The Reynolds number compares inertial and viscous effects:where is fluid mass density, a characteristic swimming speed, a characteristic body length, and the dynamic viscosity. Both swimmers are in the same fluid, so the fluid properties cancel from the ratio:For an order-of-magnitude estimate, take , , and . With water values and , these giveand henceThe dimensions and swimming speeds are estimates, so this ratio is not a universal species-independent constant. Its physical significance is robust: viscous forces dominate the bacterium's motion, whereas fluid inertia is crucial for the whale.
single-molecule force spectroscopy measures force and extension of an individual tether while controlling position or load. In an atomic-force arrangement, a synthetic chain connects a cantilever probe to a translated substrate. For the cantilever compliance correction, a deflection sensor gives , a calibrated spring constant gives , and substrate displacement gives chain extension after geometric offsets are removed. Additional linkers and instrument compliance must be included if appreciable. Thermal deflection calibration uses only after isolating the cantilever's calibrated thermal contribution.
An optical-tweezers implementation detects a tethered bead's displacement from a calibrated trap centre, with in the harmonic regime. Detector calibration, drag and trap linearity determine the usable force and frequency range. These instruments measure individual force–extension curves and distributions; averaging many curves can hide multiple tether populations.
For a synthetic freely jointed chain with Kuhn length ,A strongly stretched worm-like chain instead has before backbone stretching becomes important. Fits can estimate contour and persistence lengths only in their appropriate regimes. Hysteresis and pulling-rate dependence test whether an apparent mechanical transition is quasistatic or activated.
Control single versus multiple attachments, subtract nonspecific adhesion, vary pulling speed, calibrate temperature and stiffness, and correct drift. A rupture peak is not a universal bond strength independent of loading history. A primary nonbiological example measured individual polydimethylsiloxane chains by atomic-force methods; its flexibility interpretation combines those measurements with molecular calculations.[ref]
Let the channel length be and assume uniform solution conductivity. Its Ohmic resistance scales as , whereas access resistance of a reservoir mouth scales as . The fraction of voltage in the entrance regions is therefore of order . Most of the potential drop lies inside the long channel; the small entrance field region is neglected in the model, not asserted identically zero.
Write for inserted contour length and choose to pull the chain inward. The charge already inside feels force , givingConfinement removes polymer configurations. In the stiff-chain regime, the confinement deflection length obeys , hence . A free-energy cost of order per deflection gives a roughly constant resisting entropic force . The insertion barrier of a charged polymer follows from , with an entry maximum at when that point lies within the insertion interval. Its height is . The field supplies work against this confinement entropy.
Put , so . After capture, neglect the entry barrier, exterior-chain drag and thermal corrections to strong directed motion. ThenThe confined-polymer entry and recoil times have different length dependence; this entry graph is linear through the origin. Charge and drag both grow with inserted length, leaving a constant velocity. The same cancellation explains length-independent mobility in an ideal free-draining electrophoresis model. It does not include a capture waiting time or claim that every free-solution chain has identical hydrodynamic drag.
A measured superlinear entry time can arise when exterior-coil drag, tension propagation, wall adsorption or nonuniform friction adds length dependence absent from this model. For example with the same drive gives for . Under the assumptions of uniform wall charge and polymer entry scaling, a homogeneous thin-double-layer electro-osmotic model adds a length-independent fluid velocity . It changes the drift coefficient, not its length exponent. This does not rule out charge heterogeneity, adsorption or near-cancellation followed by diffusion in a real channel; those are additional mechanisms.
With the field off, the confinement entropy drives outward motion. Assuming the constant force and the same local friction,The small final end region lies outside the long-confined-segment approximation but gives only a small correction. Thus ideal insertion scales as , while recoil scales as .
TODO: user-deferred DNA-specific numerical stopping-voltage estimate and its biological parameter-based inference. No biological quantities are evaluated.
For entropic-trap length separation, a reservoir/channel array can repeat length-dependent capture, confinement and relaxation delays, turning them into different mean residence times. The uniform inside-channel drift speed derived above is itself length independent, so that drift alone cannot separate lengths. Separation must retain length dependence of the barrier or of the capture/recoil dynamics and can be tuned with a forward-biased time-dependent field. For large bulk throughput, pressure-driven advection is preferable to diffusion alone; a pressure gradient can be combined with electric capture control. In the unobstructed continuum limit . Excessive driving erases trapping differences, so throughput and resolution compete; the question supplies no geometry or adsorption law selecting a unique optimal drive.
Past exam of the symmetry and relativity course of the University of Oxford 2019 1 b Solution 2026-10-25
Let denote the constant rest mass, set , and put . The relativistic three-force is , soIt follows thatIntegrating the velocity with the initial position fixed givesThese formulas allow either sign of ; their limit is rest at the origin. For , the trajectory obeysThis is hyperbolic motion. Its coordinate acceleration decreases while its proper acceleration has constant magnitude . In particular, a constant three-force does not give constant coordinate acceleration at relativistic speed.
Past exam of the symmetry and relativity course of the University of Oxford 2019 1 e Solution 2026-10-25
For causal reachability on a spatial circle, put and use a representative of the spatial circle. The lower-left panel of part c is a fundamental strip with its vertical edges identified. On the covering space the charged world line is still the solution of part b; on the quotient it isA jump between opposite strip edges is a coordinate seam, not a discontinuity of the physical world line. At its th complete lap, , soFor , the speed increases on each return while remaining below . Its kinetic energy increases byThere is no single-valued electrostatic potential energy on a circle: the nonzero electromotive force is . A globally defined magnetic vector potential one-form instead makes the driving explicit. In an embedded circuit, Faraday's law realizes this electromotive force through changing magnetic flux. More generally an external apparatus maintaining the field supplies the increasing particle energy. In an isolated dynamical field-plus-particle system, backreaction would change the field. Thus this is not a cyclic machine extracting work from a conservative potential, and it does not violate conservation of energy.
Past exam of the symmetry and relativity course of the University of Oxford 2019 4 a Solution 2026-10-25
Use and the mostly-plus Minkowski metric. Then the source's Klein-Gordon equation is . For a plane wave , substitution givesThus a real propagating wave vector requires , or on restoring units. The positive-energy branch has a rest-energy threshold . At , ; frequencies below the mass threshold give evanescent spatial dependence rather than real-wave-vector propagation. Both signs of occur in the classical equation; a real scalar field combines complex-conjugate modes. Its group velocity is and is subluminal, though the positive-branch phase speed exceeds one when .
For a static spherically symmetric scalar field, the equation outside the source isSetting gives , soDecay at infinity selects , the Yukawa potential. It is singular at the origin and describes a point source distributionally; a source-free solution regular at the origin and decaying at infinity must be zero. For , , and decay sets the constant to zero.
Past exam of the symmetry and relativity course of the University of Oxford 2021 3 a ii Solution 2026-10-25
In the magnetic-dominated case the suitable Lorentz boost instead hasThe hypothesis gives . The electromagnetic field invariants now have , allowing a purely magnetic inertial frame. The initial velocity is again , perpendicular to . Since a magnetic field does no work, the electron's relativistic energy and speed in this inertial frame remain constant. Its trajectory is a circle in the plane with Lorentz factor and cyclotron frequency .
For , set and . A parametrization with the correct initial velocity and Lorentz force isTransforming the world line back to the laboratory givesThe laboratory trajectory is a stretched cycloid, with cusps at where the electron is momentarily at rest. It first accelerates toward , then curves toward , returning to its original coordinate each cycle while advancing in . Its mean drift is , the E-cross-B drift. Its laboratory kinetic energy oscillates as the electric field does positive and then negative work; it does not grow indefinitely. The strict inequalities in the two branches exclude the null case , where neither field can be removed by a finite Lorentz boost.
Past exam of the symmetry and relativity course of the University of Oxford 2022 3 d Solution 2026-10-25
Let and in A. Each has Lorentz factor . The relative Lorentz factor of in the rest frame of follows from their four-velocity tensor contraction:Let be the relative speed divided by . In the rest frame of , take between the photon's propagation direction and 's velocity. The observed angular frequency is the invariant . Applying it to the emitter, whose rest angular frequency is , gives . Since ,This is a relativistic Doppler effect calculation using both emitters' and receivers' rest clocks; the time delay of reception introduces no extra factor for constant velocities.
For the direction in A, write the wave four-vector as , where is a unit vector. Equality of the emitted and received angular frequencies gives . Since the two laboratory Lorentz factors are equal, their time components cancel:Thus the complete answer in three spatial dimensions isIf propagation is additionally assumed to lie in the stars' motion plane, this reduces to either direction along the internal angle bisector, or from . Reflection exchanging the stars' laboratory velocities explains the angle bisector by symmetry. The source does not specify coplanar propagation or the stars' positions, so it does not fix the sign or exclude an out-of-plane ray. For example gives and satisfies the same no-shift condition. Initial positions can be chosen to make such a ray connect emission and reception. All these possibilities give the same rest-frame above.
Past exam of the symmetry and relativity course of the University of Oxford 2022 4 a Solution 2026-10-25
For constant laboratory force and initial rest, integration gives three-momentum . The energy–momentum relation gives , and , soFor and , its speed increases monotonically, is strictly below the speed of light at every finite time, and obeys . Thus is the limiting supremum, rather than a speed attained at a finite time. The degenerate case leaves the particle at rest and does not have this limit.
Use the amplitude placement in the original PDF: . Introduce the actual peak and , so . Its derivatives satisfyThe static equation is . Matching the constant and terms givesChanging the sign of leaves the profile unchanged. If is instead defined as an outside prefactor, as in the held TeX transcription, its value is , not the PDF's . This notation discrepancy does not change the physical profile.
The nonconstant positive power-law nonlinear Klein-Gordon pulse is even, smooth, has peak at zero and decays as . The requested sketches below compare several powers with illustrative . For odd , its negative is also a solution. A separate constant branch occurs for : the positive equilibrium has , or in the PDF convention. The zero solution is another equilibrium, obtained as a limiting profile rather than finite positive .
Now apply the Lorentz boost with rapidity to the static field. It givesFor positive , the centre moves to the right at , with speed one the wave-speed unit. The peak stays and the width contracts by . The shape translates without changing in time. This establishes a travelling solitary pulse; it does not by itself prove stability or elastic multi-pulse scattering.


