Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 45 4 Solution Created 2026-10-03 Updated 2026-10-07
An effective field theory is a controlled description of specified low-energy degrees of freedom at a chosen accuracy. It does not require knowing all physics at arbitrarily short distances. If new particles or strong dynamics enter at a scale , processes with characteristic energy and momentum transfers can be described using the light fields and interactions consistent with their symmetries. In natural units, four-dimensional power counting in quantum field theory organizes a local Lagrangian asHere has mass dimension , the dimensionless are Wilson coefficients, and is a renormalization scale. In a relativistic vacuum with canonical fields, a typical insertion of a dimension- interaction contributes an additional power , multiplied by its couplings and any light mass ratios. Additional expansions, such as a loop expansion, must also be specified. Symmetry or on-shell identities can postpone a particular observable's first correction.
The theory is useful when its retained states and expansion parameters adequately describe the experiment. It ceases to be a reliable truncated local description near an omitted particle's production threshold, near a heavy propagator pole, or where the retained dynamics become too strongly coupled for an assumed perturbative expansion. A light particle cannot be removed merely because one wants fewer variables: its propagation can produce nonanalytic momentum dependence that must be represented by retained light fields. Heavy-field decoupling can shift renormalizable masses and couplings as well as generate suppressed interactions; those low-energy parameters must be measured or matched, not assumed unchanged. The ultraviolet cutoff is an organizational scale, while a calculation may use a regulator other than a hard momentum cutoff.
Construction starts by identifying the light particles, the hierarchy of scales, and the exact or approximate symmetries relevant to the problem. Form all allowed local field operators through the desired order in power counting in quantum field theory. Choose an operator basis in effective field theory: remove equivalent terms by integration by parts, algebraic identities and allowed field redefinitions. Operators proportional to lower-order equations of motion can be redundant operators for on-shell amplitudes, provided coefficients are consistently transformed. This reduces bookkeeping without imposing additional physics assumptions.
If an ultraviolet completion is known, determine the Wilson coefficients by matching in effective field theory: calculate low-energy amplitudes or appropriate correlation functions in both descriptions using the same infrared conventions, and adjust coefficients so they agree to the chosen order. Equivalently, integrating out a field performs its path integral while retaining the light fields as backgrounds. Heavy propagators have an analytic expansion below their singularities, producing a derivative expansion; heavy loops also generate local terms and logarithms in their coefficients. Without a specified ultraviolet completion, the coefficients are parameters to be constrained by data.
An effective field theory remains predictive even when it contains nonrenormalizable interactions. At each fixed order in energy and loops there are finitely many required coefficients and counterterms. Renormalization absorbs divergences into that order's allowed operators. The renormalization group evolves the Wilson coefficients between matching and measurement scales, compensating scale dependence in matrix elements and, when appropriate, resumming large logarithms. The truncation error in effective field theory is estimated from the first omitted orders, under a stated coupling-size assumption; it is separate from parameter uncertainty and cannot be inferred merely by writing down infinitely many terms.
A concrete example is heavy scalar exchange in effective field theory. Take a light real scalar field and a heavy real scalar field , withThe coupling has mass dimension one. The light-field symmetry is . For and , the displayed scalar potential is bounded below: completing the square in leaves a positive light quartic. Thus the example can be treated as a stable theory around , with weak enough couplings for the tree approximation.
At tree level the heavy equation of motion is . Substitute its solution back into the action, including both its quadratic and source terms, to obtainThis is a derivative expansion valid for small momentum transfers, not an exact local replacement near the pole. The first term gives in the convention. After integration by parts, the next term is ; it is a dimension-six local operator. Writing puts its coefficient in the usual form. These coefficients are a tree-level matching in effective field theory result.
One can directly check the matching through the on-shell scattering amplitude for . With the Mandelstam variables, the full theory has three heavy-exchange channels:For ,The effective field theory reproduces these terms in order: a shifted quartic, then local derivative interactions. Since on shell, the first derivative correction is a light-mass-dependent constant; it vanishes for . This illustrates why an operator basis in effective field theory can trade some derivative operators for mass-dependent or higher-field interactions using field redefinitions. For massless external particles, the first nonconstant correction in this four-point tree amplitude starts at the following order.
The example exhibits the central logic: keep the light field, encode virtual heavy exchange in matched local coefficients, and control the error by expanding in momentum divided by the heavy scale. No heavy particle is actually produced in the domain of the approximation. Near , the full propagator is resonant and the truncated effective field theory fails; retaining or adopting a different description is then necessary. Light loops are computed within the effective field theory, while higher-order matching supplies the corresponding heavy corrections.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 46 1 Solution Created 2026-10-03 Updated 2026-10-07
Actions and equations. Use a mostly-plus Minkowski metric and define the induced worldsheet metric . For a nondegenerate timelike worldsheet, the Nambu–Goto action isVarying the independent metric in the Polyakov action sets its worldsheet stress tensor to zero:In two dimensions this says for a positive local factor. The factor drops out of , and substitution gives the Nambu–Goto action. Conversely, any nondegenerate induced metric solves the auxiliary-metric equation up to a Weyl transformation. This classical equivalence of Polyakov and Nambu–Goto actions is a statement about classical embeddings; quantum equivalence additionally requires treatment of the metric measure and anomaly.
Variation of in the metric action, followed by elimination of , gives the Nambu–Goto equations of motionA closed string has periodic and no spatial endpoint variation.
For a background metric , Kalb–Ramond field , and dilaton , one consistent Lorentzian convention isThe orientation fixes the two-form sign; here the Lorentzian curvature convention is chosen so Wick rotation gives the positive Euclidean dilaton term . This avoids hiding the convention in the topology argument. For constant vacuum value , the Gauss-Bonnet theorem gives . A connected closed oriented surface of genus has Euler characteristic , soThe connected vacuum amplitude has a string genus expansion ; disconnected vacuum diagrams exponentiate the connected sum. Each additional handle supplies a factor . This is dilaton Euler-characteristic weighting.
The rotating circle. For the specified embedding, the squared spatial speed and tangent length are both , and their spatial inner product is zero. Including therefore givesThe metric is constant. Its equation reduces to , satisfied by the left- and right-moving trigonometric components and the linear time component. On a constant-time slice with , the proper length of a string isIt is time-independent.
Let be an ordinary two-dimensional rotation matrix. Rotate the first coordinate pair by and the second by . In these time-dependent Cartesian coordinates both pairs become . A further fixed orthogonal change of basis givesThus every spatial slice is a planar circle of radius ; its plane rotates in the ambient four-space. This is a rigid circular string in four spatial dimensions, not a pulsating circle. The rotating axes establish its spatial shape, not a transformation to an inertial spacetime frame.
The momentum density obtained from the Nambu–Goto action is . Here , hence the conserved target-space energy isThe material velocity is transverse to the tangent and has magnitude . Its Lorentz factor is , so the excess over is kinetic energy. The spatial circle being stationary in rotating axes does not eliminate this energy.
Constraints and endpoints. Varying the multipliers in the Nambu-Goto phase-space action imposesThese are first-class constraints generating normal and tangential worldsheet diffeomorphisms. They remove the two longitudinal embedding degrees of freedom; they are not extra physical force laws. Hamilton's equations areFor an open string, integration by parts leaves the spatial boundary variationAllowed variational open-string boundary conditions must make this vanish for every permitted endpoint displacement, and be preserved by the evolution. The bracketed expression is the open-string endpoint momentum flux. For free displacements, set that flux to zero. In a boundary-preserving gauge with and finite nonzero , this is the Neumann boundary condition at each end. This shows that free-end string boundary conditions are consistent.
At such an end, gives , and gives . For a nontrivial endpoint trajectory with nonzero time velocity, its spatial speed is therefore one. This null motion of a free string endpoint follows from the boundary condition together with the constraints, not merely from the bulk wave equation. The induced metric may degenerate right at a free end; the result is understood as the endpoint limit or in the Polyakov description.
For a fixed spatial -plane, split coordinates into along its -dimensional worldvolume, including time, and transverse to it. Set and at the ends. Tangential variations are free and their momentum flux vanishes; normal variations vanish, so their flux need not vanish. Evolution preserves the fixed normal values with at the boundary in the same gauge. These mixed Neumann boundary conditions and Dirichlet boundary conditions consistently restrict the endpoint worldlines to the plane.
The massless open-string excitations then separate into a gauge vector along the worldvolume and transverse scalar fields. A scalar displacement changes the corresponding ; its interpretation is a fluctuation of the plane's embedding. These worldvolume fields from open-string massless states support the interpretation as a dynamical planar D-brane. In the bosonic theory the still lower ground state is a tachyon, indicating an unstable brane; the interpretation does not require pretending that this tachyon is a stable massless field. Appropriate superstring sectors can remove that instability.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 47 2 Solution Created 2026-10-03 Updated 2026-10-07
To keep the paper's coupling convention explicit, write and use physical coordinates , . Assume and weak coupling . The canonical real scalar field is , and the physical potential isThe symbol is the coupling usually appearing in canonical Sine-Gordon theory; the paper's is its square. The vacua have . A static Sine-Gordon kink has and satisfies . Since , its classical mass isThe topological sector is important: this energy is measured relative to a vacuum, and the kink joins distinct vacua at the two spatial ends. Expanding around a spatially constant vacuum cannot construct this state by any finite-order perturbation in .
For the general one-loop soliton mass correction, start with a canonical scalar field potential and a stable static soliton . Write . The term linear in vanishes by the classical Euler-Lagrange field equation. The quadratic fluctuation Hamiltonian isChoose a common large box and a common finite-mode regularization in quantum field theory. Expand the nonzero normal modes as , with and normalized eigenfunctions. Each pair is a quantum harmonic oscillator contributing ground-state energy . In the vacuum, replace by . Subtract the two ground-state energies and add the local counterterms evaluated on the soliton relative to the vacuum. This derives the general formulaThe prime excludes exact zero modes in field theory from oscillator quantization; their zero frequencies contribute no zero-point energy, but their role in mode counting must not be forgotten. The two sums mean a paired finite regulator, not separate subtractions of divergent answers. Equivalently the nonzero-mode term is the regulated difference of the square-root traces of the two fluctuation operators. Discrete bound states and continuum modes both contribute. This is a vacuum-subtracted soliton mass and the first term in the semiclassical soliton mass expansion.
Translation gives a zero mode in field theory because differentiating the static equation yields . A Gaussian oscillator or an unprimed functional determinant is inappropriate along this flat direction. Replace its amplitude by the position collective coordinate and require the residual fluctuation to obey , preventing double counting. The associated change-of-variables Jacobian supplies the zero-mode normalization. At low speed the collective-coordinate effective Lagrangian for a soliton is ; quantizing the position gives the soliton momentum and its translational states, not an extra oscillator rest energy. More generally, every physical continuous modulus needs a collective coordinate; gauge directions require gauge fixing rather than additional physical states.
The Sine-Gordon kink fluctuation operator is particularly simple:while . This supersymmetric factorization of the one-soliton potential shows stability and generates all nonzero eigenfunctions from vacuum plane waves. The sole normalizable bound state is the translational zero mode of a sine-Gordon kink, proportional to ; there is no positive-frequency internal bound oscillator. The continuum has and no reflection. Applying to gives a transmission amplitudeThis scattering phase shift changes the density of continuum modes. The high-frequency vacuum subtraction cancels the extensive vacuum contribution but still leaves a logarithmic ultraviolet divergence.
The finite part also requires consistent mode-number regularization of soliton masses. The periodic-box phase-shift quantization condition is . Match modes: the kink has its translation mode plus the two continuum modes at each , while the vacuum has the oscillator of frequency and the corresponding continuum pairs. With and , expanding givesIntegration by parts uses and yieldsThe cutoff surface term for a Sine-Gordon kink tends to . It cannot be dropped merely because : grows at the same time.
A renormalization condition must specify which mass and coupling are held fixed. For vacuum normal ordering, or cancellation of the vacuum tadpole diagram with the elementary mass fixed at , the quartic interaction gives the mass countertermEvaluating this Sine-Gordon vacuum tadpole counterterm on the kink givesThe logarithmic ultraviolet divergence cancels, leaving the renormalized one-loop Sine-Gordon kink mass in the stated vacuum scheme:This example illustrates why a zero mode in field theory must be treated as a collective coordinate, why vacuum subtraction alone need not remove ultraviolet divergences, and why the finite relation between the two regulators matters. Different finite counterterms amount to different definitions of the renormalized parameters; an unregulated frequency difference without a renormalization condition is not a physical mass prediction.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 47 3 Solution Created 2026-10-03 Updated 2026-10-07
In elastic diagonal factorized scattering, the Faddeev-Zamolodchikov algebra describes an exchange of two particle operators. Exchanging the pair twice must restore the original state. This is analytic unitarity:Keeping the reversed species in this identity avoids an unstated parity assumption. For the particular amplitudes derived below, crossing and analytic unitarity also imply . Hermitian analyticity of a two-particle S-matrix states and, together with analytic unitarity, gives for real rapidity differences. Crossing symmetry analytically turns an incoming particle into an outgoing antiparticle, relating the two channels by , with the reverse relation obtained by crossing again. The shift follows from the sign reversal of the two-momentum .
Put . The given amplitude is the unit-modulus hyperbolic scattering block . Its numerator and denominator interchange under , proving analytic unitarity. For real it also obeys Hermitian analyticity of a two-particle S-matrix. Applying crossing symmetry givesThis crossed amplitude also has unit modulus on the real axis. Thus both requested channel constraints hold.
The bound-state conclusion needs a coupling range. In the fundamental attractive range , equivalently , the denominator has a simple pole at inside the physical rapidity strip. Its residue iswith positive imaginary coefficient. Under the usual one-particle interpretation of this direct-channel bound-state pole, it couples two charge- particles to a new charge- particle . In the center-of-mass frame its constituents have analytically continued rapidities , and their total two-momentum is . Thus the relativistic bound-state mass from a rapidity pole givesIt is positive and less than the two-particle threshold . Without the coupling qualification the requested deduction is false: at the amplitude is identically one after removing the apparent at the origin. A free massive complex scalar field has this diagonal amplitude, charge- particles and no isolated charge- bound state. At the amplitude similarly becomes constant and the apparent boundary pole cancels. Neither endpoint supplies the claimed particle.
For bound-state fusion of factorized S-matrices, represent as the residue of at its bound-state separation. Move a third through both constituents using the Faddeev-Zamolodchikov algebra, then take the same residue. The bound-state normalization occurs on both sides and cancels. Consequently bootstrap fusion giveswhere . This has analytic unitarity as a product of two shifted blocks. Its poles occur at and , modulo ; numerator zeroes occur at the corresponding negative positions, subject to cancellations at special couplings.
The nearer pole, , has residue . It is a crossed-channel pole in diagonal factorized scattering, not a new direct-channel charge- state. Indeed, the exchanged momentum has invariantusing . The exchanged particle is therefore the already present , with the appropriate charge flow at the crossed vertex. Equivalently, crossing symmetry puts a positive-residue direct pole of at , corresponding to . This distinction avoids assigning an extra mass by applying the direct-channel formula to every pole.
The farther pole, , lies in the physical rapidity strip only for , equivalently . Its residue iswhich has positive imaginary coefficient in that range. It gives a charge- bound state . The relativistic bound-state mass from a rapidity pole now yieldsThe positive root in the admitted range isThis is the three-particle bound state from equal-mass fusion; in its own rest frame the constituent rapidities are . At the farther apparent pole cancels because its numerator also vanishes; for it lies outside the physical rapidity strip and does not require a new charge- particle. Charge-conjugate partners carry charges and where the corresponding states exist. Fusion distinguishes an existing crossed-channel particle from a genuinely new direct-channel bound state, and the latter requires the stated smaller coupling range.
Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 42 3 Solution Created 2026-10-03 Updated 2026-10-06
The parameters of a cutoff statistical field theory describe only the retained modes. Changing the ultraviolet cutoff changes which fluctuations have already been integrated out, so its effective mass, interaction coefficients and gradient normalization must change to preserve the same long-distance physics. They are not separately cutoff-independent observables. Because the source's weight is , its statistical Hamiltonian is dimensionless, with the physical inverse-temperature factor already absorbed.
For example split the scalar field into slow modes with and shell modes with . Define the momentum-shell renormalization group step byThis integrates out short-wavelength fluctuations exactly if all generated terms are retained. The new Hamiltonian can be expanded in local symmetry-allowed operators when the retained external momenta are well below the shell scale. A cumulant expansion of a coarse-grained free energy gives perturbative coefficients. Restoring the cutoff with and, for a canonical gradient term, , gives and . Interaction corrections also change the field normalization. Repeating the step produces the effective theory at successively longer distances.
To obtain the LG theory, assume a short-range scalar theory, slowly varying retained fields, analytic local couplings, positive gradient stiffness and stability, and a regime in which fluctuation corrections at the remaining scales are small. Keeping the leading gradient, quadratic and quartic operators gives a local Landau-Ginzburg theory functional. Its equilibrium in the Landau approximation is a uniform minimum, with a quadratic coefficient proportional to after the critical mass has been tuned. The RG explains why this is asymptotically consistent for the ordinary transition above four dimensions: the quartic interaction is irrelevant near the Gaussian fixed point, while it must still be retained to stabilize the ordered phase. Below four dimensions it cannot be dropped in the asymptotic critical region; an interacting Wilson-Fisher fixed point rather than the elementary saddle generally controls the transition. At four dimensions the interaction is marginal and produces logarithmic corrections. Tuning a quartic coefficient through zero requires a sextic stabilizing term and leads to tricriticality.
More concretely, in the Gaussian scaling regime let so the local quartic term is . At a total blocking scale , the leading couplings are , , . Apply the saddle approximation to the blocked potential and multiply its minimum by to convert back to original volume units. Rescaling the saddle field by givesAll blocking-scale factors cancel. This explicitly recovers mean-field scalar free-energy scaling with . Although above four dimensions, the saddle free energy is proportional to ; setting it to zero before minimization would remove the ordered phase. This is the dangerously irrelevant coupling mechanism rather than homogeneous two-variable hyperscaling.
For the perturbative calculation make the source's kinetic convention explicit. Write . The canonical normalization of a scalar gradient term uses , so the canonical quadratic and quartic coefficients are and . In what follows denote those canonical coefficients; then the reference propagator has denominator . Without this normalization the propagator denominator is , and the unmodified printed integral would not apply. At one loop the quartic tadpole is momentum independent, so it produces no gradient renormalization at this order.
In the convention fixed by the displayed equation, the truncated two-point function is the one-particle-irreducible two-point vertex, not the connected two-point cumulant itself. If and is the Legendre transform, then its second derivative is the inverse of . For a translation-invariant background,Decompose the canonically normalized statistical Hamiltonian into a Gaussian part of mass , a mass counterterm , and the quartic interaction . With the Euclidean sign convention in which a positive mass correction increases the inverse propagator, the self-energy expansion isHere contains loop corrections from proper two-point diagrams, excluding the separately displayed mass counterterm. The corresponding connected propagator begins . This fixes the sign, which would be reversed if “self-energy” instead denoted the insertion added with a plus sign inside a Dyson series.
The one-loop proper diagram is the tadpole diagram. Attaching two external fields to the quartic vertex gives contractions, divided by , so its symmetry factor is . With the loop momentum restricted by the cutoff,It is independent of external momentum. Impose the zero-momentum mass condition . This gives , henceThis is the one-loop relation using a renormalized mass in the reference propagator, or the corresponding self-consistent tadpole approximation if solved without expanding in . It is not an exact all-orders gap equation. Away from the critical infrared problem, replacing the loop mass by the bare one changes a strict perturbative result only at higher order.
Take smooth and nonzero for an ordinary stable quartic transition. To test the assumed linear thermal mass, work from the disordered side and put . For , is infrared finite. The critical bare mass is shifted, not generically zero: . Absorb the smooth temperature dependence of couplings into an analytic thermal tuning , with . Critical subtraction gives the one-loop critical-mass subtractionwhereThe infrared asymptotics of the critical-mass subtraction now distinguish the dimensions. For , is finite, soFor , diverges logarithmically. For , substitution givesso the correction to scales as and dominates the analytic linear term. Pure mean-field linear mass scaling is therefore consistent only aboveAt the boundary dimension logarithms modify the simple power law. Below it this calculation diagnoses the failure of the Gaussian expansion; the exponent obtained by treating the self-consistent one-loop equation as exact is not automatically the exponent of the interacting scalar theory. For , the massless subtraction itself has an infrared divergence, so this perturbative argument cannot establish absence of a transition. In particular it does not rule out the two-dimensional Ising critical point.
The same upper dimension follows by engineering dimension counting: a canonical scalar field has dimension , so . For a tricritical point tune the renormalized quadratic and quartic terms to zero and retain a positive sextic interaction . Its engineering dimension isIt is marginal at , irrelevant above three, and relevant below three. More generally the upper critical dimension of an even scalar interaction is .
A Ginzburg criterion check gives the same result: at tricritical mean-field scaling and , whereas fluctuations in a correlation volume scale as . Their ratio to is , which tends to zero only for . ThusThe tricritical tuning concerns renormalized couplings: shell contractions of a sextic term can regenerate quadratic and quartic terms even when their bare coefficients vanish. At three dimensions the marginal sextic coupling produces logarithmic corrections rather than a strictly fluctuation-free mean-field limit.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 44 2 Solution Created 2026-10-03 Updated 2026-10-06
For a differentiable curve in the SO(3) group with , differentiating gives , where . Conversely, if is a real skew-symmetric matrix, is an orthogonal matrix and has determinant . HenceThe displayed generators of the SO(3) Lie algebra areThey are linearly independent and span the three independent entries of a real skew-symmetric matrix. Equivalently, . The vector triple-product identity then givesThus the structure constants of a Lie algebra in this basis are
Use a real, antisymmetric convention throughout the SO(3) vector Higgs model. With gauge coupling , the gauge covariant derivative and gauge field strength areThere is no factor of in these formulas because are real antisymmetric generators. For a local non-Abelian gauge transformation , with in the SO(3) group, the compatible transformation of the gauge potential isIt gives and . These covariance laws fix the relative signs in the gauge covariant derivative and gauge field strength.
An SO(3) invariant quartic scalar potential isSince , this scalar potential is gauge-invariant. Its minimum is the sphere , rather than a preferred direction in the internal vector space.
Writing , the cross product form of the gauge covariant derivative is . In components this isCorrespondingly, the gauge field strength has components
A covariantly constant vector Higgs field has constant norm, becauseThe last equality uses antisymmetry of the gauge potential. On a connected region write this norm as . If , the vector Higgs field is identically zero. If , the SO(3) group acts transitively on unit vectors, so choose a smooth local non-Abelian gauge transformation rotating to . In this unitary gauge, with constant. This is a local construction, and is global on a trivial contractible region; a nontrivial bundle can require more than one gauge patch.
For nonzero , substituting the constant aligned vector Higgs field into gives . For nonzero gauge coupling, the most general compatible gauge potential and gauge field strength arewhere is an arbitrary real one-form. Thus the surviving gauge group is the stabilizer subgroup of . A covariantly constant vector Higgs field does not force the gauge field strength to vanish: it only requires the curvature to annihilate that field.
For the Higgs mechanism, choose a vacuum of the SO(3) invariant quartic scalar potential, so the constant norm is . The canonically normalized kinetic term then containsThe two broken-direction gauge bosons have mass (or if the sign of is unrestricted), while the gauge boson remains massless. The two angular Goldstone bosons supply the massive vectors' longitudinal gauge-boson polarizations. The radial fluctuation remains a physical scalar field, with for this normalization. The condition selects backgrounds without broken-direction gauge potentials; fluctuations about such a vacuum exhibit the two massive modes. Constancy of the norm alone does not require it to minimize the scalar potential.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 46 1 a Solution Created 2026-10-03 Updated 2026-10-06
Decompose the original scalar field as , where has support in and has support in . This is a momentum-shell decomposition of a scalar field. The two collections of integration variables are disjoint. Define the lower-scale Wilsonian effective action by integrating out the second collection:A field-independent normalization may be retained as a vacuum term or absorbed into the measure. Integrating this identity over the low modes recovers the original Euclidean path integral, so it preserves all observables depending only on those modes.
Put . The quadratic cross terms integrate to zero: in Fourier transform variables each pairs a low momentum with its negative, which cannot be a shell momentum. Expanding the interaction therefore givesFactoring out of the shell integral and taking minus its logarithm yieldsThis definition is a Wilsonian effective action, rather than a Legendre transform generating only one-particle-irreducible Feynman diagrams.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 52 2 b iii Solution Created 2026-10-03 Updated 2026-10-06
For the minimally coupled scalar field, keep the metric tensor fixed and vary . A scalar's first covariant derivative equals its ordinary derivative, soApply integration by parts for tensor fields. The boundary contribution is proportional to and vanishes under the given boundary condition, leavingThe interior variation is arbitrary. Thus the scalar equation of motion isHere the d'Alembert operator contains the Levi-Civita connection in the second covariant derivative, even though the first derivative of the scalar field is ordinary.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 52 3 ii Solution Created 2026-10-03 Updated 2026-10-06
On the other hand, metric compatibility givesUsing the Christoffel trace identity in the last term yieldsSince the volume density never vanishes in a valid chart, the harmonic coordinate conditions are equivalent:
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 54 4 b Solution Created 2026-10-03 Updated 2026-10-06
Quantize the real massless scalar field using the normalized in-modes:Use the Klein-Gordon inner product convention that is antilinear in its first argument. Mode normalization givesThe out annihilation operator is . Applying the Bogoliubov transformation and the negative norm of conjugate modes givesBoth the complex conjugation and the minus sign follow from the inner-product convention. These operators annihilate the out-vacuum, but need not annihilate the in-vacuum. The particle number operator in out-mode is . In the in-vacuum, the only nonzero contraction is , obtained from the canonical commutation relation. ThusThis is particle number from Bogoliubov coefficients: mixing with negative-frequency in-modes produces out-particles even though no in-particles were present. For continuous mode labels the sum becomes an integral; normalized wave packets make an individual occupation number well-defined. No explicit collapse geometry or thermal spectrum is needed for this conclusion.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 55 2 a Solution Created 2026-10-03 Updated 2026-10-06
In the Spatially flat FLRW metric, neglect metric perturbations and write . The kinetic invariant is then exactly quadratic in field derivatives:Subtracting gives the second-order expansionIn the derivative-dominated approximation, with treated as slowly varying. Thus andThis uses the linear flat-to-comoving slicing relation. Differentiating its slowly varying coefficient would add terms involving undifferentiated ; it is not an exact nonlinear gauge transformation, and those neglected terms do not alter the leading pure coefficient computed here.
Only and contribute to the requested three-time-derivative term. Therefore the directly evaluated cubic coefficient isThis is the derivative-cubic coefficient of a noncanonical scalar. For a physical scalar field theory, differentiating at fixed gives . Its sound speed is consequentlyThe minus sign printed in the denominator of reverses the asserted coefficient identity; it must be a plus. The printed background equation also lacks a power: it is in the stated reduced-Planck units. A stable propagating scalar has positive time-kinetic coefficient and positive gradient coefficient , as summarized by noncanonical scalar kinetic stability.
The unfactored expression for stays meaningful if , although separately then need not exist. For a canonical kinetic term with no higher kinetic derivatives, . The cubic curvature action for a P(X, phi) scalar field can include other vertices and gravitational terms; they are outside this requested derivative coefficient.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 302 4 Solution Created 2026-10-03 Updated 2026-10-06
A Non-Abelian gauge theory promotes an internal group representation symmetry to a spacetime-dependent transformation and introduces a gauge field so that differentiation transforms covariantly. The symmetry is a gauge redundancy: physically meaningful quantities must be invariant under local changes of field representative. We work in four-dimensional Minkowski spacetime with signature , and use skew-Hermitian matrix generators throughout.
For the compact Simple Lie group , its real Lie algebra has a negative-definite Killing form. Hence is a positive invariant bilinear form on a Lie algebra. Choose a -orthonormal basis , , with . Invariance makes fully antisymmetric. This construction uses the Adjoint representation and works independently of any chosen scalar representation.
Let be a Lie-algebra-valued gauge potential, with the coupling absorbed into this connection. If is the given finite-dimensional irreducible representation of , its Lie algebra representation definesFor a finite local transformation , require and . Differentiating the first equation forces the gauge-field transformation lawThus the gauge potential transforms inhomogeneously; an ordinary derivative alone would leave an uncancelled derivative of .
The commutator of gauge covariant derivatives determines the gauge field strength:The Lie algebra representation preserves the bracket, so this formula holds for any , including a trivial scalar representation. The gauge field strength itself is defined in the gauge algebra. The transformation of the connection impliesIt is therefore covariant, rather than invariant as a Lie-algebra-valued quantity.
For infinitesimal , the same equations give the infinitesimal gauge transformation with an anti-Hermitian connection:Substitution into cancels the terms containing and gives , the gauge covariance of a scalar covariant derivative.
The Yang-Mills theory has Lagrangian densityThis is the Killing-form Yang-Mills Lagrangian. Its sign uses a positive internal form and the stated spacetime signature. In a -orthonormal basis it is . Gauge invariance follows because is invariant under the adjoint group action. Infinitesimally, the variation is proportional toAfter rescaling , the gauge coupling appears in and in the non-Abelian part of the canonically normalized field strength. Squaring that field strength gives cubic and quartic gauge-field self-interactions. An ordinary local quadratic mass term in the gauge potential is not invariant because its transformation contains .
For the scalar field kinetic term, compactness supplies a positive invariant Hermitian form on its representation space. One can obtain it by averaging any positive form with normalized Haar measure, the unitarization of a compact-group representation. Then is unitary for , and is anti-Hermitian. The Yang-Mills theory coupled to an arbitrary scalar representation hasHere is any real gauge-invariant scalar potential, so . For example,is available for every unitary representation, with giving a bounded quartic contribution. Other invariant interactions may exist for particular representations; the potential is not required to depend only on .
The scalar kinetic term is gauge-invariant because both covariant derivatives transform by the same unitary . Infinitesimally its variation vanishes byThe potential is invariant by its defining condition. For a real irreducible representation, use the averaged positive symmetric form instead and write the kinetic term as ; all transformation and invariance arguments remain valid. Expansion of the covariant kinetic term produces both the linear gauge-scalar interaction and the quadratic term needed by local gauge invariance.
The invariant inner products, gauge covariant derivatives and gauge field strength together construct the full theory for every compact Simple Lie group and every supplied finite-dimensional irreducible representation of the scalar fields. Both finite and infinitesimal transformation laws have been included, and every sign follows the same anti-Hermitian convention.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 307 1 ii Solution Created 2026-10-03 Updated 2026-10-06
On shell, a massless vector multiplet contains a gauge boson with two transverse polarizations and a gaugino with two fermionic states. A chiral superfield contains a complex scalar field, hence two real bosonic states, and a Weyl spinor with two fermionic states. Their total is bosonic and fermionic states.
Suppose charged scalar fields acquire vacuum expectation values at a supersymmetric vacuum, where F-flatness and D-flatness hold. For each broken generator of the gauge symmetry, the supersymmetric Higgs mechanism combines one massless vector multiplet and one chiral superfield into a massive N=1 vector multiplet. The gauge boson absorbs one real Goldstone boson, acquiring its third polarization. The other real scalar field remains physical. The gaugino and the relevant higgsino mix into the four fermionic states. Thus the spin content isUnbroken supersymmetry gives all these states the same mass through supersymmetric mass degeneracy. Remaining massive chiral superfields instead have spin content , with two fermionic and two bosonic states of a common mass. The auxiliary fields ensure matching off shell but are not additional propagating particles in these counts.
The super-Higgs mechanism occurs when local supersymmetry is spontaneously broken in supergravity. Its spin- gauge field, the gravitino, absorbs the spin- goldstino:The extra states have helicities , supplementing . The ordinary supersymmetric Higgs mechanism can preserve supersymmetry while breaking the internal gauge symmetry; the super-Higgs mechanism breaks the local supersymmetry itself. Spontaneously broken global supersymmetry leaves a physical massless goldstino, because there is no dynamical gravitino to absorb it.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 307 1 v Solution Created 2026-10-03 Updated 2026-10-06
Use left Grassmann derivatives and place the odd constant transformation parameters on the left. A scalar superfield transformation can be writtenEquivalently, pull back the scalar function under the infinitesimal superspace translationThe term involving has the displayed sign because interchanging it with reverses the sign in the Grassmann algebra. Overall factors of in the definition of the supercharges can be changed together without changing this coordinate transformation.
For two even scalar superfields , the odd generators obey the graded Leibniz rule, while the full parameter-weighted variation is even. ThusThis is precisely the transformation of a product of scalar superfields. The finite version is even clearer: if and for the same transformed superspace point, then . No new representation law is required.
The expression needs a distinction between a configuration and a closed field content. As a function on superspace, it is a valid special configuration of an unconstrained superfield. But its variation isFor nonconstant , this generates nonzero components depending on Grassmann variables. Therefore the pure-scalar truncation is not a supersymmetric multiplet: an isolated spacetime scalar field with all its partners permanently set to zero is not closed under supersymmetry. This is the pure-scalar truncation of a superfield. A constant gauge-singlet is the trivial invariant exception. Calling a special superfield configuration is consistent; claiming that its restricted field content remains a superfield representation is not.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 307 4 Solution Created 2026-10-03 Updated 2026-10-06
First assume global four-dimensional N=1 supersymmetry, canonical positive Kähler potential, and tree level. Write and at the stationary vacuum. The chiral-superfield fermion mass matrix is the symmetric matrix , and the sum of squared Weyl spinor masses is . From the F-term scalar potential , its mixed and holomorphic Hessian matrix blocks areFor canonically normalized real and imaginary parts of the scalar fields, the real scalar mass matrix has trace twice the mixed trace. Its holomorphic blocks can split the two real scalar masses but do not change their sum. HenceA Weyl spinor has two spin states, so this proves the tree-level supertrace mass sum rule,The paper defines its supertrace with , the negative of the conventional boson-minus-fermion supertrace used here. The asserted zero is the same in either convention. The result requires the stated canonical tree-level hypotheses; a noncanonical Kähler metric, supergravity, or radiative corrections can change the sum rule.
If vector multiplets are also present, the gauge contributions to the F-term supertrace cancel rather than being omitted. At , define for the scalar expectation vector . Differentiating adds to the real-scalar trace. The symmetric gaugino-matter mass matrix has off-diagonal entries , giving an extra in its fermion squared-mass trace. The covariant scalar kinetic term gives vector squared-mass trace . Thus their contribution is . The gauge-theory result uses all spin states, including the vector weight three; it is not obtained by dropping massive gauge partners.
The MSSM tree-level sfermion mass constraint explains the phenomenological difficulty with direct visible-sector breaking. If F-term breaking is neutral under an unbroken electric and color gauge symmetry, and no D-term shifts are present, the same trace argument applies within each conserved-charge fermion block. Its corresponding scalar partners cannot all have squared masses above the mean of the light fermion squared masses. Thus canonical tree-level visible-sector supersymmetry breaking alone cannot make every squark and other scalar partner heavy while leaving the observed fermions light. The usual effective soft supersymmetry breaking terms arise after communicating breaking from a separate sector; integrating out that sector, noncanonical interactions and radiative effects evade the hypotheses. The global trace identity alone would not identify a particular light squark without the conserved-charge block argument.
For the specified O'Raifeartaigh model, phases may be chosen so that are real and positive. Its superpotential derivatives areand its F-term scalar potential isFor fixed , choose to minimize the final square. Since ,Thus makes a global minimum with arbitrary . The hierarchy ensures this for fixed perturbative , rather than for arbitrarily large . The origin is one member of this classically flat family, with and . The complex field is a pseudomodulus.
At the origin the chiral-superfield fermion mass matrix, in the basis, isIts physical fermion masses are ; the two massive Weyl spinors form one massive four-component fermion. The massless is the goldstino. More generally, stationarity gives , so the nonzero auxiliary field direction is a null vector of , proving the goldstino zero mode from vacuum stationarity.
Writing and similarly for , the quadratic scalar potential isThe mass spectrum of the quadratic-cubic O'Raifeartaigh model is thereforeThe scalar squared-mass sum is , while twice the fermion squared-mass sum is also , so the supertrace is zero, as required. The two massless real modes are tree-level pseudomoduli, which can be lifted by a quantum effective potential; their tree-level masslessness is not the exact symmetry protection enjoyed by the goldstino.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 308 1 Solution Created 2026-10-03 Updated 2026-10-14
Use the Minkowski metric with signature , and write . The Euler-Lagrange equation isFor the static phi-four kink, and , so the field equation is satisfied. The centre is arbitrary by translation invariance, and the hyperbolic tangent profile increases monotonically from to , crossing zero at . The static kink and its endpoint topological charge are
The phi-four kink rises between the two vacuum values and crosses zero at its centre
. Details. Both endpoint values are isolated classical vacua, since only at . A continuous finite-energy deformation preserving the vacuum boundary conditions cannot change either endpoint to the other isolated classical vacuum. The topological charge is therefore unchanged: this kink cannot deform into a homogeneous classical vacuum, whose charge is zero. There is also a direct Bogomolny bound in this sector. The square completion for a one-dimensional kink givesThe phi-four kink saturates the bound, so its mass is in these units and it minimizes the energy within its topological sector. Its arbitrary position is a collective coordinate, not an instability. A kink and an antikink together have total charge zero and can annihilate without contradicting the protection of an isolated kink.
For the momentum, the canonical stress-energy tensor of this scalar field isConsequently the physical spatial momentum density and the spatial momentum flux areThe sign of makes a right-moving translated kink carry positive momentum. Direct use of the field equation, rather than an assumed static field, yields the scalar-field momentum flux identityThe finite-energy field configuration has by . Integrating the stress-energy conservation law over the left half-line gives the boundary forceUnder the usual vacuum falloff, the stress at the left endpoint is zero. More generally, smooth spatial cutoffs with derivative of order remove the left endpoint using the integrable energy density, so no pointwise limit of every derivative at infinity is needed. The identity expresses the force on the field to the left of : positive force transfers momentum to the right. For well separated solitons, a cut between them measures the interaction force on the left soliton.
Take that cut at . The specified symmetric pair has, at the initial time,The printed field profile does not itself specify the initial velocity. If , the exact initial half-line force isFor the intended initially resting pair, or more generally , put and use . The at-rest force for a symmetric phi-four pair isThe leading force is attractive, towards the antikink:The antikink feels the opposite force by the symmetry of the resting pair. This is an initial, large-separation interaction calculation, not a claim that the superposed profile is an exact static two-soliton solution. Without the initial-velocity condition, the additional momentum flux above prevents a unique force from being inferred from the printed profile alone.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 310 2 c Solution Created 2026-10-03 Updated 2026-10-06
Because density is a scalar field, . Write both sides as background plus perturbation and expand the background time shift:The coordinate shift acting on an already first-order perturbation contributes only at second order. Thus the density perturbation gauge transformation isThe uniform-density curvature perturbation in the paper's sign convention isThe derivative on is essential and is present in the PDF; the TeX transcription drops it. The scalar-curvature combination transforms aswhile the density term changes by . Hence the two time-slicing changes cancel:On a uniform-density slice, and this variable is the signed spatial-curvature perturbation. The construction assumes ; a pure constant-density cosmological constant does not define such a time slicing.
In Newtonian gauge in cosmology, and . The background cosmological perfect-fluid continuity equation gives , so, writing ,Set the cosmological adiabatic sound speed . Then . Differentiate the previous expression and insert the perturbed energy-conservation equation:Consequently the curvature evolution equation in this sign convention isThe last equality defines the total energy-frame velocity by . For adiabatic cosmological perturbations, the non-adiabatic pressure perturbation vanishes. On superhorizon scales, the stated suppression of the velocity divergence makes the remaining gradient term negligible. Thus is conserved to leading order in . The positive sign of the pressure source follows from the paper's definition of and must not be replaced by a formula using the opposite curvature convention.
Superhorizon conservation of uniform-density curvature lets one carry a primordial perturbation from its inflationary generation through otherwise complicated eras and predict the initial conditions for later Cosmic microwave background anisotropy and structure growth. It relies on adiabaticity: an isocurvature perturbation can source curvature evolution, so the same conclusion is not automatic in an arbitrary multifield model.
