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An Abelian Chern--Simons theory describes topological gauge fields in two spatial dimensions and time. In units $\hslash =1$, its bulk action can be writtenwhere $a^I$ are compact Abelian gauge field one-forms, $\wedge$ is the wedge product of differential forms, and the K-matrix is symmetric, integral and invertible. This supplies a long-distance description of gapped Abelian quantum Hall states. ^[ref]

A quasiparticle labeled by an integer vector $q$ couples to the corresponding combination of gauge fields. The full encircling phase of charges $q,q^{\prime }$ isThus global particle paths can carry measurable braiding information even though the pure bulk action has no metric-dependent local wave term. Boundaries require their own treatment; the bulk formula alone does not specify every allowed boundary condition.

For a smooth one-form $A$, the components ${\partial }_a{A}_b-{\partial }_b{A}_a$ transform as a covariant rank-two tensor. The non-tensorial second derivatives in the ordinary covector derivative under nonlinear coordinate changes are symmetric in $a,b$ and cancel. For a torsion-free connection the same components are ${\nabla }_a{A}_b-{\nabla }_b{A}_a$. This is the coordinate expression of $dA$, without choosing a metric.

The pure Abelian Chern--Simons theory has zero metric stress. For a source written as $-c\int \star J\wedge A$, holding the covariant components of the one-forms $J,A$ fixed makes the source equal to $-c\int \sqrt{-g}{g}^{\mu \nu }{J}_{\mu }{A}_{\nu }{d}^{3}x$. Variation using $\delta \sqrt{-g}=-\sqrt{-g}{g}_{\mu \nu }\delta g^{\mu \nu }/2$ gives the displayed stress-energy tensor. If the independent source is instead the fixed two-form $\mathcal{J}=\star J$, the source action is metric-independent and its stress vanishes. The variational data must therefore be stated.

Write a local frame of a rank-$r$ vector bundle as the row $e=(e_1,\dots ,e_r)$. The connection one-form of a connection on a vector bundle is the matrix of one-forms $A$ determined byThe placement of $A$ matters: its entry $A^i{}_j$ is the coefficient of $e_i$ in $\nabla e_j$. If $e^{\prime }=eg$, substitution in the Leibniz rule givesThe derivative term means that $A$ is not itself a global endomorphism-valued one-form. The curvature form $F=dA+A\wedge A$ instead changes by $F^{\prime }=g^{-1}Fg$, and the difference of two connections on a vector bundle has the same homogeneous change law. These formulas fix the row-frame convention consistently.

Contact topology studies global properties of contact structures on odd-dimensional smooth manifolds. Locally such a structure is a hyperplane distribution $\xi =\ker \alpha$ with $\alpha \wedge (d\alpha {)}^n$ nowhere zero in dimension $2n+1$. Multiplying $\alpha$ by a nowhere-zero function leaves the hyperplane distribution unchanged: the structure is the field of hyperplanes, not a preferred one-form.^[ref]

In ${\mathbb{R}}^3$, take $\alpha =dz-ydx$. Then $d\alpha =dx\wedge dy$ and $\alpha \wedge d\alpha =dz\wedge dx\wedge dy\ne 0$. The spanning vector fields ${\partial }_x+y{\partial }_z$ and ${\partial }_y$ have Lie bracket $-{\partial }_z$, outside the distribution. Thus the planes cannot be tangent to a foliation by surfaces. The local normal form is universal, while global topology distinguishes contact structures and constrains their relation to symplectic geometry.

For a codimension-one tangent distribution, a coorientation is an orientation of its normal quotient line bundle. An oriented real line bundle is trivial: local positive sections can be combined with a partition of unity without cancellation. Hence a cooriented distribution is the kernel of a global nowhere-vanishing one-form. This choice is independent of the orientation of the ambient manifold, and reversing it does not change the Godbillon-Vey invariant.

The untwisted skew-symmetric Courant bracket on sections of the generalized tangent bundle $TM\oplus T^{\ast }M$ isHere $[X,Y]$ is the Lie bracket of vector fields, $\mathcal{L}$ is the Lie derivative, and $d$ is the exterior derivative. It extends the Lie bracket of vector fields, but its Jacobi identity has an exact-form defect; it is not simply another Lie algebra bracket.^[ref]

For pure vector fields, $[X,Y{]}_C=[X,Y]$, and two pure one-forms have zero bracket. On the real line, $[{\partial }_x,f(x)dx{]}_C=\frac{1}{2}{f}^{\prime }(x)dx$. This mixed example shows how the bracket couples tangent and cotangent information through differentiation. Omitting the final exact term gives the nonskew Dorfman operation, a related convention with different identities.

A differential form is a smooth field of alternating multilinear maps that can be integrated over an appropriately oriented manifold of matching dimension. A one-form measures a directed displacement; a two-form measures an oriented area element. The point is to express what is being accumulated along a curve or over a surface without tying the answer to one set of coordinates. This makes line integrals, surface integrals, and the integral theorems of vector calculus parts of one construction.

For a concrete one-form, take $\alpha =xdy$ in the plane. Travel from $(0,0)$ to $(1,1)$ along the bottom and then the right edge of the unit square. The horizontal leg contributes zero because $dy=0$; the vertical leg has $x=1$ and contributes ${\int }_0^{1}dy=1$. Taking the left and then the top edge instead gives zero: the vertical leg has $x=0$, and the horizontal leg again has $dy=0$. The two paths have the same endpoints but different integrals.

Now replace $\alpha$ with the exact differential $\beta =d(xy)=ydx+xdy$. Both paths give $1$, because integrating an exact differential along a curve gives the endpoint difference of its potential. Here that difference is $xy{|}_{(1,1)}-xy{|}_{(0,0)}=1$. This is the fundamental theorem of calculus applied to a function along a parametric curve, and is the basic reason conservative vector fields have path-independent work.

The exterior derivative records the local obstruction in the first example: $d(xdy)=dx\wedge dy$. The Generalized Stokes theorem turns the difference between the two path integrals into the integral of this two-form over the square, whose oriented area is $1$. Interior edges cancel when adjoining pieces are added; only the outer boundary survives. That cancellation connects a local calculation with a global measurement.

More precisely, a degree-$k$ differential form assigns to each point $p$ a multilinear scalar-valued function of $k$ tangent vectors at $p$. Interchanging two arguments changes its sign. A one-form is therefore a covector field, while a two-form vanishes on a pair of parallel vectors. Degree zero simply means a smooth function. The space ${\Omega }^k(M)$ is a vector space; the wedge product of differential forms combines degrees, and the exterior derivative raises degree by one.

The usefulness goes beyond bookkeeping. Pullbacks of a differential form supply the right transformation law automatically under a coordinate change. The Generalized Stokes theorem unifies the fundamental theorem of calculus, Green theorem, Stokes theorem, and divergence theorem. Meanwhile, the distinction between closed differential forms and exact differential forms detects holes through de Rham cohomology. Reyer Sjamaar develops these connections in sections 5.4 and 9.3 of his university notes. ^[ref].

For the Levi-Civita connection of a Riemannian metric, the divergence of $X$ is ${\mathrm{div}}_{g}X=\mathrm{tr}(Y\mapsto {\nabla }_{Y}X)$. In coordinates it equals $(\det g{)}^{-1/2}{\partial }_i((\det g{)}^{1/2}{X}^i)$. On an oriented manifold it satisfies ${\mathcal{L}}_X{\omega }_g=({\mathrm{div}}_{g}X){\omega }_g$. The codifferential on a one-form satisfies $\delta \theta =-{\mathrm{div}}_g({\theta }^{♯})$, where $♯$ is the musical isomorphism; this follows by integration by parts or the Hodge star formula.

The exterior derivative is the unique graded derivation $d:{\Omega }^p(M)\to {\Omega }^{p+1}(M)$ that agrees with the differential on functions and satisfies $d^2=0$.

On a smooth planar one-form $\alpha =Pdx+Qdy$, the product rule and antisymmetry of the wedge product of differential forms giveFor $\alpha =xdy$, the coefficient is $1$: there is a nonzero integral around the boundary of every positively oriented rectangle. For $\beta =d(xy)$, the coefficient is ${\partial }_{x}x-{\partial }_{y}y=0$. More generally, the identity $d^2=0$ makes every exact differential form a closed differential form. It expresses cancellation between mixed partial derivatives locally; it does not imply that every closed differential form has a global potential.

A constant-rank smooth distribution $D$ is an integrable distribution exactly when it is involutive. In differential-form language, let ${\alpha }^1,\dots ,{\alpha }^q$ be a local basis of its annihilator, so $D={\bigcap }_i\ker {\alpha }^i$. The equivalent condition isfor suitable local one-forms ${\beta }^i{}_j$. More precisely, the ideal generated by the annihilating forms inside the exterior algebra of differential forms is closed under the exterior derivative; this is an exterior differential ideal. It is not a claim that a two-form lies in the one-form annihilator itself.

For local vector fields $X,Y$ tangent to $D$, the definition of exterior derivative givesThus the displayed closure condition says exactly that the Lie bracket of vector fields remains tangent to $D$. The theorem turns this local algebraic condition into integral manifolds through every point.

For a nowhere-zero one-form $\alpha$, its kernel is tangent to local hypersurfaces precisely when $\alpha \wedge d\alpha =0$. In general relativity, applying this to a metric-dual one-form characterizes hypersurface orthogonality and vanishing twist.

Fix a complex line bundle with a Hermitian metric over a closed oriented Riemannian manifold $X$. For a unitary connection $A$, the real curvature form $i{F}_A$ represents a fixed de Rham cohomology class. The Hodge theorem gives its unique harmonic representative $\eta$. Write $\eta -i{F}_A=d\beta$ with $\beta$ a real one-form. Then $A-i\beta$ is a unitary connection with real curvature form equal to $\eta$.

Two such unitary connections differ by a closed imaginary-valued one-form. A gauge transformation removes exactly those differences whose real periods lie in $2\pi \mathbb{Z}$. Their classes under gauge equivalence of principal connections carry a free transitive action ofwhere the integral cohomology is understood through its image in real cohomology. If the first Betti number is zero, there is just one such equivalence class. The compactness assumption supplies the Hodge theorem used here.^[ref]

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The graph of a one-form $\alpha$ on a smooth manifold $Q$ is a Lagrangian submanifold of its cotangent bundle exactly when $d\alpha =0$. Indeed the graph pulls the tautological one-form back to $\alpha$, and therefore pulls the canonical symplectic form back to $-d\alpha$. Locally the Poincaré lemma writes $\alpha =dS$, giving $p_i={\partial }_{i}S$. Globally a closed one-form may have nonzero periods and no single generating function.

Let $X$ be a smooth vector field with local flow ${\varphi }_t$. The Lie derivative of a differential form isPulling back before taking the derivative compares forms in the same cotangent space. The Lie derivative of a differential form preserves degree and obeys the Leibniz rule for the wedge product of differential forms.

Cartan's magic formula expresses it using two intrinsic operations:where $d$ is the exterior derivative and ${\iota }_X$ is the interior product. In particular, it commutes with the exterior derivative.

On the real line, $X=x{\partial }_x$ has local flow ${\varphi }_t(x)=e^{t}x$. Hence ${\varphi }_t^{\ast }dx=e^{t}dx$ and ${\mathcal{L}}_{X}dx=dx$. The vector field vanishes at zero, but its differential still stretches the one-form there. For a volume form $\omega$, the equation ${\mathcal{L}}_X\omega =0$ defines a volume-preserving vector field.

On the punctured plane, this one-form is closed and locally the differential of the polar angle. Its line integral around a closed curve is $2\pi$ times the winding number. A once-winding circle therefore has nonzero integral, proving that no global single-valued angle potential exists and the form is not an exact differential form.

For a counterclockwise circle of radius $R>0$, substitute $x=R\cos t$, $y=R\sin t$. The pullback of a differential form isThe radius cancels. In coordinates, $P=-y/(x^2+y^2)$ and $Q=x/(x^2+y^2)$ satisfy ${\partial }_{x}Q={\partial }_{y}P$ away from the origin, so $d\omega =0$ there. The nonzero integral is a global obstruction to being an exact differential form, not a nonzero local exterior derivative.

Compare this with the smooth one-form $\eta =(-ydx+xdy)/2$ on the whole plane. Here $d\eta =dx\wedge dy$, and its integral around a radius-$R$ circle is $\pi R^2$, the enclosed area. The Generalized Stokes theorem applies to the full disc for $\eta$. For $\omega$, that disc crosses the excluded origin, where the one-form is undefined. On an annulus the theorem applies, but its induced inner boundary is clockwise: the two integrals $2\pi$ and $-2\pi$ cancel. This explains exactly why closedness and nonzero circulation can coexist.

A differential 1-form is a smooth section of the cotangent bundle; it assigns a covector to every point of a smooth manifold. In planar coordinates, $\alpha =P(x,y)dx+Q(x,y)dy$ evaluates a tangent vector $v$ as $P(x,y)v_x+Q(x,y)v_y$.

Along a parametric curve $\gamma (t)=(x(t),y(t))$, its line integral isReversing the direction reverses the integral. A force expressed as a one-form therefore accumulates work along a directed path. In Euclidean coordinates its components can be displayed as arrows, but identifying a one-form with a vector field uses an inner product; the covector field itself does not require a Riemannian metric.

Let $A_b^{\prime }=J^d{}_b{A}_d$, where $J^d{}_b=\partial x^d/\partial x^{\prime b}$. ThenThe second term prevents the ordinary derivative from being a generally covariant tensor. It vanishes for affine coordinate changes, including Cartesian Lorentz transformations, so the restricted claim of Lorentz covariance is valid. Antisymmetrization cancels the same term for arbitrary smooth coordinate changes and gives the exterior derivative of a one-form.

Choose a basis $T_a$ of the Lie algebra, with $[T_b,T_c]=c^a{}_{bc}{T}_a$. On the Matrix Lie group setLeft multiplication by a constant matrix preserves $\lambda$, while right multiplication preserves $\rho$. Differentiating $g^{-1}g=I$ gives $d(g^{-1})=-g^{-1}(dg)g^{-1}$. Apply the graded Leibniz rule to obtainBecause the wedge product antisymmetrizes the matrix products, these Maurer-Cartan equations becomeFollow the vector-field naming used in the question: $L_a(g)=T_{a}g$ is right-invariant and generates left multiplication, whereas $R_a(g)=g{T}_a$ is left-invariant and generates right multiplication. They are dual to ${\rho }^a$ and ${\lambda }^a$, respectively. For any one-form $\eta$, $d\eta (X,Y)=X(\eta (Y))-Y(\eta (X))-\eta ([X,Y])$. Evaluating the two Maurer-Cartan equations on the corresponding invariant fields yieldsFor the last identity, the left and right multiplication flows commute. The opposite sign for the right-invariant vector fields is therefore intrinsic; the letters attached to the two families are only a convention.

Use ${\iota }_{X_f}\omega =df$ and $\{f,g\}=\omega (X_f,X_g)$. For an actual infinitesimal left Lie group action, define ${\xi }_P(p)={\frac{d}{dt}|}_0\exp (t\xi )\cdot p$. Its fundamental vector fields obey $[{\xi }_P,{\eta }_P]=-[\xi ,\eta {]}_P$ with this convention.

Existence and its global obstruction. Preservation of the symplectic form gives ${\mathcal{L}}_{{\xi }_P}\omega =0$. By Cartan's magic formula, ${\iota }_{{\xi }_P}\omega$ is closed. Locally it equals $d{\mu }_{\xi }$; globally this requires its class in $H_{\mathrm{dR}}^1(P)$ to vanish. If it does for every $\xi$, choose potentials linearly in $\xi$ and defineThis gives the component Hamiltonians of a weakly Hamiltonian action. The assumption in the question does not alone guarantee a global moment map: on $T^2$ with $\omega =dx\wedge dy$, translation in $x$ preserves $\omega$, but its contraction is $dy$, whose integral around the $y$ circle is nonzero. It is not an exact one-form. Thus no global real-valued component Hamiltonian exists for that circle action. The intended construction is valid locally, or globally with this exactness condition, for example if $H_{\mathrm{dR}}^1(P)=0$.

Matching the Lie algebra. On each connected component, the moment-map equivariance obstruction is the constantIndeed, the identities $[X_f,X_g]=-X_{\{f,g\}}$ and $[{\xi }_P,{\eta }_P]=-[\xi ,\eta {]}_P$ show that its differential vanishes. The Jacobi identity for the Poisson bracket saysChanging ${\mu }_{\xi }$ by a linear constant $b(\xi )$ changes $c$ to $c-b([\xi ,\eta ])$. Consequently the necessary and sufficient infinitesimal condition is the cocycle must be a coboundary, so that the constants can be chosen withEquivalently its class in $H^2(\mathfrak{g},\mathbb{R})$ vanishes. For a connected group this infinitesimal equivariance integrates to equivariance under its coadjoint action. A disconnected group can impose additional conditions. Here “coincides” means representing the specified Lie brackets; it does not guarantee injectivity when the group action has ineffective generators.

Proof using the Killing form. A nondegenerate Killing form $B$ makes $\mathfrak{g}$ semisimple. First, it is perfect: the $B$-orthogonal complement of $[\mathfrak{g},\mathfrak{g}]$ is the center by invariance, and the center is zero by nondegeneracy. For symplectic fields,by Cartan's magic formula and the antihomomorphism sign. Every commutator therefore has an exact contraction. Perfectness supplies component Hamiltonians for every generator, even when $P$ is not simply connected: this is Hamiltonian existence for a semisimple symplectic action.

It remains to eliminate the cocycle, not merely to name an existence theorem. Define a linear operator $D$ on $\mathfrak{g}$ by $B(D\xi ,\eta )=c(\xi ,\eta )$. Antisymmetry of $c$ makes $D$ skew for $B$. Combining its cocycle identity with invariance of $B$ givesChoose $Z\in \mathfrak{g}$ by $B(Z,\xi )=\mathrm{tr}(D{\mathrm{ad}}_{\xi })$, possible because $B$ is nondegenerate. Since $D$ is a derivation, $[D,{\mathrm{ad}}_{\xi }]={\mathrm{ad}}_{D\xi }$. Cyclicity of the matrix trace then givesThus $D={\mathrm{ad}}_Z$, and $c(\xi ,\eta )=B(Z,[\xi ,\eta ])$. Taking $b(\xi )=B(Z,\xi )$ removes $c$, proving the required condition. This applies to semisimple Lie groups, including $SU(n)$ for $n\ge 2$, $SO(3)$ and $SL(n,\mathbb{R})$ for $n\ge 2$. It is nondegeneracy, not positive definiteness, that matters. Groups with a nonzero central Lie algebra, such as $U(3)$, do not satisfy this Killing-form criterion, although particular actions can still have equivariant moment maps.

The isotropic oscillator. On $T^{\ast }{\mathbb{R}}^3$, putThe action $z\mapsto Uz$, $U\in U(3)$, preserves the Hermitian norm and the symplectic form, and therefore preserves $H$. A Hermitian matrix $A$ parametrizes the Lie algebra generator $\xi =-iA$. Its unitary moment map of an isotropic oscillator isSince $\{z_j,{\bar{z}}_k\}=-i{\delta }_{jk}$, direct differentiation yieldsThe matrix $-i[A,B]$ is Hermitian and corresponds precisely to $[{\xi }_A,{\xi }_B]$; no central defect remains. The full moment map can be identified, using the pairing with Hermitian matrices, with the rank-one matrix $z{z}^{†}$. The central generator $A=I$ gives ${\mu }_I=H$, whose flow is $z(t)=e^{-it}z(0)$. Globally $U(3)=(SU(3)\times U(1))/{\mathbb{Z}}_3$, so the “$U(1)$ factor” refers to this central circle, rather than a literal direct-product decomposition.

The real orthogonal subgroup acts geometrically by $(x,p)\mapsto (Rx,Rp)$, the cotangent lift of a diffeomorphism of ${\mathbb{R}}^3$. If $K$ is real antisymmetric and $A=iK$, then ${\mu }_A=-x^{T}Kp$. For $Kv=\Omega \times v$, this is $\Omega \cdot (x\times p)$, so its three components are the usual angular momentum $L_i={ϵ}_{ijk}{x}_j{p}_k$.

The remaining six independent Hermitian directions can be taken as real symmetric matrices. Their moment functions spanThe diagonal ones are the individual oscillator energies; their sum is $H$. The off-diagonal ones correlate two oscillator modes. Their flows mix positions and momenta and are not cotangent lifts of the obvious spatial rotation action: for a real symmetric $A$, $\dot{x}=Ap$ and $\dot{p}=-Ax$, rather than $\dot{x}=Kx$, $\dot{p}=Kp$. All nine quadratic functions commute with $H$, since the entire unitary group action preserves the oscillator Hamiltonian.

Let $\mathcal{J}=\star J$ be the current $(d-1)$-form on an oriented $d$-dimensional spacetime. For a slab bounded by two spacelike hypersurfaces ${\Sigma }_1,{\Sigma }_2$ and a side boundary $B$, the Stokes theorem givesThus $Q(\Sigma )={\int }_{\Sigma }\mathcal{J}$ is conserved if the side flux vanishes, for example for a spatially compact current or appropriate falloff at infinity. With side flux it instead obeys the corresponding charge-balance equation. This is the differential-form version of current conservation.

For the Abelian Chern--Simons theory, take $A\mapsto A+d\chi$ with a smooth compactly supported gauge parameter. The change in the gauge-field term is a boundary term because $d\chi \wedge dA=d(\chi dA)$. For the source,Discarding the boundary terms, the action variation isGauge invariance for every such $\chi$ and $c\ne 0$ therefore gives $d\star J=0$. If $c=0$, the current decouples and gauge invariance places no condition on it. On a spacetime with boundary, boundary conditions or boundary degrees of freedom are also needed to handle the discarded terms; on a nontrivial compact gauge bundle, large-gauge invariance is an additional global issue.

For the field equation, useThe one-form $\delta A$ commutes with the two-form $\mathcal{J}$ under the wedge product, soup to the boundary term. ConsequentlyApplying $d$ and using $d^2=0$ again gives current conservation for $c\ne 0$. The factor two comes from varying both occurrences of $A$.

Orient a spatial region $D$ so its boundary is $\gamma$, and define $Q_D={\int }_D\mathcal{J}$. Applying Stokes theorem and the field equation yieldsFor a U(1) connection, in a convention with unit minimal charge, the gauge-invariant quantity is its holonomy $e^{i\Phi }$, the Wilson-loop or Aharonov-Bohm phase. A large gauge transformation can change the chosen representative of $\Phi$ by $2\pi n$. Therefore $\Phi$ is a phase angle modulo $2\pi$, rather than an absolute gauge-invariant real number. A particle of charge $q$ has phase $e^{iq\Phi }$ in the corresponding normalization. The flux-charge relation thus attaches a gauge phase to enclosed charge.

The metric variation requires specifying the independent source. The pure Chern-Simons term $A\wedge dA$ has no metric dependence, hence contributes zero stress-energy tensor. If the one-forms named in the question have fixed covariant components $A_{\mu },J_{\mu }$, the Hodge star in the source does depend on the metric:Using $\delta \sqrt{-g}=-\sqrt{-g}{g}_{\mu \nu }\delta g^{\mu \nu }/2$ givesUnder that literal fixed-one-form convention,There is another common convention in the topological source theory: hold the conserved two-form $\mathcal{J}=\star J$, equivalently the vector current density, fixed as the metric varies. Then both $A\wedge dA$ and $\mathcal{J}\wedge A$ are metric-independent, and $T_{\mu \nu }=0$ for this action. These are different variations, not contradictory calculations. The Chern-Simons source stress convention explains why a source prescription is necessary; a dynamical matter source would contribute its own action and stress as well.