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The hydrogenosomes and mitosomes are specialized mitochondrion-related organelles found in various anaerobic or oxygen-limited eukaryotes. Typical hydrogenosomes support anaerobic ATP production, converting substrates such as pyruvate into products including acetate, carbon dioxide and molecular hydrogen. Substrate-level phosphorylation supplies ATP, while hydrogenase disposes of reducing equivalents as hydrogen; oxygen is not the terminal acceptor of a conventional respiratory chain in this pathway.^[ref]

The mitosomes retain selected essential metabolic functions but do not generate ATP by oxidative phosphorylation. In Giardia, their role includes iron-sulfur cluster assembly and protein maturation, demonstrated using organelle markers and biochemical reconstitution.^[ref] Their functions are lineage-dependent: Entamoeba histolytica mitosomes compartmentalize a sulfate activation pathway.^[ref] Thus neither organelle class should be described simply as a nonfunctional mitochondrion.

Atomic-resolution cryo-electron microscopy became possible by retaining high-frequency structural information through the whole experiment: specimen preparation, electron optics, detection and computation. The decisive advances improved the information obtained per damaging electron and made it possible to align and average many weak images without averaging away structural differences. A short de Broglie wavelength had always been available; the practical limit was preserving and extracting the information carried by those electrons.

First, vitrification preserves hydrated biological material in a thin noncrystalline layer of water. Rapid freezing avoids the strong periodic scattering and disruption associated with ordinary ice crystals, while cryogenic imaging slows some damage processes. The specimen still suffers radiation damage, and a thicker layer adds background and multiple scattering. Reproducible thin ice, clean grids, stable supports and reduced mechanical drift are therefore prerequisites. The specimen must remain structurally intact and occupy enough orientations for a three-dimensional reconstruction. Adsorption at the air–water interface, preferred orientation and variable thickness can defeat an otherwise excellent microscope. Sample optimization should include independent checks of assembly integrity and activity where feasible.

Second, direct electron detection greatly improved the useful signal relative to earlier indirect cameras. In a counting detector, individual electron events can be localized and recorded without treating the deposited signal merely as a continuous intensity. detective quantum efficiency measures how efficiently the detector preserves the input signal-to-noise ratio as a function of spatial frequency. High efficiency matters particularly because the permissible exposure is limited. At excessive event rates, overlapping events cause coincidence losses, so faster readout permits useful counting at practical collection rates. A nominally smaller camera pixel alone cannot replace a detector that preserves high-frequency information.

Fast detectors also turn an exposure into a sequence of movie frames. Aligning those frames corrects specimen drift and beam-induced movement; local correction handles different movements across the imaged area. Uncorrected movement preferentially smears fine features. dose weighting then combines early and later frames according to the information they retain: later exposure can help low-frequency alignment even after fine structural details have been damaged. ^[ref] exemplifies this computational use of detector movies. Frame alignment cannot restore chemistry already destroyed by radiation damage, and extremely noisy individual frames require constrained motion estimates.

Third, stable and coherent electron optics increase contrast transfer at the finest spacings. A narrow source energy spread reduces chromatic aberration, because electrons with different energies otherwise focus differently. A cold field emission gun provides one route; a monochromator provides another. An energy filter removes many inelastically scattered electrons that otherwise contribute background. This does not remove all damage or every unwanted scattering event. Improved mechanical and electrical stability, reproducible lens settings, accurate coma-free alignment and calibrated magnification make the information more consistent across images.

The 2020 apoferritin reconstructions illustrate the final hardware step. One study combined a cold source, improved energy filtering and a fast direct camera with advanced correction to obtain a map at about $1.22\text{A˚}$. Another used an instrument with monochromation and aberration correction to reach about $1.25\text{A˚}$.^[ref][ref] The two instruments demonstrate complementary ways of preserving coherent high-frequency information. These unusually rigid, symmetric particles are favorable test specimens; their resolutions do not imply that a flexible cellular assembly will reach the same limit.

Fourth, modern reconstruction treats the noisy images statistically. single-particle analysis estimates how many randomly oriented projections correspond to a common three-dimensional structure. Bayesian inference and maximum likelihood estimation permit uncertainty in image orientations and class membership to be handled rather than committing every weak image to a single exact alignment from the beginning. ^[ref] provides a concrete implementation. Two-dimensional classes reject many damaged or overlapping particles; three-dimensional classification can separate different compositions or conformations. Appropriate symmetry increases the effective information, but an incorrect symmetry assumption can erase a real asymmetric feature.

Refinement increasingly corrects individual particle movements and optical imperfections. Per-particle defocus estimates accommodate height differences in ice. Beam tilt, higher-order aberrations and anisotropic magnification need correction when their accumulated phase errors become important. The contrast transfer function changes the magnitude and sign of Fourier components; combining images recorded with different defocus values recovers information suppressed at particular transfer-function zeros. Near atomic spacings, accounting for Ewald sphere curvature can further improve reconstruction. Such corrections require adequate signal and calibration; simply adding more adjustable parameters to weak data risks fitting noise.

Automation and fast computation make these methods practical. Stable automated acquisition and beam-image-shift strategies collect large image sets; parallel computation permits repeated alignment, classification and refinement. More particles improve the average only if they carry consistent signal. Under an ideal independent-noise model, the amplitude signal-to-noise ratio improves in proportion to $\sqrt{N}$; a systematic alignment error or persistent structural heterogeneity will not disappear by this scaling. For a target spacing $d$ and real-space pixel size $a$, Nyquist–Shannon sampling theorem requires $a\le d/2$. For $d=1.2\text{A˚}$ this gives $a\le 0.6\text{A˚}$ per pixel, a necessary sampling condition rather than a guarantee of such resolution.

Validation is part of the technological achievement. Split particles into independent halves and refine them independently; calculate their Fourier shell correlation, commonly reporting the spacing at the $0.143$ criterion for independently refined half-maps. Shared high-resolution references, poorly handled masks or correlated data can inflate agreement, so independence and mask correction matter. Inspect directional coverage and local resolution, compare models against held-out map information, and check stereochemistry. The global resolution is a summary: flexible loops, bound lipids and minor components may be much worse than the ordered core.

Finally, distinguish an atomistic model from atomically resolved data. At ordinary near-atomic resolution, side chains and backbone features can support building an atomic model while individual neighboring chemical atoms are not all separated. At true atomic resolution, many individual atomic peaks become distinguishable and some hydrogen contributions may be detectable under favorable conditions. cryo-electron microscopy reconstructs scattering electrostatic potential, so interpretation of very fine features is not identical to interpreting X-ray crystallography electron-density maps. The breakthrough was the combined improvement of specimen quality, counting movies, optical coherence and statistical reconstruction, with independent validation showing that the fine detail was supported by the data.

A planar rigid rotor has angular eigenfunctions $e^{im\varphi }$ and single-valuedness imposes $m=0,\pm 1,\pm 2,\dots$. Its energy depends on $m^2$, so if the level is labelled by $J=|m|$, thenThe two states at $J>0$ represent opposite directions of angular momentum. If the signed quantum number itself is called $J$, each signed state is counted once instead; one must not both sum over both signs and multiply by two again.

For an unrestricted three-dimensional linear rigid rotor, $J=0,1,2,\dots$ has $M=-J,\dots ,J$ and state degeneracy $2J+1$, with $E_J={\hslash }^{2}J(J+1)/(2I)$. Planar confinement removes one rotational coordinate and changes both the spectrum and degeneracy. These are the spatial counts before nuclear spin statistics. For homonuclear hydrogen, the allowed even/odd spatial states must also be paired with the appropriate parahydrogen or orthohydrogen nuclear states, as considered explicitly in A8.

Define ${\theta }_{\mathrm{rot}}={\hslash }^2/(2I{k}_{\mathrm{B}})$. Summing the spatial states counted in part (c),When $T\gg {\theta }_{\mathrm{rot}}$ the closely spaced terms can be replaced by a Gaussian integral:Here labelled means that the two ends of the molecular axis were distinguished in the angular count. In the usual high-temperature molecular convention that removes equivalent orientations and factors out nuclear-spin multiplicity, divide by the rotational symmetry number $s=2$ for homonuclear hydrogen:The full exact spin isomers of hydrogen count is instead the even-$m$ spatial sum plus three times the odd-$m$ sum; its high-temperature limit is $2\sqrt{\pi T/{\theta }_{\mathrm{rot}}}$, including the four nuclear-spin states. These conventions differ only by temperature-independent factors in this limit. All give $U_{\mathrm{rot},\mathrm{m}}=RT/2$ and $C_{V,m}^{\mathrm{rot}}=R/2$, consistent with one quadratic rotational degree of freedom. By comparison, the free linear rigid rotor has $q_{\mathrm{rot}}\propto T$ and $C_{V,m}^{\mathrm{rot}}=R$.

At low temperature, retain $J=0$ in the even sum and $J=1$ in the odd sum. Their weights are respectively $1$ and $3e^{-2{\theta }_{\mathrm{rot}}/T}$ before the nuclear-spin multiplicity, soEquilibrium hydrogen then becomes almost entirely parahydrogen. At high temperature, many even and odd rotational levels contribute, and their spatial sums have the same leading value. HenceThis is normal hydrogen. Its familiar high-temperature ratio is a nuclear-spin multiplicity ratio, not the $9:1$ ratio of the two lowest levels. Maintaining conversion is essential: a sample cooled without an effective conversion mechanism can retain its earlier composition instead of following $K(T)$. NBS thermodynamic data distinguish equilibrium composition from normal hydrogen and compare the state-sum prediction with spectroscopic and thermal evidence.^[ref]

Each hydrogen lies on the radial line through its attached carbon. Consequently every molecular symmetry operation fixes or permutes the hydrogen sites exactly as it does the carbon sites, and the Cartesian trace is the same. Thus ${\Gamma }_H={\Gamma }_C$ and the complete benzene displacement group representation is ${\Gamma }_{3N}=2{\Gamma }_C$, of dimension $36$.

Subtract translations $A_{2u}+E_{1u}$ and rotations $A_{2g}+E_{1g}$. The full set of normal modes isThe one-dimensional components contribute $2+1+2+1+2+2=10$ coordinates. The two-dimensional components contribute $2(1+4+3+2)=20$, giving $30=3(12)-6$ vibrational degrees of freedom. There are twenty distinct symmetry-labelled fundamentals before accidental coincidences, because each doubly degenerate pair has one frequency.

Subtracting translations and rotations directly from the carbon-only result would instead give twelve carbon-skeleton coordinates. That is a six-site mechanical model, not all the normal modes of ${\mathrm{C}}_6{\mathrm{H}}_6$. The hydrogen contribution is required for the actual molecule.

From the complete normal mode result, the vibrational infrared activity belongs toThe $A_{2u}$ fundamental couples to the out-of-plane dipole component and each $E_{1u}$ fundamental to the two in-plane components. Counting one frequency for each degenerate pair, the expected number is $1+3=4$ fundamental bands, containing seven vibrational coordinates.

This is the symmetry count for the full molecule, including hydrogen displacements. The experimental compilation likewise lists the out-of-plane $A_{2u}$ fundamental and three $E_{1u}$ fundamentals; anharmonic resonances and weak intensity borrowing can produce additional observed features beyond the ideal fundamental count.^[ref]

Let $\mathrm{Ar}$ denote the 2,5-dimethoxyphenyl group. A is the doubly C-alkylated beta-ketoesterThe central carbon has no hydrogen after the second step. The alkene, ester and tert-butyl ether remain intact.

carbonate reversibly removes a proton from the methylene group between the two carbonyl groups. The resulting resonance-stabilized enolate attacks the primary iodoethyl carbon of the aryl-containing reagent by an $S_{\mathrm{N}}2$ displacement, releasing iodide. The monoalkylated intermediate still has one proton at the same activated carbon. A second deprotonation followed by $S_{\mathrm{N}}2$ attack on the primary bromide introduces the but-3-en-1-yl group.

The beta-dicarbonyl position is much more acidic than the methylene group next to the ketone and ether at the other end, explaining the alkylation site. Counting the retained carbon skeleton gives ${\mathrm{C}}_{24}{\mathrm{H}}_{36}{\mathrm{O}}_6$, including the two carbonyl groups and one terminal alkene. The second panel of the original product drawing specifies this connectivity.

Number the enone carbonyl carbon C1, the adjacent alkene carbon C2 and the ethoxy-bearing alkene carbon C3. In the bromine-first pathway, the enol-ether-like $C2=C3-\mathrm{OEt}$ unit attacks $\mathrm{B}{\mathrm{r}}_2$ at C2, breaking the Br–Br bond. The intermediate has a new C2–Br bond and positive charge at C3, stabilized as an oxonium chemical resonance contributor by donation from the ethoxy oxygen.

triethylamine removes the remaining C2 hydrogen. Its C–H bonding pair reforms C2=C3 and neutralizes the oxonium system. The result is replacement of the vinylic C2–H by C2–Br, with the original enone and ethoxy group retained. If bromide first captures the cationic intermediate, the equivalent vicinal dibromide can eliminate HBr to reach the same product.

The ethoxy group makes this alkene sufficiently electron-rich for the electrophilic-addition description. It is important to place bromine at C2 and restore the double bond, rather than stop at a saturated addition product.

Both reactions are E2 eliminations requiring an axial chloride and an axial beta hydrogen in an antiperiplanar conformation relative to the C–Cl bond. The reacting C–H bond supplies the alkene $\pi$ bond as the C–Cl bond breaks; hydroxide accepts the proton.

For the trans-1,2 substrate, the low-energy chair has methyl and chlorine both equatorial. ring inversion is needed to place chlorine axial, but this also places methyl axial. The population of the reactive chair is consequently small, explaining the slow reaction. At the methyl-bearing neighboring carbon the axial position is occupied by methyl, not hydrogen. Only the other beta carbon has the needed anti axial H, so elimination gives 3-methylcyclohexene rather than the more substituted alkene.

For the cis substrate, a favorable chair has methyl equatorial and chlorine axial. It can react without paying the axial-methyl penalty, explaining the faster rate. Both adjacent carbons now supply an anti axial hydrogen. Removing the H on the methyl-bearing carbon gives 1-methylcyclohexene, the major product; removing the other gives 3-methylcyclohexene, the minor product. The former has the more substituted double bond.

Thus alkene stability selects between accessible pathways in the cis case, but it cannot create the missing antiperiplanar conformation H in the trans case.

The alcohol oxygen attacks sulfur of methanesulfonyl chloride, chloride leaves, and triethylamine removes the O–H proton. This gives an O-mesylate with retention of the carbon configuration: the original carbon–oxygen bond has not been displaced.

An accessible chair places the mesylate axial. triethylamine then removes the anti axial hydrogen on the carbon between the ketone and mesylate. Its C–H bond forms the new C=C bond while the C–O bond expels mesylate. The result is the conjugated cyclohexenone.

The neighboring carbon on the acetonide side has its relevant axial position occupied by its oxygen substituent, rather than an anti axial hydrogen. The elimination toward the ketone is therefore favored both by the trans-diaxial geometry and by conjugation of the resulting alkene with C=O. The acetonide remains intact. No inversion of the original alcohol carbon is required during mesylation, and it becomes planar during elimination.

B is the major product: the newly formed OH is the dashed bond in the printed zigzag structure. Retain the existing solid-wedge OH and the configuration at the carbamate-bearing carbon.

zinc coordinates the ketone oxygen and the adjacent hydroxyl oxygen, forming a five-membered O–Zn–O chelate. This constrains rotation around the carbonyl–alpha-carbon bond. In the favored chelated conformation the bulky $\mathrm{CH}(\mathrm{NHC}{\mathrm{O}}_2{\mathrm{R}}^{\prime })\mathrm{C}{\mathrm{H}}_2\mathrm{OR}$ group shields one face of the ketone, while the alpha hydrogen leaves the other more accessible. hydride attacks from that less crowded face, the carbonyl $\pi$ bond opens onto oxygen, and aqueous work-up gives the second alcohol.

Mapping this Cram chelation model back onto the printed zigzag gives B, not A. Merely placing a new OH “on the same side” of an unrotated page drawing is not a valid chelation argument: the reactive chelate and that drawing use different conformations. Zinc-borohydride reductions of alpha-hydroxy ketones are experimentally known to favor the corresponding anti-1,2-diol family under chelation control.^[ref]

The reagent combination can generate zinc borohydride and related zinc-associated reducing species. The stereochemical justification is coordination-controlled facial selectivity; it does not require identifying a unique solution aggregate from the reagent list. The quoted yield is not itself a measurement of a 95:5 diastereomeric ratio.

The first step is a vinylogous aldol condensation at C5 of the unsaturated lactam. Number nitrogen N1, the lactam carbonyl C2, and then the methoxy-substituted alkene C3=C4 and the methylene group C5.

hydroxide reversibly removes a C5 proton. The resulting vinylogous enolate is delocalized through C5–C4–C3–C2–O: it is not necessary to create an unstabilized isolated carbanion beside nitrogen. Its C5 nucleophilic contributor attacks acetone. protonation gives a C5-linked tertiary alcohol, $C5-\mathrm{C}(\mathrm{OH})(\mathrm{Me}{)}_2$. Further removal of the remaining C5 hydrogen and elimination through an aldol-dehydration sequence forms C5=C(Me)2, leaving the original methoxy enol ether in place.

In the second step, aqueous acid hydrolyses that enol ether to a ketone at C4. protonation at C3 gives an oxygen-stabilized cation at C4. water attacks C4, proton transfers form a hemiacetal-like intermediate, and loss of methanol followed by deprotonation produces C4=O and the C3 methylene group.

The lactam carbonyl and N–H group remain, as does the exocyclic isopropylidene group. This accounts for replacement of the C3=C4–OMe unit by C3H2–C4=O without inserting a new oxygen into the ring skeleton.

The hydroxyl group first binds aluminium, normally by deprotonation to an aluminium alkoxide with release of hydrogen. Coordination also brings aluminium close to the alkyne. directed trans-hydroalumination then puts hydride on the alkyne carbon proximal to CH2O and aluminium on the distal carbon.

One useful mechanistic description has external hydride attacking the coordinated alkyne opposite the aluminium-containing face. The resulting vinylaluminate is stabilized by a five-membered O–Al–C–C–CH2 chelate. This is not the ordinary undirected syn addition of a neutral dialkylaluminium hydride. Propargylic-alcohol-directed trans-hydroalumination with Red-Al gives vinylaluminate intermediates that can be intercepted by electrophiles.^[ref]

iodine replaces the distal C–Al bond with C–I without scrambling the alkene geometry; aqueous work-up releases the alcohol. hydride and iodine are consequently trans across the alkene, while iodine and the CH2OH group are on the same side.

By Cahn-Ingold-Prelog priority rules priority the product is therefore $Z$: CH2OH outranks H at one alkene carbon and I outranks CH2R' at the other. Describing the two carbon chains as trans would not make this an $E$ alkene, because the iodine changes which substituent has higher priority.

Two molecules of the aminopyridine form a self-complementary dimer through two N–H···N contacts. In each direction, one exocyclic amino hydrogen is the donor and the pyridine ring nitrogen of the other molecule is the acceptor.

Orient the two amino/pyridine-N edges toward one another, as in the second panel of the original homodimer drawing. Each molecule donates one NH and accepts at one ring N; the second amino H remains available for additional packing contacts. The chlorine substituent is retained but is not one of the two principal donor–acceptor sites.

Two molecules of the carboxylic acid form a cyclic carboxylic-acid dimer. Let Ar denote the meta-methylphenyl group. One molecule donates its OH hydrogen to the other's carbonyl oxygen, and the second donates back:
The two contacts close an eight-membered hydrogen-bonded ring, shown explicitly below.

Both molecules therefore act once as hydrogen-bond donor and once as hydrogen-bond acceptor, giving two O–H···O=C contacts. This is the conventional self-complementary dimer motif; the schematic is not a prediction of every weaker contact in an unprovided crystal structure.

B is 1,3-dibromo-2-hydroxyxanthone: both bromines are on the hydroxy-substituted outer ring, at its two available positions ortho to OH. Define C2 as the OH-bearing carbon; C1 lies between it and the carbonyl-side ring junction, and C3 lies on its other side. These labels specify the substitution independently of the orientation of the printed drawing.

Phenolic lone pair donation strongly activates its ortho and para positions towards electrophilic substitution. The para position is a fused junction and has no replaceable hydrogen, leaving C1 and C3 as the two directly activated sites. C1 also benefits from the conjugative influence of the ring ether oxygen. Although other positions receive some activation from that oxygen, they lack the stronger local phenolic activation of the selected pair. Excess bromine can therefore replace both ortho hydrogens. Replacing two hydrogens in ${\mathrm{C}}_{13}{\mathrm{H}}_8{\mathrm{O}}_3$ gives ${\mathrm{C}}_{13}{\mathrm{H}}_6\mathrm{B}{\mathrm{r}}_2{\mathrm{O}}_3$, consistent with the stated composition. Addition across an outer-ring double bond would sacrifice aromaticity and would not account for the hydrogen loss.

amide ion removes a methyl-side alpha proton of pinacolone. The C–H electrons form the enolate C=C bond as the carbonyl pi pair moves onto oxygen; ammonia is formed. The tert-butyl-side alpha carbon has no hydrogen, fixing the ordinary enolate regiochemistry.

The carbon end of D attacks the acyl chloride carbonyl carbon. Move the C=O pi pair onto oxygen, then collapse the tetrahedral intermediate with chloride departure. This nucleophilic acyl substitution gives $\mathrm{tCO}-\mathrm{C}{\mathrm{H}}_2-\mathrm{COt}$ and constructs the bond between the original enolate methylene and the incoming carbonyl. The observed product requires carbon acylation, rather than an O-acyl enol ester. A further equivalent of D removes the much more acidic central proton of the new 1,3-diketone, generating its extensively delocalized enolate and returning that second D equivalent to pinacolone. Aqueous acid workup protonates the product enolate; keto–enol equilibration gives the conjugated, internally stabilized by a hydrogen bond enol observed by NMR. The acyl chloride contributes its entire pivaloyl group; neither tert-butyl group is lost.

Write $t=\mathrm{C}(\mathrm{C}{\mathrm{H}}_3{)}_3$. D is the sodium enolate $\mathrm{t}-\mathrm{C}({\mathrm{O}}^{-})=\mathrm{C}{\mathrm{H}}_2\mathrm{N}{\mathrm{a}}^{+}$. Its two resonances in the alkene-proton region belong to the two hydrogens of the terminal methylene group. One is cis to oxygen and the other trans to oxygen, so they are not related by a symmetry operation even though both belong to the same carbon. Replacing one or the other gives different alkene geometries, so they are diastereotopic. Their weak or unresolved geminal coupling is consistent with the reported singlet descriptions. Without an additional spatial assignment, it is not justified to decide uniquely which numerical shift belongs to which of those two orientations. The nine-proton singlet is the tert-butyl group. The formula ${\mathrm{C}}_6{\mathrm{H}}_{11}\mathrm{ONa}$ follows from removing one alpha hydrogen from pinacolone.

E is the enol-dominated 1,3-diketone $\mathrm{tCO}-\mathrm{C}{\mathrm{H}}_2-\mathrm{COt}$, observed as $\mathrm{tC}(\mathrm{OH})=\mathrm{CH}-\mathrm{COt}$. The very downfield broad signal belongs to the enol OH in a six-membered intramolecular O–H···O chelate. The one-proton signal in the vinyl region is its central enol CH; a predominantly diketo structure would instead require a two-proton central CH2 signal and no enol OH. The eighteen-proton singlet accounts for both tert-butyl groups. Rapid exchange between the two degenerate enol orientations can average their different local environments; accidental unresolved equality cannot be excluded by the supplied spectrum alone. Thus one should not infer a permanently symmetric single enol Lewis structure from that singlet. The total integration is $1+1+18=20$, agreeing with ${\mathrm{C}}_{11}{\mathrm{H}}_{20}{\mathrm{O}}_2$.

Let $\mathrm{Ar}=4-\mathrm{N}{\mathrm{O}}_2{\mathrm{C}}_6{\mathrm{H}}_4$ and number the carbon substituent from oxygen: $\mathrm{ArO}-\mathrm{C}{\mathrm{H}}_2(1)-\mathrm{C}{\mathrm{H}}_2(2)-\mathrm{C}{\mathrm{H}}_2(3)-\mathrm{CN}$. sodium hydride removes a proton from C3, alpha to the nitrile, forming hydrogen and a nitrile-stabilized carbon anion. That carbon attacks the nitroaryl ipso carbon bearing O. The tether closes a five-membered cyclic Meisenheimer intermediate with sequence C3–C2–C1–O–aryl ipso carbon. The para nitro group stabilizes the negative charge generated by temporary loss of aromaticity.

Rearomatization breaks the aryl–O bond, releasing the tether oxygen as an alkoxide while retaining the new aryl–C3 bond. protonation gives $\mathrm{Ar}-\mathrm{CH}(\mathrm{CN})-\mathrm{C}{\mathrm{H}}_2-\mathrm{C}{\mathrm{H}}_2\mathrm{OH}$. This is a Truce–Smiles rearrangement: the aryl group migrates from oxygen to carbon. The nitrile remains attached to its original side-chain carbon; the original ether oxygen becomes the terminal alcohol oxygen. The substrate and product have identical atomic composition. Ordinary substitution at a saturated chain carbon would not produce this aryl–carbon bond or restore the terminal OH.