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Past exam of the advanced quantum physics course of the University of Cambridge 2013 Paper 1 2 b Solution by
Codex 0 2026-10-20
A single-mode coherent state is an annihilation operator eigenstate:Its photon statistics are Poisson distribution: . For optical quadratures , , one has and . Its field mean oscillates classically while retaining vacuum fluctuations.[ref]
Topics in Quantum Mechanics by David Tong. §4.4.2, printed pp.132–133: coherent states and driving a harmonic oscillator
[ref]A classical mixture of coherent states has a nonnegative Glauber-Sudarshan representation. A nonclassical state of light cannot be represented that way. Examples are a squeezed vacuum state, with quadrature variances and , and a nonvacuum number state, with zero photon number variance. Noise below the vacuum level in one quadrature, sub-Poisson number noise, or photon antibunching can witness nonclassicality. For , ; coherent light has . Thermal light has excess noise but is a classical mixture: noncoherent does not by itself mean nonclassical.
Past exam of the advanced quantum physics course of the University of Cambridge 2013 Paper 1 2 a Solution by
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For identical particles, the particle exchange operator exchanges both spatial and spin labels. The symmetrization postulate requires a symmetric full state for bosons and an antisymmetric full state for fermions. A product must therefore have spatial and spin exchange eigenvalues whose product is or , respectively; a general state may be a sum of such products.
For orthonormal spatial orbitals , the combinations have opposite exchange parities. Two spin-one-half fermions combine with the antisymmetric spin-one-half singlet state , or with one of the three symmetric spin-one-half triplet states. Two particles in the same spatial orbital must be a spin singlet. This is the Pauli exclusion principle applied to complete spin orbitals, not a ban on sharing a spatial orbital with opposite spins.
A Slater determinant enforces fermionic antisymmetry for many occupied spin orbitals. Bosonic symmetrization instead uses a permanent; repeated orbital occupations are allowed. These exchange requirements apply even when particles do not interact.
Past exam of the advanced quantum physics course of the University of Cambridge 2013 Paper 1 1 c Solution by
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Centre the infinite square well at zero. Its ground state wavefunction is inside the well and zero outside. The momentum representation in quantum mechanics gives the wavevector amplitudeConsequently the unnormalised wavevector distribution of an infinite-well ground state isThe apparent singularities at are removable. The normalized probability density is times the boxed expression and has limit there. Translating the well changes only the Fourier transform's phase. The wavevector is continuously distributed; a box energy eigenstate is not a free momentum eigenstate.
Past exam of the advanced quantum physics course of the University of Cambridge 2013 Paper 1 1 b Solution by
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Adjacent nodes of a wavefunction are separated by roughly , so a locally sinusoidal wavefunction has typical wavevector . The kinetic-energy estimate from wavefunction nodes is thereforeEquivalently, . The robust scaling is ; the precise coefficient depends on how the extent is defined and how the oscillations vary near classical turning points. For few nodes, use an order-one offset to : the nodeless ground state still has confinement energy bound from position support of order , rather than zero.
Past exam of the advanced quantum physics course of the University of Cambridge 2013 Paper 1 1 a Solution by
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Put . Angular momentum addition gives , and the spin-dot-product eigenvalue isThus the spin-three-halves pair spectrum isFor identical fermions, exchange parity of two coupled identical spins makes spin-antisymmetric and spin-symmetric. Corresponding spatial exchange symmetries make the full state antisymmetric; without a specified spatial state, none of these total-spin sectors is excluded.
Past exam of the advanced quantum physics course of the University of Cambridge 2012 Paper 1 2 c Solution by
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A three-level laser uses a pump transition from ground level1 to a higher level3, rapid relaxation , and a long-lived upper lasing level2. The laser transition is , so its lower level is the ground state. Fast feeding and slow upper-state decay allow excitation to accumulate, unlike steady resonant pumping of a simple two-level transition.
Stimulated emission adds photons to the stimulating optical mode, but ground-state photon absorption competes with it. The population inversion condition is when the relevant transition strengths obey the usual Einstein relations. For equal degeneracies and negligible , it reduces to , requiring more than half the active population in level2.
For a simple pump rate R per ground-state emitter, fast relaxation and negligible laser intensity, the three-level laser rate equation reduces toThis three-level ground-state inversion threshold is only transparency; positive gain must also overcome optical losses. For an illustrative uniformly filled cavity of length , equal absorption/emission cross-section , internal intensity-loss coefficient and mirror power reflectivities , the threshold condition isHere are number densities, unlike the total populations . The optical resonator supplies feedback and selects modes; a partially transmitting mirror couples out light. Spontaneous emission seeds the field, and stimulated transitions deplete the inversion until saturated gain balances loss. A ruby laser is the standard example. Real level degeneracies, branching losses and pump saturation modify the simple equations. [ref]
Fundamentals of Photonics and Quantum Electronics lecture notes by Franz X. Kärtner. Chapter7§§7.1–7.2.1, printed pp.293–298, optical feedback and three-/four-level media; original reduced ground-state model specified above
Past exam of the advanced quantum physics course of the University of Cambridge 2012 Paper 1 2 b Solution by
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For a point, stationary proton, the leading hydrogen fine structure comes from three order- contributions to the nonrelativistic electron Hamiltonian:These are the relativistic kinetic-energy correction, spin-orbit interaction and Darwin term. The spin-orbit coefficient includes the Thomas precession factor of one half; . The Coulomb Darwin contribution is a positive contact term, relevant for S states. These corrections distinguish total angular momentum , while leaving magnetic substates degenerate without an external field.
Writing , the combined hydrogen fine-structure correction isThus the splitting is of order times the principal binding energy. In the shell, and remain degenerate in this approximation, while is higher by . The Lamb shift lifts the remaining S–P degeneracy; hyperfine structure is a separate nuclear-spin effect. Neither is part of the displayed correction. Nuclear recoil and finite nuclear size have also been neglected. [ref]
Past exam of the advanced quantum physics course of the University of Cambridge 2012 Paper 1 2 a Solution by
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The WKB approximation, also called JWKB, describes a short local de Broglie wavelength in a slowly varying potential energy. For in a classically allowed region, its two local waves areThe phase follows the classical momentum; its amplitude varies to conserve probability current. In a forbidden region, putting gives , with boundary conditions selecting the physical combination.
The WKB validity condition is , with the analogous condition on . It fails at a turning point where . For a simple turning point, locally linearizing V yields an Airy function; matching fixes the relative amplitudes and a phase. Two such turning points give the two-turning-point WKB quantization conditionFor an opaque barrier, the WKB tunnelling exponent instead givesThe factor two distinguishes probability from amplitude. Matching determines the prefactor; the exponential alone is not accurate near the barrier top. These formulas connect bound state energy eigenvalues and quantum tunnelling to classical actions. [ref]
Topics in Quantum Mechanics by David Tong. §2.2, printed pp.37–49, semiclassical expansion, Airy matching and tunnelling
Past exam of the advanced quantum physics course of the University of Cambridge 2012 Paper 1 1 c Solution by
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The coherent state satisfies , and . The canonical commutation relation adds the vacuum term . Thereforeand the coherent-state electric-field variance isHere is taken positive as the field-amplitude scale. The coherent state displaces the mean field without changing this vacuum optical quadrature noise.
Past exam of the advanced quantum physics course of the University of Cambridge 2012 Paper 1 1 b Solution by
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For the linear rigid rotor, and the electric electric dipole moment interaction is . The isotropic state has no first-order shift. Its only coupled rotational state is , at gap , giving the quadratic Stark shift of a polar linear rotorUsing and the supplied I and d givesThe negative sign is the expected second-order Stark effect of a nondegenerate ground state. The mixing parameter is small, supporting the weak-field estimate. The constants h and use their defined SI values; no molecular input beyond the supplied data is needed.
Past exam of the advanced quantum physics course of the University of Cambridge 2012 Paper 1 1 a Solution by
Codex 0 2026-10-20
The closed shells have , so only the two equivalent p electrons matter. Their addition of angular momentum allows and , subject to the Pauli exclusion principle. Interchanging two orbital states has sign : even L is spatially symmetric and needs the antisymmetric spin singlet; odd L is spatially antisymmetric and needs the symmetric spin triplet. Thus the allowed LS terms of a p-squared configuration are , and .
In LS coupling, . The complete list of term symbols is thereforeThey contain magnetic substates, exhausting the antisymmetric two-electron space. All have even spatial parity, since each p orbital is odd.
Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2016 Paper 1 3 c Solution by
Codex 0 2026-10-20
Use a three-dimensional electron gas with a uniform positive background, the jellium model. The Hartree-Fock method minimizes the expectation of the interacting Hamiltonian over normalized Slater determinants. Antisymmetry is exact within that trial class, but correlations requiring a superposition of determinants are omitted. For orthonormal occupied spin orbitals , the energy iswhere is the direct Coulomb integral and the exchange integral; the spin overlap makes exchange vanish between opposite-spin orbitals. The self-interaction terms and cancel. Variation gives a self-consistent Fock operator ; exchange is nonlocal. Its eigenfunctions define occupied orbitals of a stationary determinant, and the determinant must be compared with competing self-consistent solutions to select a variational ground state.
The eigenvalues are orbital Lagrange multipliers. Their sum counts each interaction twice:Frozen-orbital removal energies may be estimated using Koopmans' theorem, but measured quasiparticle energies can contain relaxation and correlations absent from this approximation. Unoccupied orbital energies are not automatically an exact excitation spectrum. In particular, unscreened exchange in a uniform three-dimensional gas produces an unphysical logarithmic slope singularity at its Fermi surface; a one-determinant mean field does not reproduce the interacting Fermi liquid's screened response.
For a spatially uniform plane-wave determinant, electron-background and background-background terms cancel the uniform direct Coulomb contribution. Retain the background when making this cancellation: an isolated infinite electron charge distribution would have a divergent direct energy. The surviving contributions per particle are kinetic energy and negative same-spin exchange energy. Let define the Dimensionless Wigner-Seitz radius, with , and . ThenFor the unpolarized state this is approximately . The kinetic contribution penalizes spin polarization because it enlarges an occupied Fermi sphere; exchange favors polarization because equal-spin occupation gains more exchange energy. As density falls, the exchange scale overtakes the kinetic scale. The uniform fully polarized and unpolarized energies cross atThis is a variational comparison within the homogeneous Hartree-Fock electron gas, not an exact physical ferromagnetic phase boundary. It demonstrates how Pauli kinetic energy and exchange compete and why the allowed trial states matter.
Allowing spatial symmetry breaking changes the result: the Overhauser instability lowers the paramagnetic determinant's Hartree-Fock energy through a spin density wave, even in the high-density limit. A calculation restricted to uniform Fermi spheres therefore does not give the unrestricted Hartree-Fock ground state.[ref]
Spin Density Waves in an Electron Gas by A. W. Overhauser. abstract and p. 1437, instability of the uniform paramagnetic state to spin-density waves
At still lower density, localization and a Wigner crystal compete with fluid states. electron-gas correlation energy beyond a single determinant is important in assessing their competition. Quantum Monte Carlo provides a concrete route to comparing correlated fluid and crystal energies; the original stochastic calculation demonstrates why exchange-only energy differences are insufficient.[ref]Ground State of the Electron Gas by a Stochastic Method by D. M. Ceperley and B. J. Alder. abstract and pp. 566–569, correlation energies and competing fluid/crystal states
Hartree-Fock is a useful variational baseline with exact exchange, not a controlled complete low-density phase diagram. At high density the kinetic scale dominates, but even a small symmetry-breaking energy gain can invalidate a restricted determinant as the exact Hartree-Fock minimizer. At low density neglected correlations, screening and localization can change both transition locations and the ordering of candidate phases. A numerical phase boundary should therefore state dimension, spin constraints, background model and whether correlation and spatially modulated states were included.
Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2016 Paper 1 3 b Solution by
Codex 0 2026-10-20
A quantum dot confines electronic motion in all three directions. A semiconductor dot can be thin enough that only one transverse subband is occupied, with discrete lateral states controlled by gates. In a rectangular hard-wall model,A smooth circular lateral confinement is often better approximated by , giving above the transverse ground energy. Shell contains orbitals, twice that many electrons before interactions split the spin degeneracy. Hence closed-shell electron numbers are . These are single-particle quantum numbers; an interacting dot's states are many-electron eigenstates, not simply one orbital occupied by a whole charged island.
A perpendicular magnetic field changes the harmonic spectrum to the Fock-Darwin spectrum. For an electron of charge , take and in the usual symmetric gauge. ThenReversing the definition of the angular label changes the displayed sign of its orbital term, not the set of energies. The Zeeman term lifts spin degeneracy, while exchange can favor parallel-spin filling in partially filled shells. These effects are distinguished by how peaks evolve with field rather than by identifying every irregular peak spacing with one-particle confinement.
For electrostatics, let and , where represents a fixed offset charge in the chosen convention. The constant interaction model givesThe charging energy is conventionally , whereas adjacent charge-state potentials differ byThis addition energy separates a capacitive contribution from orbital spacing. Exchange, nonuniform screening and correlations are corrections to the constant interaction model; a change in dot shape or effective capacitance can also alter spacings.
Connect the island weakly to source and drain reservoirs through tunnel barriers. sequential tunnelling is suppressed in a charge-stable region when neither adding nor removing an electron is energetically accessible. Sweeping the gate brings a charge electrochemical potential through the reservoir Fermi level, giving a Coulomb-blockade conductance peak. The gate lever arm is , so locally if the capacitances and level spectrum do not vary appreciably. At finite source-drain bias, alignment with either reservoir defines the boundaries of a Coulomb diamond. Its slopes constrain capacitance ratios, and lines parallel to its edges can reveal excited-state transport. The conversion from a diamond's bias height to an energy depends on bias convention; a full-height/half-height factor must not be assumed without declaring the circuit.
A clear charging spectrum requires and tunnel broadening smaller than the relevant addition energy; resolving individual orbital levels additionally requires them smaller than the orbital spacing. Tunnel resistances large compared with suppress strong charge fluctuations in the usual weak-junction regime. Blockade is not an assertion of mathematically zero current: higher-order cotunnelling can remain, and strong coupling or low-temperature spin correlations can invalidate the sequential model. An experimental check therefore combines gate sweeps with bias spectroscopy, temperature dependence and barrier tuning to separate level structure from broadening or uncontrolled charge traps.
In a primary vertical-dot experiment, gate-controlled current oscillations were converted into addition energies using finite-bias diamond spectroscopy; varying magnetic field then followed shell and spin filling. Reproducing enhanced addition energies at electron numbers 2 and 6 in several devices strengthened the shell assignment. The electron temperature was independently estimated above the refrigerator base temperature, an essential distinction when judging spectral resolution. Field-dependent reordering also revealed exchange effects beyond a purely spin-degenerate orbital model.[ref]
Shell Filling and Spin Effects in a Few Electron Quantum Dot by S. Tarucha and others. pp. 3613–3616, gate control, finite-bias calibration, sample comparisons, electron-temperature estimate and field-dependent spin filling
Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2016 Paper 1 3 a Solution by
Codex 0 2026-10-20
A Bravais lattice is the translation set generated by primitive lattice translation vectors. Translating by any member of leaves its surroundings equivalent. A crystal structure requires both this lattice and an atomic basis attached to every lattice point. The basis can lower the symmetry of the bare point lattice; a familiar-looking geometrical arrangement of atoms is not necessarily itself a Bravais lattice. For example, the diamond cubic structure is a face-centred cubic lattice with an identical-atom basis at fractional positions and in conventional cubic coordinates. The displacement between those two basis atoms is not itself a lattice translation.
The seven three-dimensional crystal systems are triclinic, monoclinic, orthorhombic, tetragonal, trigonal, hexagonal and cubic; the distinct translation types give 14 Bravais lattices. A conventional cell can contain several lattice points, while a primitive unit cell contains one. Simple cubic primitive lattice translation vectors can be chosen along the cube edges; for face-centred cubic they can be , and . Their primitive volume is , explaining the four lattice points per conventional face-centred cell.
A crystallographic point group comprises the orthogonal parts of the crystal's spatial symmetry operations. It constrains possible rotations, reflections, inversion and their combinations, while forgetting translations. Lattice preservation restricts proper rotational orders in three dimensions to ; a fivefold axis cannot be a symmetry of a periodic three-dimensional lattice. One quick argument restricts a rotation's integral lattice representation through , an integer trace, producing these orders. There are 32 crystallographic point-group types. Examples are the cubic full octahedral group with Hermann–Mauguin symbol , the tetrahedral class with symbol , and the polar tetragonal class with symbol .
The space group retains the full isometry. In Seitz notation acts by , and multiplication isIts translation subgroup is normal and the quotient is the crystallographic point group. A screw axis combines rotation with translation along the axis; for example, applying a screw twice gives one whole lattice translation. A glide plane combines reflection with a translation parallel to the plane; applying the glide twice likewise gives a translation. These operations can preserve the complete crystal without their rotation or reflection alone preserving it.
A symmorphic space group admits an origin and representatives for which the point-group operations have no translation component. A nonsymmorphic space group has essential fractional translations that cannot all be removed by moving the origin. There are 230 three-dimensional space-group types, distinguished more finely than their point groups. These counts refer to ordinary, nonmagnetic periodic space groups; magnetic and aperiodic generalizations are different classifications.[ref]
International Tables for Crystallography, Volume A: Space-group symmetry. 2016 edition, overview and Part 1 introduction to crystallographic and space-group symmetry
For concrete comparisons, a monatomic simple-cubic crystal has space group and point group . Rock salt has a face-centred cubic lattice, a two-species basis and symmorphic space group . Diamond has the same cubic point group and translation-lattice type, but its basis leads to nonsymmorphic . Replacing the two diamond basis sites by distinct species gives the zinc blende structure, exemplified by GaAs, with and point group ; inversion that would interchange the species is no longer a symmetry. The lattice specifies translations, the point group specifies the linear symmetry classes, and the space group specifies their complete spatial implementation. These examples show why none alone uniquely describes an atomic structure.
Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2016 Paper 1 1 c Solution by
Codex 0 2026-10-20
electron confinement raises the conduction edge and hole confinement lowers the corresponding valence edge, so their positive confinement energies add. With nm, the common bare-mass scale isWriting and , the quantum-well interband thresholds areUse eV and eV. The thresholds in the requested window, using the printed masses without fitting, areThe next heavy-hole and split-off thresholds are about and eV, outside the interval. Each threshold marks a continuum onset or shoulder, not the stronger bound-exciton peak below it. The six heavy- and light-hole onsets follow the six paired peak groups in the supplied diagram. Their first members lie roughly 20 and 12 meV below their respective onsets, as the common solution above explains.
A qualification is necessary for the split-off branch. Its p-like bloch states have nonzero matrix elements to the s-like conduction states, so in-plane polarization does not generally forbid them. For example, a state has a nonzero orbital component with the appropriate spin, which couples to an s-like state through . The same-envelope rule therefore allows the two split-off thresholds in the table. The first nearly coincides with the third heavy-hole edge, while the second would give an additional onset near 2.086 eV. The supplied figure and twelve peak energies appear to retain only the heavy- and light-hole series; they do not specify a split-off-series oscillator strength or identify its extra features. Omitting the split-off transitions would require an additional approximation beyond the four-band information and polarization given. Their expected ideal two-dimensional first-state peaks would be near 1.9010 and 2.0701 eV; these are predictions of the stated model, not additional listed data.
Original calculated continuum-edge map for all supplied bands and comparison of heavy- and light-hole peak-pair splittings
. Details. Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2016 Paper 1 1 b Solution by
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For a fixed allowed band/subband pair, parabolic dispersions give . If the photon energy exceeds the edge, the contour is a circle of radius and the gradient magnitude is . ThusBelow threshold the contour is absent. With the conventional normalization, the two-dimensional joint density of states per area and independent channel isWith a locally energy-independent optical matrix element, each allowed pair therefore adds a constant step to the continuum dielectric function in the approximation of the supplied equation. Different hole families need not have equal step heights: reduced masses, spin multiplicities and Bloch-state matrix elements differ. Frequency-dependent overall optical prefactors, nonparabolicity, broadening and excitonic Coulomb enhancement can modify the literal step shape outside this approximation.
Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2016 Paper 1 1 a Solution by
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Choose the growth direction as and the well as . In the envelope function approximation, write a subband state as , where is the band-edge cell-periodic Bloch factor. The infinite square well hasThe envelope has the same shape for electron and hole states: changing their effective masses changes the eigenenergies, but not these infinite-well eigenfunctions. With in-plane polarization, the leading interband momentum matrix element acts on the Bloch factors, while the slow envelopes giveorthonormality therefore yields the infinite-well interband selection rule . A nonzero band-level matrix element is still required; the overlap rule does not replace polarization selection rules. Finite barriers can make electron and hole envelopes different, and interface asymmetry or band mixing can relax this ideal same-index rule.
Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2015 Paper 1 3 f Solution by
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Use an oxygen-mediated superexchange path between two magnetic metal orbitals. A minimal one-active-orbital three-site charge-transfer superexchange Hamiltonian is clearest in a hole representation:Here describes a metal hole, a ligand hole, and is the energy needed to create the virtual ligand hole. The low-energy configuration has one hole on each metal orbital and no ligand hole, corresponding to a filled bridging ligand orbital in the electron picture. and penalize double hole occupancy on the corresponding sites.
Virtual metal–ligand hopping transfers charge through oxygen without producing a real mobile carrier. Eliminating the ligand gives an effective metal–metal hopping . Combining it with the large metal repulsion givesA ligand double-occupancy channel adds a contribution of the same sign for the simple half-filled straight-bond model, often organized as . The precise coefficients depend on the orbitals and hopping conventions; the essential mechanism is virtual charge transfer plus spin-selective access to intermediate states. The effective spin interaction favors antiparallel alignment while the material can remain insulating.
For MnO's rock salt structure, the strong approximately Mn–O–Mn path joins next-nearest Mn sites. It is not the nearest fcc Mn–Mn separation used in the direct-overlap estimate of part e. The oxygen-mediated path avoids relying on the tiny direct overlap of the two distant 3d tails. A realistic model includes several Mn 3d orbitals, Hund coupling and the high-spin Mn ion; the single-orbital Hamiltonian above isolates the antiferromagnetic exchange channel. Approximately paths and different orbital occupancies need not have the same sign.
Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2015 Paper 1 3 e Solution by
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An overlap estimate must use nearest magnetic-ion separations. For the face-centered cubic lattice of Mn, ; for the body-centered cubic lattice of Fe, . The supplied radial functions have inverse decay lengths . Their intersite overlap therefore contains approximately , up to polynomial and angular factors. The decisive exponent difference isThe exponential orbital-tail estimate of exchange thus gives a hopping suppression approximately before polynomial corrections. Keeping the supplied radial prefactor in a midpoint overlap proxy givesThis proxy is not an evaluated hopping integral, but confirms that the polynomial factors do not undo the exponential loss. If comparable Coulomb denominators and nonexponential prefactors are assumed, a kinetic-exchange scale proportional to is suppressed by roughly –. Direct intersite Coulomb exchange likewise contains products of the small tails. Coordination-number differences cannot compensate for many orders of magnitude.
By contrast, the measured ordering-temperature ratio supplied in the question is , not an exponentially tiny number. Within this overlap model, direct Mn–Mn exchange cannot explain MnO's substantial magnetic ordering scale by extrapolating the Fe mechanism. Another exchange path is required.
This is an order-of-magnitude argument, not an exact relation between an itinerant Curie temperature and a localized-spin Néel temperature. The hydrogenic functions use the printed bare values; actual solid-state orbitals are screened and hybridized. Their literal absolute exchange scales should not be treated as quantitative predictions for Fe or MnO.
Past exam of the advanced Quantum Condensed Matter Physics course of the University of Cambridge 2015 Paper 1 3 d Solution by
Codex 0 2026-10-20
Use for the six printed basis vectors. The three singly occupied triplets areEach has energy zero: either Pauli exclusion prevents hopping to double occupancy or the two contributions cancel. DefineThe state has energy . In the subspace the Hamiltonian is , withFor , the fourth low-energy eigenstate is the normalized singletwhere . Its energy isThe four lowest energies are to leading order, with the singlet and triplets just given. The upper pair lie near and .
The low-energy Hamiltonian can be writtenusing dimensionless spin-half operators. It places the singlet below the triplet by , hence favors antiferromagnetic alignment. A lattice of such bonds can support antiferromagnetism, although its ordering pattern also depends on geometry and competing couplings. The physical energy gain comes from virtual charge fluctuations, not from a permanent double occupancy in the large- limit.
Exact singlet-triplet spectrum of the two-site repulsive Hubbard model and the large-U exchange scale
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