Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 62 2 c Solution Created 2026-10-03 Updated 2026-10-14
Vary the scalar field with compactly supported variation, leaving the metric tensor fixed. The action variation isIntegration by parts moves the derivative from and gives the Euler-Lagrange equationFor the FRW metric, , so the covariant wave operator becomesRearranging gives the requested scalar field evolution:The damping term is Hubble friction; it comes from the expanding volume factor , not from a microscopic dissipative force.
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 62 2 d Solution Created 2026-10-03 Updated 2026-10-14
For a homogeneous scalar field, every spatial derivative vanishes. The stress-energy tensor consequently has no momentum density or directional stress:The only spatial tensor left is , so the stress is isotropic. This is the perfect fluid form in its comoving frame. Now expand the time component of stress-energy conservation using the covariant derivative:The first term is . In the second, only contributes, and , giving . The third isHere the quoted Christoffel symbols include their lower-index symmetry . Therefore the cosmological continuity equation isAs a check using the scalar field equation, , with exactly the same sign.
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 62 2 e Solution Created 2026-10-03 Updated 2026-10-14
With zero scalar potential and a homogeneous scalar field, the preceding perfect fluid identification givesThis equation of state is that of a stiff fluid. The field equation integrates to , since . Hence , agreeing with the cosmological continuity equation for . If this nonzero component dominates a flat universe, the Friedmann equation giveson the expanding branch. Integrating once more, . Choosing the Big Bang at yieldsThe homogeneous free scalar as a stiff fluid construction requires ; a constant zero-potential field has zero energy density and cannot dominate this expansion.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 46 1 Solution Created 2026-10-03 Updated 2026-10-14
Use target signature and worldsheet signature . The Polyakov action has local worldsheet diffeomorphism and Weyl invariance, together with global target-space Poincaré symmetry. Under a worldsheet coordinate change , the embedding coordinates are scalars and the worldsheet metric is a tensor:A Weyl transformation acts as and leaves unchanged. In two dimensions scales by and by , so the action is invariant. Target translations act by , and Lorentz transformations by with ; they leave unchanged. Infinitesimally the latter have , where .
Locally, the two diffeomorphism functions put the metric into the form , and Weyl invariance removes the conformal factor. In this conformal gauge, the embedding coordinates are free scalar fields and satisfyThe metric equation must still be imposed after gauge fixing. Varying the ungauged metric gives the worldsheet stress-energy tensor constraintWith a dot and prime denoting the two coordinate derivatives, the independent Virasoro constraints areequivalently . Local conformal gauge leaves residual conformal transformations; on general worldsheet topologies it also leaves global moduli, rather than removing all metric information.
For target translations, differentiation of the Lagrangian with respect to gives the Noether currentThe embedding equation is . In conformal gauge, , so integration over the closed string givesPeriodic boundary conditions make its time derivative vanish. For an infinitesimal Lorentz transformation, the antisymmetric coefficient of gives the current . Its divergence vanishes because the remaining product of embedding derivatives is symmetric in . Thus the Noether charge isThese are the target-space Noether charges of a string.
For the circular solution take , and let and . Its derivatives areEach spatial coordinate has equal second derivatives in and , while the time coordinate has both second derivatives zero. Furthermoreso both the field equations and the Virasoro constraints hold, including the collapse instants.
At target time , the string is a circle in the plane of radius . It contracts from radius to zero and re-expands; the negative cosine reverses material labels by a half-turn rather than creating a negative radius. The spatial configuration repeats after target time . This is a pulsating circular string. Its induced metric degenerates at collapse, but the conformal-gauge embedding and constraints give its continuation.
The integrals of and vanish, so the momentum isThe spatial velocity is radial, giving zero angular momentum density in the plane; all boost-charge terms integrate to zero as well. Hence for every pair of indices.
At maximum expansion, all string elements are instantaneously at rest, and the length is . Thus the rest mass per unit length, equal to the string tension, isAt other times the instantaneous circumference is , and the elements have speed . Their Lorentz factor is , so the energy remains . The rest-energy density is ; the total rest-frame energy divided by the changing circumference is not constant. This distinguishes the requested intrinsic mass density from the larger energy density of moving string elements.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 46 4 Solution Created 2026-10-03 Updated 2026-10-14
The string nonlinear sigma model regards the target-space metric, the Kalb–Ramond field and the dilaton as couplings of the two-dimensional worldsheet theory. Schematically its Euclidean terms areQuantization produces running background couplings and a possible worldsheet Weyl anomaly. Gauge-fixed matter bosons contribute central charge , while the reparameterization bc ghost system contributes in each chirality. In the critical flat background cancellation therefore requires . In a curved background, vanishing improved sigma-model beta functions further imposes field equations for . For example, the leading metric condition isThese are spacetime conditions because the couplings are functions of the embedding coordinates, not additional worldsheet coordinates.
The leading equations arise by varying the string-frame massless effective actionThe factor is the sphere contribution in the string genus expansion. Higher sigma-model orders generate higher-derivative terms in the expansion; higher genera give string-loop corrections. Thus conformal consistency of the quantum worldsheet determines the low-energy target equations and their action. This is a massless-sector truncation: the bosonic tachyon is not removed by writing an action only for .
For a brane embedding , the D-brane worldvolume pullbacks areThe dilaton is evaluated at the embedding. When denotes the physical tension in a background with constant mode , the convention is , so in that vacuum. Equivalently one can use and a coefficient with the constant not already included. The physics is the same; the two conventions must not count that constant factor twice.
Several features motivate the Dirac-Born-Infeld action. Without gauge or two-form fields, it is the relativistic induced-volume action for a tensionful extended object. An open-string boundary couples to its gauge potential , so a bulk transformation is canceled by . Thus only can enter. For slowly varying constant field strength, the open-string disk partition function resums its dependence into the determinant; expansion gives the Maxwell kinetic term. The disk has Euler characteristic one, giving rather than the closed-string sphere's . Worldvolume covariance and the induced metric then combine these ingredients into the determinant expression.
Explicitly, in flat background and static gauge with transverse fluctuations , the weak-field expansion starts asThe linear term in the antisymmetric matrix vanishes; the quadratic term follows from expanding . Thus the DBI action contains both the scalar and gauge kinetic energies, while higher powers and derivatives are string-scale corrections.
For two coincident D-branes, an oriented open string has independent labels at its ends. Its Chan-Paton factors are the matrix units . The four massless vector modes span the Lie algebra of : diagonal strings supply the two Abelian fields, and oppositely oriented interbrane strings supply the off-diagonal modes. Joining strings multiplies these matrices, producing the non-Abelian commutators. Transverse vector polarizations become adjoint scalar fields. This is Coincident-D-brane gauge enhancement.
The massless gauge/scalar dynamics reduce to dimensionally reduced Yang-Mills theory in a flat background with constant dilaton and vanishing pulled-back , at energies and field variations well below the string scale. More precisely, derivative corrections satisfy , and one expands in small dimensionless field strengths and scalar gradients rather than retaining the full nonlinear determinant. Weak string coupling suppresses loop corrections. After subtracting the constant brane vacuum energy and using the scalar normalization fixed below, the coefficient isA bosonic brane additionally has an open-string tachyon; the displayed action governs its massless sector and is not a stable complete truncation. For supersymmetric branes the corresponding leading action also has the massless fermions.
There is a sign qualification in the printed scalar potential. With the stated , take Hermitian and to mean the literal matrix product. Then dimensional reduction hasConsequently . The consistent low-energy action isThis is the Hermitian commutator potential in D-brane Yang-Mills theory. Its potential energy is , because a Hermitian-matrix commutator is anti-Hermitian. For a concrete check, take , with Pauli matrices. Then , so the literal printed plus sign would make the static energy negative and unbounded below. The printed plus sign is consistent only if its square denotes the positive norm , rather than a literal square. The gauge-boson mass calculation below uses the unambiguous kinetic terms.
In an ordinary separated-brane vacuum the scalar expectation values commute and can be simultaneously diagonalized:Their eigenvalue vectors specify the transverse positions, up to the normalization to be determined. The trace encodes the center of mass; their difference encodes separation. When the two vectors coincide, every transformation commutes with the vacuum. When they are distinct, only independent diagonal phases do, so the unbroken group is . The off-diagonal vectors acquire mass by the Higgs mechanism.
Write the off-diagonal entries of as and and put . At a constant diagonal vacuum, , soThe quadratic off-diagonal gauge kinetic term is with , and the scalar kinetic term supplies . Comparing these with the complex massive-vector action givesHere the term W-boson means this broken-generator vector, not specifically an electroweak particle. The normalization places the gauge coupling outside the action, so no extra multiplies these ; rescaling to canonically normalized scalar fields moves that coupling into the usual Higgs mass formula.
The corresponding open-string vector oscillator stretched over distance has classical stretching mass . Its unstretched mass contribution vanishes because it is the vector level, rather than the bosonic tachyon level. Equating it with the gauge-theory mass givesThe component relation follows by rotational covariance and a common choice of transverse origin; a uniform translation adds the same constant to both brane coordinates. This is the D-brane scalar-position normalization. Together with the string tension determined in Question 1, it fixes the exact normalization of scalar eigenvalues as brane positions.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 58 5 Solution Created 2026-10-03 Updated 2026-10-14
Let a dot denote differentiation with respect to an affine geodesic parameter . The five-dimensional geodesic Lagrangian isBecause is cyclic, its Euler-Lagrange equation gives the conserved quantityThis is the conserved momentum per unit five-dimensional mass associated with the Killing vector field . For the other coordinates, differentiate . Using givesThe first two terms combine into , with the Christoffel symbols of . Define the four-dimensional electromagnetic field tensor and raise its index with . The complete reduced geodesic equations areThis is the Kaluza-Klein geodesic Lorentz force. The Christoffel symbols describe the gravitational motion in general relativity in the four-dimensional metric tensor, while the right-hand side is antisymmetric in its lowered indices and gives the relativistic Lorentz force. In particular,Thus the force preserves the four-dimensional velocity norm, as a Lorentz force must. A particle with is neutral and follows an ordinary four-dimensional geodesic. Nonzero compact momentum gives electric charge, with its sign determined by the direction of motion around the circle.
To identify the actual charge-to-mass ratio, suppose the five-dimensional particle has mass and is its five-dimensional proper time, so . Then . Four-dimensional proper time obeys ; since is constant, satisfiesHere is in the geometric normalization of the supplied potential . The relation also follows directly from the five-dimensional mass shell, and continues to identify the effective mass when the higher-dimensional particle is massless. The distinction between the two proper times prevents mistaking itself for the physical four-dimensional charge-to-mass ratio. A rescaling of to a canonically normalized electromagnetic potential correspondingly rescales .
For the wave calculation, take a scalar field of five-dimensional mass in units , obeying . In the coordinate order , direct inversion of the metric tensor givesThe determinant follows by the triangular change of coframe from to , whose determinant is one. Write . Since all coefficients are -independent, the scalar covariant wave operator isExpanding the right-hand side verifies both cross terms , the term , and the coefficient of .
Single-valuedness under the compact coordinate period requires the Fourier seriesFor the th Kaluza-Klein mode, put and . The five-dimensional Klein-Gordon equation reduces toThis is the charged four-dimensional Klein-Gordon equation: the divergence expression includes both the spacetime connection and the gauge connection. Its interpretation as electric charge can also be checked directly. Under the fibre coordinate change , the metric retains its form with , and the scalar Fourier coefficient changes by . Hence , exactly the transformation law for a field of charge .
The Kaluza-Klein charge quantization is thereforePositive and negative integers give opposite charges, and the zero mode is neutral. Restoring gives compact momenta , so their fundamental spacing is . These are charges in the metric's geometric normalization. If for a physically normalized electromagnetic potential , the physical charge unit is in natural units, or with restored. Determining requires an electromagnetic action normalization not specified by the metric ansatz alone.
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 53 1 ii Solution 2026-10-14
For an expanding universe, cosmic inflation requires . Including any vacuum contribution in the total density and pressure, the acceleration equation gives , or for positive density. Equivalently the comoving Hubble radius decreases. Since , prolonged acceleration suppresses curvature and addresses the flatness problem. A sufficiently long inflationary phase also stretches a region that was initially causally connected to encompass the observed region, addressing the horizon problem. The condition on acceleration must last long enough; an arbitrarily short interval is insufficient.
For a homogeneous canonical scalar field with potential ,Thus is sufficient for inflation. A suitably flat positive potential gives slow-roll inflation: Hubble damping in keeps the kinetic energy small compared with , so .
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 53 4 Solution 2026-10-14
Use . For a canonical light scalar field with effective mass , define the canonical Fourier mode . In the nearly de Sitter approximation it obeysDeep inside the Hubble radius, , the mode behaves like a Minkowski oscillator. Choosing the Bunch-Davies vacuum sets . The normalized de Sitter solution isInflation stretches the physical wavelength until it exits the Hubble radius. For , the growing scalar solution freezes with . The dimensionless power spectrum is thereforeHere is evaluated when , since slow evolution near horizon exit fixes the frozen amplitude. Nearly constant and a light field make this spectrum almost scale-invariant; slow background evolution and small mass corrections produce a small tilt. The stretched vacuum modes supply the primordial stochastic fluctuations.
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 54 4 Solution Created 2026-10-03 Updated 2026-10-14
Work initially in units and consider gravitational collapse settling to a nonextremal Schwarzschild black hole. Classically, outgoing rays sufficiently close to the forming event horizon suffer an arbitrarily large redshift. Quantum mechanically, the meaning of positive frequency at past null infinity differs from that at future null infinity; a Bogoliubov transformation between these two mode descriptions can therefore mix creation operators and annihilation operators. Hawking's argument computes that mixing and obtains a thermal occupation, even when the incoming state has no particles.
To see why the frequency mixing is universal, use final Schwarzschild time , the Schwarzschild tortoise coordinate , and retarded time . Near the final event horizon, , with Schwarzschild surface gravity . On a fixed advanced-time section, , so is proportional to . Tracing a ray back through the regular collapsing region maps this small separation smoothly to its separation from the last escaping incoming ray. If is an affine incoming null coordinate and labels that limiting ray, the Hawking exponential ray map isThe logarithm at a simple horizon root fixes the exponent. Smooth propagation through the earlier collapse changes and phases but not the leading exponential redshift.
For a massless bosonic test scalar field, an outgoing mode of frequency at future null infinity behaves as . Trace it backward in the high-frequency geometric optics approximation. Its relevant incoming dependence is, up to normalization and a phase,Here is the Heaviside step function. Incoming rays with do not escape. This truncated logarithmic phase is not purely positive frequency with respect to . Decomposing it into incoming positive-frequency solutions and negative modes gives the Bogoliubov transformation. With , the two relevant Fourier transform integrals areThe former is the positive-frequency coefficient and the latter is the negative-frequency coefficient; the Klein-Gordon inner product introduces the same frequency normalization into their modulus ratio. By the defining integral of the Gamma function and analytic continuation in its Laplace parameter,For a complex number in the right half-plane, . As , the two arguments tend to and . This gives the thermal ratio of Hawking Bogoliubov coefficients:The regulator fixes the branches and is essential to the sign of the thermal exponent.
Expand the outgoing annihilator as , including a complete set of incoming channels. The canonical identities for a bosonic Bogoliubov transformation express . For normalized outgoing wave packets, they give . In the incoming Fock vacuum, the outgoing mean of the particle number operator is . Combining the two identities with the thermal ratio, in the late-time narrow-frequency packet limit, yieldsWave packets avoid interpreting the divergent normalization of infinitely long continuum modes as a finite particle count. The temperature is the Hawking temperature, and the occupation is the zero-chemical-potential Bose-Einstein distribution. Restoring constants, the Schwarzschild black hole temperature is for physical mass .
The preceding thermal occupation describes the horizon-originating channel before exterior scattering. The exterior angular and curvature potential partly reflects it. For a scalar field, the number flux at future null infinity is consequentlywhere the greybody factor is the transmission probability of a partial wave. Multiplication by gives its energy flux. Thus the asymptotic spectrum has the thermal denominator but is not an exact blackbody spectrum. For fermionic fields the canonical anticommutation relations replace the minus sign in the occupation denominator by a plus sign, at the same Hawking temperature.
The relevant state is the collapse vacuum for Hawking radiation: no incoming thermal bath at past null infinity, and regular short-distance behavior in freely falling coordinates at the forming event horizon. It predicts an outgoing flux, unlike equilibrium with a thermal bath on an eternal black hole. The derivation uses quantum field theory in curved spacetime on a prescribed classical geometry; it does not require outgoing particles to follow forbidden classical paths out of the interior. Positive energy carried to infinity is accompanied, in the semiclassical description, by negative Killing-energy flux into the black hole. Including that flux in slow backreaction decreases its mass, giving black-hole evaporation.
The approximation applies to the late radiation of a large nonextremal black hole while its surface gravity changes slowly on a time scale . Backward propagation involves very high locally measured frequencies, so the calculation assumes the usual regular short-distance quantum-field state. It determines the leading radiation and temperature, not the Planck-scale endpoint of black-hole evaporation. The exponential horizon redshift forces positive/negative frequency mixing with a thermal ratio, giving outgoing Hawking radiation at .
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 56 5 Solution Created 2026-10-03 Updated 2026-10-14
The gravitational variable and the fields held fixed in a variation must be specified. For bosonic matter a second-order metric tensor formulation is sufficient. For spinorial matter a vierbein and a spin connection are needed to define the local Lorentz representation and its covariant derivative. “Second order” refers to a connection already expressed through derivatives of the vierbein; “first order” treats that connection as an independent variable.
For a metric tensor, a scalar field and an Abelian gauge field, consider the Einstein-Hilbert action with matter,Here and the connection in is Levi-Civita. The metric tensor variation uses andMetric compatibility makes the last two terms a divergence. ThusStationarity for arbitrary compactly supported variations givesExplicitly,Scalar field and gauge-potential variations give and . Their equations imply stress-energy conservation, consistently with the contracted Bianchi identity. If the boundary metric tensor is fixed instead of using compactly supported variations, add the Gibbons–Hawking–York boundary term, , with the outward-normal orientation. Fixing the metric tensor alone does not otherwise remove the normal derivatives of its variation.
For spinorial matter, write and . In the second-order theory set before varying. A symmetrized Dirac action, in the same no-, mostly-plus convention as the earlier solutions, isVarying and integrating by parts gives ; varying gives the adjoint equation. The spinor components held fixed in a gravitational variation are components in the Lorentz frame. Both and vary with the vierbein. The former gives the canonical stress, and integrating the spin-connection variation supplies its spin-current improvement. On the Dirac equations the resulting symmetric stress tensor isThe off-shell expression also contains ; this vanishes on the matter equations for the displayed symmetrized action. Treating the coordinate gamma matrices as fixed while varying the metric tensor would miss the displayed stress. Local Lorentz invariance removes the independent antisymmetric vierbein equation, leaving the symmetric Einstein field equations with this matter source.
In a first-order vierbein formulation, and an antisymmetric Lorentz connection are independent. Defineand use . The curvature form of a connection variation is . For the Einstein-Hilbert term, integration by parts in form notation gives a connection equation proportional towhen matter has no connection dependence. For an invertible vierbein this forces , so . The vierbein equation then becomes the second-order Einstein field equations. This applies to the scalar and Maxwell examples: use , which is independent of and remains gauge invariant even if torsion is present.
A Dirac field changes the connection equation. Directly varying its two covariant derivatives givesThus its spin density sources totally antisymmetric torsion. This is Einstein-Cartan theory, and the connection equation is algebraic rather than a propagation equation for an extra field. To see both its solution and its effect, writeFor the totally antisymmetric component sourced by this field, the Ricci scalar is up to a divergence. The other irreducible contorsion components have no spinor source and their connection equations set them to zero. The auxiliary part of the Lagrangian is thereforeIts algebraic variation gives the algebraic torsion of a Dirac field,Here the first index of labels the derivative, and the torsion convention is ; specifying this convention fixes the sign. Eliminating leaves the second-order effective action with contact interactionIt is a local axial-current four-fermion interaction. Hence first-order gravity with Dirac spin density is equivalent to torsion-free second-order gravity with this additional interaction. It is not equivalent to simply declaring the spin connection torsion-free and dropping the contact term. In the effective formulation the Einstein field equations have the stress tensor of the full effective matter action. Before eliminating the connection, the antisymmetric stress and its spin current are related by the local Lorentz Noether identity.
Finally, the 1.5-order formalism is a convenient way to vary this effective action. Let solve the algebraic connection equation and let . The chain rule givesThus vary as in first order, then insert the solved connection. One does not need to calculate the complicated induced connection variation. This procedure is justified by its connection equation, not by discarding that variation arbitrarily. In supergravity the gravitino sources a contorsion quadratic in fermions; substituting it generates the four-fermion terms, while the 1.5-order method simplifies the local supersymmetry cancellation through the lower orders considered above.
Past exam of the mathematics course of the University of Cambridge 2011 ia Paper 3 10C Solution Created 2026-09-24 Updated 2026-10-14
The divergence theorem states that a continuously differentiable vector field on a bounded region with piecewise smooth boundary satisfieswith the unit normal pointing out of . Apply it separately to , where is each constant Cartesian basis vector. Since and , the three component identities combine to give
For the specified scalar field, . The term integrates to zero by reflection symmetry. At height , the region has a disk cross-section of area , and . Therefore the volume integral isTo check the surface integral independently, split the boundary into the base disk and the curved graph . On the base , so its contribution vanishes. The region lies below the curved graph, whose outward vector surface element of a graph isOver the disk , the and components of are odd in and integrate to zero. Its component gives, in polar coordinates,Thus the two explicitly evaluated integrals agree, with the outward orientation included.
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 57 1 i Solution Created 2026-10-03 Updated 2026-10-07
Use signature and write for the spatial induced metric, for its spatial covariant derivative, and . The negative shift vector convention gives and . Decomposing the scalar field derivative givesVarying the scalar field matter action with respect to the inverse metric tensor, including the variation of , gives the stress-energy tensorRaising both indices gives the requested . Contracting with the unit normal twice, or once with the spatial projection tensor, givesProjecting both indices of the stress-energy tensor onto the spatial hypersurface givesTwo printed identifications require correction. The canonical momentum of the displayed density is , not : explicitly and differentiation with respect to supplies . Thus is the normal scalar-field momentum. Also, the printed trace-free stress has an extra factor and uses where the general spatial induced metric requires . In an orthonormal spatial frame the latter becomes , but the coefficient is still one. For a gradient in that frame, direct projection gives , rather than the printed . The PDF's energy-density gradient is spatial ; the TeX aid's spacetime index there is an OCR defect.
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 57 1 iv Solution Created 2026-10-03 Updated 2026-10-07
Now impose the stipulated negligible shear and work where . The Hamiltonian constraint, momentum constraint and local expansion evolution giveTime differentiation of the first equation, followed by , gives . Spatial differentiation of the same equation and use of the momentum constraint givesThese are the temporal and spatial identities needed for the nonlinear curvature covector. Differentiate its definition, keeping the spatially varying lapse function:The terms proportional to cancel. The terms and cancel by the momentum constraint, and the remaining two terms cancel by the spatial momentum identity. Thereforeto the retained gradient order. No homogeneous-lapse assumption was needed.
For linear adiabatic cosmological perturbations, expansion of the local scale and scalar field gives . For nonzero spatial modes, linearizing the Hamiltonian constraint and the momentum constraint givesThusThis uses the paper's overall sign for the uniform-density curvature perturbation; the opposite overall sign is also common. For an adiabatic single-field attractor, superhorizon conservation of single-field comoving curvature allows the primordial amplitude to be transported through later epochs without following every short-scale process. This proof specifically discarded the shear contribution to the momentum constraint and assumed a usable field clock. It is not a claim that every single-field background conserves every curvature mode: growing curvature perturbation in ultra-slow-roll inflation is a non-attractor counterexample, and makes this particular covector undefined.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 44 4 Solution Created 2026-10-03 Updated 2026-10-07
Fix the current sign convention by defining the localized variation as . For a first-derivative Lagrangian invariant without a boundary term under constant parameters, this means ; include the usual improvement term if the constant variation is a total derivative. On solutions, arbitrary compactly supported parameters imply . The Noether charge is and is conserved if the spatial flux vanishes. This sign convention matches the printed Ward identity; reversing the current also reverses the corresponding generator convention.
Assume an invariant regulated functional measure, invariant vacuum boundary conditions and no quantum anomaly. Changing variables in the normalized path integral gives . Integration by parts then yieldsFor a product of scalar fields, the local Ward identity contact terms areAway from the insertions this is current conservation. Time-ordering or the distributional functional identity supplies the contact terms.
For the gauge theory write and use the left-acting BRST differential , with . It obeys the graded Leibniz rule andAssume the structure constants satisfy the Jacobi identity and the dot product is invariant; antisymmetry alone would not be enough. Since and are odd, their Lie brackets are symmetric in these two arguments. ConsequentlyAlso . The graded Jacobi identity gives , so ; the other three fields have zero second variation immediately. For independent odd parameters, . These are off-shell BRST nilpotence identities because the Nakanishi-Lautrup field is retained.
The Yang-Mills theory variation is proportional to . The gauge-fixing variation is , while the ghost variation is its negative; the term does not vary. Equivalently these terms are for the gauge-fixing fermion . BRST nilpotence makes this expression invariant. Ghost-number scaling also leaves every term invariant: the ghost and antighost factors carry opposite weights.
Here are the two explicit currents in the same sign convention as the Ward identity. Localizing the even ghost parameter gives coefficient . Localizing the odd parameter, keeping it on the left, gives coefficientThe last sign comes from moving the odd parameter through the odd antighost derivative. Since the current was defined as minus this coefficient,These are the ghost-number Noether current and the BRST current in derivative-b gauge fixing. If the opposite Noether sign is used, both displayed currents acquire an overall minus sign. Integrating the gauge-fixing term by parts changes the Noether representative by the associated boundary improvement; mixing the two Lagrangian conventions without that improvement gives incorrect signs.
With no BRST anomaly, the conserved odd BRST charge has . The BRST cohomology identifies closed states modulo exact states . Nilpotence puts every exact state in the closed space. In the usual indefinite gauge-fixed state space, a Hermitian BRST charge makes exact states orthogonal to closed states; the standard no-ghost/positivity assumptions then give a physical inner product on the quotient. The physical sector is its ghost-number-zero component,The ghost number assigns to , to and zero to gauge and auxiliary fields. Gauge-invariant observables and the chosen vacuum have ghost number zero; unphysical ghost excitations are removed in BRST pairs. Thus physical representatives are expected to satisfy . This zero-grading selection is part of the physical-state prescription, not a consequence of nilpotence alone.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 45 1 a Solution Created 2026-10-03 Updated 2026-10-07
Take real field coordinates ; for complex scalar fields, split them into real and imaginary parts. Assume a smooth scalar potential and positive, canonically normalized kinetic terms in a relativistic theory. At a classical vacuum, . The Taylor expansion isThus the scalar mass matrix is the Hessian matrix, and its eigenvalues give squared masses of the linearized scalar excitations.
Put . Infinitesimal invariance of the scalar potential gives the identity at every field value. Differentiate with respect to and evaluate at the classical vacuum:Every nonzero infinitesimal symmetry direction therefore lies in the kernel of the scalar mass matrix. This is the classical Goldstone theorem expressed through Goldstone directions in the scalar mass matrix.
Let be the full stabilizer subgroup of . The linear map from the Lie algebra of to field space, , has kernel equal to the Lie algebra of . The rank-nullity theorem givesThere are consequently at least massless scalar directions, namely the tangent directions to the symmetry orbit through the classical vacuum. If the intended is , these are the symmetry-required Goldstone bosons. Exactly that many massless modes occur if the scalar mass matrix is positive definite on a complement of those tangent directions. A nonsingular positive field-space kinetic metric changes normalization, but not the number of zero masses.
Two qualifications are needed for the literal assumptions. A subgroup fixing the classical vacuum need not be the full stabilizer subgroup. For example, take acting on a real triplet and with . At , the scalar mass matrix is : there are two massless modes. Choosing satisfies the printed invariance condition but would incorrectly predict three. The full stabilizer subgroup is .
Even with the full stabilizer subgroup, symmetry does not exclude an accidental massless scalar. Take rotating , with an invariant singlet , andAt the full continuous stabilizer is trivial, but the scalar mass matrix is . One zero direction is the Goldstone boson; the other is an accidental massless scalar at quadratic order. The proof establishes the symmetry-required count, not unconditional equality with the total number of massless fields. The statement concerns global internal symmetry; gauging it changes the physical interpretation through the Higgs mechanism.