The vector field has zero curl away from its excluded axis, but has circulation around a positively oriented circle enclosing that axis. Stokes theorem gives zero total circulation for a smooth annular surface avoiding the axis, whose inner and outer boundary circles have opposite orientations. It cannot be applied directly to a disk meeting the axis, because the field is undefined there.
Boundary orientation Created 2026-09-24 Updated 2026-10-03
An orientation of a surface induces the boundary direction used in Stokes theorem. Walking in the positive boundary direction keeps an upward-oriented surface on the left.
For a smooth map between oriented connected closed manifolds of the same dimension, a normalized volume form on the target gives . The formula agrees with the degree as a sum of local degrees. A change of normalized top-form adds an exact form by top-dimensional de Rham cohomology, whose pullback has zero integral by Stokes theorem.
The coupling integrates the pullback of the two-form gauge field over the string worldsheet. Its gauge variation is , by Stokes theorem. It therefore vanishes for a closed worldsheet, while an open surface requires suitable boundary fields or boundary-state transformations.
On an oriented boundaryless Riemannian manifold, apply Stokes theorem to the compactly supported form . The graded Leibniz rule gives . The Hodge star operator identifies these top forms with the scalar integrands displayed above. This proves that the codifferential on one-forms is , the formal adjoint of the exterior derivative. Compact support of suffices.
On a compact complex surface, the claim also holds without a Kähler metric. For a holomorphic one-form , let . It is a closed holomorphic two-form, and the Stokes theorem gives . Positivity of forces . Functions are constant on each connected component, and holomorphic two-forms are closed by dimension.
With zero cosmological constant and the component Hodge star operator convention , the Einstein field equations and Killing equation give . If is tangent to a spacelike hypersurface, the trace term pulls back to zero. For , Stokes theorem yields
The inner Komar charges cannot be dropped for a vacuum Kerr black hole, whose angular momentum is nonzero although its stress-energy tensor vanishes. A matter-only volume formula requires a regular filling with no inner boundaries.