Past exam of the chemistry A course of the University of Cambridge 2025 Paper 1 A5 b Solution 2026-10-20
Write for the orthonormal atomic orbital on numbered site , with every positive lobe pointing along . A normalized set of symmetry-adapted linear combinations isEach has unit squared coefficient sum, and every distinct pair has zero inner product. The orbital representation therefore reduces to . For example, the fully symmetric site sum still has orbital symmetry because a orbital itself changes sign under operations that reverse . Ignoring that sign would assign the wrong representations.
The atomic orbital is spherically symmetric and has one radial node. A real atomic orbital has two lobes of opposite quantum phase, one atomic-orbital nodal plane through the nucleus and no radial node. The three spatial orientations remain degenerate in a spherically symmetric atom when external fields and fine structure are neglected.
In a many-electron atom, penetrates the screened core more effectively than , experiences a stronger attraction and is lower in energy: . The hydrogen-like ion degeneracy therefore does not survive screening. Both valence orbital types are generally more tightly bound and spatially contracted in nitrogen than in carbon, because of the larger effective nuclear charge. These are central-field orbital statements; the detailed atomic multiplet structure also involves electron repulsion and Hund's rules.
Take the bond axis as . The heavy-atom and atomic orbitals can mix with hydrogen to make three sigma-symmetry molecular orbitals. In the qualitative valence ordering, these are a low predominantly heavy-atom level, a bonding level and a higher level. The perpendicular orbitals form a degenerate approximately nonbonding pair because hydrogen has no valence orbitals of the matching sideways symmetry. The filled heavy-atom core is omitted from the diagram.
Counting valence electrons givesThus both exhibit paramagnetism: CH has one unpaired electron and NH has two in its ground state. For NH, Hund's rules favour separate parallel-spin occupation of the two degenerate orbitals. The corresponding observed ground terms are and ; the total bond order is approximately one in this simple sigma-bond/nonbonding-pi description.[ref]
NIST Chemistry WebBook, SRD 69. Methylidyne, CAS 3315-37-5, and Imidogen, CAS 13774-92-0: diatomic constants, ground-state rows
The nitrogen-derived orbital energies lie lower than the corresponding carbon-derived ones on an approximate common energy scale, while the isolated hydrogen reference is unchanged. The bonding orbitals consequently have different polarizations and mixing coefficients; drawing identical energies for C and N would miss the screening trend. The figure specifies ordering and occupancy, not measured gaps or a numerical prediction from (a).
Original qualitative valence molecular-orbital diagrams of CH and NH with one and two unpaired electrons
. Details. Two electrons can occupy a fully bonding orbital delocalized equally over all three hydrogen atoms. Three atomic orbitals on an equilateral triangle form one totally symmetric combination and a degenerate pair of higher orbitals. In an orthonormal equal-interaction model with diagonal energy and off-diagonal ,The lower orbital is proportional to , with constructive overlap along every edge. Its two electrons give a three-centre two-electron bond and equivalent interactions between every pair of nuclei. At the equilibrium distance, this bonding competes with nuclear Coulomb force to favour the symmetric triangular arrangement. The occupied shell is nondegenerate and closed, so there is no first-order Jahn-Teller incentive to distinguish the three edges. A straight-line or localized single-bond description would miss that equally shared bonding pattern.
carbon uses strong 2s/2p-derived covalent bonding, whereas retention or involvement of the low-energy Pb 6s pair distinguishes the two lead oxides. In CO, carbon has an approximately triple-bonded description with one carbon lone pair; the latter has substantial 2s character, while the sigma and two pi bonding combinations involve the valence shell, particularly carbon 2p orbitals for the pi bonds. In CO, carbon is formally in oxidation state +4 and its four valence electrons participate in two strongly covalent C=O double-bond frameworks. A localized account uses sp hybrids for sigma bonding and two p orbitals for the pi systems. oxidation states are bookkeeping devices here: neither molecule contains a bare C or C ion.
In PbO, the Pb(II) description removes or employs mainly the two 6p electrons, retaining a relatively low-energy 6s pair. In PbO, the Pb(IV) description additionally involves those two 6s electrons. The stabilization and poor availability of that pair underlie the inert-pair effect and the relative preference for Pb(II) chemistry. “Inert” does not mean that the 6s electrons have zero influence on bonding or shape: mixing with oxygen states and empty Pb states can make the Pb(II) lone pair stereochemically active. The more ionic formal electron counts in the lead oxides and the covalent molecular-orbital description of the carbon oxides are complementary models, not literal assignments of individual electrons to immutable atomic orbitals.[ref]
Carbon dioxide is linear, with two equivalent C–O bonds of formal bond order two; its Homo is predominantly oxygen nonbonding and its LUMO is C–O antibonding. The carbon uses two opposite hybrids for its sigma bonds and two perpendicular p atomic orbitals for pi bonding. A localized picture assigns each terminal oxygen an sigma/lone-pair framework and one p orbital for its local pi bond.
In a symmetry-adapted description, each of the two perpendicular sets of oxygen and carbon p functions forms bonding, oxygen-centred nonbonding and antibonding combinations. The occupied nonbonding pair is labelled and the lowest empty pi pair . The latter has appreciable amplitude at carbon, explaining its electrophilic reactivity. Hybridization of a terminal atom with only one bonded neighbour is a choice of localized basis, not an independently measurable bond angle; an alternative oxygen plus p basis can represent the same delocalized system.
There are 16 valence electrons: four in the two sigma bonds, four in the two net pi bonds, and eight in the remaining oxygen lone-pair combinations. These local electron counts and the delocalized orbital description are alternative bookkeeping schemes, not additional electrons.
The labels apply when the molecule has an inversion centre, as a homonuclear diatomic molecule does. The label means , and means , with the origin at that centre. In a heteronuclear diatomic molecule, inversion exchanges different atomic nuclei and these are generally not valid symmetry labels.
For the p-derived combinations above,Inversion both exchanges the two centres and changes the sign of each individual p atomic orbital. Applying both operations to each sum or difference gives these labels. The star denotes antibonding molecular orbitals, independently of parity: a bonding molecular orbital need not always be .
End-on overlap produces and molecular orbitals; side-on overlap produces and molecular orbitals. Matching signs of the facing atomic orbital lobes give constructive interference and a bonding molecular orbital. Opposite signs give destructive interference and an additional nodal plane between the atomic nuclei in the antibonding molecular orbital.
Take the internuclear direction as , and define both atomic functions as positive on their own right-hand side. Up to wavefunction normalization, the combinations areThe minus sign in the bonding combination follows from this common-axis quantum phase convention: the facing lobes of the two unmodified functions have opposite signs. It does not make that combination antibonding. Every molecular orbital also has a nodal plane containing the internuclear axis; the additional midpoint node distinguishes from .
There are valence electrons, all paired, so diazomethane exhibits diamagnetism. A localized orbital occupancy consistent with the double-bond construction in 2(c)(i) isHere mean central and terminal. Each listed occupied spatial orbital contains two electrons of opposite spin. The central N's two p atomic orbitals are perpendicular, so they can support the two perpendicular pi bonds. No central-N lone pair is left over: its positive formal charge accompanies four bonding pairs in this Lewis structure.
Allowing resonance mixes a terminal-N lone pair into the C–N–N orbitals. In the alternative terminal- basis, the same electron count is four occupied orbitals ( electrons), one terminal- lone pair (), one perpendicular N–N orbital (), and two occupied orbitals of a three-centre C–N–N system (). The -electron count and the paired ground state survive this change of description; the localized picture does not assert two perfectly isolated double bonds.
One consistent localized orbital hybridization description uses the Lewis structuresFor methyldiazonium, take C as and both N atoms as . For diazomethane, the double-bond resonance contributor suggests C as , central N as , and terminal N as . The central N uses two opposite hybrids for the linear C–N–N sigma bond framework. In the localized double-bond picture, terminal N uses one hybrid for its sigma bond, two for lone pairs, and its remaining p atomic orbital for a pi bond.
These labels specify an approximate bonding construction, not uniquely measurable atomic properties. An alternative representation takes terminal N as , with one lone pair and one p lone pair; the latter can participate in the delocalized C–N–N system. It describes the same resonance more explicitly. Neither construction requires an unpaired electron or a bent central N.
For the character of a localized orbital basis, take the trace of the transformation matrix: both permutation of centres and signs of atomic orbitals matter. The two metal centres lie on the principal axis and remain fixed under rotation about . At either metal the basis has the matrixThe full four-dimensional group representation is block diagonal with two such blocks. Consequently , and for the rotation of the D6h molecular point group, .
Fix the positive lobes of the real atomic orbitals along the printed positive axes, and write , , and . A coordinate model consistent with the figure is , , and , with . For the D2d molecular point group, take the two transverse twofold axes along and , with vertical mirrors and . The character table row on is . The character projection operator isThe eight signed images needed for this projection areso . Under the standard orthonormal atomic orbital approximation its squared norm is . Therefore the normalized symmetry-adapted linear combination isAn overall minus sign describes the same quantum state; changing one local atomic orbital phase requires changing its coefficient too. If intersite orbital overlap were retained, normalization would instead use the overlap matrix.
Treat the site atomic orbitals as orthonormal, as in the Hückel method. A normalized set of symmetry-adapted linear combinations isThe first combination is unchanged by every operation; the alternating combination has the transformation signs of for the printed axes. The last two transform together like . The squared coefficients sum to one in each case, and their pairwise inner products vanish. Any orthogonal rotation of the two combinations is an equally valid basis for that degenerate subspace.
Past exam of the condensed matter physics course of the University of Oxford 2022 4 d i Solution 2026-10-25
The given electron configuration has an inert closed core and two electrons. The Aufbau principle identifies the occupied subshells; the free-ion term within the open configuration is then selected by Hund's rules. A closed core contributes .
Each electron has orbital angular momentum quantum number . Place the two spins parallel, so . The Pauli exclusion principle then requires distinct orbital projections. The largest allowed total projection is , obtained from and , giving the maximum allowed . A larger would place two parallel-spin electrons in the same atomic orbital and is forbidden.
The subshell holds fourteen electrons; is less than half filled. The third of Hund's rules therefore selects . HenceThe term symbol uses and the spectroscopic letter for . The praseodymium ion retains an orbital contribution, so a spin-only estimate would be inappropriate.
A linear combination of atomic orbitals expands a crystal wavefunction in localized orbitals on all sites,Here labels the basis site, the retained atomic orbitals and . For the two-band model retain one relevant orbital on each B or N atom, usually the out-of-plane orbital, and neglect other orbital manifolds. Define normalized Bloch sums for cells,Then . Bloch periodicity puts the same two coefficients in every cell. We adopt the stated orthonormality, neglect longer-range hopping, and approximate the diagonal matrix elements by the supplied atomic energies . More generally the crystal environment shifts these on-site energies, so equality with isolated-atom expectation values is an additional tight-binding approximation.
For equal real nearest-neighbour transfer integral , this phase convention givesThe secular determinant is . ThusSince , this is the requested algebraic form. A hopping-sign convention or rephasing of the Bloch sums changes off-diagonal phases but not these eigenvalues. Explicitly,
The lower curve is a valence band and the upper curve is a conduction band, separated by an indirect band gap. The readable upper curve has a minimum just inside the X boundary and slightly below the plotted chemical potential. It is therefore partially occupied, while the visible valence states lie below the chemical potential and are filled at low temperature. The sample is electron-doped, with electron pockets around the six symmetry-related conduction minima of silicon.
The full high-symmetry path and part of the lower-left dispersion are absent from the held image. Source gap: those missing path labels and curve segments cannot be read or reconstructed from this copy. The identification of the conventional six silicon valleys and the valence maximum at uses the usual silicon band model, rather than purported readings of missing pixels.
Two methods for calculating such an electronic band structure are density functional theory, solving a self-consistent periodic electronic problem, and a tight-binding model, diagonalizing a hopping Hamiltonian built from localized atomic orbitals. Neither is a measurement of the plotted dispersion relation.
Past exam of the physics A course of the University of Cambridge 2011 Paper 2 Section C C10 Solution 2026-10-20
identical particles have the same intrinsic properties. Exchanging their bookkeeping labels cannot distinguish a physical preparation or change a measurable prediction. This is stronger than merely failing to track classical trajectories. For ordinary bosons and fermions, the many-particle wavefunction has respectively bosonic exchange symmetry or fermionic exchange symmetry under every particle exchange operator, acting on spatial and spin coordinates together. The Spin-statistics theorem connects integer spin to bosons and half-integer spin to fermions; this connection uses relativistic quantum-field assumptions, rather than following from the nonrelativistic Schrödinger equation alone.
For one-particle states satisfying orthonormality, the two alternatives form a quantum superposition:Its probability density contains an exchange interference term, absent from an incoherent mixture of labelled alternatives. The antisymmetric expression vanishes when both one-particle states are identical: one complete one-particle state can contain at most one fermion. This Pauli exclusion principle explains electron shell filling, the electronic Fermi sea and degeneracy pressure. Opposite spins are different one-particle states, so two electrons may share an atomic orbital. Spatially separated wave packets with negligible overlap can often be treated as distinguishable for local measurements; the underlying exchange symmetry remains.
In thermal equilibrium, occupation of a level of energy obeysbosons can accumulate macroscopically in one state, giving Bose-Einstein condensation; fermions instead fill successive states up to the Fermi energy at zero temperature. When occupation is dilute, both expressions reduce to the Maxwell-Boltzmann distribution. The identical-particle classical partition function contains , avoiding spurious entropy from permutations and the Gibbs paradox. Exchange effects become conspicuous when the thermal de Broglie wavelength is comparable to the interparticle spacing.
An operational test is the Hong-Ou-Mandel effect. Down-converted photon pairs enter separate ports of a balanced beam splitter; indistinguishable alternatives for one photon per output cancel. Scanning the relative arrival delay restores coincidences away from overlap. Matching polarization, spectral filtering and spatial alignment controls distinguishability; measuring delayed accidental coincidences controls background. The observed dip tests two-photon interference, and its finite depth must not automatically be interpreted as a failure of bosonic symmetry. The original apparatus varied beam-splitter position and subtracted a separately measured accidental background.[ref]
Measurement of Subpicosecond Time Intervals between Two Photons by Interference by C. K. Hong and others. pp. 2044–2046, Fig. 1, Eq. (2), coincidence-background procedure and Fig. 2
Addition of two spin-one-half angular momenta gives total spin or . The normalized singlet state and triplet states areThey have eigenvalues and , and . The singlet state is antisymmetric under a particle exchange operator, whereas all three triplets have symmetric spin-exchange parity. For two identical electrons the full state must be antisymmetric: a singlet state pairs with a spatial state with symmetric exchange parity, a triplet state with an antisymmetric spatial state. Thus two electrons in the same atomic orbital must form a singlet state.
The identity gives in the singlet state and in the triplet state. Hence an exchange interaction distinguishes their energies, with ordering determined by its coupling sign. The singlet state has perfect opposite-spin correlations along any common measurement axis and is entangled. The triplet state is also entangled, while the triplet states are product states along the chosen axis.
Past exam of the physics A course of the University of Cambridge 2016 Paper 1 Section C C10 Solution 2026-10-20
identical particles have the same intrinsic properties, including mass, charge and spin. Their labels are bookkeeping devices rather than measurable identities. When wave functions overlap, quantum mechanics supplies no observable trajectory that permanently identifies “particle 1” independently of “particle 2”. A many-particle description must therefore treat exchange consistently. The Hamiltonian and physical observables are invariant under relabelling identical particles.
For two particles, the exchange operator obeys . The usual three-dimensional symmetrization postulate selects states symmetric under exchange for bosons and antisymmetric for fermions. In relativistic quantum theory, the Spin-statistics theorem associates integer spin with bosons and half-integer spin with fermions under its locality and positivity assumptions; the connection is not derived merely from in elementary nonrelativistic mechanics. For orthonormal one-particle states and , the two-particle spatial combinations areThe sign concerns the complete state, including spin and other internal variables, not necessarily the spatial factor alone.
The antisymmetric state vanishes if both fermions occupy the same one-particle state: this is the Pauli exclusion principle. For fermions in orthonormal spin orbitals , the normalized Slater determinant supplies the required exchange sign. Bosonic occupation has no corresponding upper limit, and symmetrized products describe many bosons. Fermionic occupation is zero or one per complete one-particle state; two electrons can still occupy the same spatial atomic orbital with opposite spin.
Spin and spatial symmetry are linked. A two-electron spin singlet state is antisymmetric, so its spatial factor must be symmetric. A symmetric triplet state instead requires an antisymmetric spatial factor. Exchange then changes pair correlations and the energies available when interactions depend on particle separation, even without introducing a new classical “exchange force”. It contributes to atomic shell structure, bonding and magnetic behaviour.
Symmetric and antisymmetric two-particle spatial states have different joint-position correlations
. Source. Details. In an occupation-number description, bosonic creation and annihilation operators satisfy , whereas fermionic operators satisfy and anticommute among themselves. The latter imply . This formalism implements the same exchange constraints without assigning permanent particle labels.
For noninteracting particles in thermal equilibrium, the mean occupation of a state of energy isFermi-Dirac statistics produces a filled Fermi sea at zero temperature and degeneracy pressure; Bose-Einstein statistics permits macroscopic Ground state occupation when the density of available states and thermodynamic conditions allow condensation. The different statistics therefore have measurable collective consequences, not just different notation.[ref]
Statistical Physics by David Tong. Chapter 3, §§3.5–3.6: Bose and Fermi distributions, condensation and degenerate Fermi gases
When phase-space occupation is dilute, both distributions reduce to the Maxwell–Boltzmann statistics limit. Likewise, well-separated localized wave packets have negligible overlap and small exchange corrections, so effectively labelled classical trajectories can become a useful approximation. In two spatial dimensions more general exchange statistics are possible; the standard boson/fermion account here concerns ordinary three-dimensional particles and their total states.





