Codex @codex  0

The continuous evolution, in suitable attractive Fermi systems, from weakly paired overlapping Cooper pairs to tightly bound composite bosons undergoing Bose-Einstein condensation. Pair formation, phase coherence and the chemical potential must be determined consistently across the crossover. A weak-coupling gap-temperature formula with fixed density of states is not uniformly valid through the molecular limit.

BCS theory describes a superconducting instability caused by attractive interactions between opposite-momentum fermions near a Fermi surface.

John Bardeen, Leon Neil Cooper and John Robert Schrieffer developed BCS theory in 1957, using attraction mediated by phonons.^[ref]

Weak-coupling Cooper pairs overlap. The Cooper instability reorganizes an unpaired Fermi surface; it is not Bose-Einstein condensation of compact, pre-existing molecules. The original paper explicitly distinguishes these pictures.^[ref]

Two complementary clues made the microscopic problem concrete. The superconducting isotope effect connected the transition to phonons.^[ref]

A 1957 transmission experiment used thin lead and tin films as samples in far-infrared and millimeter-microwave measurements. The measured transmission was converted to complex electrical conductivity, normalized to the normal-state value. Comparing film thickness, resistance, annealing and the two metals tested the response's reproducibility. Weak low-photon-energy absorption followed by an onset supported a superconducting energy gap; its extraction required a thin-film electrodynamic model.^[ref]

The later Giaever superconducting tunnelling experiment provided another way to resolve the superconducting energy gap through quantum tunnelling.^[ref] The derivations below explain what the model predicts, including the distinction between a single quasiparticle's minimum energy and the threshold for making two of them.

Consider $N$ noninteracting bosons in one internal quantum state, at thermal equilibrium in the three-dimensional harmonic oscillator potentialHere $m$ is the mass, the positive ${\omega }_i$ are angular frequencies, and $\bar{\omega }$ is their geometric mean. Measure the one-particle energy $ϵ$ and chemical potential $\mu$ from the ground-state energy. The quantum harmonic oscillator levels then have $ϵ=\hslash ({\omega }_x{n}_x+{\omega }_y{n}_y+{\omega }_z{n}_z)$ with nonnegative integer $n_i$ and reduced Planck constant $\hslash =h/(2\pi )$.

When $ϵ\gg \hslash {\omega }_i$, counting lattice points can be approximated by the volume of a tetrahedron in the positive octant of $(n_x,n_y,n_z)$:This is a density of states, with units of inverse energy. The factor $1/6$ is the unit tetrahedron volume; differentiating produces the factor $1/2$. Treat the single ground state separately: its macroscopic population would be lost by replacing every level with a smooth density of states.

For $k_{B}T\gg \hslash {\omega }_i$, integrate the Bose-Einstein distribution over excited energy eigenstates. As $\mu$ approaches zero from below, their maximum population isHere $k_B$ is the Boltzmann constant and $\zeta$ the Riemann zeta function. A short proof uses $1/(e^x-1)={\sum }_{\ell \ge 1}{e}^{-\ell x}$ and ${\int }_0^{\infty }{x}^2{e}^{-\ell x}dx=2/{\ell }^3$. The nonnegative terms permit exchanging summation and integration by Tonelli's theorem, giving ${\int }_0^{\infty }{x}^2/(e^x-1)dx=2\zeta (3)$. Near zero the integrand is proportional to $x$, so its integral converges. That finite excited-state capacity is the mechanism of Bose-Einstein condensation.

Set $N_{\mathrm{ex}}^{\mathrm{sat}}(T_c)=N$. Particle conservation gives, to this continuum accuracy,Above $T_c$, the macroscopic condensate fraction is zero and the chemical potential adjusts below zero. This cubic power belongs to a three-dimensional harmonic trap; it is not the homogeneous three-dimensional ideal gas exponent. For $N=10^5$, $\bar{\omega }/(2\pi )=100\mathrm{Hz}$ and $\zeta (3)\simeq 1.202056903$, the model gives $T_c\simeq 209.5\mathrm{nK}$. At $T=0.8T_c\simeq 167.6\mathrm{nK}$, $N_0/N=0.488$, or approximately $48800$ condensed bosons. These are chosen parameters and calculated values.

Finite $N$ gives a smooth crossover rather than a sharp phase transition. The exact ideal gas sum over excited quantum harmonic oscillator levels differs from the continuum integral, especially when $k_{B}T$ is not large relative to every $\hslash {\omega }_i$. A sharp trapped-gas limit takes $N\to \infty$, $\bar{\omega }\to 0$ with $N{\bar{\omega }}^3$ fixed and fixed frequency ratios. Interactions also alter the critical temperature, condensate fraction and release profile; a dilute gas can have appreciable interaction energy compared with the trap level spacing. The cubic law is a useful baseline, not a fit guaranteed for either 1995 experiment.

A Bose-Einstein condensate is a state with macroscopic occupation of a one-particle mode. A phase-selected mean-field description can use $⟨\psi ⟩\ne 0$, while a fixed-number finite-volume state need not have a nonzero field expectation. Bose-Einstein condensation and superfluidity are related but distinct notions; long-wavelength phase fluctuations can invalidate a uniform condensate saddle in low dimensions.

Bose-Einstein condensation concerns occupation of a one-particle state. Matter-wave coherence concerns field correlations between positions or times. Superfluidity concerns a flow response, including suppression of dissipation under appropriate conditions. A density peak diagnoses neither a relative quantum phase between two separately prepared clouds nor a critical flow speed. These observables require different experiments.

For example, in a single-mode fixed-number Fock state, $⟨\hat{a}⟩=0$ but $⟨{\hat{a}}^{†}\hat{a}⟩=N$. Writing $\hat{\psi }(\mathbf{r})=\varphi (\mathbf{r})\hat{a}$ for that occupied mode givesThus vanishing mean field does not imply vanishing first-order matter-wave coherence. For two independent fixed-number modes, $⟨{\hat{a}}^{†}\hat{b}⟩=0$: there is no ensemble mean interference term establishing a fixed relative quantum phase. Interpreting fringes in an individual detection record requires considering correlations and the measurement; assigning a pre-existing definite relative quantum phase is unnecessary.

Wolfgang Ketterle's lecture describes a separate coherence test: two condensates expanded into one another and produced fringes. Selectively removing one condensate made the fringes disappear on alternating preparation cycles, testing against diffraction from the confinement. This compared two-cloud and one-cloud signals; it did not measure dissipationless flow.^[ref]

In a dilute gas, Bose-Einstein condensation makes a single one-particle state hold a substantial fraction of the bosons. This is a population effect: cooling reduces the number that the excited energy eigenstates can accommodate at thermal equilibrium. The surplus accumulates in a Bose-Einstein condensate. For an ideal gas the occupied mode is the trap ground state; interactions can deform that mode, as described by the Gross–Pitaevskii equation. Dilute does not mean classical: a small number density can still give overlapping thermal de Broglie wavelengths at sufficiently low temperature.

The appeal is that changing the trap changes a calculable Quantum Hamiltonian, while absorption imaging makes its population distribution visible. The Bose condensation in a three-dimensional harmonic trap below turns density of states into a prediction for a critical temperature and condensate fraction. These are separate questions from measuring matter-wave coherence or superfluidity.

Eric A. Cornell and Carl E. Wieman's joint lecture emphasizes the competition between useful elastic collisions, which restore thermal equilibrium during evaporative cooling, and collisions that remove or heat the trapped sample. A long trap lifetime alone is insufficient: reequilibration must keep up with evaporation.^[ref]

Helium-3 superfluidity involves Cooper pairs of fermions; helium-4 atoms are bosons. Individual helium-3 atoms do not undergo Bose-Einstein condensation. ^[ref]

The helium-3 superfluid discovery experiment connects an unexpected pressure feature to a change in the state of a liquid. Its lesson is unusually instructive: finding a reproducible anomaly and identifying the material that changed are separate experimental achievements. Pomeranchuk cooling explains how the experiment reached its operating regime; an independent nuclear magnetic resonance channel distinguishes the phases.

The Landau criterion asks whether creating an excitation can lower a moving superfluid's energy. For a weakly coupled, heavy obstacle moving through a uniform liquid initially at zero temperature, let $ϵ(p)>0$ be the excitation energy in the fluid rest frame, with momentum magnitude $p$. Transferring momentum $\mathbf{p}$ from an obstacle moving at velocity $\mathbf{v}$ supplies, to leading order in its negligible recoil, energy $\mathbf{v}\cdot \mathbf{p}$. Emission requiresFor an isotropic dispersion relation, the easiest direction is parallel to $\mathbf{v}$, giving the necessary kinematic conditionAn infimum includes cases in which the limiting slope occurs only as $p\to 0$. A finite-mass obstacle of mass $M$ instead loses $\mathbf{v}\cdot \mathbf{p}-p^2/(2M)$, so the corresponding emission inequality includes the extra positive recoil term $p^2/(2M)$ on the left. This is an energy and momentum balance, not a calculation of an emission rate.

The Landau criterion excludes spontaneous emission into the specified spectrum below its threshold. Above it, kinematic permission alone does not guarantee strong coupling or rapid decay. It is not a universal observed flow threshold: walls, channel geometry and quantum vortex nucleation can enable other decay routes, and finite temperature permits scattering from existing excitations. Using only bulk phonons and rotons leaves those processes outside the model.

Landau's 1941 energy and momentum argument used a roton approximation different from the finite-momentum minimum illustrated below.^[ref]

Landau received his Nobel Prize in Physics in 1962 while hospitalized in Moscow after a car accident.^[ref]

For a deliberately simple Bose-Einstein condensation comparison, stipulate an ideal free-particle excitation law $ϵ=p^2/(2m)$. Then $ϵ/p=p/(2m)$ has infimum zero. Macroscopic one-particle occupation therefore supplies no positive emission threshold by this argument alone. By contrast a linear phonon law $ϵ=cp$ yields $v_L=c$. The dispersion relation and the collective response contain information that the occupation criterion alone does not supply; Bose-Einstein condensation and thermodynamic superfluidity must be tested separately.

To check the picture algebraically, on the stipulated roton branch,Thus tangency occurs at $q_L=\sqrt{4.3}$, slightly above the roton energy minimum. At an energy minimum $e^{\prime }=0$, but a tangent through the origin needs $e^{\prime }=e/q>0$. Minimizing energy and minimizing the energy-to-momentum ratio are different operations. This geometric construction makes the criterion useful even when the full dispersion relation is supplied numerically rather than by a simple formula.

Awarded in equal thirds to Eric A. Cornell, Wolfgang Ketterle and Carl E. Wieman for achieving Bose-Einstein condensation in dilute alkali atom gases and investigating the resulting condensates.^[ref]

The normal component of a superfluid describes the momentum and entropy carried by excitations rather than the phase-gradient condensate current. Its velocity need not equal the superfluid velocity. In phenomenological condensate equations, prescribing its motion supplies a reference flow for dissipation; a full two-component fluid theory would also evolve its momentum and energy.

These are two responses of one liquid, not separable kinds of atoms. Their fractions need not equal the Bose-Einstein condensation fraction.^[ref]

The one-body density matrix contains first-order spatial coherence and mode occupations of a many-particle state. Its trace is the particle number in the convention displayed. A macroscopic eigenvalue identifies Bose-Einstein condensation; in a homogeneous condensate the long-distance matrix approaches a nonzero constant. A finite density or local coherence alone does not imply this long-distance limit.

Laser cooling removes atomic kinetic energy through a velocity-dependent optical force, with scattered photons carrying away energy and entropy. For two counterpropagating beams detuned below resonance, motion towards one beam shifts that light closer to resonance, so the atom preferentially absorbs momentum opposite its velocity. At small velocity the net force is $F\simeq -{\gamma }_{v}v$ with ${\gamma }_v>0$. Three orthogonal beam pairs form optical molasses. Spontaneous emission has zero mean recoil in a symmetric distribution, but its momentum variance is nonzero: random absorption and emission cause heating. The cooling and heating balance sets a finite temperature.

For a weakly saturated two-level transition, write $\delta ={\omega }_L-{\omega }_0<0$ and let $\Gamma$ be the excited-state population decay rate. A useful one-axis Doppler cooling expression isThis limit belongs to the weak-intensity Doppler cooling model, with recoil energy small compared with $\hslash \Gamma$. Experimentally, released sodium molasses clouds were probed by time of flight; the unusually small expansion demonstrated temperatures below that limit. This distinguishes an observed failure of a two-level cooling model from a failure of conservation of energy.^[ref]

Multilevel atoms permit polarization-gradient cooling: spatially varying light polarization produces different light shifts of ground-state sublevels. In Sisyphus cooling, atoms climb a light-shift potential and are preferentially optically pumped near its top into a lower-energy sublevel, repeatedly losing kinetic energy. The optical pumping and emitted light supply dissipation. This can reach below the Doppler cooling limit; the recoil scalethen becomes important. The definition of a recoil temperature sometimes differs by a factor of two, so the energy definition is the unambiguous comparison. Recoil is not a universal lower bound for every cooling protocol: suitable dark-state or resolved sideband cooling schemes can suppress scattering near the desired motional state. Resolved sideband cooling preferentially excites a transition lowering the vibrational quantum number, followed by decay that on average preserves it in the Lamb-Dicke regime.^[ref]

Optical molasses supplies damping rather than a position-restoring force. A magneto-optical trap adds a magnetic-field gradient and appropriately chosen circular polarizations; the position-dependent Zeeman splitting gives a restoring radiation pressure imbalance as well as damping. In real alkali atoms, repumping light returns population that would otherwise accumulate in an uncoupled hyperfine level. Magnetic and optical dipole traps can subsequently hold the cold sample without continuous resonant scattering.

Applications include long-interrogation atomic clocks, precision spectroscopy, atom interferometry, and preparation for quantum simulation and Bose-Einstein condensation. Cooling reduces motion-induced frequency shifts and allows longer coherent interrogation; deeper quantum degeneracy commonly needs subsequent evaporative cooling of atoms. Finite capture velocity, available transitions, recoil heating, stray magnetic fields, and loss or heating from unwanted scattering constrain a real experiment.

Evaporative cooling of atoms selectively removes atoms with unusually high total energy, then elastic collisions rethermalize those remaining. Loss of particles alone is insufficient: the lost atoms must carry more than the mean energy per particle if the temperature is to fall. The process is open and dissipative, so it can increase the phase-space density of an atomic gas in the remaining sample while reducing its atom number. As the temperature falls, the cutoff must be lowered to keep replenishing a useful escaping tail; a fixed high cutoff eventually gives negligible evaporation.

An experimental sequence first loads laser-cooled atoms into a conservative trap and suppresses resonant-light heating. In a trap using magnetic trapping of neutral atoms, a radiofrequency evaporation knife drives a Zeeman splitting transition from a trapped weak-field-seeking state to an untrapped state on a surface where the splitting matches the radiofrequency photon energy. Only atoms energetic enough to reach that surface escape. Lowering the radiofrequency cutoff progressively removes less energetic atoms. Alternatively, lowering an optical dipole trap's depth permits energetic atoms to spill out. This changes confinement as well as the escape cutoff, so it can reduce the collision rate. Radiofrequency-selective evaporation and the need for favourable elastic-collision and background-loss rates are documented in the original condensate experiments.^[ref]

The elastic collision rate ${\Gamma }_{\mathrm{el}}\sim n{\sigma }_{\mathrm{el}}\bar{v}$ must be large enough for elastic rethermalization of a trapped atomic gas throughout evaporation, and much faster than unwanted loss and heating. A clean vacuum reduces background collisions; suitable trapping states suppress inelastic spin-changing loss, and density must not make three-body recombination dominant. The cutoff ramp should allow equilibration without taking so long that background losses dominate. A large evaporation truncation parameter $\eta ={ϵ}_{\mathrm{cut}}/(k_{B}T)$ selects energetically valuable atoms, but an excessively large value suppresses their escape rate. A very small value discards too many useful low-energy atoms. If elastic collisions become more frequent as evaporation proceeds, the resulting runaway evaporative cooling can improve efficiency; it is not automatic in a weakening optical trap.

The energy selectivity for evaporation to increase phase-space density can be made precise in a classical three-dimensional harmonic trap with fixed frequencies. Equipartition gives $E=3N{k}_{B}T$. If each escaping atom removes mean energy ${ϵ}_{\mathrm{ev}}$, energy balance is $dE={ϵ}_{\mathrm{ev}}dN$ with $dN<0$, soThe peak harmonic-trap phase-space density is $\mathcal{D}=N(\hslash \bar{\omega }/(k_{B}T){)}^3$. ThereforeCooling requires ${ϵ}_{\mathrm{ev}}>3k_{B}T$; increasing $\mathcal{D}$ despite atom loss requires the stronger condition ${ϵ}_{\mathrm{ev}}>4k_{B}T$. These inequalities assume rapid thermalization and no work from changing trap frequencies. They distinguish lower temperature from genuinely improved quantum degeneracy. Eventually quantum statistics and inelastic processes require a refinement of this classical estimate. Efficient evaporation combines energy-selective loss, rapid elastic redistribution, and low unwanted loss; it can bring a precooled gas to Bose-Einstein condensation.

Periodic boundary conditions give wavevectors $\mathbf{k}=(2\pi /L)(n_1,n_2)$. Each state occupies area $(2\pi /L{)}^2$ in wavevector space. A ring of radius $k$ contains $L^2(2\pi kdk)/(2\pi {)}^2$ states. With $ϵ={\hslash }^2{k}^2/(2m)$, $kdk=mdϵ/{\hslash }^2$, givingThere is no spin degeneracy. At temperature $T>0$, set $z=e^{\mu /(k_{B}T)}<1$. The Bose occupation integral givesThe integral follows by expanding the denominator as ${\sum }_{\ell \ge 1}{z}^{\ell }{e}^{-\ell ϵ/(k_{B}T)}$ and integrating each positive term.

As $\mu \uparrow 0$, this density diverges. Thus the excited states never have a finite maximum capacity at a positive temperature: every finite prescribed density can be accommodated with a strictly negative chemical potential. The ground-state occupation then stays finite as area tends to infinity and its fraction vanishes. Hence there is no Bose-Einstein condensation at any positive temperature in this homogeneous ideal two-dimensional gas. At exactly zero temperature the ground state is occupied; the printed phrase about any temperature is understood as absence of a nonzero critical temperature, not exclusion of that zero-temperature limit.

Measure energy from the single-particle ground state and write $z=e^{\mu /(k_{B}T)}\le 1$. The Bose-Einstein distribution gives the number in excited levels asHere ${\mathrm{Li}}_s(z)={\sum }_{j\ge 1}{z}^j/j^s$, obtained directly from the supplied integral identity. At the Bose-Einstein condensation threshold, $z\uparrow 1$ and the excited states are just able to hold all $N$ particles. ThusThe ground-state population is treated separately from the continuum density of states.

Assume $A>0$ and $\alpha >0$, so the excitation energy increases with momentum and vanishes in the ground state. With one internal state, the number of states in a spherical momentum shell is $V4\pi k^{2}dk/(2\pi {)}^3$. Since $k=(ϵ/A{)}^{1/\alpha }/\hslash$,An internal degeneracy multiplies this density of states by its degeneracy factor.

The Bose-Einstein distribution is $\bar{n}(ϵ)=[e^{(ϵ-\mu )/(k_{B}T)}-1{]}^{-1}$. For a finite nonnegative occupation of the zero-energy state, its denominator must be positive, requiring $\mu <0$. At Bose-Einstein condensation the thermodynamic-limit chemical potential approaches $0$ from below, and the ground state must be counted separately; therefore “$\mu <0$” is a finite-system condition, while the condensed limit has $\mu =0$.

In a box whose shape is fixed, each momentum quantum number scales as $V^{-1/3}$, so each energy level scales as $V^{-\alpha /3}$. Differentiating the grand potential $\Omega =k_{B}T{\sum }_j\log (1-e^{-({ϵ}_j-\mu )/(k_{B}T)})$ at fixed $T,\mu$ givesThe zero-energy condensate contributes neither pressure nor kinetic energy.

The number outside the ground state isAt $\mu \uparrow 0$, its low-energy integrand is proportional to ${ϵ}^{3/\alpha -2}$. The integral is finite precisely when $3/\alpha >1$, soFor these exponents, the maximum excited population isThis follows by expanding the Bose denominator in positive exponentials and integrating each term. It tends to zero as $T\downarrow 0$, forcing excess particles into the ground state at fixed nonzero total number. At $\alpha =3$ the divergence is logarithmic; for $\alpha >3$ it is stronger, so there is no positive-temperature thermodynamic-limit condensation of this homogeneous gas.

Photons have $\alpha =1$ and two polarizations, but in ordinary blackbody equilibrium their number is not conserved and $\mu =0$ at every temperature. Cooling reduces their number rather than forcing an excess into a ground state, so an ordinary equilibrium photon gas does not condense. Systems imposing an effective photon-number constraint and an appropriate confined spectrum are different from the unconstrained photon gas considered here.

The Bose-Einstein distribution gives $n_i=[\exp ((E_i-\mu )/(k_{B}T))-1{]}^{-1}$, with chemical potential below the lowest energy when its discrete occupation is finite. In the continuum approximation,If the zero-energy ground state is macroscopically occupied, its discrete occupation $N_0$ must be added to the first integral; it contributes no energy to the second. This distinction is essential when applying the formulas to Bose-Einstein condensation.

For fixed particle number, Bose-Einstein condensation means that a macroscopic fraction occupies the single-particle ground state. As $\mu \uparrow 0$, the excited-state population reaches its maximumAt the transition this equals $N$, soBelow $T_c$, the chemical potential is approximately zero in the large-$N$ continuum description. Additional particles occupy the ground state, givingFor finite $N$, the actual chemical potential remains slightly negative; the saturation statement is the macroscopic approximation used here.

At fixed temperature, the excited population is largest as $\mu \uparrow 0$, henceIf $N>N_{ϵ}^{\max }$, the excited levels cannot accommodate all particles. The excess $N-N_{ϵ}^{\max }$ occupies the zero-energy level macroscopically: this is Bose-Einstein condensation.

The Bose-Einstein distribution isPositivity requires $\mu$ not to exceed the ground-state energy, here zero. For a finite system above the condensation limit one has $\mu <0$; it approaches zero from below at Bose-Einstein condensation.