric and drops out when contracted with . ThusThere is no initial-spin average because the kaon is spinless. For the integrated massless leptonic tensor, keep every factor of explicit and define the unnormalized two-lepton Lorentz-invariant phase spaceThe leptons are massless, so . Its trace is . ThereforeThe three Lorentz-invariant phase-space measures and their momentum delta function contribute , in addition to in the decay rate. Combining them with the spin sum givesThis massless semileptonic pseudoscalar decay rate uses a two-lepton integral over future-timelike and the pion integral is restricted to the physically allowed region. The null endpoint follows by continuity. The coefficient has mass dimension , so the complete expression has mass dimension one, as a decay rate must in natural units.
In the kaon centre-of-momentum frame, put and . ThenThe dimensionally consistent Källén function isThe pion-only mass term must have fourth power: the second power printed in the PDF is dimensionally inconsistent. This repair also follows directly from squaring . Angular integration and the change of variable givewhere the negative sign reverses the endpoints. Combining this with the bracket yieldsThus . The lower limit is the minimum invariant mass of two massless leptons; at the upper limit the pion is at rest. The coefficient has mass dimension , while has dimension eight. The Källén function also shows why the differential decay rate vanishes at zero pion momentum.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 47 3 b Solution Created 2026-10-03 Updated 2026-10-20
Flavour issue in the printed effective interaction. The displayed charged-current factor uses an electron field even for the muon-neutrino term. Taken literally, this introduces an extra charged-current interaction, contradicting the Standard Model diagrams in part (a). In the Standard Model that factor uses the charged lepton of the same flavour; for electron scattering the charged-current contribution is therefore present only for . The weak flavour selection in neutrino-electron scattering fixes the physically consistent assignment used below. The literal printed consequence is given afterwards, so the discrepancy is explicit.
At leading order in the electron mass and in the four-fermion regime, define . The weak neutral current yields the scattering amplitudeAn overall amplitude phase has no observable effect. The Fermi interaction is valid when the exchanged invariants are small compared with the squared weak-boson masses.
Average over the two initial electron spin states, and sum over final spins. There is no averaging over a sterile right-handed incoming neutrino. Using the fermion spin sum, the averaged square isTo display the trace contraction, defineThe supplied gamma matrix trace identities give the two tensors and . Symmetric-antisymmetric mixed contractions vanish. Set and . The remaining contractions are and , using the stated negative epsilon-contraction sign. Their sum givesThe massless Mandelstam variables satisfy , and the two products are and , respectively. Therefore
In the centre-of-momentum frame, momentum conservation gives . If is the angle cosine between and , then . The massless two-body Lorentz-invariant phase space is , while the flux is . ThusIntegrate and :Consequently the intended coefficients areThis is the massless neutrino-electron contact cross-section.
For completeness, the literal printed muon-neutrino charged-current term would instead shift both couplings by one, exactly as in part (c):For arbitrary real , its linear terms cannot be represented by the requested quadratic form with coupling-independent constants. The Standard Model result and the literal printed interaction are not the same problem.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 305 4 b Solution Created 2026-10-03 Updated 2026-10-14
The two tree-level Feynman diagrams have t-channel W boson exchange. The antiquark process reverses the fermion-flow arrows on the lower line.
Each vertex contributes multiplying a chiral current. At momentum transfer , the gauge-boson propagator is approximated by its momentum-independent term , up to the overall phase. The longitudinal term does not contribute to these conserved massless currents. Thus the coefficient is , giving the Fermi interaction. For the quark and antiquark amplitudes, apart from irrelevant overall phases,andThe low-energy operator form is ; its external spinor matrix elements are the displayed products.
For an unpolarized initial parton, average over its two spin states. There is no factor for the incoming active neutrino, which has one allowed helicity. The initial color average cancels the final color sum, so there is no surviving color multiplicity in this parton cross section. DefineThe symmetric and antisymmetric parts have zero cross contraction. Their separate contractions are and . Thus the given Levi-Civita symbol identity yieldsIncluding the coefficient and the initial-parton spin average givesMassless kinematics and imply . From , . ThereforeTo reduce the supplied phase-space formula, use the massless center-of-mass flux and . This gives . In that frame , so . HenceThe antiquark channel's angular factor is a consequence of the chiral current and the reversed lower-line spinor order, rather than a color factor.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 305 3 b Solution Created 2026-10-03 Updated 2026-10-05
Use metric , and relativistically normalized external spinors. The Fermi interaction givesup to an irrelevant phase. The fermion spin sums replace and by the slashed massless momenta. Write . The gamma matrix trace identities yieldThe symmetric-antisymmetric mixed contractions vanish. The symmetric contraction is , while the two epsilon tensors contract to . Including and the initial-spin average therefore givesThe singlet color charge contractions have net factor one after summing final colours and averaging initial color charge states. Thus this is also the colour-averaged partonic result; no extra factor three is required.
In the centre-of-momentum frame, let . The Mandelstam variables satisfy and , giving and . HenceThe massless invariant flux factor is and , so the weak charged-current quark scattering cross-section isFor a purely left-handed weak charged current, , , this reduces to , fixing the sign of the forward term. Purely right-handed weak charged currents at both vertices have the same unpolarized angular law. The factorization convention for could be rescaled by a common numerical factor; the displayed product fixes the normalization.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 305 3 c Solution Created 2026-10-03 Updated 2026-10-05
For fixed the effective Fermi interaction predicts . The angular odd term integrates to zero, while , soThe corresponding fixed-spin scattering amplitudes grow as , eventually conflicting with partial-wave unitarity. This is a failure of extrapolating the effective field theory, whose contact approximation requires , not a failure of the Standard Model.
Restoring the virtual W boson Feynman propagator replaces its constant low-energy denominator by , away from the resonance. The massless external Dirac equations give zero contraction of each current with the exchanged momentum, so the longitudinal numerator does not contribute. Its squared modulus multiplies the effective cross-section. For the resulting tree-level rate decreases as rather than growing as . Near the pole one must include the W boson decay width. These statements assume the same massless conserved external currents; the contact expression alone is not valid there.
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 305 3 b Solution 2026-10-03
The first four-fermion operator is the low-energy Fermi interaction obtained by replacing the crossed propagator in the charged-current diagram by . The second operator is obtained analogously from the -exchange weak neutral current; and are its electron vector and axial-vector couplings. Thus the two terms represent respectively the charged-current and neutral-current diagrams in part (v), with their interference retained when the amplitude is squared.
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 305 3 d Solution 2026-10-03
The result grows linearly with the squared centre-of-momentum energy, . This growth eventually violates partial-wave unitarity and signals the breakdown of the pointlike Fermi interaction. At energies comparable to or , the full gauge-boson propagators must replace the contact interaction; the renormalizable electroweak theory then softens the high-energy behavior.
The negative muon emits a virtual and becomes a muon neutrino; the boson creates an electron and an electron antineutrino:Both vertices are weak charged currents.
Typical transfers satisfy , so the propagator factor expands as plus small corrections. Contracting this short-distance exchange produces the local Fermi interaction, with strength contained in . This effective description does not assume that the real W mass vanishes. The same treatment applies to leptonic tau decays with the relevant masses changed.[ref]
Review of Particle Physics by Particle Data Group (2022). Muon Decay Parameters, §57.1 introduction and §57.2
In GeV units, and . ThusThe modest difference from a precision experimental lifetime is expected from the rounded mass and omitted radiative and final-electron-mass corrections.
Use an inclusive spectator model: one heavy constituent decays through the Fermi interaction, and sum the open charged-current channels. In weak-decay channel counting, each massless final lepton pair gives basic widthA quark pair contributes three colors multiplied by its squared Cabibbo-Kobayashi-Maskawa matrix element. Do not multiply by three just because the initial quark has three colors: its lifetime is the width of one initial state, averaged over initial color when appropriate. Define
For the tau lepton, two leptonic channels contain an electron or a muon; light hadronic channels have or . ThereforeNo charmed hadron can be produced: the lightest charmed meson exceeds the tau mass. [ref]
Review of Particle Physics by Particle Data Group (2022). D-zero and D-plus listings, physical page 1 of each, masses 1864.84 and 1869.66 MeV
The supplied charm-quark parameter is not a free asymptotic final-particle mass. The leading count neglects electron and muon masses and light hadronic threshold effects.For the charm quark, and dominate. The emitted current has two light leptonic channels and the same light hadronic channels as above; a tau cannot be produced:
For the bottom quark, retain with the supplied and neglect the much smaller channel. The emitted current can produce three lepton flavors and two up-type quark families, with three colors for each family. In particular is open at the given masses, although suppressed by phase space. Counting each open channel as massless givesSetting Cabibbo sums to one recovers the familiar counts , and . Despite its larger mass, the bottom quark is slowed by its small interfamily mixing factor.
These are leading estimates rather than precise lifetimes of free quarks. confinement makes charm and bottom observable in hadrons, whose lifetimes involve spectator interactions, Quantum chromodynamics corrections and bound-state effects. mass corrections are significant for bottom: even the single-charm channel with massless leptons has the three-body weak-decay mass correctionTau and double-charm channels have different suppressions, so multiplying the entire width by this one factor is inconsistent. Accurate hadron lifetimes require those channel-dependent factors and hadronic dynamics; the exercise supports the explicitly stated leading counts.


